Univerzita Komenského v Bratislave Fakulta matematiky, fyziky a informatiky

Relativistic methods in non-commutative quantum mechanics Diploma thesis

2018 Adam Hložný Comenius University in Bratislava, Slovakia Faculty of mathematics, physics and computer science

Relativistic methods in non-commutative quantum mechanics Diploma thesis

Workplace: Department of theoretical physics Thesis advisor Prof. RNDr. Peter Prešnajder, DrSc.

Bratislava, 2018 Adam Hložný iii

Thanks to: My thesis advisor, Peter Prešnajder, for his always friendly attitude, patience and exceptional understanding of mathematics and physics. iv Abstrakt

1 Venujeme sa konštrukcii Diracovho operátora častice so spinom 2 . Diracov operá- tor je dôležitým objektom nekomutatívnej geometrie a tiež relativistickej kvantovej teórie poľa. Staviame na fakte, že Poincarého algebra je pod-algebrou su (2, 2). Potom môžeme použiť su (2, 2) na explicitnú konštrukciu reprezentácií Poincarého algebry. Ukazuje sa, že fundamentálna reprezentácia sama o sebe nestačí, pretože z nej nemožno 2 µ vybudovať hmotnú teóriu. Toto má pôvod v tom, že Casimirov element mˆ =p ˆµpˆ reprezentácie Poincarého algebry je rovný nule. Obdobná situácia nastáva pre duálnu 2 µ reprezentáciu: m˜ =p ˜µp˜ = 0. Vezmeme priamy súčet týchto dvoch reprezentácií a op- erátor hybnosti definujeme ako Pµ =p ˆµ +p ˜µ. Casimirov element M je teraz nenulový a interpretovaný ako hmotnosť. Toto nám umožnňuje zadefinovať relativistický Diracov operátor na fuzzy priestore. Hľadáme jeho vlstné funkcie a ukazuje sa, že netriviálna časť v porovnaní sa komutatívnym Diracovym operátorom spočíva v hľadaní vlstných funkcií operátora hybnosti Pµ.

Kľúčové slová: Fuzzy priestor, su(2,2), Diracov operátor, oscilátorová reprezentácia, relativistický v Abstract

1 We present approach of constructing relativistic Dirac operator of 2 particle in fuzzy space, which is very important object for both non-commutative geometry and relativistic quantum field theory. We build on the fact that Poincaré algebra is sub- algebra of su (2, 2). We can thus use oscillator representation of su (2, 2) to explicitly construct representation of Poincaré algebra. During the process, we find out that just fundamental representation does not suffice, since it is impossible to define massive 2 µ theory. This is due to the fact that Casimir element mˆ =p ˆµpˆ of representation of Poincaré algebra is equal to zero. The same situation arises for dual representation: 2 µ m˜ =p ˜µp˜ = 0. We take direct sum of them, the momentum operator is then defined as

Pµ =p ˆµ +p ˜µ. Casimir element M is now non-vanishing and interpreted as mass. This allows us to define relativistic Dirac operator in fuzzy space. Eigen-problem for the operator is then investigated. The non-trivial part in comparison with commutative

Dirac operator is to find eigenfunctions of momentum operator Pµ.

Keywords: Fuzzy space, relativistic, Dirac operator, su (2, 2), oscillator representa- tion Contents

Introduction 1

1 Fuzzy spacess 2 1.1 Motivation ...... 2 1.2 Fuzzy spaces in our case ...... 3

2 spin (4, 2), su (2, 2), oscillator representation 5 2.1 Basic definitions and theorems ...... 5 2.2 su (2, 2) algebra ...... 6 2.2.1 Review of Poincaré algebra ...... 6 2.2.2 spin(4,2) and su(2,2) ...... 7 2.3 Gauss decomposition ...... 9 2.3.1 Gauss decomposition for sl (2, C) ...... 10 2.3.2 Calculating boost ...... 10

3 Momentum operator 14 3.1 Definition ...... 14 3.2 Eigenvalue problem for the momentum operator ...... 16

4 Noncommutative Dirac operator 19 4.1 Dirac operator and Dirac equation ...... 19 4.2 Non-commutative version ...... 19

5 Conclusions 21

6 Appendix: calculations and formulas 22

vi Introduction

It is well known fact that current well established theory of fundamental interac- tions, quantum field theory, is not UV finite and it fails to describe gravity since it is non-renormalizable. Lack of advances in qft approach to quantum gravity led to devel- opment of different approaches such as string theory and non-commutative geommetry - both of them often combined together.

Aspiring non-commutative theories often start by defining Dirac operator since one can learn a lot about underlying geometry by studying solutions of Dirac equation. This is due to the fact, that Alain Connes proved spin manifold theorem (see [5]) that given spectral triple and Charge conjugation operator, we can reconstruct whole man- ifold from spectrum of Dirac operator. We will pursue the path of constructing Dirac operator too, our aim is to define relativistic-covariant Dirac operator and investigate solutions to the free Dirac equation.

Our approach stands on the fact, that su (2, 2) algebra contains Poincaré algebra as sub-algebra. To obtain massive theory, we have to take direct sum of two su (2, 2) representations - fundamental and dual representation. This approach relies on oscilla- tor representations of su (2, 2) (see [12] or [9]). We give detailed description of massless oscillator representation of su (2, 2), massive(constructed from two massless represen- tations) as well as Poincaré algebra which it contains as sub-algebra. In our case, we defined 4-momentum operator Pµ which allows us to define free Dirac operator in fuzzy space.

Chapter 1 contains brief introduction into the problematics. Chapter 2 contains introduction to the su (2, 2) as well as explicit construction of infinite-dimensional rep- resentation of su (2, 2). In "physical" part of this work - chapters 4 and 3 we omitted most of the lengthy calculations and moved them to chapter 6 to highlight conceptual part and also to make reading little easier.

1 Chapter 1

Fuzzy spacess

1.1 Motivation

Reason to study non-commutative spaces is to make description of space fuzzy - that is to introduce some fundamental scale which determines the shortest observable length. This is usually done by making coordinates non-commutative, possible "positions" are then determined by their spectra. Non-commutativity necessarily leads to uncertainty relations between coordinates. This fact can be utilized e.g. to get regular description of quantum field theory. Another reason to introduce non-commutativity to the space is to naturally incorporate fundamental scale relevant for physics at Planck length. Very important theorem in non-commutative geometry is theorem of Alain Connes for (commutative) manifolds.

