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7 of the Free Dirac

7.1 The and Field Theory The Dirac equation is a relativistic equation that describes the quan- tum dynamics of . We will see in this section that a consistent de- scription of this theory cannot be done outside the frameworkof(local) relativistic . The Dirac Equation i∂ − m ψ = 0, (7.1) can be regarded as the equation of of a complex field ψ.Muchas ( / ) in the case of the scalar field, and also in close analogy to the theory of non-relativistic many systems discussed in the last chapter, we will regard the Dirac field as an that acts on a ofstates. We have already discussed that the Dirac equation also follows from a least-action-principle. Indeed the Lagrangian

i µ L = ψ¯∂ψ − ∂ ψ¯ γ ψ − mψψ¯ ≡ ψ¯ i∂ − m ψ (7.2) 2 µ has the Dirac equation for its equation of motion. Also, the [ / ( ) ] ( / ) Πα x canonically conjugate to ψα x is δL ψ = = † ( ) Πα x ( ) iψα (7.3) δ∂0ψα x Thus, they obey the equal-time( ) Poisson Brackets ( ) ψ = 3 ψα x , Πβ y PB δαβ δ x − y (7.4) Thus { ( ) ( )} ( ) † = 3 ψα x ,ψβ y PB iδαβ δ x − y (7.5) † In other words the{ field( ψ)α and( )} its adjoint ψα(are a) canonical pair. This 190 Quantization of the Free Dirac Field result follows from the fact that the Dirac Lagrangian is first order in time derivatives. Notice that the field theory of non-relativistic many-particle systems (for both and bosons) also has a Lagrangian which is first order in time derivatives. We will see that, because of this property, the quantum field theory of both types of systems follows rather similar lines, at least at a formal level. As in the case of the many-particle systems, two types of statistics are available to us: Fermi-Dirac and Bose-Einstein. We will see that only the choice of Fermi statistics leads to a physically meaningful theory of the Dirac equation. The Hamiltonian for the Dirac theory is

3 H = d x ψ¯α x − iγ ⋅ ! + m ψβ x (7.6) ! αβ ¯ † where the fields ψ x and ψ =( ψ)!γ0 are operators" which( ) act on a to be specified below. Notice that the one-particle operator in Eq. (7.6) is just the one-particle( ) Dirac Hamiltonian obtained if we regard the Dirac Equation as a Schr¨odinger Equation for spinors. We will leave the issue of their commutation relations (Fermi or Bose) open for the timebeing.In any event, the equations of motion are independent of that choice (do not depend on the statistics). In the Heisenberg representation, we find ! iγ0∂0ψ = γ0ψ,H = −iγ ⋅ + m ψ (7.7) which is just the Dirac equation. ! " ( ) We will solve this equation by means of a Fourier expansion in modes of the form 3 d p m −ip⋅x ip⋅x ψ x = ψ˜+ p e + ψ˜− p e (7.8) ! 2π 3 ω p where ω p is a( quantity) with units# of( energy,) and which( ) will$ turn out to 2 ( 2 ) ( ) ˜ be equal to p0 = p + m ,andp ⋅ x = p0x0 − p ⋅ x.Intermsofψ± p ,the Dirac equation( ) becomes% ˜ ( ) p0γ0 − γ ⋅ p ± m ψ± p = 0(7.9)

In other words, ψ˜± p creates one-particle states with energy ±p .Letus ( ) ( ) 0 make the substitution

( ) ψ˜± p = ±p + m φ˜ (7.10) We get ( ) ( / ) p ∓ m ±p + m φ˜ = ± p2 − m2 φ˜ = 0(7.11)

(/ )( / ) ( ) 7.1 The Dirac equation and Quantum Field Theory 191 This equation has non-trivial solutions only if the -shell condition is obeyed p2 − m2 = 0(7.12)

Thus, we can identify p = ω p = p2 + m2.Atzeromomentumthese 0 ⃗ states become % ˜ ˜ ψ± p0, p(=)0 = ±p0γ0 + m φ (7.13) where φ˜ is an arbitrary 4-. Let us choose φ˜ to be an eigenstate of γ . ( ) ( ) 0 Recall that in the Dirac representation γ0 is diagonal I 0 γ = (7.14) 0 0 −I

