FINDING EIGENVECTORS: FAST and NONTRADITIONAL APPROACH 1. Introduction for Decades If Not Centuries, We Have Been Overlooking Th
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Arxiv:2003.06292V1 [Math.GR] 12 Mar 2020 Eggnrtr N Ignlmti.Tedaoa Arxi Matrix Diagonal the Matrix
ALGORITHMS IN LINEAR ALGEBRAIC GROUPS SUSHIL BHUNIA, AYAN MAHALANOBIS, PRALHAD SHINDE, AND ANUPAM SINGH ABSTRACT. This paper presents some algorithms in linear algebraic groups. These algorithms solve the word problem and compute the spinor norm for orthogonal groups. This gives us an algorithmic definition of the spinor norm. We compute the double coset decompositionwith respect to a Siegel maximal parabolic subgroup, which is important in computing infinite-dimensional representations for some algebraic groups. 1. INTRODUCTION Spinor norm was first defined by Dieudonné and Kneser using Clifford algebras. Wall [21] defined the spinor norm using bilinear forms. These days, to compute the spinor norm, one uses the definition of Wall. In this paper, we develop a new definition of the spinor norm for split and twisted orthogonal groups. Our definition of the spinornorm is rich in the sense, that itis algorithmic in nature. Now one can compute spinor norm using a Gaussian elimination algorithm that we develop in this paper. This paper can be seen as an extension of our earlier work in the book chapter [3], where we described Gaussian elimination algorithms for orthogonal and symplectic groups in the context of public key cryptography. In computational group theory, one always looks for algorithms to solve the word problem. For a group G defined by a set of generators hXi = G, the problem is to write g ∈ G as a word in X: we say that this is the word problem for G (for details, see [18, Section 1.4]). Brooksbank [4] and Costi [10] developed algorithms similar to ours for classical groups over finite fields. -
Orthogonal Reduction 1 the Row Echelon Form -.: Mathematical
MATH 5330: Computational Methods of Linear Algebra Lecture 9: Orthogonal Reduction Xianyi Zeng Department of Mathematical Sciences, UTEP 1 The Row Echelon Form Our target is to solve the normal equation: AtAx = Atb ; (1.1) m×n where A 2 R is arbitrary; we have shown previously that this is equivalent to the least squares problem: min jjAx−bjj : (1.2) x2Rn t n×n As A A2R is symmetric positive semi-definite, we can try to compute the Cholesky decom- t t n×n position such that A A = L L for some lower-triangular matrix L 2 R . One problem with this approach is that we're not fully exploring our information, particularly in Cholesky decomposition we treat AtA as a single entity in ignorance of the information about A itself. t m×m In particular, the structure A A motivates us to study a factorization A=QE, where Q2R m×n is orthogonal and E 2 R is to be determined. Then we may transform the normal equation to: EtEx = EtQtb ; (1.3) t m×m where the identity Q Q = Im (the identity matrix in R ) is used. This normal equation is equivalent to the least squares problem with E: t min Ex−Q b : (1.4) x2Rn Because orthogonal transformation preserves the L2-norm, (1.2) and (1.4) are equivalent to each n other. Indeed, for any x 2 R : jjAx−bjj2 = (b−Ax)t(b−Ax) = (b−QEx)t(b−QEx) = [Q(Qtb−Ex)]t[Q(Qtb−Ex)] t t t t t t t t 2 = (Q b−Ex) Q Q(Q b−Ex) = (Q b−Ex) (Q b−Ex) = Ex−Q b : Hence the target is to find an E such that (1.3) is easier to solve. -
Implementation of Gaussian- Elimination