Theorem 1. ( Alain Connes) Given spectral triple

1. C∞ (M) smooth functions on manifold

2. L2 (M, S) spinor fileds on manifold

3. D Dirac operator together with charge conjugation and chirality operator, then metric g can be recon- structed from spectrum of the Dirac operator.

It is usually good practice to define non-commutative analogue of Dirac operator in the spirit of this theorem. We will, however, do this just very loosely.

To develop some intuition about non-commutative spaces, let us consider following two-dimensional non-commutative toy model. Define two non-commutative coordi- nates x1,x2 with commutation relation given by

[x1, x2] = λ (1.1)

2 CHAPTER 1. FUZZY SPACESS 3

This coordinates can be constructed from annihilation and creation operators x = √ √ 1 † λa, x2 = λa . Recall that for n-tuple of annihilation and creation operators h †i ai, aj = δij holds. These operators act on auxiliary Hilbert space. Now we define non-commutative (analytic) function as:

∞ X n m φ (x1, x2) = cmnx1 x2 (1.2) m,n=0

So far it does not seem much extra-ordinary, since it is obvious that the set of com- mutative analytic functions is of the same size as the set of non-commutative analytic functions. Let’s look at product of the functions now and where commutativity takes place. We will use coherent states to get the job done. Recall that coherent state is eigenstate of annihilation operator i.e. a |αi = α |αi. |αi can be expressed as (see [15]):

∞ n 2 X (α) |αi = e−|α| √ |ni (1.3) n=0 n! but for our purposes here it is useful to redefine this as:  √ n √ ∞ α λ √ 2 X | λαi = e−|α λ| √ |ni (1.4) n=0 n! for which √ √ x1 | λαi = λα | λαi (1.5) We now take symbol of non-commutative function φ (¯χ, χ) = hχ| φ |χi where χ = αλ √ and we denote | λαi as |χi. Assignment of symbol is bijective. !!!!tuto nieco doplnit!!!! Let’s take two non-commutative functions ζ and ψ. Their product is:

∞ X m n i j ζψ = cmnkijx1 x2 x1x2 (1.6) m,n,i,j=0

Using Wick’s theorem for x1 and x2 and assigning symbol to the product of functions we get the following structure:

hχ| ζψ |χi = ζ (¯χ, χ) + λ (single contractions) + λ2 (double contractions) + ... (1.7)

We can see now, that as λ → 0 we get commutative point-wise product.

1.2 Fuzzy spaces in our case

In this work we will not constrain ourselves to the specific non-commutative model, since our considerations are more general. Typically, non-commutativity (or fuzziness) CHAPTER 1. FUZZY SPACESS 4 is introduced as non-commutativity forced to coordinate functions (for example see [6]):

[xk, xl] = Θkl (1.8)

Where Θkl is not specified. This in turn leads to non-commutativity of algebra of functions(since they are functions of coordinates) and uncertainty relations for them as well. Different commutation relations define, of course, different geometries. Common example of fuzzy space (with "fuzzy" Dirac operator) is fuzzy sphere or it’s variations, see for example [8]. Often there is quantum theory constructed on fuzzy space to investigate some im- plications of non-commutativity. To get some picture of non-commutative space we shall construct space of functions. This is done by using two pairs of annihilation and

0i creation operators ai and a (reasons for doing so will be discussed later). Recall that:

† 0i 0† [ai, aj] = [a , aj ] = δij 0 [ai, aj] = 0 (1.9)

Space of functions then consists of normal-ordered states of the form:

Ψ = Ψ a, a†, a0, a0†

And more precisely:

m n o p X 0  †  †  0†  0† i j 0 k 0 l Ψ = CmnijCopkl a1 a2 a1 a2 (a1) (a2) (a1) (a2) (1.10)

0 Where aα and aα are two pairs of annihilation (together with corresponding creation) operators. We additionally put one constraint for Ψ: it has to have the same number of annihilation and creation operators (of the same kind) - this effectively reduces two degrees of freedom from both C and C0. Chapter 2 spin (4, 2), su (2, 2), oscillator representation

We shall begin this section by mentioning some important definitions and theorems. We give introduction to fundamental representations of spin (4, 2) and su (2, 2). In the end, we give oscillator representation of those mentioned algebras.

2.1 Basic definitions and theorems

Definition 1. An enveloping algebra A of g is an associative algebra in which can g be embedded (denoting embedding as Φ) such that abstract brackets [f, g] (f, g ∈ g) are realized as XY − YX for X = Φ (f) and Y = Φ (g).

Proposition 1. The Universal enveloping algebra U (g) is the most general (max- imal) enveloping algebra.

This is rather vague statement, but we will give more precise definition soon. The key to this is to give precise meaning of "the most general". We will not, however, give complete theory behind universal enveloping algebra. For thorough description see [10] chapter 9.

Definition 2. The Universal enveloping algebra U (g) is Tensor algebra over g with condition A ⊗ B − B ⊗ A = [A, B] imposed. That is quotient of Tensor algebra over g with respect to ideal generated by elements of the form A ⊗ B − B ⊗ A − [A, B].

It is very intuitive that "the most general enveloping algebra" should be unique to be well defined. From Theorem 9.7. of [10] we can take this as a fact and in addition we can deduce that for any enveloping algebra A there exist (unique) homomorphism h : A → U (g) such that for φ : g → A it holds that h ◦ φ is the desired embedding. This gives rise to the fact, that we can compute Casimir operators (central operators for

5 CHAPTER 2. SPIN (4, 2), SU (2, 2), OSCILLATOR REPRESENTATION 6

U (g)) in given representation entirely in terms of the basis matrices (of that algebra in given matrix representation), since embedding into algebra of matrices is embedding into associative algebra. Existence (and uniqueness) of mentioned homomorphism then gives clear relationship to U (g). This allows us to express Casimir elements in terms of some finite-dimensional associative algebra.