Thus the spinors u 1 m, 0 and u 2& m, 0 ' ( ) 1 ( ) 0 ( ) 0 ( ) 1 u 1 m, 0 = u 2 m, 0 = (7.15) ⎛0⎞ ⎛0⎞ ( ) ⎜0⎟ ( ) ⎜0⎟ ⎜ ⎟ ⎜ ⎟ ( ) ⎜ ⎟ ( ) ⎜ ⎟ have γ -eigenvalue +1 ⎜ ⎟ ⎜ ⎟ 0 ⎝ ⎠ ⎝ ⎠ i σ γ0u m, 0 = +u m, 0 σ = 1, 2(7.16) ( ) ( ) and the spinors v σ m, 0 σ = 1, 2 ( ) ( ) ( ) 0 0 ( )( 0 ) 0 v 1 m, 0 = v 2 m, 0 = (7.17) ⎛1⎞ ⎛0⎞ ( ) ⎜0⎟ ( ) ⎜1⎟ ⎜ ⎟ ⎜ ⎟ ( ) ⎜ ⎟ ( ) ⎜ ⎟ have γ -eigenvalue −1, ⎜ ⎟ ⎜ ⎟ 0 ⎝ ⎠ ⎝ ⎠ σ σ γ0v m, 0 = −v m, 0 σ = 1, 2(7.18) ( ) ( ) Let ϕ i m, 0 be the 2-spinors σ = 1, 2 ( ) ( ) ( ) 1 0 ϕ 1 = ϕ 2 = (7.19) ( ) ( 0 ) 1 ( ) ( ) In terms of ϕ i the solutions are& ' & ' ( ) p + m p0+m ϕ σ m, σ σ 2m 0 ψ˜+ p = u p = u m, 0 = σ⋅p σ 2m p + m . ϕ( ) m, 0 ( ) 0 ( ) 2m p0+m (/ ) ⎛ ( )( ) ⎞ ( ) ( ) % ( ) ⎜ % (7.20)⎟ ( ) ⎝ ( ) ( ) ⎠ 192 Quantization of the Free Dirac Field and

−p + m σ⋅p ϕ σ m, 0 σ σ 2m p +m ψ˜− p = v p = v m, 0 = 0 p0+m (σ) 2m p + m % ϕ m, 0 ( ) 0 ( ) 2m ( / ) ⎛ ( ) ( )⎞ ( ) ( ) % ( ) ⎜ . ( ) (7.21)⎟ ˜ 2 2 where the two solutions ψ+( p have) energy +p0 =⎝ + p + m while( the) two⎠ ˜ − = − 2 + 2 solutions ψ− p have energy p0 p m . % Therefore, the one-particle( ) states of% the Dirac theory can have both posi- tive and negative( ) energy and, as it stands, the spectrum of the one-particle Dirac Hamiltonian, shown schematically in Fig. 7.1, is not positive. In ad- dition, each Dirac state has a two-fold degeneracy due to .

E

m

p

−m ∣ ∣

Figure 7.1 Single particle spectrum of the Dirac theory.

The spinors u i and v i obey the orthogonality conditions

( ) ( ) σ ν u¯ p u p =δσν (σ) (ν) v¯ p v p = − δσν ( ) ( ) σ ν u¯( ) p v( ) p =0(7.22) ( ) ( ) ( ) ( ) † † whereu ¯ = u γ0 andv ¯ = v γ0.Itisstraightforwardtocheckthattheopera-( ) ( ) tors Λ± p 1 Λ p = ±p + m (7.23) ( ) ± 2m are projection operators of the( spinors) onto( / the subspaces) with positive Λ+

( ) 7.1 The Dirac equation and Quantum Field Theory 193 and negative Λ− energy respectively. These operators satisfy

2 = = = ( ) Λ± Λ± Tr Λ± 2Λ+ + Λ− 1(7.24)

Hence, the four 4-spinors u σ and v σ are orthonormal and complete natural bases of the Hilbert space( of) single-particle( ) states. We can use these results to write the expansion of the field operator

3 d p m σ − ⋅ σ ⋅ ψ x = a p u p e ip x+a p v p eip x 3 p σ,+ + σ,− − (7.25) ! 2π 0 #= σ 1,2 ( ) ( ) ( ) ! ( ) ( ) ( ) ( ) " where the coe( ffi)cients aσ,± p are operators with as yet unspecified commu- tation relations. The (formal) Hamiltonian for this system is ( ) 3 d p m † † H = p0 aσ,+ p aσ,+ p − aσ,− p aσ,− p (7.26) ! 3 p0 # 2π σ=1,2 [ ( ) ( ) ( ) ( )] Since the single-particle( ) spectrum does not have a lower bound, any attempt to quantize the theory with canonical commutation relations will have the problem that the total energy of the system is not bounded from below.In other words “Dirac bosons” do not have a and the system is unstable since we can put as many bosons as we wish in states with arbitrarily large but . Dirac realized that the simple and elegant way out of this problem was to require the to obey the Pauli Exclusion Principle since, inthat case, there is a natural and stable ground state. However, this assumption implies that the Dirac theory must be quantized as a theory of fermions. Hence we are led to quantize the theory with canonical anticommutation relations

′ as,σ p ,as′,σ′ p = 0 † ′ 3 p0 3 ′ as,σ p ,a ′ ′ p = 2π δ p − p δss′ δσσ′ { ( ) s ,σ ( )} m (7.27) { ( ) ( )} ( ) ( ) where s = ±.Letusdenoteby 0 the state anihilated by the operators as,σ p , ∣ ⟩ a p 0 = 0(7.28) ( ) s,σ We will see now that this state is( not)∣ the⟩ (or ground state) of the Dirac theory. 194 Quantization of the Free Dirac Field 7.1.1 Ground state and normal ordering We will show now that the ground state or vacuum vac is the state in which all the negative energy states are filled (as shown in Fig.7.2)

† ∣ ⟩ vac = a p 0 (7.29) $ −,σ σ,p ∣ ⟩ ( )∣ ⟩ E

p

∣ ∣

Figure 7.2 Ground State of the Dirac theory.

