Pythagorean Triangle and Special Pyramidal Numbers
Total Page:16
File Type:pdf, Size:1020Kb
Load more
Recommended publications
-
Triangular Numbers /, 3,6, 10, 15, ", Tn,'" »*"
TRIANGULAR NUMBERS V.E. HOGGATT, JR., and IVIARJORIE BICKWELL San Jose State University, San Jose, California 9111112 1. INTRODUCTION To Fibonacci is attributed the arithmetic triangle of odd numbers, in which the nth row has n entries, the cen- ter element is n* for even /?, and the row sum is n3. (See Stanley Bezuszka [11].) FIBONACCI'S TRIANGLE SUMS / 1 =:1 3 3 5 8 = 2s 7 9 11 27 = 33 13 15 17 19 64 = 4$ 21 23 25 27 29 125 = 5s We wish to derive some results here concerning the triangular numbers /, 3,6, 10, 15, ", Tn,'" »*". If one o b - serves how they are defined geometrically, 1 3 6 10 • - one easily sees that (1.1) Tn - 1+2+3 + .- +n = n(n±M and (1.2) • Tn+1 = Tn+(n+1) . By noticing that two adjacent arrays form a square, such as 3 + 6 = 9 '.'.?. we are led to 2 (1.3) n = Tn + Tn„7 , which can be verified using (1.1). This also provides an identity for triangular numbers in terms of subscripts which are also triangular numbers, T =T + T (1-4) n Tn Tn-1 • Since every odd number is the difference of two consecutive squares, it is informative to rewrite Fibonacci's tri- angle of odd numbers: 221 222 TRIANGULAR NUMBERS [OCT. FIBONACCI'S TRIANGLE SUMS f^-O2) Tf-T* (2* -I2) (32-22) Ti-Tf (42-32) (52-42) (62-52) Ti-Tl•2 (72-62) (82-72) (9*-82) (Kp-92) Tl-Tl Upon comparing with the first array, it would appear that the difference of the squares of two consecutive tri- angular numbers is a perfect cube. -
Integer Partitions
12 PETER KOROTEEV Remark. Note that out n! fixed points of T acting on Xn only for single point q we 12 PETER KOROTEEV get a polynomial out of Vq.Othercoefficient functions Vp remain infinite series which we 12shall further ignore. PETER One KOROTEEV can verify by examining (2.25) that in the n limit these Remark. Note that out n! fixed points of T acting on Xn only for single point q we coefficient functions will be suppressed. A choice of fixed point q following!1 the large-n limits get a polynomial out of Vq.Othercoefficient functions Vp remain infinite series which we Remark. Note thatcorresponds out n! fixed to zooming points of intoT aacting certain on asymptoticXn only region for single in which pointa q we a shall further ignore. One can verify by examining (2.25) that in the n | Slimit(1)| these| S(2)| ··· get a polynomial out ofaVSq(n.Othercoe) ,whereS fficientSn is functionsa permutationVp remain corresponding infinite to series the choice!1 which of we fixed point q. shall furthercoe ignore.fficient functions One| can| will verify be suppressed. by2 examining A choice (2.25 of) that fixed in point theqnfollowinglimit the large- thesen limits corresponds to zooming into a certain asymptotic region in which a!1 a coefficient functions will be suppressed. A choice of fixed point q following| theS(1) large-| | nSlimits(2)| ··· aS(n) ,whereS Sn is a permutation corresponding to the choice of fixed point q. q<latexit sha1_base64="gqhkYh7MBm9GaiVNDBxVo5M1bBY=">AAAB8HicbVBNS8NAEN3Ur1q/qh69LBbBU0lEUG9FLx4rWFtsQ9lsJ+3SzSbuTsQS+i+8eFDx6s/x5r9x2+agrQ8GHu/NMDMvSKQw6LrfTmFpeWV1rbhe2tjc2t4p7+7dmTjVHBo8lrFuBcyAFAoaKFBCK9HAokBCMxheTfzmI2gjYnWLowT8iPWVCAVnaKX7DsITBmH2MO6WK27VnYIuEi8nFZKj3i1/dXoxTyNQyCUzpu25CfoZ0yi4hHGpkxpIGB+yPrQtVSwC42fTi8f0yCo9GsbalkI6VX9PZCwyZhQFtjNiODDz3kT8z2unGJ77mVBJiqD4bFGYSooxnbxPe0IDRzmyhHEt7K2UD5hmHG1IJRuCN//yImmcVC+q3s1ppXaZp1EkB+SQHBOPnJEauSZ10iCcKPJMXsmbY5wX5935mLUWnHxmn/yB8/kDhq2RBA==</latexit> -
Input for Carnival of Math: Number 115, October 2014
