The General Formula to Find the Sum of First N Kth Dimensional S Sided Polygonal Numbers and a Simple Way to Find the N-Th Term of Polynomial Sequences
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Special Kinds of Numbers
Chapel Hill Math Circle: Special Kinds of Numbers 11/4/2017 1 Introduction This worksheet is concerned with three classes of special numbers: the polyg- onal numbers, the Catalan numbers, and the Lucas numbers. Polygonal numbers are a nice geometric generalization of perfect square integers, Cata- lan numbers are important numbers that (one way or another) show up in a wide variety of combinatorial and non-combinatorial situations, and Lucas numbers are a slight twist on our familiar Fibonacci numbers. The purpose of this worksheet is not to give an exhaustive treatment of any of these numbers, since that is just not possible. The goal is to, instead, introduce these interesting classes of numbers and give some motivation to explore on your own. 2 Polygonal Numbers The first class of numbers we'll consider are called polygonal numbers. We'll start with some simpler cases, and then derive a general formula. Take 3 points and arrange them as an equilateral triangle with side lengths of 2. Here, I use the term \side-length" to mean \how many points are in a side." The total number of points in this triangle (3) is the second triangular number, denoted P (3; 2). To get the third triangular number P (3; 3), we take the last configuration and adjoin points so that the outermost shape is an equilateral triangle with a side-length of 3. To do this, we can add 3 points along any one of the edges. Since there are 3 points in the original 1 triangle, and we added 3 points to get the next triangle, the total number of points in this step is P (3; 3) = 3 + 3 = 6. -
10901 Little Patuxent Parkway Columbia, MD 21044
10901 Little Patuxent Parkway Columbia, MD 21044 Volume 1 | 2018 We would like to thank The Kalhert Foundation for their support of our students and specifically for this journal. Polygonal Numbers and Common Differences Siavash Aarabi, Howard Community College 2017, University of Southern California Mentored by: Mike Long, Ed.D & Loretta FitzGerald Tokoly, Ph.D. Abstract The polygonal numbers, or lattices of objects arranged in polygonal shapes, are more than just geometric shapes. The lattices for a polygon with a certain number of sides represent the polygon where the sides increase from length 1, then 2, then 3 and so forth. The mathematical richness emerges when the number of objects in each lattice is counted for the polygons of increasing larger size and then analyzed. So where are the differences? The polygonal numbers being considered in this project represent polygons that have different numbers of sides. It is when the integer powers of the polygonal sequence for a polygon with a specific number of sides are computed and their differences computed, some interesting commonalities emerge. That there are mathematical patterns in the commonalities that arise from differences are both unexpected and pleasing. Background A polygonal number is a number represented as dots or pebbles arranged in the shape of a regular polygon, or a polygon where the lengths of all sides are congruent. Consider a triangle as one polygon, and then fill the shape up according to figure 1, the sequence of numbers will form Triangular Numbers. The nth Triangular Numbers is also known as the sum of the first n positive integers. -
Triangular Numbers /, 3,6, 10, 15, ", Tn,'" »*"