We will normal-order all the operators relative to the vacuumstate vac . This amounts to a particle-hole transformation for the negative energy states. † Thus, we define the creation and operators bσ p ,b∣ σ p⟩ † and dσ p ,dσ p to be ( ) ( ) b p = a p ( ) ( ) σ σ,+ † dσ p = aσ,− p (7.30) ( ) ( ) which obey ( ) ( ) bσ p vac = dσ p vac = 0(7.31) The Hamiltonian now reads ( )∣ ⟩ ( )∣ ⟩ 3 d p m † † H = p0 bσ p bσ p − dσ p dσ p (7.32) ! 3 p0 # 2π σ=1,2 ˆ [ ( ) ( ) ( ) ( )] We now normal order( H) relative to the vacuum state

H =∶ H ∶+E0 (7.33) 7.1 The Dirac equation and Quantum Field Theory 195 with a normal-ordered Hamiltonian 3 d p m † † ∶ H ∶ = p0 bσ p bσ p + dσ p dσ p (7.34) ! 3 p0 # 2π σ=1,2 The constant E is the (negative and! ( divergent)) ( ) ground( ) state( )" energy 0 ( ) E = −2V d3p p2 + m2 (7.35) 0 ! . similar to the expression we already countered in the Klein-Gordon theory, but with opposite sign. The factor of 2 is due to spin. In terms of the operators bσ and dσ the Dirac field has the mode expansion 3 d p m σ −ip⋅x † σ ip⋅x ψ x = b p u p e + d p v p e (7.36) α 3 p σ α σ α ! 2π 0 #= σ 1,2 ( ) ( ) which( satisfy) equal-time canonical! ( ) anticommutation( ) ( relat) ions( ) " ( ) † ′ = 3 ′ ψα x ,ψβ x δαβ δ x − x ′ † † ′ ψα x ,ψβ x = ψα x ,ψ x = 0(7.37) { ( ) ( )} ( β ) { ( ) ( )} { ( ) ( )} 7.1.2 One-particle states The excitations of this theory can be constructed by using thesamemethods employed for non-relativistic many-particle systems. Let us first construct the total four- P µ 3 µ 3 0µ d p m µ † † P = d xT = p ∶ bσ p bσ p − dσ p dσ p ∶ (7.38) ! ! 3 p0 # 2π σ=1,2 Hence ( ) ( ) ( ) ( ) ( ) 3 µ d p m µ † † ∶ P ∶= p bσ p bσ p + dσ p dσ p (7.39) ! 3 p0 # 2π σ=1,2 † † ! ( ) ( ) ( )= ( 2)" 2 The states bσ p vac( )and dσ p vac have energy p0 p + m and mo- mentum p, % ( )∣ ⟩ †( )∣ ⟩ † ∶ H ∶ bσ p vac =p0bσ p vac † † ∶ H ∶ dσ p vac =p0dσ p vac i † ( )∣ ⟩ i † ( )∣ ⟩ ∶ P ∶ bσ p vac =p bσ p vac i † ( )∣ ⟩ i † ( )∣ ⟩ ∶ P ∶ dσ p vac =p dσ p vac (7.40) ( )∣ ⟩ ( )∣ ⟩ ( )∣ ⟩ ( )∣ ⟩ 196 Quantization of the Free Dirac Field We see that there are four different states which have the same energy and momentum. Let us find quantum numbers to classify these states.

7.1.3 Spin

The Mµνλ for the Dirac theory is

µ ν λ λ ν 1 νλ M = d3x ψ¯ x γ i x ∂ − x ∂ + σ ψ x (7.41) µνλ ! 2 where σνλ is the ( ) 1 # $ 2 ( ) νλ i ν λ σ = γ ,γ (7.42) 2 νλ The conserved angular momentum J 3 is 4 νλ νλ † ν λ λ ν 1 νλ J = M0 = d3xψ x i x ∂ − x ∂ + σ ψ x (7.43) ! 2

In particular, out of its space( components) 1 ( J ij,wecanconstructthetotal) 2 ( ) angular momentum three-vector J

i 1 ijk jk † ijk j k 1 ijk jk J = * J = d3xψ i* x ∂ + * σ ψ (7.44) 2 ! 2

It is easy to check that, in the Dirac representation,& the lasttermrepresents' the spin. In the quantized theory, the angular momentum operator is J = L + S (7.45) where L is the orbital angular momentum

† L = d3xψ x x × i∂ψ x (7.46) ! while S is the spin ( ) ( ) † S = d3xψ x Σ ψ x (7.47) ! where Σ is the 4 × 4matrix ( ) ( ) 1 σ 0 1 Σ = ≡ σ (7.48) 2 0 σ 2

In order to measure the spin polarization& ' of a state we first go to the rest frame in which p = 0. In this frame we can consider the four-vector W µ µ W = 0,mΣ (7.49)

( ) 7.1 The Dirac equation and Quantum Field Theory 197 Let nµ be the space-like 4-vector nµ = 0, n ,wheren has unit length. Thus, µ µ n nµ = −1. We will use n to fix the direction of polarization in the rest frame. ( ) µ The scalar product Wµn is a Lorentz invariant scalar and, hence, its value is independent of the choice of frame. In the rest frame we have

