Semiring Unions of a Ring and a Half-Body

Semiring Unions of a Ring and a Half-Body

ISSN 1066-369X, Russian Mathematics (Iz. VUZ), 2008, Vol. 52, No. 12, pp. 65–68. c Allerton Press, Inc., 2008. Original Russian Text c M.A. Lukin, 2008, published in Izvestiya Vysshikh Uchebnykh Zavedenii. Matematika, 2008, No. 12, pp. 76–80. Semiring Unions of a Ring and a Half-Body M. A. Lukin1* 1Vyatka State University of Humanities, ul. Krasnoarmeiskaya 26, Kirov, 610002 Russia Received May 03, 2007; in final form, October 09, 2008 Abstract—We describe the structure of semirings which are unions of a ring and a half-body. DOI: 10.3103/S1066369X08120104 Key words and phrases: ring, semiring, half-body, semiring disjoint union. Brief communication In the theory of semirings the following classes of semirings play an important role: (associative) rings, distributive lattices with zero, and half-bodies with zero. A natural problem is the investigation of semirings reducible to these three types. In [1] (proposition 12.15) one describes semirings which are subdirect products of a certain ring and a certain bounded distributive lattice. In paper [2] one studies Abelian regular positive semirings S, whose structure essentially depends on a distributive lattice of idempotents L(S) and a half-body of invertible elements U(S). This paper follows [3], it is dedicated to the investigation of semirings which represent the union of their two subsemirings, one of which is isomorphic to a ring, and other one is isomorphic to a half-body withzero.Wegiveadefinition of the semiring disjoint union S = R∪˙ U of a ring R and a half-body U and adduce several examples. The case of the semiring union is reduced to the semiring disjoint union. Further we study the structure of the ring R and the half-body U which enter in S = R∪˙ U; based on them, we construct semirings R∪˙ U themselves. Finally, we solve the question about the uniqueness of S = R∪˙ U for given R and U. 1. Preliminary information. A semiring is an algebraic structure S;+, · , 0 such that S;+, 0 is a commutative monoid, S; · is a semigroup, and in S the identities a(b + c)=ab + ac, (a + b)c = ac + bc,anda0=0a =0are fulfilled [1]. A division semiring different from a ring is said to be a half-body with zero.Excluding0 from a half- body S, we obtain the structure S;+, ·;wecallitahalf-body. A half-body U is said to be reducible, if the implication a + c = b + c ⇒ a = b is fulfilled in it. Let S be a certain semiring with unit 1. We denote by r(S) the set of all elements of S which have the opposite one, we do by U(S) the set of all invertible elements of the semiring S.Evidently,r(S) isaring with respect to operations in S. Definition. We call a semiring S with a unit the semiring disjoint union of a ring R and a half-body U; we denote it by R∪˙ U, if it is the union of its nonintersecting subsets r(S) and U(S),wherer(S) is a ring R, U(S) is a half-body U. Example 1.1. Let P be a field and let T be its certain subhalf-body (without zero), let Mn(P ) stand for the ring of all quadratic matrices of the nth order over the field P . The union of the set R of matrices with zero coordinates on the main diagonal and above it and the set U of matrices with zero coordinates above the main diagonal and coordinates from T on the main diagonal with matrix operations Mn(P ) is the semiring disjoint union R∪˙ U. *E-mail: [email protected]. 65.

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    1 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us