International Journal of Innovative Technology and Exploring Engineering (IJITEE) ISSN: 2278-3075, Volume-5 Issue-11, April 2016 Implementation of Gaussian- Elimination Awatif M.A. Elsiddieg Abstract: Gaussian elimination is an algorithm for solving systems of linear equations, can also use to find the rank of any II. PIVOTING matrix ,we use Gaussian Jordan elimination to find the inverse of a non singular square matrix. This work gives basic concepts The objective of pivoting is to make an element above or in section (1) , show what is pivoting , and implementation of below a leading one into a zero. Gaussian elimination to solve a system of linear equations. The "pivot" or "pivot element" is an element on the left Section (2) we find the rank of any matrix. Section (3) we use hand side of a matrix that you want the elements above and Gaussian elimination to find the inverse of a non singular square matrix. We compare the method by Gauss Jordan method. In below to be zero. Normally, this element is a one. If you can section (4) practical implementation of the method we inherit the find a book that mentions pivoting, they will usually tell you computation features of Gaussian elimination we use programs that you must pivot on a one. If you restrict yourself to the in Matlab software. three elementary row operations, then this is a true Keywords: Gaussian elimination, algorithm Gauss, statement. However, if you are willing to combine the Jordan, method, computation, features, programs in Matlab, second and third elementary row operations, you come up software. -
Linear Algebra Handbook
CS419 Linear Algebra January 7, 2021 1 What do we need to know? By the end of this booklet, you should know all the linear algebra you need for CS419. More specifically, you'll understand: • Vector spaces (the important ones, at least) • Dirac (bra-ket) notation and why it's quite nice to use • Linear combinations, linearly independent sets, spanning sets and basis sets • Matrices and linear transformations (they're the same thing) • Changing basis • Inner products and norms • Unitary operations • Tensor products • Why we care about linear algebra 2 Vector Spaces In quantum computing, the `vectors' we'll be working with are going to be made up of complex numbers1. A vector space, V , over C is a set of vectors with the vital property2 that αu + βv 2 V for all α; β 2 C and u; v 2 V . Intuitively, this means we can add together and scale up vectors in V, and we know the result is still in V. Our vectors are going to be lists of n complex numbers, v 2 Cn, and Cn will be our most important vector space. Note we can just as easily define vector spaces over R, the set of real numbers. Over the course of this module, we'll see the reasons3 we use C, but for all this linear algebra, we can stick with R as everyone is happier with real numbers. Rest assured for the entire module, every time you see something like \Consider a vector space V ", this vector space will be Rn or Cn for some n 2 N. -
Naïve Gaussian Elimination Jamie Trahan, Autar Kaw, Kevin Martin University of South Florida United States of America [email protected]
nbm_sle_sim_naivegauss.nb 1 Naïve Gaussian Elimination Jamie Trahan, Autar Kaw, Kevin Martin University of South Florida United States of America [email protected] Introduction One of the most popular numerical techniques for solving simultaneous linear equations is Naïve Gaussian Elimination method. The approach is designed to solve a set of n equations with n unknowns, [A][X]=[C], where A nxn is a square coefficient matrix, X nx1 is the solution vector, and C nx1 is the right hand side array. Naïve Gauss consists of two steps: 1) Forward Elimination: In this step, the unknown is eliminated in each equation starting with the first@ D equation. This way, the equations @areD "reduced" to one equation and@ oneD unknown in each equation. 