µ m m n ⋅ σ 0 W n = −mn ⋅ Σ ≡ − n ⋅ σ = − (7.50) µ 2 ⃗ 2 0 n ⋅ σ

µ & ' In particular, if n = ez then Wµn is

µ m σ3 0 Wµn = − (7.51) 2 0 σ3 & ' − 1 W ⋅n which is diagonal. The operator m is a Lorentz scalar which measures the spin polarization:

1 1 − W ⋅ nu 1 p = + u 1 p m 2 1 ( ) 1 ( ) − W ⋅ nu 2 p = − u 2 p m ( ) 2 ( ) 1 ( ) 1 ( ) − W ⋅ nv 1 p = + v 1 p m ( ) 2 ( ) 1 ( ) 1 ( ) − W ⋅ nv 2 p = − v 2 p (7.52) m ( ) 2 ( ) ( ) ( ) −(1 ) ⋅ ( ) It is straightforward to check that m W n is the Lorentz scalar

1 1 µ ν λρ 1 − W ⋅ n = * n p σ = γ n p (7.53) m 4m µνλρ 2m 5 which enables us to write the spin projection operator P/ /n

1 P n = I + γ n ( ) (7.54) 2 5 where we used that ( ) ( /)

1 σ 1 σ σ 1 σ γ n pu p = γ nu p = −1 u p 2m 5 2 5 2 1 (σ) 1 (σ) σ 1 (σ) γ n pv p = − γ nv p = −1 v p (7.55) 2m 5 / / ( ) 2 5 / ( ) ( ) 2 ( ) ( ) ( ) ( ) / / ( ) / ( ) ( ) ( ) 198 Quantization of the Free Dirac Field 7.1.4 Charge The Dirac Lagrangian is invariant under the global (phase) transformation ′ ψ → ψ = eiαψ ′ − ψ¯ → ψ¯ = e iαψ¯ (7.56) Consequently, it has a locally conserved current jµ µ µ j = ψγ¯ ψ (7.57) which is also locally gauge invariant. As a result it has a conserved total charge Q = −e d3xj0 x .Thecorrespondingoperatorinthequantized ∫ theory Q is ( ) 3 0 3 † Q = −e d xj x = −e d xψ x ψ x (7.58) ! !

The total charge operator Q commutes( ) with the Dirac( ) Hamiltonian( ) Hˆ Q, H = 0(7.59) Hence, the eigenstates of the Hamiltonian H have a well defined charge. [ ] In terms of the creation and annihilation operators, the total charge op- erator Q becomes 3 d p m † † Q = −e bσ p bσ p + dσ p dσ p (7.60) ! 3 p0 # 2π σ=1,2 which is not normal-ordered relative# to( )vac( .Thenormal-orderedcharge) ( ) ( )$ ( ) operator ∶ Q ∶ is 3 ∣ ⟩ d p m † † ∶ Q ∶= −e bσ p bσ p − dσ p dσ p (7.61) ! 3 p0 # 2π σ=1,2 and we can write ! ( ) ( ) ( ) ( )" ( ) Q = ∶ Q ∶+Qvac (7.62) where Qvac is the unobservable (and divergent) vacuum charge d3p Qvac = −eV (7.63) ! 2π 3 V being the volume of space. From now on we will define the charge to be the subtracted charge operator ( )

∶ Q ∶= Q − Qvac (7.64) 7.1 The Dirac equation and Quantum Field Theory 199 which annihilates the vacuum state

∶ Q∶ vac = 0(7.65) the vacuum is neutral. In other words, we measure the charge of a state ∣ ⟩ relative to the vacuum charge which we define to be zero. Equivalently, this amounts to a definition of the order of the operators in ∶ Q ∶

1 † ∶ Q ∶ = −e d3x ψ x ,ψ x (7.66) ! 2

† † The one-particle states bσ vac and dσ vac[ (have) ( well)] defined charge: † † ∶ Q ∶ b p vac = − eb p vac ∣ σ ⟩ ∣ ⟩ σ † † ∶ Q ∶ dσ p vac = + edσ p vac (7.67) ( )∣ ⟩ ( )∣ ⟩ † − Hence we identify the state b(σ )p∣ vac⟩ with an( )∣ ⟩ of charge e,spin 2 2 † σ,momentump and energy p0 = p + m .Similarly,thestatedσ p vac is a with the same quantum( )%∣ ⟩ numbers and energy of the electron but with positive charge +e. ( )∣ ⟩

7.1.5 The Dirac energy-momentum tensor The energy-momentum tensor of the Dirac theory is obtained following the standard approach presented earlier. On general grounds, weexpectthat the energy-momentum tensor should be given by µν µ ν T = iψγ¯ ∂ ψ − L (7.68)

Using the equation of motion of the free Dirac filed, i.e the Dirac equation, we find that the energy-momentum tensor for the Dirac theory reduces to µν µ ν T = iψγ¯ ∂ ψ (7.69)

From this expression it follows that the Hamiltonian is

† H = d3xT00iψγ¯ 0∂0ψ = d3xψ γ0 −iγ ⋅ ∂ + m ψ (7.70) ! ! which is indeed the Hamiltonian of the Dirac( field. )