TRIANGULAR NUMBERS V.E. HOGGATT, JR., and IVIARJORIE BICKWELL San Jose State University, San Jose, California 9111112 1. INTRODUCTION To Fibonacci is attributed the arithmetic triangle of odd numbers, in which the nth row has n entries, the cen- ter element is n* for even /?, and the row sum is n3. (See Stanley Bezuszka [11].) FIBONACCI'S TRIANGLE SUMS / 1 =:1 3 3 5 8 = 2s 7 9 11 27 = 33 13 15 17 19 64 = 4$ 21 23 25 27 29 125 = 5s We wish to derive some results here concerning the triangular numbers /, 3,6, 10, 15, ", Tn,'" »*". If one o b - serves how they are defined geometrically, 1 3 6 10 • - one easily sees that (1.1) Tn - 1+2+3 + .- +n = n(n±M and (1.2) • Tn+1 = Tn+(n+1) . By noticing that two adjacent arrays form a square, such as 3 + 6 = 9 '.'.?. we are led to 2 (1.3) n = Tn + Tn„7 , which can be verified using (1.1). This also provides an identity for triangular numbers in terms of subscripts which are also triangular numbers, T =T + T (1-4) n Tn Tn-1 • Since every odd number is the difference of two consecutive squares, it is informative to rewrite Fibonacci's tri- angle of odd numbers: 221 222 TRIANGULAR NUMBERS [OCT. FIBONACCI'S TRIANGLE SUMS f^-O2) Tf-T* (2* -I2) (32-22) Ti-Tf (42-32) (52-42) (62-52) Ti-Tl•2 (72-62) (82-72) (9*-82) (Kp-92) Tl-Tl Upon comparing with the first array, it would appear that the difference of the squares of two consecutive tri- angular numbers is a perfect cube. -
Integer Partitions
12 PETER KOROTEEV Remark. Note that out n! fixed points of T acting on Xn only for single point q we 12 PETER KOROTEEV get a polynomial out of Vq.Othercoefficient functions Vp remain infinite series which we 12shall further ignore. PETER One KOROTEEV can verify by examining (2.25) that in the n limit these Remark. Note that out n! fixed points of T acting on Xn only for single point q we coefficient functions will be suppressed. A choice of fixed point q following!1 the large-n limits get a polynomial out of Vq.Othercoefficient functions Vp remain infinite series which we Remark. Note thatcorresponds out n! fixed to zooming points of intoT aacting certain on asymptoticXn only region for single in which pointa q we a shall further ignore. One can verify by examining (2.25) that in the n | Slimit(1)| these| S(2)| ··· get a polynomial out ofaVSq(n.Othercoe) ,whereS fficientSn is functionsa permutationVp remain corresponding infinite to series the choice!1 which of we fixed point q. shall furthercoe ignore.fficient functions One| can| will verify be suppressed. by2 examining A choice (2.25 of) that fixed in point theqnfollowinglimit the large- thesen limits corresponds to zooming into a certain asymptotic region in which a!1 a coefficient functions will be suppressed. A choice of fixed point q following| theS(1) large-| | nSlimits(2)| ··· aS(n) ,whereS Sn is a permutation corresponding to the choice of fixed point q. q<latexit sha1_base64="gqhkYh7MBm9GaiVNDBxVo5M1bBY=">AAAB8HicbVBNS8NAEN3Ur1q/qh69LBbBU0lEUG9FLx4rWFtsQ9lsJ+3SzSbuTsQS+i+8eFDx6s/x5r9x2+agrQ8GHu/NMDMvSKQw6LrfTmFpeWV1rbhe2tjc2t4p7+7dmTjVHBo8lrFuBcyAFAoaKFBCK9HAokBCMxheTfzmI2gjYnWLowT8iPWVCAVnaKX7DsITBmH2MO6WK27VnYIuEi8nFZKj3i1/dXoxTyNQyCUzpu25CfoZ0yi4hHGpkxpIGB+yPrQtVSwC42fTi8f0yCo9GsbalkI6VX9PZCwyZhQFtjNiODDz3kT8z2unGJ77mVBJiqD4bFGYSooxnbxPe0IDRzmyhHEt7K2UD5hmHG1IJRuCN//yImmcVC+q3s1ppXaZp1EkB+SQHBOPnJEauSZ10iCcKPJMXsmbY5wX5935mLUWnHxmn/yB8/kDhq2RBA==</latexit> -
Induction for Tetrahedral Numbers
Induction for Tetrahedral Numbers Teacher Notes and Answers 7 8 9 10 11 12 TI-84PlusCE™ Investigation Student 50 min Teacher Notes: “Inductive Tetrahedrals” is part two of this three-part series. [Refer to Inductive Whole Numbers for Part One]. Part two follows a similar format to part one but is slightly more challenging from an algebraic perspective. Teachers can use part two in this series as a more independent environment for students focusing on providing feedback rather than instruction. A set of Power Point slides is provided that can be used to enhance the visual aspect of this lesson, the ability to visualise solutions can give