2) Back Substitution: In this step, starting from the last equation, each of the unknowns is found. To learn more about Naïve Gauss Elimination as well as the pitfall's of the method, click here. A simulation of Naive Gauss Method follows. Section 1: Input Data Below are the input parameters to begin the simulation. This is the only section that requires user input. Once the values are entered, Mathematica will calculate the solution vector [X]. èNumber of equations, n: n = 4 4 è nxn coefficient matrix, [A]: nbm_sle_sim_naivegauss.nb 2 A = Table 1, 10, 100, 1000 , 1, 15, 225, 3375 , 1, 20, 400, 8000 , 1, 22.5, 506.25, 11391 ;A MatrixForm 1 10@88 100 1000 < 8 < 18 15 225 3375< 8 <<D êê 1 20 400 8000 ji 1 22.5 506.25 11391 zy j z j z j z j z è nx1 rightj hand side array, [RHS]: z k { RHS = Table 227.04, 362.78, 517.35, 602.97 ; RHS MatrixForm 227.04 362.78 @8 <D êê 517.35 ji 602.97 zy j z j z j z j z j z k { Section 2: Naïve Gaussian Elimination Method The following sections divide Naïve Gauss elimination into two steps: 1) Forward Elimination 2) Back Substitution To conduct Naïve Gauss Elimination, Mathematica will join the [A] and [RHS] matrices into one augmented matrix, [C], that will facilitate the process of forward elimination. -
Lecture 6 — Generalized Eigenspaces & Generalized Weight
18.745 Introduction to Lie Algebras September 28, 2010 Lecture 6 | Generalized Eigenspaces & Generalized Weight Spaces Prof. Victor Kac Scribe: Andrew Geng and Wenzhe Wei Definition 6.1. Let A be a linear operator on a vector space V over field F and let λ 2 F, then the subspace N Vλ = fv j (A − λI) v = 0 for some positive integer Ng is called a generalized eigenspace of A with eigenvalue λ. Note that the eigenspace of A with eigenvalue λ is a subspace of Vλ. Example 6.1. A is a nilpotent operator if and only if V = V0. Proposition 6.1. Let A be a linear operator on a finite dimensional vector space V over an alge- braically closed field F, and let λ1; :::; λs be all eigenvalues of A, n1; n2; :::; ns be their multiplicities. Then one has the generalized eigenspace decomposition: s M V = Vλi where dim Vλi = ni i=1 Proof. By the Jordan normal form of A in some basis e1; e2; :::en. Its matrix is of the following form: 0 1 Jλ1 B Jλ C A = B 2 C B .. C @ . A ; Jλn where Jλi is an ni × ni matrix with λi on the diagonal, 0 or 1 in each entry just above the diagonal, and 0 everywhere else. Let Vλ1 = spanfe1; e2; :::; en1 g;Vλ2 = spanfen1+1; :::; en1+n2 g; :::; so that Jλi acts on Vλi . i.e. Vλi are A-invariant and Aj = λ I + N , N nilpotent. Vλi i ni i i From the above discussion, we obtain the following decomposition of the operator A, called the classical Jordan decomposition A = As + An where As is the operator which in the basis above is the diagonal part of A, and An is the rest (An = A − As). -
Calculus and Differential Equations II
Calculus and Differential Equations II MATH 250 B Linear systems of differential equations Linear systems of differential equations Calculus and Differential Equations II Second order autonomous linear systems We are mostly interested with2 × 2 first order autonomous systems of the form x0 = a x + b y y 0 = c x + d y where x and y are functions of t and a, b, c, and d are real constants. Such a system may be re-written in matrix form as d x x a b = M ; M = : dt y y c d The purpose of this section is to classify the dynamics of the solutions of the above system, in terms of the properties of the matrix M. Linear systems of differential equations Calculus and Differential Equations II Existence and uniqueness (general statement) Consider a linear system of the form dY = M(t)Y + F (t); dt where Y and F (t) are n × 1 column vectors, and M(t) is an n × n matrix whose entries may depend on t. Existence and uniqueness theorem: If the entries of the matrix M(t) and of the vector F (t) are continuous on some open interval I containing t0, then the initial value problem dY = M(t)Y + F (t); Y (t ) = Y dt 0 0 has a unique solution on I . In particular, this means that trajectories in the phase space do not cross. Linear systems of differential equations Calculus and Differential Equations II General solution The general solution to Y 0 = M(t)Y + F (t) reads Y (t) = C1 Y1(t) + C2 Y2(t) + ··· + Cn Yn(t) + Yp(t); = U(t) C + Yp(t); where 0 Yp(t) is a particular solution to Y = M(t)Y + F (t). -