Input for Carnival of Math: Number 115, October 2014 I visited Singapore in 1996 and the people were very kind to me. So I though this might be a little payback for their kindness. Good Luck. David Brooks The “Mathematical Association of America” (http://maanumberaday.blogspot.com/2009/11/115.html ) notes that: 115 = 5 x 23. 115 = 23 x (2 + 3). 115 has a unique representation as a sum of three squares: 3 2 + 5 2 + 9 2 = 115. 115 is the smallest three-digit integer, abc , such that ( abc )/( a*b*c) is prime : 115/5 = 23. STS-115 was a space shuttle mission to the International Space Station flown by the space shuttle Atlantis on Sept. 9, 2006. The “Online Encyclopedia of Integer Sequences” (http://www.oeis.org) notes that 115 is a tridecagonal (or 13-gonal) number. Also, 115 is the number of rooted trees with 8 vertices (or nodes). If you do a search for 115 on the OEIS website you will find out that there are 7,041 integer sequences that contain the number 115. The website “Positive Integers” (http://www.positiveintegers.org/115) notes that 115 is a palindromic and repdigit number when written in base 22 (5522). The website “Number Gossip” (http://www.numbergossip.com) notes that: 115 is the smallest three-digit integer, abc, such that (abc)/(a*b*c) is prime. It also notes that 115 is a composite, deficient, lucky, odd odious and square-free number. The website “Numbers Aplenty” (http://www.numbersaplenty.com/115) notes that: It has 4 divisors, whose sum is σ = 144. -
1 + 4 + 7 + 10 = 22;... the Nth Pentagonal Number Is Therefore
CHAPTER 6 1. The pentagonal numbers are 1; 1 + 4 = 5; 1 + 4 + 7 = 12; 1 + 4 + 7 + 10 = 22;... The nth pentagonal number is therefore n 1 2 − n(n 1) 3n n (3i +1) = n + 3 − = − . i 2 ! 2 X=0 Similarly, since the hexagonal numbers are 1; 1+5 = 6; 1+5+9 = 15; 1+5+9+13 = 28;... it follows that the nth hexagonal number is n 1 − n(n 1) (4i +1) = n + 4 − = 2n2 n. i 2 ! − X=0 2. The pyramidal numbers with triangular base are 1; 1+3 = 4; 1+3+6 = 10; 1+3+6+10 = 20; ... Therefore the nth pyramidal number with triangular base is n n k(k + 1) 1 1 n(n + 1)(2n + 1) n(n + 1) = (k2 + k)= + k 2 2 k 2 " 6 2 # X=1 X=1 . n(n + 1) 2n + 1 1 n(n + 1)(n + 2) = + = 2 6 2 6 The pyramidal numbers with square base are 1; 1+4 = 5; 1+4+9 = 14; 1+4+9+16= 30;... Thus the nth pyramidal number with square base is given by the sum of the squares from 1 to n, namely, n(n + 1)(2n + 1) . 6 3. In a harmonic proportion, c : a =(c b):(b a). It follows that ac ab = bc ac or that b(a + c) = 2ac. Thus the sum of− the extremes− multiplied by the mean− equals− twice the product of the extremes. 4. Since 6:3=(5 3) : (6 5), the numbers 3, 5, 6 are in subcontrary proportion. -
Newsletter 91
Newsletter 9 1: December 2010 Introduction This is the final nzmaths newsletter for 2010. It is also the 91 st we have produced for the website. You can have a look at some of the old newsletters on this page: http://nzmaths.co.nz/newsletter As you are no doubt aware, 91 is a very interesting and important number. A quick search on Wikipedia (http://en.wikipedia.org/wiki/91_%28number%29) will very quickly tell you that 91 is: • The atomic number of protactinium, an actinide. • The code for international direct dial phone calls to India • In cents of a U.S. dollar, the amount of money one has if one has one each of the coins of denominations less than a dollar (penny, nickel, dime, quarter and half dollar) • The ISBN Group Identifier for books published in Sweden. In more mathematically related trivia, 91 is: • the twenty-seventh distinct semiprime. • a triangular number and a hexagonal number, one of the few such numbers to also be a centered hexagonal number, and it is also a centered nonagonal number and a centered cube number. It is a square pyramidal number, being the sum of the squares of the first six integers. • the smallest positive integer expressible as a sum of two cubes in two different ways if negative roots are allowed (alternatively the sum of two cubes and the difference of two cubes): 91 = 6 3+(-5) 3 = 43+33. • the smallest positive integer expressible as a sum of six distinct squares: 91 = 1 2+2 2+3 2+4 2+5 2+6 2. -
PENTAGONAL NUMBERS in the PELL SEQUENCE and DIOPHANTINE EQUATIONS 2X2 = Y2(3Y -1) 2 ± 2 Ve Siva Rama Prasad and B