Theorem 2. Poincaré-Birkhoff-Witt (PBW) Let g be finite-dimensional Lie al- gebra with basis e1...en and i : g → U (g) be injective homomorphism, and Xj = i (ej) then elements of the form:

n1 nk X1 ⊗ ... ⊗ Xk are linearly independent and span U (g).

Definition 3. The real Clifford algebra Cl (p, q) is associative algebra with unit for which it additionally holds: eiej = ηij (2.1) where ηij is bilinear form with signature (p, q). We will assume that ηij is diagonal and non-degenerate.

Definition 4. spin (m, n) is lie algebra of Spin (m, n) group that is positive- determinant invertible part of Clifford algebra.

For us, spin (4, 2) is relevant, since it is isomorphic to su (2, 2).

2.2 su (2, 2) algebra

2.2.1 Review of Poincaré algebra

Recall (see [18], we use, however, different signature convention) that for Poincaré group generators following commutation relations hold:

[Ji,Jj] = iijkJk (2.2)

[Ji,Kj] = iijkKk (2.3)

[Ki,Kj] = −iijkJk (2.4)

[Ji,Pj] = iijkPk (2.5)

[Ki,Pj] = −iδijP0 (2.6)

[Ji,P0] = i [Pi,P0] = 0 (2.7)

[Ki,P0] = −iPi (2.8) where Ji, Ki are generators of rotations and boosts respectively. Pµ is generator of translations, four-vector and can be considered as momentum operator (given the right representation). CHAPTER 2. SPIN (4, 2), SU (2, 2), OSCILLATOR REPRESENTATION 7

2.2.2 spin(4,2) and su(2,2)

Importance of su (2, 2) for this work lies in the fact, that it contains Poincaré algebra as an sub-algebra. SU (2, 2) group is real which preserves scalar product hψ†φi with signature (2, 2) where ψ and φ are four-dimensional complex vectors. We can thus write element of su (2, 2) algebra as: ! AB S = (2.9) B† D where A, D are hermitian and B, B† are general matrices. su (2, 2) algebra in funda- mental representation is then given by following matrices: ! ! 1 σk 0 1 σk 0 Sij = εijk ,Sk4 = , 2 0 σk 2 0 −σk ! ! i 0 σk i 0 1 S0k = ,S45 = , 2 σk 0 2 1 0 ! ! 1 0 σk 1 0 1 Sk5 = ,S04 = , 2 −σk 0 2 −1 0 ! 1 1 0 S05 = . (2.10) 2 0 −1 Where i, j, k = 1..3. Now where can one see Poincaré group? Eagle-eyed reader should have already spot- ted that for example Sij are generators of rotations. Boost matrices and generators of translations (momentum) are more intricate. One can straightforwardly (calculating commutators) verify that S0k correspond to boosts and Sµ5 − Sµ4 correspond to trans- lation generators, let’s call them pµ. We have to stress out, that this is not the single option how to choose Poincaré subgroup, rather most obvious. From complexified ver- sion of the algebra we can get even richer structure.

Let’s briefly discuss anti-fundamental (dual) representation of su (2, 2) denoted as 0 ? T Sab. For dual (matrix) representation of any Lie algebra holds that ρ (g) = −ρ (g) 0 where g is an element of Lie algebra. It then follows that Sa5 = −Sa5. These repre- sentations are inequivalent. From anti-fundamental representation we choose Poincaré 0 0 0 generators in the same manner as in fundamental representation and so pµ = Sµ5 −Sµ4. As it has already been mentioned, we will take S ⊕ S0 for our considerations. This is, however, fundamental representation of spin (4, 2). Let us explicitly write generators CHAPTER 2. SPIN (4, 2), SU (2, 2), OSCILLATOR REPRESENTATION 8 of the dual representation. ! ! 1 σT 0 1 σT 0 S0 = − ε k ,S0 = − k , ij ijk T k4 T 2 0 σk 2 0 −σk ! ! i 0 σT i 0 1 S0 = − k ,S0 = − , 0k T 45 2 σk 0 2 1 0 ! ! 1 0 σT 1 0 1 S0 = k ,S0 = , k5 T 04 2 −σk 0 2 −1 0 ! 1 −1 0 S0 = . (2.11) 05 2 0 1 And we can write down an element of fundamental representation of spin (4, 2) as: ! S 0 Σ = ab (2.12) ab 0 0 Sab

0 where Sab and Sab denote fundamental and anti-fundamental representation of su (2, 2). This is very analogous to situation when one constructs spinor representation of Lorentz group. One can roughly say that su (2, 2) is to so (4, 2) (or spin (4, 2)) what sl (2, C) is to so (3, 1). Now we construct oscillator representation of su (2, 2) (and also spin (4, 2) as conse- + ˆ + quence). Define operators on NC states aˆi, aˆi , bi, aˆi for i = 1, 2 as:

aˆiΨ = aiΨ ˆ biΨ = Ψai (2.13) and analogously for + operators. Commutation relations for these operators are:

 + hˆ ˆ+i aˆi, aˆj = − bi, bj = δij (2.14)

Now we can arrange these operators into quadruple(s):

ˆT ˆ ˆ ˆ+ + + ˆ+ ˆ+ A = (ˆa1, aˆ2, b1, b2) , A = (ˆa1 , aˆ2 , b1 , b2 ) (2.15)

And for oscillator representation we can write:

ˆ ˆ+ ˆ Sab = A Γ Sab A a, b = 0..5 (2.16) ! 1 0 where Γ = is 4 × 4 matrix with 1 and −1 being 2 × 2 matrices. 0 −1 This (or similar) approach can be seen for example in [12] or [9], we build mostly on the first one. 0 To construct oscillator realization Sab of Sab we proceed very similarly. We now use 0 0† ˆ ˆ+ second pair of a/c operators a and a introduced in (1.9). Operators bi and bi are CHAPTER 2. SPIN (4, 2), SU (2, 2), OSCILLATOR REPRESENTATION 9

0i 0† defined for a and ai in the same manner as operators in (2.13). There is one difference ˜ in operator realization for Sab- Γ matrix has now swapped position to ensure that representation is dual: ˜ ˜+ 0 ˜ Sab = A SabΓA a, b = 0..5 (2.17) where A˜ and A˜+ are:

˜T ˜ ˜ ˜+ + + ˜+ ˜+ A = (˜a1, a˜2, b1, b2) , A = (˜a1 , a˜2 , b1 , b2 ) (2.18)

˜ ˆ 0 Theorem 3. Sab and Sab obey the same commutation relations as Sab and Sab and thus they are indeed representations.