Linear Programming
Linear Programming Lecture 1: Linear Algebra Review Lecture 1: Linear Algebra Review Linear Programming 1 / 24 1 Linear Algebra Review 2 Linear Algebra Review 3 Block Structured Matrices 4 Gaussian Elimination Matrices 5 Gauss-Jordan Elimination (Pivoting) Lecture 1: Linear Algebra Review Linear Programming 2 / 24 columns rows 2 3 a1• 6 a2• 7 = a a ::: a = 6 7 •1 •2 •n 6 . 7 4 . 5 am• 2 3 2 T 3 a11 a21 ::: am1 a•1 T 6 a12 a22 ::: am2 7 6 a•2 7 AT = 6 7 = 6 7 = aT aT ::: aT 6 . .. 7 6 . 7 1• 2• m• 4 . 5 4 . 5 T a1n a2n ::: amn a•n Matrices in Rm×n A 2 Rm×n 2 3 a11 a12 ::: a1n 6 a21 a22 ::: a2n 7 A = 6 7 6 . .. 7 4 . 5 am1 am2 ::: amn Lecture 1: Linear Algebra Review Linear Programming 3 / 24 rows 2 3 a1• 6 a2• 7 = 6 7 6 . 7 4 . 5 am• 2 3 2 T 3 a11 a21 ::: am1 a•1 T 6 a12 a22 ::: am2 7 6 a•2 7 AT = 6 7 = 6 7 = aT aT ::: aT 6 . .. 7 6 . 7 1• 2• m• 4 . 5 4 . 5 T a1n a2n ::: amn a•n Matrices in Rm×n A 2 Rm×n columns 2 3 a11 a12 ::: a1n 6 a21 a22 ::: a2n 7 A = 6 7 = a a ::: a 6 . .. 7 •1 •2 •n 4 . 5 am1 am2 ::: amn Lecture 1: Linear Algebra Review Linear Programming 3 / 24 2 3 2 T 3 a11 a21 ::: am1 a•1 T 6 a12 a22 ::: am2 7 6 a•2 7 AT = 6 7 = 6 7 = aT aT ::: aT 6 . -
SUPPLEMENT on EIGENVALUES and EIGENVECTORS We Give
SUPPLEMENT ON EIGENVALUES AND EIGENVECTORS We give some extra material on repeated eigenvalues and complex eigenvalues. 1. REPEATED EIGENVALUES AND GENERALIZED EIGENVECTORS For repeated eigenvalues, it is not always the case that there are enough eigenvectors. Let A be an n × n real matrix, with characteristic polynomial m1 mk pA(λ) = (λ1 − λ) ··· (λk − λ) with λ j 6= λ` for j 6= `. Use the following notation for the eigenspace, E(λ j ) = {v : (A − λ j I)v = 0 }. We also define the generalized eigenspace for the eigenvalue λ j by gen m j E (λ j ) = {w : (A − λ j I) w = 0 }, where m j is the multiplicity of the eigenvalue. A vector in E(λ j ) is called a generalized eigenvector. The following is a extension of theorem 7 in the book. 0 m1 mk Theorem (7 ). Let A be an n × n matrix with characteristic polynomial pA(λ) = (λ1 − λ) ··· (λk − λ) , where λ j 6= λ` for j 6= `. Then, the following hold. gen (a) dim(E(λ j )) ≤ m j and dim(E (λ j )) = m j for 1 ≤ j ≤ k. If λ j is complex, then these dimensions are as subspaces of Cn. gen n (b) If B j is a basis for E (λ j ) for 1 ≤ j ≤ k, then B1 ∪ · · · ∪ Bk is a basis of C , i.e., there is always a basis of generalized eigenvectors for all the eigenvalues. If the eigenvalues are all real all the vectors are real, then this gives a basis of Rn. (c) Assume A is a real matrix and all its eigenvalues are real. -
Math 2280 - Lecture 23
Math 2280 - Lecture 23 Dylan Zwick Fall 2013 In our last lecture we dealt with solutions to the system: ′ x = Ax where A is an n × n matrix with n distinct eigenvalues. As promised, today we will deal with the question of what happens if we have less than n distinct eigenvalues, which is what happens if any of the roots of the characteristic polynomial are repeated. This lecture corresponds with section 5.4 of the textbook, and the as- signed problems from that section are: Section 5.4 - 1, 8, 15, 25, 33 The Case of an Order 2 Root Let’s start with the case an an order 2 root.1 So, our eigenvalue equation has a repeated root, λ, of multiplicity 2. There are two ways this can go. The first possibility is that we have two distinct (linearly independent) eigenvectors associated with the eigen- value λ. In this case, all is good, and we just use these two eigenvectors to create two distinct solutions. 