7.1.6 Causality and the spin-statistics Let us finally discuss the question of causality and the spin-statistics con- nection in the Dirac theory. To this end we will consider the anticommutator 200 Quantization of the Free Dirac Field of two Dirac fields at different times

i∆αβ x − y = ψα x ,ψβ y (7.71)

By using the field expansion( we obtain) { the( expression) ( )} 3 d p m −ip⋅ x−y σ σ ip⋅ x−y σ σ i∆ x−y = e u p u¯ p +e v p v¯ p αβ 3 p α β α β ! 2π 0 #= σ 1,2 ( ) ( ) ( ) ( ) ( ) ( ) ! ( ) ( ) ( )(7.72)( )" By using the (completeness)( ) identities p + m σ σ = uα p u¯β p #= 2m αβ σ 1,2 ( ) ( ) /p − m σ ( ) σ ( ) = & ' vα p v¯β p (7.73) #= 2m αβ σ 1,2 ( ) ( ) / we can write the anticommutator( ) in the( ) form& '

3 d p m p + m −ip⋅ x−y p − m ip⋅ x−y i∆ x − y = e + e αβ 3 p ! 2π 0 2m αβ 2m αβ ( ) ( ) / / (7.74) ( ) 5& ' & ' 6 After some straightforward( ) algebra, we obtain the result

3 d p 1 −ip⋅ x−y ip⋅ x−y i∆αβ x − y = i∂x + m e − e ! 2π 3 2p0 ( ) ( ) 3 d p − ⋅ − ⋅ − ( ) = i∂ + m ( / )! e ip x y − eip x "y x( ) αβ 3 (7.75) ! 2π 2p0 ( ) ( ) We recognize the integral( / on) the r.h.s. of Eq.(7.75)! to be the " of ( ) two free scalar (Klein-Gordon) fields, ∆KG x − y . Hence, the anticommutator two Dirac fields of the Dirac theoryis ( ) i∆αβ x − y = i∂ + m αβ i∆KG x − y (7.76) − − Since ∆KG x y vanishes( at) space-like( / ) separations,( so) does ∆αβ x y . Hence, the Dirac theory quantized with anticommutators obeys causality. On the other( hand,) had we had quantized the Dirac theory with commuta-( ) tors (which, as we saw, leads to a theory without a ground state) we would have also found a violation of causality. Indeed, we would have obtained instead the result

∆αβ x − y = i∂ + m αβ∆˜ x − y (7.77)

( ) ( / ) ( ) 7.2 The of the field 201 where ∆˜ x − y is given by d3p ˜ − = −ip⋅ x−y + ip⋅ x−y ( ∆) x y 3 e e (7.78) ! 2π 2p0 ( ) ( ) which does not vanish( at) space-like separations.7 Instead, atequaltimesand8 − ( ) at long distances ∆& x y decays as e−mR (∆˜ R,)0 ≃ , for mR ≫ 1(7.79) R2 Thus, if the Dirac theory( were) to be quantized with , the field operators would not commute at equal times at distances shorter than the . This would be a violation of locality. The same result holds in the theory of the scalar field if it is quantized with anticommutators. These results can be summarized in the Spin-Statistics Theorem:fields with half- spin must be quantized as fermions,obeycanonicalanti- commutation relations, whereas fields with integer spin must be quantized as bosons,obeycanonicalcommutation relations. If a field theory is quantized with the wrong spin-statistics connection, either the theory becomes non- local, with violations of causality, and/or it does not have agroundstate, or it contains states in its spectrum with negative norm. Notice that the arguments we have used were derived for free local theories. It is a highly non-trivial task to prove that the spin-statistics connection also remains valid for interacting theories. Although this can be done by making suffi- ciently strong assumptions of the behavior of perturbation theory, in reality it must the spin-statistics connection must be regarded as an axiom of local relativistic quantum field theories.

7.2 The Propagator of the Dirac spinor field

We will now compute the propagator for a spinor field ψα x .Wewillfind that it is essentially the Green function for the the . The propagator is defined by ( ) ′ ′ Sαβ x − x = −i vac Tψα x ψ¯β x vac (7.80) where we have used the time ordered product of two fermionic field opera- ( ) ⟨ ∣ ( ) ( )∣ ⟩ tors, which is defined by ¯ ′ ′ ¯ ′ ′ ¯ ′ Tψα x ψβ x = θ x0 − x0 ψα x ψβ x − θ x0 − x0 ψβ x ψα x (7.81) Notice the change in sign with respect to the time ordered product of bosonic ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) operators. The sign change reflects the anticommutation properties of the 202 Quantization of the Free Dirac Field field. In other words, inside a time ordered product, Fermi fields behave as if they were anticommuting c-numbers. We will show now that this propagator is closely connected to the propaga- tor of the free scalar field, the Green function for the Klein-Gordon operator ∂2 + m2. ′ By acting with the Dirac operator on Sαβ x − x we find