PENTAGONAL NUMBERS IN THE PELL SEQUENCE AND DIOPHANTINE EQUATIONS 2x2 = y2(3y -1) 2 ± 2 Ve Siva Rama Prasad and B. Srlnivasa Rao Department of Mathematics, Osmania University, Hyderabad - 500 007 A.P., India (Submitted March 2000-Final Revision August 2000) 1. INTRODUCTION It is well known that a positive integer N is called a pentagonal (generalized pentagonal) number if N = m(3m ~ 1) 12 for some integer m > 0 (for any integer m). Ming Leo [1] has proved that 1 and 5 are the only pentagonal numbers in the Fibonacci sequence {Fn}. Later, he showed (in [2]) that 2, 1, and 7 are the only generalized pentagonal numbers in the Lucas sequence {Ln}. In [3] we have proved that 1 and 7 are the only generalized pentagonal numbers in the associated Pell sequence {Qn} delned by Q0 = Qx = 1 and Qn+2 = 2Qn+l + Q„ for n > 0. (1) In this paper, we consider the Pell sequence {PJ defined by P 0 =0,P 1 = 1, and Pn+2=2Pn+l+Pn for«>0 (2) and prove that P±l, P^, P4, and P6 are the only pentagonal numbers. Also we show that P0, P±1, P2, P^, P4, and P6 are the only generalized pentagonal numbers. Further, we use this to solve the Diophantine equations of the title. 2. PRELIMINARY RESULTS We have the following well-known properties of {Pn} and {Qn}: for all integers m and n, a a + pn = "-P" a n d Q = " P" w herea = 1 + V2 and p = 1-V2, (3) l P_„ = {-\r Pn and Q_„ = (-l)"Qn, (4) a2 = 2P„2+(-iy, (5) 2 2 e3„=a(e„ +6P„ ), (6> ^ + n = 2PmG„-(-l)"Pm_„. -
On Ternary Cubic Equation
ISSN: 2277-3754 ISO 9001:2008 Certified International Journal of Engineering and Innovative Technology (IJEIT) Volume 3, Issue 9, March 2014 ON TERNARY CUBIC EQUATION P. Thirunavukarasu, S. Sriram Assistant Professor -P.G & Research Department of Mathematics, Periyar E.V.R College Tiruchirappalli – 620 023, Tamilnadu, India Assistant Professor–P.G & Research Department of Mathematics, National College, Tiruchirappalli – 620 001, Tamilnadu, India equations are analyzed for the non-trivial integral Abstract we obtain the non-trivial integral solutions for the solutions. These results have motivated us to search for ternary cubic equation non-trivial integral solutions of their varieties of ternary cubic Diophantine equation. This paper concerns with the problem of determining non-trivial integral solutions of . the equation with three unknowns given by A few interesting relations among the solutions are presented. Index Terms: Ternary Cubic, integral solutions, Pell’s explicit integral solutions of the above equation are form, nasty numbers presented. A few interesting relations among the solutions Notations are obtained. Oblong number of rank n obln n n 1 II. METHOD OF ANALYSIS Tetrahedral number of rank The ternary cubic equation under consideration is n n12 n n Tet n 6 Triangular number of rank (1) Taking (2) Polygonal number of rank n with sides nm12 (3) m tnmn, 1 2 We get Square pyramidal number of rank n n1 2 n 1 (4) Again taking the transformation n Sqpn 6 Pentagonal pyramidal number of rank Star number = and apply in (4) we get (5) 2 Stella Octangula number = St. oct n 2 n 1 n It is well known that the general form of the integral solutions of the Pellian equation. -
International Journal of Engineering Research-Online a Peer Reviewed International Journal Vol.1., Issue.3., 2013 Articles Available Online
International journal of Engineering Research-Online A Peer Reviewed International Journal Vol.1., Issue.3., 2013 Articles available online http://www.ijoer.in RESEARCH ARTICLE ISSN: 2321-7758 AN INTERESTING TRANSCENDENTAL EQUATION WITH SIX UNKNOWNS 3 2 x2 y 2 xy X 2 Y 2 z 2 w 2 M.A.GOPALAN, S.VIDHYALAKSHMI, K.LAKSHMI Department of Mathematics, Shrimati Indira Gandhi College,Trichy-620002. Article Received: 11/11/2013 Article Revised on: 21/11/2013 Article Accepted on: 22/11/2013 ABSTRACT The transcendental equation with six unknowns involving surds represented by the 3 equation 2 x2 y 2 xy X 2 Y 2 z 2 w 2 is analyzed for its patterns of non-zero distinct integral solutions. Infinitely many non-zero integer sextuple (,,,,,)x y X Y z w satisfying the above equation are obtained. Three different patterns for finding the solution to the above problem