Phys 322 Chapter 11 Lecture 33 Fourier Optics
Optical applications: Linear optical system Fraunhofer diffraction Other applications Optical application: linear system
Function f(y,z) passes through an optical system and is transformed into g(Y,Z): gY ,Z L f y, z The system is linear if: • multiplying f(y,z) with constant a produces output ag(Y,Z) L af y, z aL f y, z • when the input is a sum of two (or more) functions,
f1 (y,z) +f2 (y,z), the output would be g1 (y,z) +g2 (y,z), where g1 and g2 are outputs of f1 and f2, respectively
L f1y, z f2 y, z L f1y, zL f2 y, z Optical application: linear system
gY ,Z L f y, z
Linear system is space invariant if it possesses the property of stationarity. changing the position of input merely changes the position of output without altering its functional form
Idea behind: at each point in image plane g(Y,Z) is a linear superposition of outputs arising from each of the individual points on the object f(y,z) Optical application: linear system
gY ,Z L f y, z
f y, z f y', z ' y' y z'z dy'dz' gY ,Z L f y', z' y'y z'z dy'dz' gY ,Z f y', z ' L y'y z'z dy 'dz' Impulse response Optical application: linear system g Y ,Z f y', z ' L y'y z'z dy 'dz' yz
Impulse response: gY ,Z L f y, z L y' y z'z
image of a single object point at (y’,z’)
If we knew the impulse response of the system, we could construct the image g of any object f. Optical application: linear system
Example: lens system Image: upright, same size
I0(y,z) - irradiance in object plane Image blur due to diffraction etc: S y, z,Y ,Z 2f point spread function 2f Image intensity due to one element radiant flux I0(y,z)dydz
dIi Y ,Z S y, z,Y ,Z I0 y, zdydz If the object emits incoherent light, intensities add up
I Y ,Z S y, z, Y ,Z I y, z dydz i 0 Optical application: linear system
I Y ,Z S y, z, Y ,Z I y, z dydz i 0 Meaning of S Suppose object is just a single
luminous point at y0, z0
I Y ,Z S y, z, Y ,Z A y y z z dydz i 0 0 A = 1 W/m2
Ii Y ,Z AS y0, z0,Y ,Z
Ideal system will show far-field diffraction, Airy distribution Optical application: linear system
dIi Y ,Z AS y0, z0,Y,Z Space invariance: Spread function is the same for
any x0,y0 (reality: spread function varies slightly with position)
for MT=1 S y, z,Y ,Z S Y y,Z z
For source in center:S Y ,Z
I Y ,Z I y, z S Y y,Z z dydz i o convolution integral Linear systems summary
For simplicity, considering the case 1) incoherent light, and
2) MT = +1. The flux density arriving at the image point from dydz is
dIi (Y, Z) S(y, z;Y, Z)I0 (y, z)dydz Point-spread function z Z
I0 (y,z) Ii (Y,Z) y Y Ii (Y, Z) S(y, z;Y, Z)I0 (y, z)dydz Ii (Y, Z) S(y, z;Y, Z)I0 (y, z)dydz z Z Ii (Y,Z) Point-spread function I0 (y,z) Example: I (y, z) A (y y ) (z z ) y Y 0 0 0 Ii (Y, Z) A (y y0 ) (z z0 )S(y, z;Y, Z)dydz
AS(y0 , z0 ;Y, Z) The point-spread function is the irradiance produced by the system with an input point source. In the diffraction-limited case with no aberration, the point-spread function is the Airy distribution function. The image is the superposition of the point-spread function, weighted by the source radiant fluxes.