Proof. We proceed for Sˆ. Let S, K be from su (2, 2). Define A¯ = A+Γ, then  ¯  ˆ ¯ ˆ ¯ Ai, Ai = δij where i, j = 1..4. We write S = SijAiAj and K = KmnAmAn. Cal- culating commutator: h ˆ ˆ i  ¯ ¯ ¯ ¯ S, K =SijKmn AiAjAmAn − AmAnAiAj  ¯ ¯  ¯ ¯  =SijKmn Ai δmj − Am AjAn − Am δin − AiAn Aj =A¯ [S,K] A (2.19)

Theorem 4. This representation is also unitary.

Proof. Let us write the most general element of given lie algebra as: ! AB ˆ + + T + + + † + S = u , −v (u1, v1) = u Au + u Bv − v B u − v Dv. B† D Now computing hermitian conjugate of this operator we get

Sˆ+ = −u+Au − u+Bv + v+B†u + v+Dv = −Sˆ

Sˆ is thus anti-hermitian which is desired result. Since exponential of anti-hermitian operator gives unitary one. We now used mathematician’s convention (this is the only time we use it).

Remark: These considerations also make clear, why we defined NC wave functions with two pairs of annihilation and creation operators. The first pair ai corresponds 0 to fundamental representation and the second pair ai corresponds to anti-fundamental representation. This makes direct sum structure very visible.

2.3 Gauss decomposition

We now show technique how to boost non-commutative functions in operator repre- sentation. CHAPTER 2. SPIN (4, 2), SU (2, 2), OSCILLATOR REPRESENTATION 10

2.3.1 Gauss decomposition for sl (2, C)

For SL (2, C) we have only one constraint. Let g be general element of the group, then it is necessary for det (g) = 1 to hold. I the terms of Lie algebra sl (2, C) it means that T r (X) = 0 where X is from Lie algebra. We now choose (very common) basis for sl (2, C). ! ! ! 1 −1 0 0 0 0 1 H = K+ = K− = 2 0 1 1 0 0 0 (2.20)

[H,K±] = ± K±

Every element of sl (2, C) (technically not every, however exception is set of zero mea- sure) can be expressed as:

X = exp (tK−) exp (τH) exp (sK+) − 1 τ 1 τ 1 τ ! e 2 + ste 2 te 2 = 1 τ 1 τ se 2 e 2 (2.21) ! ! ! 1 t γ−1 0 1 0 = 0 1 0 γ s 1

From this we can see that for (almost, for reasons given above) general element of sl (2, C) it is possible to write: ! ! ! ! d c 1 0 d 0 1 cd−1 = (2.22) b a bd−1 1 0 d−1 0 1

We will use rather special case: ! ! ! ! CS 1 SC−1 C−1 0 1 0 = (2.23) SC 0 1 0 C SC−1 1

We should remember that unit determinant condition is C2 − S2 = 0 so we choose natural parametrization C = cosh (t) and S = sinh (t). Additionally we introduce new variable T = SC−1 = tanh (T ) and thus ! ! ! ! CS 1 T C−1 0 1 0 = (2.24) SC 0 1 0 C T 1

2.3.2 Calculating boost

Since oscillator representation introduced in this work is complex, we are allowed to work also with complex linear combinations of generators introduced in (2.9) and CHAPTER 2. SPIN (4, 2), SU (2, 2), OSCILLATOR REPRESENTATION 11

thus to work with complexified algebra su (2, 2)⊗C. This is due to fact that complex representations are the same as representations of complexified algebra. We can then choose full sl (2, C) from it. It is then given by matrices S45, S04 and S05. ˆ We shall now examine how boost B45 acts on non-commutative functions.

−2iT Sˆ45 T Kˆ− 2i ln(C)Sˆ05 T Kˆ+ Bˆ45 = e = e e e (2.25) ! ! 0 1 0 0 ˆ +ˆ where K+ = and K− = . In oscillator representation then K+ =a ˆ b, 0 0 1 0   ˆ ˆ+ ˆ 1 + ˆ+ˆ ˆ K− = b aˆ, iS05 = 2 i aˆ aˆ + b b . We now introduce new labels rˆ = −iS05 and 1 τ = 2 ln (C). So we can rewrite above equation as:

−2iT Sˆ45 T Kˆ− τrˆ T Kˆ+ Bˆ45 = e = e e e (2.26)

We will now choose more convenient basis for non-commutative functions generated by ˆ |n1, n2i hm1, m2|. Consequently we need to calculate matrix elements hm1, m2| B45 |n1, n2i. The calculation we are going to do is approached in somewhat simplified form, just for one pair of annihilation/creation operators, however without loss of generality, since calculation is done in exactly the same way with two pairs of operators. We calculate ˆ matrix elements for K− acting on ψ.

∞ k ˆ X T hn0| eT K− ψ |ni = hn0| akψa†k |ni k! k=0 ∞ r X (k + n0)! (k + n)! = T k hn0 + k| ψ |n + ki (2.27) k!n0!k!n! k=0 ∞ s X k + n0k + n = T k hn0 + k| ψ |n + li k k k=0 ˆ And in the similar fashion for K+:

∞ k ˆ X T hn0| eT K+ ψ |ni = hn0| a†kψak |ni k! k=0 ∞ s X n0!n! = T k hn0 − k| ψ |n − ki (2.28) k!(n − k)!k!(n0 − k)! k=0 ∞ s X k + n0k + n = T k hn0 + k| ψ |n + li k k k=0 CHAPTER 2. SPIN (4, 2), SU (2, 2), OSCILLATOR REPRESENTATION 12

ˆ Let’s investigate action of K± on non-commutative functions now.