problems more meaning. “Cubes and Squares” is part three of this three-part series. This section is designed as an assessment tool, marks have been allocated to each question. The questions are more reflective of the types of questions that students might experience in the short answer section of an examination where calculators may be used to derive answers or to simply verify by-hand solutions. A set of Power Point slides is provided that can be used to introduce students to this task. Introduction The purpose of this activity is to use exploration and observation to establish a rule for the sum of the first n tetrahedral numbers then use proof by mathematical induction to show that the rule is true for all whole numbers. What are the Tetrahedral numbers? The prefix ‘tetra’ refers to the quantity four, so it is not surprising that a tetrahedron consists of four faces, each face is a triangle. -
Input for Carnival of Math: Number 115, October 2014
Input for Carnival of Math: Number 115, October 2014 I visited Singapore in 1996 and the people were very kind to me. So I though this might be a little payback for their kindness. Good Luck. David Brooks The “Mathematical Association of America” (http://maanumberaday.blogspot.com/2009/11/115.html ) notes that: 115 = 5 x 23. 115 = 23 x (2 + 3). 115 has a unique representation as a sum of three squares: 3 2 + 5 2 + 9 2 = 115. 115 is the smallest three-digit integer, abc , such that ( abc )/( a*b*c) is prime : 115/5 = 23. STS-115 was a space shuttle mission to the International Space Station flown by the space shuttle Atlantis on Sept. 9, 2006. The “Online Encyclopedia of Integer Sequences” (http://www.oeis.org) notes that 115 is a tridecagonal (or 13-gonal) number. Also, 115 is the number of rooted trees with 8 vertices (or nodes). If you do a search for 115 on the OEIS website you will find out that there are 7,041 integer sequences that contain the number 115. The website “Positive Integers” (http://www.positiveintegers.org/115) notes that 115 is a palindromic and repdigit number when written in base 22 (5522). The website “Number Gossip” (http://www.numbergossip.com) notes that: 115 is the smallest three-digit integer, abc, such that (abc)/(a*b*c) is prime. It also notes that 115 is a composite, deficient, lucky, odd odious and square-free number. The website “Numbers Aplenty” (http://www.numbersaplenty.com/115) notes that: It has 4 divisors, whose sum is σ = 144. -
On Some Polynomial Values of Repdigit Numbers
ON SOME POLYNOMIAL VALUES OF REPDIGIT NUMBERS T. KOVACS,´ GY. PETER,´ N. VARGA (DEBRECEN) Abstract. We study the equal values of repdigit numbers and the k dimensional polygonal numbers. We state some effective finiteness theorems, and for small parameter values we completely solve the corresponding equations. Let x(x + 1) ··· (x + k − 2)((m − 2)x + k + 2 − m) (1) f (x) = k;m k! be the mth order k dimensional polygonal number, where k ≥ 2 and m ≥ 3 are fixed integers. As special cases for fk;3 we get the bi- x+k−1 nomial coefficient k , for f2;m(x) and f3;m(x) we have the corre- sponding polygonal and pyramidal numbers, respectively. These fig- urate numbers have already been investigated from several aspects and therefore have a rich literature, see Dickson [9]. For example, the question whether a perfect square is a binomial coefficient, i.e., if fk;3(x) = f2;4(y) and also the more general question on the power val- ues of binomial coefficients was resolved by Gy}ory[12]. The equation x y n = 2 has been investigated by several authors, for general effective finiteness statements we refer to Kiss [17] and Brindza [6]. In the spe- cial cases m = 3; 4; 5 and 6, the corresponding diophantine equations were resolved by Avanesov [1], Pint´er[19] and de Weger [23] (inde- pendently), Bugeaud, Mignotte, Stoll, Siksek, Tengely [8] and Hajdu, Pint´er[13], respectively. The equal values of polygonal and pyrami- dal numbers were studied by Brindza, Pint´er,Turj´anyi [7] and Pint´er, Varga [20]. -
