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Physics 557 – Lecture 8

Quantum numbers of the Standard Model – (See Chapter 2 in Griffiths and Part B and Chapter 15 in Rolnick.) We want to organize the experimental results of the last 70 years produced by the accelerators and experiments introduced in Lecture 7 in terms of the “particle” content – the building blocks. To this end we will make extensive use of the idea of quantum numbers and symmetries. Recall that in quantum mechanics (and ) we can characterize a complete set of basis states in terms of their eigenvalues with respect to a maximal set of commuting operators. Generally this set of commuting operators includes the full Hamiltonian, i.e., the states have definite (real) energy so that the states do not decay and the quantum numbers in question are conserved. For our purposes it is useful to expand these ideas a bit (to allow decay). In particular we imagine the Hamiltonian as having 3 distinct parts

HHHH~strong EM weak . (8.1)

For now we will ignore the role of both gravity and the Higgs sector. The former can be ignored on the grounds that it is a very and, in any case, we do not have an adequate quantum description. The Higgs sector has yet to be established experimentally (although there have been hints) and we will return to it later. The separation into 3 sectors makes sense since the three interactions of the Standard -1 -7 model have distinctly different “strengths”, i.e., gstrong ~ 1, gEM ~ 10 , gweak ~ 10 , and preserve different quantum numbers (commute with different charges). Of course, the second two sectors are intimately related through electro-weak unification and symmetry-breaking but first we want to understand the organization of the observed particles. From this standpoint the masses of the and massive vector bosons are determined by externally provided masses terms. The masses of the observed (strongly interaction particles) are “explained” by Hstrong and in that sense we think of Hstrong as the dominant member of this trio. The other two terms enter our discussion essentially as the explanation for particle decays. (Of course, HEM is also the source of atomic and thus of chemistry and life!). We will be interested in those generators of symmetry operations that commute with Hstrong, but not necessarily with HEM or Hweak.

The idea of resonances will play an important in our understanding of the structure of the standard model. As discussed earlier, resonances correspond to bona fide states of the underlying theory, which, however, are produced and decay via the . Thus their lifetimes (~ 10-23 s) are so short that these states are not

Lecture 8 1 Physics 557 Autumn 2012 detected as observable tracks in detectors. Rather their existence is detected via enhanced interaction rates in specific channels, i.e., channels with specific quantum numbers. They play an essential role in our counting of the possible degrees of freedom and the confirmation of the Standard Model.

In contrast, “particles” are characterized by living long enough to be “seen” as tracks (or at least displaced vertices) in detectors. However, it is still true that most of these particles eventually decay (often inside of today’s large detectors) and it is precisely by the analysis of these decays that we come to understand the identity of these particles and the structure of the Standard Model. Note that only the , the and the are apparently free from decay and that this observation is presumably of limited validity, i.e., limited by the quality of our experiments. If the idea of Grand Unification is valid, there must be (extremely weak!) interactions (i.e., symmetry generators) that connect even the light quarks to the leptons and allow to decay. Likewise, since at least some of the neutrinos are massive, oscillations between different kinds of neutrinos are possible, and have been observed.

The observed hierarchy of decay times is understood in terms of the conservation of certain quantum numbers by some of the interactions but not by the others. In particular, the strong interactions respect (commute with the charge operators of) essentially all readily observable quantum numbers. The underlying operators of the strong interaction operate on (i.e., do not commute with) the , but for distances > 1 fm we observe only color singlets. Thus the strong interactions cannot contribute to processes that change any of the interesting quantum numbers ( flavors, , , etc.). On the other hand, the weak interaction respects very few quantum numbers.

Once we have discussed the general properties of quantum numbers, we will proceed to discuss the various particles observed, essentially in historical order, and describe how the various relevant quantum numbers were introduced. We can think of the quantum numbers as being the eigenvalues of some operator acting on the appropriate “single” (or multi-) particle state (with the “” ’s to remind us that we will include resonances in the counting of 1-particle states). Generally, for the case of an eigenstate of an operator, we can write

Op Op XX X . (8.2)