1Admittedly, not one of Sherlock Holmes’s more popular mysteries. 1 Example - Find a general solution to the system: 9 4 0 ′ x = −6 −1 0 x 6 4 3 Solution - The characteristic equation of the matrix A is: |A − λI| = (5 − λ)(3 − λ)2. So, A has the distinct eigenvalue λ1 = 5 and the repeated eigenvalue λ2 =3 of multiplicity 2. For the eigenvalue λ1 =5 the eigenvector equation is: 4 4 0 a 0 (A − 5I)v = −6 −6 0 b = 0 6 4 −2 c 0 which has as an eigenvector 1 v1 = −1 . -
Chapter 2 a Short Review of Matrix Algebra
Chapter 2 A short review of matrix algebra 2.1 Vectors and vector spaces Definition 2.1.1. A vector a of dimension n is a collection of n elements typically written as ⎛ ⎞ ⎜ a1 ⎟ ⎜ ⎟ ⎜ ⎟ ⎜ a2 ⎟ a = ⎜ ⎟ =(ai)n. ⎜ . ⎟ ⎝ . ⎠ an Vectors of length 2 (two-dimensional vectors) can be thought of points in 33 BIOS 2083 Linear Models Abdus S. Wahed the plane (See figures). Chapter 2 34 BIOS 2083 Linear Models Abdus S. Wahed Figure 2.1: Vectors in two and three dimensional spaces (-1.5,2) (1, 1) (1, -2) x1 (2.5, 1.5, 0.95) x2 (0, 1.5, 0.95) x3 Chapter 2 35 BIOS 2083 Linear Models Abdus S. Wahed • A vector with all elements equal to zero is known as a zero vector and is denoted by 0. • A vector whose elements are stacked vertically is known as column vector whereas a vector whose elements are stacked horizontally will be referred to as row vector. (Unless otherwise mentioned, all vectors will be referred to as column vectors). • A row vector representation of a column vector is known as its trans- T pose. We will use⎛ the⎞ notation ‘ ’or‘ ’ to indicate a transpose. For ⎜ a1 ⎟ ⎜ ⎟ ⎜ a2 ⎟ ⎜ ⎟ T instance, if a = ⎜ ⎟ and b =(a1 a2 ... an), then we write b = a ⎜ . ⎟ ⎝ . ⎠ an or a = bT . • Vectors of same dimension are conformable to algebraic operations such as additions and subtractions. Sum of two or more vectors of dimension n results in another n-dimensional vector with elements as the sum of the corresponding elements of summand vectors. -
23. Eigenvalues and Eigenvectors
23. Eigenvalues and Eigenvectors 11/17/20 Eigenvalues and eigenvectors have a variety of uses. They allow us to solve linear difference and differential equations. For many non-linear equations, they inform us about the long-run behavior of the system. They are also useful for defining functions of matrices. 23.1 Eigenvalues We start with eigenvalues. Eigenvalues and Spectrum. Let A be an m m matrix. An eigenvalue (characteristic value, proper value) of A is a number λ so that× A λI is singular. The spectrum of A, σ(A)= {eigenvalues of A}.− Sometimes it’s possible to find eigenvalues by inspection of the matrix. ◮ Example 23.1.1: Some Eigenvalues. Suppose 1 0 2 1 A = , B = . 0 2 1 2 Here it is pretty obvious that subtracting either I or 2I from A yields a singular matrix. As for matrix B, notice that subtracting I leaves us with two identical columns (and rows), so 1 is an eigenvalue. Less obvious is the fact that subtracting 3I leaves us with linearly independent columns (and rows), so 3 is also an eigenvalue. We’ll see in a moment that 2 2 matrices have at most two eigenvalues, so we have determined the spectrum of each:× σ(A)= {1, 2} and σ(B)= {1, 3}. ◭ 2 MATH METHODS 23.2 Finding Eigenvalues: 2 2 × We have several ways to determine whether a matrix is singular. One method is to check the determinant. It is zero if and only the matrix is singular. That means we can find the eigenvalues by solving the equation det(A λI)=0.