− − ′ = − − ¯ ′ i∂ m αβ Sβλ x x i i∂ m αβ vac( Tψβ) x ψλ x vac (7.82) We now use that : / ; ( ) : / ; ⟨ ∣ ( ) ( )∣ ⟩ ∂ ′ ′ θ x0 − x0 = δ x0 − x0 (7.83) ∂x0 and the fact that the equation( of motion) ( of the Heisenberg) fieldoperators ψα is the Dirac equation, − = i∂ m αβ ψβ x 0(7.84) to show that : / ; ( ) ′ ′ i∂ − m Sβλ x − x = −i vac T i∂ − m ψβ x ψ¯λ x vac αβ αβ ′ 0 ¯ ′ 7 / 8 ( ) + δ x⟨0 −∣x0 : /vac γ;αβψβ x( ψ) λ x( )vac∣ ⟩ ′ + ψ¯ x γ0 ψ x vac( λ )7⟨ αβ ∣β vac( ) ( )∣ ⟩ ′ † ′ = δ x − x γ0 vac ψ x ,ψ x vac γ0 ⟨ 0∣ (0 )αβ ( )∣β ⟩8 ν νλ ′ 3 ′ = δ x0 − x0 δ x − x δαλ (7.85) ( ) ⟨ ∣< ( ) ( )= ∣ ⟩ ′ Therefore we find that Sβλ x (− x is the) ( solution) of the equation − − ′ = 4 − ′ i∂ m (αβ Sβλ )x x δ x x δαλ (7.86) ′ = ¯ ′ Hence Sβλ x − x : /−i vac; Tψβ (x ψλ x) vac( is the) Green function of the Dirac operator. We saw( before) that⟨ there∣ is a( close) ( connection)∣ ⟩ between the Dirac and the Klein-Gordon operators. We will now use this connection to relate their ′ . Let us write the Green function Sαλ x − x in the form ′ ′ S x − x = i∂ + m G x − x (7.87) αλ αβ βλ ( ) ′ Since Sαλ x − x satisfies( Eq.(7.86),) : / we find; that( ) ′ ′ i∂ − m S x − x = i∂ − m i∂ + m G x − x (7.88) ( αβ )βλ αβ βν νλ

: / ; ( ) : / ; : / ; ( ) 7.3 Discrete symmetries of the Dirac theory 203 But − + = − 2 + 2 i∂ m αβ i∂ m βν ∂ m δαν (7.89) ′ Hence, Gαν x − x: /must; satisfy: / ; # $ ′ ′ − ∂2 + m2 G x − x = δ4 x − x δ (7.90) ( ) αν αν ′ Therefore Gαν x − x# is given$ by ( ) ( ) ′ ′ G x − x = −G 0 x − x δ ( ) αν αν (7.91) ( ) G 0 x−x′ where is the propagator( ) for a free( massive) scalar field, the Green function( of) the Klein-Gordon equation ( ) ′ ′ ∂2 + m2 G 0 x − x = δ4 x − x (7.92)

( ) ′ We then conclude that# the Dirac$ ( propagator) S(αβ x −) x ,andtheKlein- ′ Gordon propagator G 0 x − x are related by ( ) ′ ( ′ ) S x − x = − i∂ + m G 0 x − x (7.93) αβ ( ) αβ ( ) In particular, this relationship implies that the have essentially the same ( ) : / ; ( ) asymptotic behaviors that we discussed for the free scalar field, a power-law behavior at short distances (albeit with a different power), and exponential (or oscillatory) behavior at large distances. The spinor structure of the Dirac ′ propagator is determined by the operator in front of G 0 x−x in Eq.(7.93). In momentum space, the Feynman propagator for( the) Dirac field,given by Eq. (7.93), becomes ( ) p + m = Sαβ p 2 2 (7.94) p − m + i* αβ / Hence we get the same pole( structure) & in the time-ordered' propagator as we did for the Klein-Gordon field.

7.3 Discrete symmetries of the Dirac theory We will now discuss three important discrete symmetries in relativistic field theories: charge conjugation, and time reversal.Thesediscretesymme- tries have a different role, and a different standing, than the continuous sym- metries discussed before. In a relativistic quantum field theory the ground state, the vacuum,mustbeinvariantundercontinuousLorentztransfor- mations, but it may not be invariant under C, P or T .However,inalocal 204 Quantization of the Free Dirac Field relativistic quantum field theory the product CPT is always a good symme- try. This is in fact an axiom of relativistic local quantum field theory. Thus, although C, P or T may or may not to be good symmetries of the vacuum state, CPT must be a good . As in the case of the symmetries we discussed before, these symmetries must also be realized in the Fock space of the quantum field theory.