∞ k ˆ X T  k ΦT = eT K+ Φ = aˆ+ˆb Φ K+ k! α α k=0 ∞ k X T k X k  l  k−l = aˆ+ˆb aˆ+ˆb Φ (2.29) k! l 1 1 2 2 k=0 l=0 ∞ †k †k X X a 1 a 2 ak1 ak2 = T k √1 2 Φ√1 2 k1!k2! k1!k2! k=0 k1+k2=k ˆ and practically the same calculation goes for K−:

∞ k ˆ X T  k ΦT = eT K− Φ = aˆ ˆb+ Φ K− k! α α k=0 ∞ †k †k (2.30) X X ak1 ak2 a 1 a 2 = T k √1 2 Φ√1 2 k1!k2! k1!k2! k=0 k1+k2=k Due to the fact that for Φ we have a constraint regarding equal number of annihilation and creation operators of the same kind, it is easy to see, that Φ acts diagonally on auxiliary Fock space i.e. Φ |n1n2i = Φn1n2 |n1n2i. Since (2.26) preserves this property, it is natural to investingate the action in terms of basis |n1n2i hn1n2|. Using similar technique as in (2.27) and (2.29) we derive how constituents of (2.26) act on Ψ. ∞    T X k X n1 n2 ΦK+ |n1, n2i = T Φn1−k1,n2−k2 |n1, n2i k1 k2 k=0 k1+k2=k ∞    T X k X k1 + n1 k2 + n2 (2.31) ΦK− |n1, n2i = T Φn1+k1,n2+k2 |n1, n2i k1 k2 k=0 k1+k2=k

−τrˆ −τ(n1+n2+1) e Φ |n1, n2i =e Φn1,n2 |n1, n2i Putting everything together, we present grand formula for boosted solution: ∞ ∞    ˆ X X X X X k1 + n1 k2 + n2 B45Φ = × k1 k2 n1,n2 k=0 j=0 k1+k2=k i1+i2=j (2.32)    k1 + n1 k2 + n2 k+j × T Φn1+k1−i1,n2+k2−i2 |n1, n2i hn1, n2| i1 i2 To get the function which will eventually correspond to non-zero three-momentum, we ! ˆ σi 0 need to rotate this solution. We choose rotation given by Ri = Oscillator 0 σi representation for this operator then gives:

ˆ + ˆ+ ˆ R =a ˆ σiaˆ − b σib (2.33) and rotation, using BCH formula:

ˆ eitRΨ = eitRi Ψe−itRi (2.34) CHAPTER 2. SPIN (4, 2), SU (2, 2), OSCILLATOR REPRESENTATION 13

† where Ri = a σa and ai are two annihilation operators on the auxiliary Fock space. We stress out that for dual representation approach is the same, it is merely interchange of some symbols and labels. Chapter 3

Momentum operator

3.1 Definition

Since we need oscillator representation of spin (4, 2) on NC wave functions (or fields, if one deals with the field theory) we can define two "small" momentum operators pˆµ and p˜µ from translation generators of fundamental and anti-fundamental representa- tions of su (2, 2):

ˆ ˆ pˆµ = Sµ5 − Sµ4 ˜ ˜ p˜µ = Sµ5 − Sµ4 (3.1)

Let’s look on the operator somewhat closer, first we take generator of translations: ! 1 1 1 −1 p0 = (S05 − S04) = (3.2) 2 4 1 −1 for time translations and ! 1 1 −σi σi pk = (Sk5 − Sk4) = (3.3) 2 4 −σi σi for space translations.

Now for operator representation we get for pˆ0: ! T  + + ˆ+ ˆ+ 1 −1  ˆ ˆ  pˆ0 = aˆ , aˆ , −b , −b aˆ1, aˆ2, b1, b2 1 2 1 2 1 −1 n o 1 + ˆ+ˆ +ˆ ˆ+ = 4 aˆα aˆα + bα bα +a ˆα bα + bα aˆα (3.4) and for spatial part: 1 n o pˆ = σi aˆ+aˆ + ˆb+ˆb +a ˆ+ˆb + ˆb+aˆ (3.5) i 4 αβ α β α β α β α β

14 CHAPTER 3. MOMENTUM OPERATOR 15

Splitting into components momentum operator acts on non-commutative functions φ as: 1 pˆ φ = {a+, [a , φ] + a+, [a , φ]} 0 4 1 1 2 2 1  +   +  pˆ1φ = − { a2 , [a1, φ] + a1 , [a2, φ] } 4 (3.6) 1 pˆ φ = − i{a+, [a , φ] − a+, [a , φ]} 2 4 2 1 1 2 1 pˆ φ = − {a+, [a , φ] − a+, [a , φ]} 3 4 1 1 2 2 Similarly for S˜ representation we get: ! T  + + ˜+ ˜+ −1 −1  ˜ ˜  p˜0 = a˜ , a˜ , b , b a˜1, a˜2, −b1, −b2 1 2 1 2 1 1 n o 1 + ˜+˜ +˜ ˜+ = − 4 a˜α a˜α + bα bα +a ˜α bα + bα a˜α (3.7) and for spatial part:

1 1,3 n + ˜+˜ +˜ ˜+ o p˜1,3 = − σαβ a˜α a˜β + bα bβ +a ˜α bβ + bα a˜β 4 (3.8) 1 n o p˜ = σ2 a˜+a˜ + ˜b+˜b +a ˜+˜b + ˜b+a˜ 2 4 αβ α β α β α β α β And again, splitting into components results in: 1 p˜ φ0 = − {a0+, [a0 , φ0] + a0+, [a0 , φ0]} 0 4 1 1 2 2 0 1  0+ 0 0   0+ 0 0  p˜1φ = { a2 , [a1, φ ] + a1 , [a2, φ ] } 4 (3.9) 1 p˜ φ0 = − i{a0+, [a0 , φ0] − a0+, [a0 , φ0]} 2 4 2 1 1 2 1 p˜ φ0 = {a0+, [a0 , φ0] − a0+, [a0 , φ0]} 3 4 1 1 2 2 Where φ0 does not mean derivative, it denotes that function corresponds to dual rep- resentation. It can be proven (see appendix) that:

µ µ pˆ pˆµ =p ˜ p˜µ = 0 (3.10)

Once again analogy with Lorentz group shows up - it is impossible to define massive theory with just fundamental or anti-fundamental representation alone. In the case of Lorentz group we have massless left-handed or right-handed spinors, in our case of spin (4, 2) we have "left-handed" or "right-handed" twistors. Twistor is 4-dimensional analogue of spinor.