Lecture 8 2 Physics 557 Autumn 2012 The quantum numbers of interest will generally fall into two classes – multiplicative and additive. This distinction arises from the way in which the quantum numbers are combined when we consider 2 (or more) particle states. Thus for multiplicative quantum numbers we simply multiply the quantum numbers of the two particles together to find the corresponding quantum number for the 2-particle state (ignoring for now the impact of any interactions and the possible influence of the composite state), 1 2 3:Op3 3 Op 1 Op 2 1 2 . Such quantum numbers are typically associated with discrete symmetry groups (see Chapter 4 in Griffiths and Chapter 12 of Rolnick) and the typical values of  are 1. Examples are parity P, charge conjugation C, the combination CP and time reversal T. The symmetry group for all of these operations is isomorphic to the two-element group we discussed earlier. P,1 G : P-1 = P, P2 = 1. Additive quantum numbers, on the other hand, are, as the name implies, additive, 1 2 3:Op3 3  Op 1 Op 2  1 2 . Examples are electric charge, baryon number, lepton number, etc. In these cases the quantum numbers of composite states are the scalar sums of the quantum numbers of the parts. More generally, the addition of the quantum numbers may be of a vector nature or be even more complex, as with SU(3) quantum numbers. Examples include momentum, angular momentum, , etc. The symmetry group associated with additive quantum numbers is generally a continuous group, which may or may not be a local symmetry.

Multiplicative Quantum Numbers (and discrete symmetries)

Parity, P: the operation of parity inverts all vectors through the origin. We can think of the corresponding passive operation as reflecting each of the unit vectors through the origin.

Thus in the transformed frame the directions of all (real) vectors are opposite, i.e., the signs of all components have changed by a factor of -1:

   rP r  r, (8.3)  x,,,,,,. y z P x y z   x y z

Thus a usual 3-vector is odd under P, i.e., has eigenvalue = –1. The usual scalar, e.g., the scalar product of two vectors

Lecture 8 3 Physics 557 Autumn 2012   s r1 r 2 P       (8.4) s  r1 r 2   r 1 r 2  r 1 r 2  s, is unchanged by P and thus has eigenvalue = +1. As we know there are quantities, with which we are already familiar, that behave in a different manner – pseudovectors (or axial vectors) and pseudoscalars. A good example of the former is angular momentum, which involves two vectors:

L  r  p  P (8.5) L  r p   r   p  r  p   L.

Unlike a vector, a pseudovector has P eigenvalue +1. With 3 independent (ordinary) vectors available we can construct a pseudoscalar using the familiar scalar triple product, which transforms as

   ps r1 r 2 r 3  P       (8.6) ps  r1 r 2 r 3   r 1 r 2  r 3    ps.

Unlike a true scalar, a pseudoscalar has P eigenvalue –1. (Note that this pseudoscalar product is constructed with our old friend jkl.)

When we combine two (or more) particles, the parity of the resulting composite state will depend on the product of the intrinsic parities of the two particles, times any collective parity of the two particle state. This latter factor is easy to determine for states of definite angular momentum, l. Such states are described by the spherical harmonic functions Yl,m(,). In the transformed frame    = -,    = + and it is easy to verify that

Yl, m ,  P l (8.7) YYYl,,, m,  l m  ,     1 l m  ,  .

Thus the parity eigenvalue of the composite state of two particles with relative P P angular momentum l and intrinsic parities  1 and  2 is the product

PPPl composite12 1  1 2 . (8.8)

Lecture 8 4 Physics 557 Autumn 2012 An extremely useful application of this form is the parity eigenvalue for a state composed of a ½ and its anti-particle. It is straightforward to verify that the structure of the Dirac equation requires that a fermion and its antiparticle have opposite intrinsic parity (see page 141 in Griffiths and Eq. 12.8 and problem 12.1 in Rolnick). In particular, as we will see in more detail later, if  t, r is a solution of the Dirac equation in the original frame, then  0 t, r is a solution in the frame reached after a parity transformation. Due to the opposite sign of 0 for upper (particle) and lower (antiparticle) components, the intrinsic parity properties of the two components are opposite. States formed of particle – antiparticle fermion pairs with definite angular momentum, such as positronium (e+e- pairs) or mesons (quark – antiquark pairs) must have parity

l1 P f fpair, l  1 f f pair, l . (8.9)

Thus we expect that a quark – antiquark pair in the ground state with l = 0 will exhibit quantum numbers

P P - 1  Pseudoscalar,  = -1, J = 0 , S0 (spin = 0, l = 0, J = 0), the ’s, K’s and ; P P - 3  Vector,  = -1, J = 1 , S1 (spin = 1, l = 0, J = 1), the ’s, K*’s and .

For bosons the particles and antiparticles have the same intrinsic parity and the corresponding formula for a state composed of a scalar particle – antiparticle pair does not have the extra (-1) factor of Eq. (8.9),

l P b0 b 0pair, l  1 b 0 b 0 pair, l . (8.10)

Interactions that respect parity, i.e., are invariant under a parity transformation, must treat left-handed and right-handed particles in the same way. This characterization applies to the strong and electromagnetic interactions but not the weak. As we have already noted, the weak interactions involve left-handed and right-handed antifermions but not the inverse. (It is also interesting to note that biology seems to give special roles to molecules of definite handedness.)