7.3.1 Charge conjugation Charge conjugation is a symmetry that exchanges and (or holes). Consider a Dirac field minimally coupled to an external electro- magnetic field Aµ.TheequationofmotionfortheDiracfieldψ is i∂ − eA − m ψ = 0(7.95) We will define the charge conjugate field ψc : / / ; c − ψ x = Cψ x C 1 (7.96) − where C is the (unitary) charge conjugation operator, C 1 = C†,suchthat ( ) ( ) ψc obeys c i∂ + eA − m ψ = 0(7.97)

ψ¯ = ψ†γ0 Since obeys : / / ; µ ←− ψ¯ γ −i ∂ µ − eAµ − m = 0(7.98) which, when transposed, becomes ! 7 8 " µ T T γ −i∂µ − eAµ − m ψ¯ = 0(7.99) where T is the transpose, and 3 : ; 4 T T ∗ ψ¯ = γ0 ψ (7.100) − Let C be an invertible 4 × 4matrix,whereC 1 is its inverse. Then, we can write µ t −1 t C γ −i∂µ − eAµ − m C Cψ¯ = 0(7.101) such that 3 : ; 4 µ t − µ C γ C 1 = −γ (7.102) Hence, : ; T i∂ + eA − m Cψ¯ = 0(7.103)

>: / /; ? 7.3 Discrete symmetries of the Dirac theory 205 For Eq. (7.103) to hold, we must have

† c T T ∗ CψC = ψ = Cψ¯ = Cγ0 ψ (7.104)

Hence the field ψc thus defined has positive charge +e. We can find the charge conjugation matrix C explicitly:

2 0 iσ − C = iγ2γ0 = = C 1 (7.105) −iσ2 0

In particular this means that ψc is@ given by A

c T t ∗ ∗ ψ = Cψ¯ = Cγ0 ψ = iγ2ψ (7.106)

Eq. (7.106) provides us with a definition for a charge neutral , i.e. ψ represents a neutral fermion if ψ = ψc.Hencetheconditionis ∗ ψ = iγ2ψ (7.107)

ADiracfermionthatsatisfiestheneutralityconditionisknown as a Majo- rana fermion. To understand the action of C on physical states we can look for instance, at the charge conjugate uc of the positive energy, up spin, and charge −e, spinor in the rest frame

ϕ −imt u = e (7.108) 0 which is & '

c 0 imt u = e (7.109) −iγ2ϕ∗ which has negative energy, down@ spin andA charge +e. At the level of the full quantum field theory, we will require the vacuum state vac to be invariant under charge conjugation:

C vac = vac (7.110) ∣ ⟩

How do one-particle states transform?∣ ⟩ ∣ To⟩ determine that we look at the action of charge conjugation C on the one-particle states, and demand that particle and anti-particle states to be exchanged under charge conjugation

† † −1 † Cbσ p vac = Cbσ p C C vac ≡ dσ p vac † † −1 † Cdσ p vac = Cdσ p C C vac ≡ bσ p vac (7.111) ( )∣ ⟩ ( ) ∣ ⟩ ( )∣ ⟩ ( )∣ ⟩ ( ) ∣ ⟩ ( )∣ ⟩ 206 Quantization of the Free Dirac Field Hence, for the one-particle states to satisfy these rules it is sufficient to require that the field operators bσ p and dσ p satisfy † † Cb p C = d p ; Cd p C = b p (7.112) σ σ ( ) σ ( ) σ Using that ( ) ( ) ( ) ( ) 2 ∗ 2 ∗ uσ p = −iγ vσ p ; vσ p = −iγ uσ p (7.113) we find that the field operator ψ x transforms as ( ) ( ( )) ( ) ( ( )) † = ¯ 0 2 T Cψ x C( ) −iψγ γ (7.114) and ( ) # $ † T Cψ¯ x C = −iγ0γ2ψ (7.115)

In particular the fermionic bilinears we discussed before satisfy the trans- ( ) # $ formation laws:

Cψψ¯ C† = +ψψ¯ , Ciψγ¯ 5ψC† = iψγ¯ 5ψ, µ † µ µ † µ Cψγ¯ ψC = −ψγ¯ ψ, Cψγ¯ γ5ψC = +ψγ¯ γ5ψ (7.116)

7.3.2 Parity − We will define as parity the transformation P = P 1 which reverses the momentum of a particle but not its spin. Once again, the vacuumstateis invariant under parity. Thus, we must require † † −1 † Pbσ p vac = Pbσ p P P vac ≡ bσ −p vac † † −1 † Pdσ p vac = Pdσ p P P vac ≡ dσ −p vac (7.117) ( )∣ ⟩ ( ) ∣ ⟩ ( )∣ ⟩ In real space this transformation is equivalent to ( )∣ ⟩ ( ) ∣ ⟩ ( )∣ ⟩ −1 0 ¯ −1 ¯ Pψ x,x0 P = γ ψ −x,x0 , Pψ x,x0 P = ψ −x,x0 γ0 (7.118)

( ) ( ) ( ) ( ) 7.3.3 Time reversal Finally, we discuss time reversal T .WewilldefineT as the operator

iHx −1 −iHx T e 0 T = e 0 , (7.119)

We will require the time reversal operator to be unitary in thesensethat − † T 1 = T (7.120) 7.4 Chiral symmetry 207 However we will also require the operator to act on c-numbers as complex conjugation, i.e. ∗ T c-number = c-number T (7.121)

An operator with these properties is said to be anti-linear (anti-unitary). ( ) ( ) As a result, time reversal is the operator that which reversesthemomen- tum and the spin of the particles: † † T bσ p T = b−σ −p , T dσ p T = d−σ −p (7.122) while leaving the vacuum state invariant: ( ) ( ) ( ) ( ) T vac = vac (7.123)