are discussed. The relations between the solutions and the Polygonal numbers, Pyramidal numbers, Pronic number, Jacobsthal number, Jacobsthal-Lucas number, Octahedral number, kynea K.LAKSHMI number, Centered pyramidal numbers and Four Dimensional Figurative numbers are presented. KEYWORDS: Transcendental equation, integral solutions, the Polygonal numbers, Pyramidal numbers, Pronic number, Jacobsthal number, Jacobsthal-Lucas number, Octahedral number, kynea number, Centered pyramidal numbers and Four Dimensional Figurative numbers. M.Sc 2000 mathematics subject classification: 11D99 NOTATIONS: KYn -kynea number of rank Tmn, -Polygonal number of rank n with size m CPn,3 - Centered Triangular pyramidal number of m Pn - Pyramidal number of rank with size rank CP - Centered hexagonal pyramidal number of PRn - Pronic number of rank n n,6 rank OHn - Octahedral number of rank n F4,n ,3 - Four Dimensional Figurative number of SOn -Stella octangular number of rank rank whose generating polygon is a triangle S -Star number of rank n F4,n ,5 - Four Dimensional Figurative number of Jn -Jacobsthal number of rank of rank whose generating polygon is a pentagon. -
Selçuk J. Appl. Math. Selçuk Journal of Vol. 12. No. 2. Pp. 71-80, 2011 Applied Mathematics
Selçuk J. Appl. Math. Selçuk Journal of Vol. 12. No. 2. pp. 71-80, 2011 Applied Mathematics On the Periods of Some Figurate Numbers Omur Deveci1, Erdal Karaduman2 1Department of Mathematics, Faculty of Science and Letters, Kafkas University, 36100 Kars, Turkiye e-mail: [email protected] Department of Mathematics, Faculty of Science, Atatürk University, 25240 Erzurum, Turkiye e-mail: [email protected] Received Date:December 7, 2010 Accepted Date: October 19, 2011 Abstract. The number which can be represented by a regular geometrical arrangement of equally spaced point is defined as figurate number. Each of polygonal, centered polygonal and pyramidal numbers is a class of the series of figurate numbers. In this paper, we obtain the periods of polygonal, centered polygonal and pyramidal numbers by reducing each element of these numbers modulo m. Key words: Period, polygonal number, centered polygonal number, pyramidal number. 2000 Mathematics Subject Classification: 11B75, 11B50. 1. Introduction The figurate numbers have a very important role to solve some problems in num- ber theory and to determine speciality of some numbers, see for example, [8,9]. The polygonal numbers, the centered polygonal numbers, the pyramidal num- bers and their properties have been studied by some authors, see for example, [1,3,6,15]. The study of Fibonacci numbers by reducing modulo m began with the earlier work of Wall [13] where the periods of Fibonacci numbers according to modulo m were obtained. The theory is expanded to 3-step Fibonacci se- quence by Özkan, Aydin and Dikici [11]. Lü and Wang [10] contributed to study of the Wall number for the k step Fibonacci sequence. -
On the Integer Solutions of the Pell Equation
International Journal of Engineering Science Invention ISSN (Online): 2319 – 6734, ISSN (Print): 2319 – 6726 www.ijesi.org || Volume 2 || Issue 12 || December 2013 || PP.01-03 On the integer solutions of the Pell equation M.A.Gopalan1,V.Sangeetha2, Manju Somanath3 1Professor,Dept.of Mathematics,Srimathi Indira Gandhi College,Trichy-620002,India. 2Asst.Professor,Dept.of Mathematics,National College,Trichy-620001,India. 3Asst.Professor,Dept.of Mathematics,National College,Trichy-620001,India. ABSTRACT: The binary quadratic diophantine equation represented by is considered. A method for obtaining infinitely many non-zero distinct integer solutions of the Pell equation considered above is illustrated. A few interesting relations among the solutions and special figurate numbers are presented.Recurrence relations on the solutions are given. KEYWORDS - Pell equation, binary quadratic diophantine equation, integer solutions. I. INTRODUCTION It is well known that the Pell equation (D > 0 and square free) has always positive integer