Tetrahedral Numbers
Tetrahedral Numbers Student Worksheet TI-30XPlus Activity Student 50 min 7 8 9 10 11 12 MathPrint™ Finding Patterns What are the Tetrahedral numbers? The prefix ‘tetra’ refers to the quantity four, so it is not surprising that a tetrahedron consists of four faces, each face is a triangle. This triangular formation can sometimes be found in stacks of objects. The series of diagrams below shows the progression from one layer to the next for a stack of spheres. Row Number 1 2 3 4 5 Items Added Complete Stack Question: 1. Create a table of values for the row number and the corresponding quantity of items in a complete stack. Question: 2. Create a table of values for the row number and the corresponding quantity of items that are added to the stack. Question: 3. The calculator screen shown here illustrates how to determine the fifth tetrahedral number. The same command could be used to determine any of the tetrahedral numbers. Explain how this command is working. Question: 4. Verify that the calculation shown opposite is the same as the one generated in Question 3. Question: 5. Enter the numbers 1, 2 … 10 in List 1 on the calculator. Enter the first 10 tetrahedral numbers in List 2. Once the values have been entered try the following: a) Quadratic regression using List 1 and List 2. Check the validity of the result via substitution. b) Cubic regression using List 1 and List 2. Check the validity of the result via substitution. Texas Instruments 2021. You may copy, communicate and modify this material for non-commercial educational purposes Author: P. -
1 + 4 + 7 + 10 = 22;... the Nth Pentagonal Number Is Therefore
CHAPTER 6 1. The pentagonal numbers are 1; 1 + 4 = 5; 1 + 4 + 7 = 12; 1 + 4 + 7 + 10 = 22;... The nth pentagonal number is therefore n 1 2 − n(n 1) 3n n (3i +1) = n + 3 − = − . i 2 ! 2 X=0 Similarly, since the hexagonal numbers are 1; 1+5 = 6; 1+5+9 = 15; 1+5+9+13 = 28;... it follows that the nth hexagonal number is n 1 − n(n 1) (4i +1) = n + 4 − = 2n2 n. i 2 ! − X=0 2. The pyramidal numbers with triangular base are 1; 1+3 = 4; 1+3+6 = 10; 1+3+6+10 = 20; ... Therefore the nth pyramidal number with triangular base is n n k(k + 1) 1 1 n(n + 1)(2n + 1) n(n + 1) = (k2 + k)= + k 2 2 k 2 " 6 2 # X=1 X=1 . n(n + 1) 2n + 1 1 n(n + 1)(n + 2) = + = 2 6 2 6 The pyramidal numbers with square base are 1; 1+4 = 5; 1+4+9 = 14; 1+4+9+16= 30;... Thus the nth pyramidal number with square base is given by the sum of the squares from 1 to n, namely, n(n + 1)(2n + 1) . 6 3. In a harmonic proportion, c : a =(c b):(b a). It follows that ac ab = bc ac or that b(a + c) = 2ac. Thus the sum of− the extremes− multiplied by the mean− equals− twice the product of the extremes. 4. Since 6:3=(5 3) : (6 5), the numbers 3, 5, 6 are in subcontrary proportion. -
Newsletter 91
Newsletter 9 1: December 2010 Introduction This is the final nzmaths newsletter for 2010. It is also the 91 st we have produced for the website. You can have a look at some of the old newsletters on this page: http://nzmaths.co.nz/newsletter As you are no doubt aware, 91 is a very interesting and important number. A quick search on Wikipedia (http://en.wikipedia.org/wiki/91_%28number%29) will very quickly tell you that 91 is: • The atomic number of protactinium, an actinide. • The code for international direct dial phone calls to India • In cents of a U.S. dollar, the amount of money one has if one has one each of the coins of denominations less than a dollar (penny, nickel, dime, quarter and half dollar) • The ISBN Group Identifier for books published in Sweden. In more mathematically