In real space this implies: ∣ ⟩ ∣ ⟩ † 1 3 ∗ T ψ x,x0 T = −γ γ ψ x, −x0 (7.124)

( ) ( ) 7.4 Chiral symmetry We will now discuss a global symmetry specific of theories of spinors known as chiral symmetry. Let us consider again the Dirac Lagrangian

L = ψ¯ i∂ − m ψ (7.125)

Let us define the chiral transformation : / ; ′ iγ θ ψ = e 5 ψ (7.126) where θ is constant phase in the range 0 ≤ θ < 2π.Wewishtofindthe Lagrangian for the new transformed field ψ.From

iγ5θ µ iγ5θ L = ψ¯e iγ ∂µ − m e ψ (7.127) and the fact that : ; γµ,γ5 = 0(7.128) after some simple algebra, which uses the identity B C µ iγ θ −iγ θ µ γ e 5 = e 5 γ , (7.129) we find that the field ψ satisfies a modified Dirac Lagrangian of the form 2iγ θ L = ψ¯ i∂ − me 5 ψ (7.130)

7 / 8 208 Quantization of the Free Dirac Field Thus for m ≠ 0, the form of the Dirac Lagrangian changes under a chiral transformation. However, if the theory is massless, the Dirac theory has an exact global chiral symmetry. It is also instructive to determine how various fermion bilinears transform under the chiral transformation. We find that the Dirac mass , ψψ¯ ,andthe axial mass, iψγ¯ 5ψ,underachiraltransformationtransformasfollows ¯′ ′ ¯ ¯ ψ ψ = cos 2θ ψψ + sin 2θ iψγ5ψ ¯′ 5 ′ ¯ ¯ iψ γ ψ = − sin 2θ ψψ + cos 2θ iψγ5ψ (7.131) ( ) ( ) and, hence, are not invariant under the chiral transformation. Instead, under ( ) ¯ ( ) ¯ the chiral transformation the Dirac mass, ψψ,andtheγ5 mass, iψγ5ψ, transform (rotate) into each other. Finally we note that, although the Dirac Lagrangian is not chiral invariant if m ≠ 0, the Dirac current ′ µ ′ µ ψ¯ γ ψ = ψγ¯ ψ (7.132) is invariant under the chiral transformation, and so is the coupling of the Dirac field to a gauge field.

7.5 Massless fermions Let us look at the massless limit of the Dirac equation in more detail. Histor- ically this problem grew out of the study of (which we now know are not necessarily massless, at least not all of them). For aneigenstateof 4-momentum pµ,theDiracequationis p − m ψ p = 0(7.133)

In the massless limit m = 0, the Dirac equation simply becomes :/ ; ( ) pψ p = 0(7.134) which is equivalent to / ( ) γ5γ0pψ p = 0(7.135) Upon expanding in components we find / ( ) γ5p0ψ p = γ5γ0γ ⋅ pψ p (7.136) However, since ( ) ( ) σ 0 γ γ γ = = Σ (7.137) 5 0 0 σ

1 2 7.5 Massless fermions 209 we can write

γ5p0ψ p = Σ ⋅ pψ p (7.138) Thus, the γ is equivalent to the helicity Σ ⋅ p of the state (only 5 ( ) ( ) in the massless limit!). This suggests the introduction of the chiral basis in which γ5 is diagonal, 0 −I I 0 0 σ γ = γ = , γ = (7.139) 0 −I 0 5 0 −I −σ 0

In this basis& the massless' Dirac equation& ' becomes & ' σ 0 I 0 ⋅ pψ p = p ψ p (7.140) 0 σ 0 −I 0

Let us write the 4-spinor& ψ'in terms( ) of& two 2-spinors' ( of) the form ψ ψ = R (7.141) ψL in terms of which the Dirac equation decomposes& ' into two separate equations for each chiral component, ψR and ψL.Thustheright handed (positive chirality) component ψR satisfies the

σ ⋅ p − p0 ψR = 0(7.142) while the left handed (negative chirality) component satisfies instead ( ) σ ⋅ p + p0 ψL = 0(7.143) Hence, one massless Dirac spinor is equivalent to two Weyl spinors. ( ) We conclude that a theory of free massless Dirac fermions has aglobal chiral symmetry. It is natural to assume that it must also havealocally 5 conserved chiral (axial) current, that we will denote by jµ.Anelementary calculation derives the result 5 ¯ 5 jµ = iψγ γµψ (7.144) However, we also know that the Dirac theory has a global U 1 phase sym- metry which, when coupled to the vector field Aµ,becomeslocalU 1 gauge invariance, and has a locally conserved gauge current, jµ = (ψγ¯)µψ.Wewill see in chapter 20 that in an interacting theory its UV divergencies( ) makes it impossible for both currents to be simultaneously conserved and that, if the theory is to be gauge-invariant, then the chiral current cannot not con- served. In other words, a classically conserved current may not be conserved at the quantum level. The phenomenon of non-conservation at the quantum 210 Quantization of the Free Dirac Field level of a classically conserved current is known as a quantum .In this case, the non-conservation of the chiral current is known as the chiral (or axial) anomaly.