solutions.When , the Pell equation may not have any positive integer solutions.For example, the equations and have no integer solutions. When k is a positive integer and , positive integer solutions of the equations and have been investigated by Jones in [1].In [2-11], some specific Pell equation and their integer solutions are considered.In [12], the integer solutions of the Pell equation has been considered. In [13], the Pell equation is analysed for the integer solutions. This communication concerns with the Pell equation and infinitely many positive integer solutions are obtained.A few interesting relations among the solutions and special figurate numbers are presented.Recurrence relations on the solutions are given. -
Euler's Pentagonal Number Theorem
Euler's Pentagonal Number Theorem Dan Cranston September 28, 2011 Triangular Numbers:1 ; 3; 6; 10; 15; 21; 28; 36; 45; 55; ::: Square Numbers:1 ; 4; 9; 16; 25; 36; 49; 64; 81; 100; ::: Pentagonal Numbers:1 ; 5; 12; 22; 35; 51; 70; 92; 117; 145; ::: Introduction Square Numbers:1 ; 4; 9; 16; 25; 36; 49; 64; 81; 100; ::: Pentagonal Numbers:1 ; 5; 12; 22; 35; 51; 70; 92; 117; 145; ::: Introduction Triangular Numbers:1 ; 3; 6; 10; 15; 21; 28; 36; 45; 55; ::: Pentagonal Numbers:1 ; 5; 12; 22; 35; 51; 70; 92; 117; 145; ::: Introduction Triangular Numbers:1 ; 3; 6; 10; 15; 21; 28; 36; 45; 55; ::: Square Numbers:1 ; 4; 9; 16; 25; 36; 49; 64; 81; 100; ::: Introduction Triangular Numbers:1 ; 3; 6; 10; 15; 21; 28; 36; 45; 55; ::: Square Numbers:1 ; 4; 9; 16; 25; 36; 49; 64; 81; 100; ::: Pentagonal Numbers:1 ; 5; 12; 22; 35; 51; 70; 92; 117; 145; ::: The kth pentagonal number, P(k), is the kth partial sum of the arithmetic sequence an = 1 + 3(n − 1) = 3n − 2. k X 3k2 − k P(k) = (3n − 2) = 2 n=1 I P(8) = 92, P(500) = 374; 750, etc. and P(0) = 0. I Extend domain, so P(−8) = 100, P(−500) = 375; 250, etc. I fP(0); P(1); P(−1); P(2); P(−2); :::g = f0; 1; 2; 5; 7; :::g is an increasing sequence. Generalized Pentagonal Numbers k X 3k2 − k P(k) = (3n − 2) = 2 n=1 I P(8) = 92, P(500) = 374; 750, etc. -
Observations on Icosagonal Pyramidal Number
International Refereed Journal of Engineering and Science (IRJES) ISSN (Online) 2319-183X, (Print) 2319-1821 Volume 2, Issue 7 (July 2013), PP. 32-37 www.irjes.com Observations On Icosagonal Pyramidal Number 1M.A.Gopalan, 2Manju Somanath, 3K.Geetha, 1Department of Mathematics, Shrimati Indira Gandhi college, Tirchirapalli- 620 002. 2Department of Mathematics, National College, Trichirapalli-620 001. 3Department of Mathematics, Cauvery College for Women, Trichirapalli-620 018. ABSTRACT:- We obtain different relations among Icosagonal Pyramidal number and other two, three and four dimensional figurate numbers. Keyword:- Polygonal number, Pyramidal number, Centered polygonal number, Centered pyramidal number, Special number MSC classification code: 11D99 I. INTRODUCTION Fascinated by beautiful and intriguing number patterns, famous mathematicians, share their insights and discoveries with each other and with readers. Throughout history, number and numbers [2,3,7-15] have had a tremendous influence on our culture and on our language. Polygonal numbers can be illustrated by polygonal designs on a plane. The polygonal number series can be summed to form “solid” three dimensional figurate numbers called Pyramidal numbers [1,4,5 and 6] that can be illustrated by pyramids. In this communication we 32 20 65n n n deal with Icosagonal Pyramidal numbers given by p and various interesting relations n 2 among these numbers are exhibited by means of theorems involving the relations. Notation m pn = Pyramidal number of rank n with sides m tmn, = Polygonal number of rank n with sides m jaln = Jacobsthal Lucas number ctmn, = Centered Polygonal number of rank n with sides m m cpn = Centered Pyramidal number of rank n with sides m gn = Gnomonic number of rank n with sides m pn = Pronic number carln = Carol number mern = Mersenne number, where n is prime culn = Cullen number Than = Thabit ibn kurrah number II.