In the end, we use pˆµ and p˜µ to construct momentum operator of the massive theory:

Pµ =p ˆµ +p ˜µ (3.11) CHAPTER 3. MOMENTUM OPERATOR 16

Since Pµ has been constructed from generators of translations it is also generator of 0 translations. From the fact, that pµ and pµ are also 4-vectors, Pµ is 4-vector too. Let’s µ µ µ define operator of mass M = P Pµ. Simplifying (ˆpµ +p ˜µ) (ˆp +p ˜ ) we get:

2 µ M = 2ˆpµp˜ (3.12) and thus M has, of course, the same eigenfunctions as Pµ.

3.2 Eigenvalue problem for the momentum operator

In addition to solve eigen-problem for spinors as in commutative case, we have to find eigenfunctions of momentum operator (momentum in NC Dirac equation is operator on NC states) if we want to find eigenfunctions of the Dirac operator. We need to do that just for pˆ0 and p˜0. This is justified by the fact, that we can consider states with zero three-momentum and then boost them in the right direction to obtain solution for any three-momentum. It is, of course, impossible to have zero three-momentum (for nonzero four-momentum) just for "small momentum operators", since they correspond to massless fields. For P µ it is possible and we will indeed capitalize this property.

0 0 Since NC states posses direct sum structure and in addition [a1, a2] = [a1, a2] = 0 holds, together with assumption of normal ordering of NC states and equal number of annihilation and creation operators, we can introduce possibilities for ansatz:  ˜ 0 φ1 (N1) φ1 (N1)   ˜ 0 φ2 (N2) φ2 (N ) Φ = 2 (3.13) ˜ 0 φ1 (N1) φ2 (N2)   ˜ 0 φ2 (N2) φ1 (N1)

† † 0 ˜ where N1 = a1a1, N2 = a2a2 and analogously for Ni . φi and φi are normally ordered.

Now we approach just for φ1. This is without loss of generality, considering that task ˜ is the same for φ2 and φi - it is merely just interchange of symbols. pˆ0 acts on φ1 as: 1 pˆ Ψ = − a+, [a , φ ] (3.14) 0 4 1 1 1 And we want to solve:

pˆ0Ψ = EΨ (3.15) Considering the fact that commutators act as derivatives (by "erasing" a/c operators) this equation can be rewritten into differential form:

xχ,, (x) + χ, (x) + 4Eχ (x) = 0 (3.16) CHAPTER 3. MOMENTUM OPERATOR 17

This equation has the solution:  √   √  χ (x) = C1J0 4 Ex + C2Y0 4 Ex (3.17) where J0 and Y0 are Bessel functions of the first and second kind. The full operator solution is then normal ordered operator-evaluated χ i.e. φα (Nα) = : χ (Nα): . For

N1 then holds(see appendix):

∞ l X (−16E) †l l φ1 (N1): χ (N1) : = a a + 2l 2 1 1 l=0 2 (l!) ( ∞ k ∞ 2k+j−i−1 ) 2 X X X k(−1) 42j+iEl+i  i+j + a† ai+j + (3.18) π i 2j 2 1 1 k=0 i=0 j=0 k2 (j!) ( ∞ k ) 2 X k−1 4 E k + (−1) H a+ ak π k 2 1 1 k=1 (k!)

What does this solution correspond to? Take a look at how operators pˆi act on φ1 (N1). h † i Since [aα, aβ] = 0 and aα, aβ = δαβ it directly follows that (considering 3.14):

pˆ1φ1 (N1) =0

pˆ2φ1 (N1) =0 (3.19)

pˆ3φ1 (N1) = − Eφ1 (N1) and for φ2 (N2) we have (again, see 3.14):

pˆ1φ2 (N2) =0

pˆ2φ2 (N2) =0 (3.20)

pˆ3φ2 (N2) =Eφ1 (N1)

There is obvious interpretation for this - one gets solution for particle moving along z axis together with solution for particle "moving" in opposite direction. The same behavior we get for p˜µ:

˜ p˜1φ1 (N1) =0 ˜ p˜2φ1 (N1) =0 (3.21) ˜ ˜ p˜3φ1 (N1) = − Eφ1 (N1)

˜ and for φ2 (N2) the similar relations hold

˜ p˜1φ2 (N2) =0 ˜ p˜2φ2 (N2) =0 (3.22) ˜ ˜ p˜3φ2 (N2) =Eφ1 (N1) CHAPTER 3. MOMENTUM OPERATOR 18

Finally, for possible solution(s) we write:  ˜ 0 φ1 (N1) φ (N1)   ˜ 0 0 0 φ2 (N2) φ2 (N2) Ψ(N1,N2,N1,N2) = (3.23) ˜ 0 φ1 (N1) φ2 (N2)   ˜ 0 φ2 (N2) φ1 (N1)

Look at eigenfunctions of Pµ now. They are, of course, eigenfunctions of pˆµ and p˜µ.

We are especially interested for solutions of motionless particle. Those are Ψ1 = ˜ 0 ˜ 0 φ2 (N2) φ1 (N1) and Ψ2 = φ1 (N1) φ2 (N2). Then Pµ acts as:

0 0 0 0 P0Ψ1 (N1,N2,N1,N2) =2EΨ1 (N1,N2,N1,N2) 0 0 0 0 P0Ψ2 (N1,N2,N ,N ) =2EΨ2 (N1,N2,N ,N ) 1 2 1 2 (3.24) 0 0 P3Ψ1 (N1,N2,N1,N2) =0 0 0 P3Ψ2 (N1,N2,N1,N2) =0 and it, of course, also vanishes on for P1 and P2. This is solution with zero three momentum. To obtain full solution, formula derived in the last section chapter 2 should be used to boost and rotate solution. Chapter 4

Noncommutative Dirac operator

The work on non-commutative Dirac operator has already been done. The nontriv- ial part, comparing to commutative Dirac operator, is eigen-problem for momentum operator Pµ. We will briefly discuss Dirac equation for the sake of completeness.