ASIDE: It is useful to note that the simple relationship between orbital angular momentum and parity in Eqs. (8.9) and (8.10) obtains only for 2 particle states. We will eventually be interested in 3 (and more) particle states where the relationship

Lecture 8 5 Physics 557 Autumn 2012 between the total angular momentum (i.e., how the state rotates) and parity (i.e., how that state looks after reflection through the origin) is more complex.

Charge Conjugation, C: The charge conjugation operation is a bit more subtle. It does not operate in configuration space but rather changes a particle into its antiparticle, i.e., it changes the sign of all of the additive quantum numbers describing the particle: electric charge, weak charge, color charge, baryon number, lepton number, etc. (Charge conjugation can also introduce an arbitrary, unobservable i phase, qC e q , which is chosen by convention, but there exist different choices for this same convention.) Thus not many (single) particles can be eigenstates of C, i.e., be their own antiparticle. Clearly only particles with vanishing additive quantum satisfy this requirement. The is the easiest example to identify. Since the photon couples to a current of electric charge and that charge changes sign under C, we find that a photon is odd under C

n CC    ; n   1 n . (8.11)

Likewise the fermion – antifermion states discussed above can also be eigenstates C, the operator simply switches the fermion and antifermion labels in the spatial and      spin wave functions. Since the spin triplet state, S = 1, is symmetric ,,  2  under interchange of the two fermions while the singlet state, S = 0, is antisymmetric

   S+1   , the spin component of the wave function contributes a factor (-1) to the  2  C eigenvalue of the composite state. The spatial symmetry of the state of definite angular momentum is given by (-1)l. Finally there is an extra factor of (-1) from Fermi statistics. The operator C exchanges the fermion and antifermion creation operators in the definition of the state and we must switch their order back to return to the original state,

†††††† af af0 a f a f 0  a f a fC 0 . (8.12)

Since fermion operators anticommute, this introduces another factor of (-1). Pulling these facts together we have

l S C f fpair, l  1 f f pair, l . (8.13)

Lecture 8 6 Physics 557 Autumn 2012 For example, the 0 composed of a quark-antiquark pair with l = 0, S = 0, obeys

C  0   0 . (8.14)

So what about the s-wave 2-photon state into which we know the 0 decays? From above the 2-photon state has C = +1 suggesting the (true!) result that the electromagnetic interactions conserve C. This explains why 0   is not observed (at least not at the level of 3 parts in 108). More generally for a particle-antiparticle pair of bosons it is the states of even spin that are symmetric under interchange of the two bosons (i.e., opposite to the behavior of the half-integer spin fermions – we will check this below). At the same time, the creation operators commute rather than anticommute. Thus there are two extra factors of (-1) compared to the fermion case and the result for a particle-antiparticle boson pair is unchanged from the fermion case (b here stands for a boson and not the ),

l S C bbpair, l  1 bb pair, l . (8.15)

You might also ask, what happened with the issue of parity for the 2-photon decay of the 0? The product of the intrinsic parities is +1 and the 2-photon state must be symmetrical by Bose-Einstein statistics, so where is the oddness under parity? It comes from the polarizations of the . The picture of what is happening at short distances is indicated in the figure, where we are looking at the u-quark component of the   wave function. If the photons have polarizations vectors1 and 2 and momenta       k1  k 2 (with 1k 1  2 k 2  0), the matrix element must be linear in each of the polarizations (i.e., the figure shows one vertex for each photon), be a scalar under rotations and be symmetric under the interchange of the two photons. The possible forms (“What else can it be?”) for such a matrix element include both a true scalar and a pseudoscalar   M s  1 2 ,    (8.16) Mps  k1 1 2 .

The first form corresponds to the two photons having their polarizations aligned while in the second the polarizations are orthogonal. In fact, it was the experimental observation that the polarizations of the two photons are always orthogonal (as required by the cross product) that confirmed the negative parity of the 0.

Lecture 8 7 Physics 557 Autumn 2012 Summarizing, both the strong interactions and the electromagnetic interactions preserve C and P. Thus states of definite C and P will remain states of definite C and P even if they experience strong or EM interactions. The same cannot be said for the weak interactions. As we have already mentioned, the weak interactions are observed to involve couplings to only left-handed neutrinos and right-handed antineutrinos. This indicates that the weak interactions are symmetric under neither P (switching left and right handedness) nor C (switching particle and antiparticle). In some sense the violation of these two symmetries is maximal. We will discuss this in more detail when we discuss the field theoretic structure of the weak interactions. On the other hand, the joint operation CP would seem to be respected by the weak interactions based on what we have said so far, i.e., a left-handed is equivalent to a right- handed antineutrino. This is true for the neutrinos (based on current measurements, but watch for future measurements!) but, as we will see when we discuss the neutral K-mesons (and the corresponding B-mesons), CP is, in fact, observed to be violated at a very low level!