related trivia, 91 is: • the twenty-seventh distinct semiprime. • a triangular number and a hexagonal number, one of the few such numbers to also be a centered hexagonal number, and it is also a centered nonagonal number and a centered cube number. It is a square pyramidal number, being the sum of the squares of the first six integers. • the smallest positive integer expressible as a sum of two cubes in two different ways if negative roots are allowed (alternatively the sum of two cubes and the difference of two cubes): 91 = 6 3+(-5) 3 = 43+33. • the smallest positive integer expressible as a sum of six distinct squares: 91 = 1 2+2 2+3 2+4 2+5 2+6 2. -
PENTAGONAL NUMBERS in the PELL SEQUENCE and DIOPHANTINE EQUATIONS 2X2 = Y2(3Y -1) 2 ± 2 Ve Siva Rama Prasad and B
PENTAGONAL NUMBERS IN THE PELL SEQUENCE AND DIOPHANTINE EQUATIONS 2x2 = y2(3y -1) 2 ± 2 Ve Siva Rama Prasad and B. Srlnivasa Rao Department of Mathematics, Osmania University, Hyderabad - 500 007 A.P., India (Submitted March 2000-Final Revision August 2000) 1. INTRODUCTION It is well known that a positive integer N is called a pentagonal (generalized pentagonal) number if N = m(3m ~ 1) 12 for some integer m > 0 (for any integer m). Ming Leo [1] has proved that 1 and 5 are the only pentagonal numbers in the Fibonacci sequence {Fn}. Later, he showed (in [2]) that 2, 1, and 7 are the only generalized pentagonal numbers in the Lucas sequence {Ln}. In [3] we have proved that 1 and 7 are the only generalized pentagonal numbers in the associated Pell sequence {Qn} delned by Q0 = Qx = 1 and Qn+2 = 2Qn+l + Q„ for n > 0. (1) In this paper, we consider the Pell sequence {PJ defined by P 0 =0,P 1 = 1, and Pn+2=2Pn+l+Pn for«>0 (2) and prove that P±l, P^, P4, and P6 are the only pentagonal numbers. Also we show that P0, P±1, P2, P^, P4, and P6 are the only generalized pentagonal numbers. Further, we use this to solve the Diophantine equations of the title. 2. PRELIMINARY RESULTS We have the following well-known properties of {Pn} and {Qn}: for all integers m and n, a a + pn = "-P" a n d Q = " P" w herea = 1 + V2 and p = 1-V2, (3) l P_„ = {-\r Pn and Q_„ = (-l)"Qn, (4) a2 = 2P„2+(-iy, (5) 2 2 e3„=a(e„ +6P„ ), (6> ^ + n = 2PmG„-(-l)"Pm_„. -
Figurate Numbers
Figurate Numbers by George Jelliss June 2008 with additions November 2008 Visualisation of Numbers The visual representation of the number of elements in a set by an array of small counters or other standard tally marks is still seen in the symbols on dominoes or playing cards, and in Roman numerals. The word "calculus" originally meant a small pebble used to calculate. Bear with me while we begin with a few elementary observations. Any number, n greater than 1, can be represented by a linear arrangement of n counters. The cases of 1 or 0 counters can be regarded as trivial or degenerate linear arrangements. The counters that make up a number m can alternatively be grouped in pairs instead of ones, and we find there are two cases, m = 2.n or 2.n + 1 (where the dot denotes multiplication). Numbers of these two forms are of course known as even and odd respectively. An even number is the sum of two equal numbers, n+n = 2.n. An odd number is the sum of two successive numbers 2.n + 1 = n + (n+1). The even and odd numbers alternate. Figure 1. Representation of numbers by rows of counters, and of even and odd numbers by various, mainly symmetric, formations. The right-angled (L-shaped) formation of the odd numbers is known as a gnomon. These do not of course exhaust the possibilities. 1 2 3 4 5 6 7 8 9 n 2 4 6 8 10 12 14 2.n 1 3 5 7 9 11 13 15 2.n + 1 Triples, Quadruples and Other Forms Generalising the divison into even and odd numbers, the counters making up a number can of course also be grouped in threes or fours or indeed any nonzero number k.