Ii (Y, Z) S(y, z;Y, Z)I0 (y, z)dydz z I (y,z) Z 0 Ii (Y,Z) I0 (y, z) Ai (y yi ) (z zi ) i y Y Ii (Y, Z) Ai S(yi , zi ;Y, Z) i Transfer functions for characterization of optical systems:
I (,Y Z ) S ( Y y , Z z ) I (,) y z dydz i 0
Iyz0 (,) Syz (,)
YYY{(,IYZi )} {(,)} I0 yz {(,)} Syz
Y {(,)}Syz Tk (YZ , k ) Optical transfer function T (OTF) M (,kk )exp(, i kk ) Modulation transfer function M (MTF) YZ YZ Phase transfer function (PTF)
We use these functions to characterize the quality of an optical system and to reconstruct the original (unknown) object. Optical application: Fraunhofer diffraction y Y Light r P (screen) x Z z Each area dydz is a source of spherical waves:
E y, zdydz itkr Source strength per dE A e yz R unit area E y, zei y,zdydz dE A eik YyZz / R R aperture function dE A y, zeikYyZz/ Rdydz
EY ,Z A y, z eikYyZz / Rdydz Optical application: Fraunhofer diffraction y Y Light r P (screen) x Substitute:
Z kY kY / R z k kZ / R EY ,Z A y, z eikYyZz / Rdxdz Z For each point Y,Z Ek ,k A y, z e ikY ykZ z dydz Y Z there is corresponding spatial frequency The field distribution in the Fraunhofer diffraction is the Fourier transform of the field distribution across the aperture (aperture function) E kkYZ,, Y T yz
1 The inverse transform:T yz,, Y EkYZ k Optical application: single slit y Y Ek ,k A y, z e ikY ykZ z dydz Y Z Light
EkY ,kZ F A y, z R k kY / R k kZ / R Z Y Z z
A 0 when z b / 2 A y, z 0 when z b / 2
b/ 2 Ek F A z A z eikZ zdz A eikZ zdz Z 0 b/ 2 k b Ek A bsinc z k kZ / R k sin Z 0 2 Z Got the same result Optical application: double slit Single A(x) A(x) Double slit slit A0 A0
E(k) E(k) Phys 322 Chapter 11 Lecture 33 Fourier Optics
Other applications: Time and frequency domains FTIR and many more Time and frequency domain
E(t)=f(t) - electric field depends on time (time domain) Energy flux ~|E(t)|2 = |f(t)|2 2 2 Total emitted energy: f t dt f t f tf *t
F()=F {f(t)} Fourier transform (frequency domain) |F()|2 = measure of energy per unit frequency interval 2 1 * it 1 * it f t dt f t F e ddt F f t e dtd 2 2
2 2 1 2 |F()| - f t dt Fd 2 power spectrum or Spectral energy Parseval’s formula distribution Emission spectrum of excited atoms/molecules Emission intensity is proportional to the number h h of molecules in excited state N dN N N N e t N et / dt 0 0
t / rate of transition Emission intensity: I I0e for t0 (damping constant) t / 2 = 1/ = lifetime Et E0e cos0t F E et / 2 cos t eitdt 0 0 0 2 2 2 E / 4 0 F 2 2 2 0 / 4 Lorentzian profile
full width at half maximum: fwhm = 0 natural linewidth Example problem:
An excited state lifetime of a chlorophyll molecule is 5 ns. What is the natural linewidth of its emission spectrum, if transition maximum occurs at 670 nm. Express linewidth in nm
fwhm = = 1/ = 1/(5 ns) = 2×1010 Hz c c 2 2 2 2.81015 Hz 0 0 0 0 0 0 c c c fwhm 2 2 2 2 0 / 2 0 / 2 0
-3 fwhm = 4.9×10 nm 0 Reality: fwhm ~ 10 nm - inhomogeneus broadening FTIR spectrometer (Fourier Transform InfraRed) IR detector What would be recorded if IR source Movable emits a single wavelength? mirror
IR source 2 I A cos Mirror Acos c What if there are two wavelengths? N I A cos i i i c i1 I A cos d c FTIR spectrometer: qualitative approach IR detector I A cos d Movable c mirror
IR source
Mirror Measure I()
FT gives spectrum:AI Y FTIR spectrometer
IR detector No sample Sample Movable mirror
IR source
Mirror With sample
Transmittance spectrum of a sample (polystyrene film) FTIR formal math: Autocorrelation
IR detector Electric field at detector: Movable mirror Ed t E t Et
IR source / c Measure intensity averaged in time: Mirror I Et 2 Et E t 2 dt d I E 2 t dt 2 E t E t dt E 2 t dt I 2 E 2 t dt 2 E t E t dt Autocorrelation Constant background Autocorrelation c f t f t dt ff
2 Wiener-Khinchine theorem: Y cFff
IR detector Movable I E t E t dt mirror
2 IR source Y IF
Mirror c f t h t dt f h Cross-correlation: hf Extraction of signal from noise
Sine function “hidden” in noise.
Autocorrelation of white noise is 0. Spectral grating. E(t) - electric field depends on time (time domain)
1 Et Feixd 2
F E t e ixdx 2 I() I() Isin I F m a sin a
Grating performs a Fourier transform - intensity distribution on screen is the Fourier image of the incoming time-dependent EM field Pulse shaping.
Et Ite it ESe i
EoutthtEt in Altering E(t) - will cause change in pulse shape and in spectrum EHEout in Altering E() - will cause change in spectrum and in pulse shape
www.physics.gatech.edu/gcuo/lectures/UFO13Pulseshaping.ppt Pulse shaping: optical Fourier transform
S() S’() H( )
x ()x
grating grating f f ff f f John Heritage, UC Davis Fourier Andrew Weiner, Purdue Transform Plane How it works: The grating disperses the light, mapping color onto angle. The first lens maps angle (hence wavelength) to position. The second lens and grating undo the spatio-temporal distortions. Pulse shaping: optical Fourier transform
Instead of amplitude mask - can use phase mask, or combination of the two
Spatial modulator Pulse shaping for telecommunication.
The goal: multiple pulses with variable separations
Real example