4.1 Dirac operator and Dirac equation

µ Recall that Dirac operator in Minkowski space is γµ∂ and then the Dirac equation:

µ (iγµ∂ − m)ψ (x) = 0 (4.1) and fourier-transforming equation we get:

µ (γµp − m)ψ (p) = 0 (4.2) this is the form that non-commutative version shall take too (with pµ, however, being an operator). Dirac equation is typically solved in a following way:

1. take fourier transform of Dirac equation (4.2)

T 2. take ansatz u (p) = (u1, u2) and solve for u1, u2 √ ! p · σζ 3. write solution in symmetric form u (p) = √ p · σζ¯ where ζ is two-componnent spinor.

4.2 Non-commutative version

We introduce Dirac equation right in p-representation in the similar way as in commu- 1 tative theory - we have no choice but ordinary gamma matrices since we want spin 2 Lorentz invariant equation. µ (γ Pµ − M)Ψp = 0 (4.3)

19 CHAPTER 4. NONCOMMUTATIVE DIRAC OPERATOR 20

Taking MΨp = mΨp and PµΨp = pµΨp we see it takes form of ordinnary Dirac equa- tion. The major difference here is that components of bi-spinor Ψp are noncommuta- tive functions, solutions from the (3.23) or their boosted/rotated versions (see 2.34 and 2.32). Chapter 5

Conclusions

Logic of our work relies on the fact, that su (2, 2) contains Poincaré algebra as sub- algebra. We proceeded straightforwardly in the beginning with fundamental repre- sentation of su (2, 2). We took translation generators Sµ4 − Sµ5 to define momentum operator. This is done by oscillator representation on non-commutative functions. The representation acts on space of NC functions, constructed from two pairs of annihilation and creation operators. First pair for fundamental and second pair for anti-fundamental (dual) representation. Lesson gathered from representation theory of so (3, 1) (mass mixes left-handed with right-handed components of spinors) can also be seen here. µ Momentum operator pˆµ has vanishing square pˆµpˆ and we need to take direct sum with dual representation. The momentum operator Pµ is then sum of operators from fundamental and dual representation pˆµ and p˜µ. In this representation we possess

Casimir element of Poincaré algebra constructed in terms of operators pˆµ and p˜µ this is naturally interpreted as mass. In chapters 2, 3 and 4 we investigated (and mostly solved) eigen-problem for Dirac operator. The spinor part is the same as in com- mutative case, however non-commutativity of functions introduces some difficulties. We overcame them and developed method how to deal with the problem, at least in P-representation.

21 Chapter 6

Appendix: calculations and formulas

We now calculate the result (3.10). For the sake of clarity we define two-dimensional T T ˆ ˆ ˆ  complex vectors aˆ = (ˆa1, aˆ2) and b = b1, b2 . Now momentum operator can be written as follows: ! T 1  + ˆ+ 1 −1  ˆ pˆ0 = aˆ , −b a,ˆ b 2 1 −1 1   = aˆ+ − ˆb+ (a − b) 2 ! (6.1) T 1  + ˆ+ −σi σi  ˆ pˆi = aˆ , −b a,ˆ b 2 −σi σi 1     = − aˆ+ − ˆb+ σ aˆ − ˆb 2 i

Lorentz square of pˆµ is:

µ pˆµpˆ =p ˆ0pˆ0 − pˆ1pˆ1 − pˆ2pˆ2 − pˆ3pˆ3 (6.2)

Since σ3 is diagonal matrix it is natural to group pˆ0 (contains identity matrix) with pˆ3 (which contains σ3) and also to group pˆ0 and pˆ0 since they contain anti-diagonal matrices σ1 and σ2. µ pˆµpˆ = (ˆp0pˆ0 − pˆ3pˆ3) − (ˆp2pˆ2 +p ˆ1pˆ1) (6.3) Now it is natural to rewrite the equation using basic product formulas:

µ pˆµpˆ = (ˆp0 − pˆ3) (ˆp0 +p ˆ3) − (ˆp1 − ipˆ2) (ˆp1 + ipˆ2) (6.4) We shall now calculate first and second term separately. For the first one: 1     pˆ ± pˆ = aˆ+ − ˆb+ (1 ∓ σ ) aˆ − ˆb 0 3 2 3 ! 1  + ˆ+ 1 ∓ 1 0  ˆ = aˆ − b σ3 aˆ − b 2 0 1 ± 1 (6.5)   + ˆ+  ˆ   aˆ2 − b2 aˆ2 − b2 case + =  + ˆ+  ˆ   aˆ1 − b1 aˆ1 − b1 case −

22 CHAPTER 6. APPENDIX: CALCULATIONS AND FORMULAS 23 and for the second one: 1   pˆ ± ipˆ = aˆ+ − ˆb+ (1 ∓ σ )(a − b) 1 2 2 3 ! 1  + ˆ+ 0 1 ± 1 = aˆ − b σ3 (a − b) 2 1 ∓ 1 0 (6.6)   + ˆ+  ˆ  − aˆ1 − b1 aˆ2 − b2 case + =  + ˆ+  ˆ  − aˆ2 − b2 aˆ1 − b1 case −

And thus we finally arrive at desired conclusion         µ + ˆ+ ˆ + ˆ+ ˆ pˆµpˆ = aˆ2 − b2 aˆ2 − b2 aˆ1 − b1 aˆ1 − b1 (6.7)  + ˆ+  ˆ   + ˆ+  ˆ  − aˆ2 − b2 aˆ1 − b1 aˆ1 − b1 aˆ2 − b2 = 0

 ˆ   + ˆ+ Where we used that aˆ1 − b1 commutes with aˆ1 − b1 . To prove this, we use  + hˆ ˆ+i commutation relations for a and b aˆi, aˆj = δij and bi, bj = −δij. Simple calculation then shows that:  + ˆ+  ˆ  + ˆ+ +ˆ ˆ+ˆ aˆ1 − b1 aˆ1 − b1 =ˆa1 aˆ1 − b1 aˆ1 − aˆ1 b1 + b1 b1 + ˆ+ +ˆ ˆ ˆ+ =ˆa1aˆ1 − 1 − b1 aˆ1 − aˆ1 b1 + b1b1 + 1 (6.8)  ˆ   + ˆ+ = aˆ1 − b1 aˆ1 − b1

 + ˆ+  ˆ  This proof, of course, passes for general product aˆi − bi aˆi − bi . We now repeat 0 0 0 previous procedure for p˜µ with some minor modifications. Recall that p = Sµ5 − Sµ4 + 0 and in oscillator representation p˜0 = A pµΓA. For momentum operator then holds: ! 1  + ˜+ −1 −1  ˜ p˜0 = a˜ , b a,˜ −b 2 1 1 (6.9) 1     = − a˜+ − ˜b+ a˜ − ˜b 2 ! 1   σ σ   p˜ = a˜+, ˜b+ 1 1 a,˜ −˜b 1 2 −σ1 −σ1 (6.10) 1     = a˜+ − ˜b+ σ a˜ − ˜b 2 1 ! 1   −σ −σ   p˜ = a˜+, ˜b+ 2 2 a,˜ −˜b 2 2 σ2 σ2 (6.11) 1     = − a˜+ − ˜b+ σ a˜ − ˜b 2 2 ! 1   σ σ   p˜ = a˜+, ˜b+ 3 3 a,˜ −˜b 3 2 −σ3 −σ3 (6.12) 1     = a˜+ − ˜b+ σ a˜ − ˜b 2 3 CHAPTER 6. APPENDIX: CALCULATIONS AND FORMULAS 24

µ And to calculate Lorentz square p˜µp˜ we proceed similarly as in previous case.

µ p˜µp˜ = (˜p0p˜0 − p˜3p˜3) − (˜p2p˜2 +p ˜1p˜1) (6.13)

Now it is natural to rewrite the equation using basic product formulas:

µ p˜µp˜ = (˜p0 − p˜3) (˜p0 +p ˜3) − (˜p1 − ip˜2) (˜p1 + ip˜2) (6.14)

We, again, calculate first and second term separately. For the first one: 1     p˜ ± p˜ = − a˜+ − ˜b+ (1 ∓ σ ) a˜ − ˜b 0 3 2 3 !     1 + ˜+ 1 ∓ 1 0 ˜ = a˜ − b σ3 a˜ − b 2 0 1 ± 1 (6.15)   + ˜+  ˜  − a˜2 − b2 a˜2 − b2 case + =  + ˜+  ˜  − a˜1 − b1 a˜1 − b1 case − and for the second one: 1     p˜ ± ip˜ = a˜+ − ˜b+ (1 ∓ σ ) a˜ − ˜b 1 2 2 3 ! 1   0 1 ∓ 1   = a˜+ − ˜b+ a˜ − ˜b 2 1 ± 1 0 (6.16)   + ˜+  ˜   a˜1 − b1 a˜2 − b2 case + =  + ˜+  ˜   a˜2 − b2 a˜1 − b1 case −

Let’s derive differential equation introduced in (3.16). We first calculate the com- mutator [a, φ] where φ is normal ordered function of N1.

m m m h †  † ni †  † n  † n † a1, a1 (a1) =a1 a1 (a1) − a1 (a1) a1 m+1 m  † n  † n−1  †  = a1 (a1) − a1 (a1) 1 + a1a1 = ... (6.17) m  † n−1 = − n a1 (a1)

h †i where ellipsis denotes repetitive use of commutation relation ai, aj = δij until one arrives to the final formula. Using the same approach we calculate:

m m−1 h  † ni  † n a1, a1 (a1) =m a1 (a1) (6.18)

This means that commutator acts as derivative (which is not at all surprising since commutators obey Leibniz rule). Let us now ask question how this commutator acts CHAPTER 6. APPENDIX: CALCULATIONS AND FORMULAS 25

on normal ordered functions of number operator N1. This is done by setting m = n in previous equations (6.17 and 6.18). One can now easily see that:

n n−1 0 [a1, : N1 :] = n : N1 : a1 =⇒ :[a1, χ (N1)] : =: χ (N1) a1 : (6.19) h n †i † n−1 h †i † 0 : N1 :, a1 = na1 : N1 : =⇒ : χ (N1) , a1 : =: a1χ (N1): 0 Now consider expression φ (N1) a1 where normal ordered function φ is χ . By using Leibniz rule we have:

h † i h † i  †  a1, φ (N1) a1 = a1, φ (N1) a1 + φ (N1) a , a1 (6.20) and after normal ordering:

h † i † 0 : a1, φ (N1) a1 : = − : a1φ a1 : −φ 00 = − : N1χ (N1) − χ0 (N1): (6.21) Recall that: n o 1 + ˆ+ˆ +ˆ ˆ+ pˆ0 = 4 aˆα aˆα + bα bα +a ˆα bα + bα aˆα n o 1 i + ˆ+ˆ +ˆ ˆ+ pˆi = 4 σαβ aˆα aˆβ + bα bβ +a ˆα bβ + bα aˆβ

From this, one can finally write equivalent differential equation for pˆ0φ1 = Eφ1 as

1 00 0 pˆ0φ1 = − 4 {: N1φ1 (N1) + φ1 (N1):} = Eφ1 (N1) =⇒ ζχ00 (ζ) + χ (ζ) + 4Eχ (ζ) = 0 (6.22)

And operator solution φ1 (N1) is then obtained from normal ordered operator evaluated solution χ (ζ). Finally φ1 (N1) =: χ (N1): . To prove result in (3.18) we first write identities for Bessel functions(exhausting information can be found in [1]): ∞ l X (−1) 2l J0 (z) = z 22l (l!)2 l=0 (6.23) (   ∞ −k 2k ) 2 1 X k+1 4 z Y (z) = ln z (z) + (−1) H 0 π 2 k 2 0 1 (k!) Pk 1 where Hk = i=1 i are harmonic numbers. The first term in expression for Y0 does not look good since it contains logarithm. This can be circumvented by exponentiating 1 argument of logarithm by 2 and multiplicating by factor 2 . As consequence, we do not have to deal with square root of operator. Writing logarithm as power series ∞ k−1 k X (−1) (x − 1) ln (X) = (6.24) k k=0 and using binomial theorem k   k X k k−i (X − 1) = (−1) Xi. (6.25) i i=0 √ Inserting 4 EN1 combining everything together we get the desired result. Bibliography

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