Time reversal, T: Above we considered what happens when we look at particles “in a mirror” or switch all particles to antiparticles. Now consider the result of running the movie of physics backwards. While thermodynamics clearly shows an “arrow of time”, interactions of particles on the smallest scale exhibit considerable symmetry with respect to time inversion, e.g., second-order equations of motion are invariant under t  -t. Note that time inversion has an extra feature compared to spatial inversion. While the later switches left and right, the former changes incoming states into outgoing states and vice versa. If we define

T T    , (8.17) then time reversal invariance (the same physics forward and backward in time) requires TT *           . (8.18)

The last step follows from the definition of such products of states, i.e., that the state in the “bra” is complex conjugated. An operator with this property is called antiunitary and it implies that

**   a1 1 a 2 2 T  a 1 T 1 a 2 T  2 , (8.19)

Lecture 8 8 Physics 557 Autumn 2012 i.e., the T operation takes the complex conjugate of any coefficients. The representations of such antiunitary operators take the form of a product of operators, UK, where K is the operator that takes the complex conjugate and U is a unitary operator. The clear implication is that interactions that introduce complex numbers, i.e., phases, can lead to T invariance violation. This is precisely what seems to be at work in the weak interactions. It is interesting to note that the presence of a non- trivial phase in the quark mixing (MKS) matrix (allowing time reversal invariance violation) is possible only because there are three (or more) generations. Maybe this is the underlying reason for this number of generations – God wants T violation. Actually we do too since, as far as we know, the product CPT is a good symmetry of all interactions (it is true in all standard field theories) and we need CP (and thus T) violation in order to understand the abundance of baryons (us) over antibaryons in the universe (although the current understanding of the magnitude of CP violation is not sufficient to explain the universe we live in).

Returning to less philosophical issues, we see that the operation of time inversion will   leave spatial locations unchanged rT r  but changes the sign of quantities that         involve single time derivatives vTTT -v,p - p , L r  p  L . This last     result applies also to all angular momenta, including spin, SSJJTT ,   . This suggests a typical experimental test of T invariance. Consider an electrically neutral particle, e.g., the or an atom. If the positive charges in the system are slightly displaced from the negative charges, the system will still be electrically neutral but exhibit a nonzero electric dipole p , proportional to the separation of the charge. This dipole with interact with an electric field as

  HEED  p  . (8.20)

Now we ask, in what direction can p point? Consider the neutron. There is only one  direction defined, the direction of the neutron’s spin, S . So by our usual, “what else   can it be?” argument, we know that pn must behave like Sn and change sign under T. Thus, since the electric field does not change under T, the electric dipole interaction must change sign under T, and thus violate time invariance. (Actually, since the electric field changes sign under P and the dipole does not, this interaction can also signal P violation.) The current limit on the neutron electric dipole is < 0.29 x 10-25 e cm. UW groups are involved in both the neutron measurement and measurements of edm’s in atomic systems. On theoretical grounds we expect a neutron edm of order

Lecture 8 9 Physics 557 Autumn 2012 10-32 e cm in the context of the Standard model, while SUSY extensions can yield much larger numbers (by factors of 104 to 108).

As noted earlier, the symmetries of CP and T are tightly coupled on theoretical grounds. A quantum field theory that a) is Lorentz invariant, b) has a well defined lowest energy state (the vacuum) and c) obeys microcausality (i.e., all field theories of immediate interest) is CPT invariant. (This may not apply to all string theories.) This result has several implications. Stated simply (a la Feynman) a forward moving in time positive energy particle is the same as a backward moving in time, in the opposite spatial direction, negative energy (i.e., anti-) particle. This implies that particles and their antiparticles must have the same mass, the same decay width and the same magnitude (but opposite direction) of magnetic moment. The measurement of these properties is also a local specialty and literally “carved in stone” on the outside of the physics building. The magnitude of the magnetic moment (“g-2”) of the electron and positron are observed to be equal at the level of 2 parts in 1012 (and to be in comparable agreement with the theory of QED).

Additive Quantum Numbers (and continuous symmetries)

Now let’s turn to the more familiar additive quantum numbers. The most familiar is probably electric charge, associated with the U(1) symmetry of EM. That symmetry ensures that the EM current is conserved

  J   0. (8.21)

The electric charges of systems can change only when individual charges move between systems. The charges of the elementary particles are unchanging. Further, the total electric charge of a system is the algebraic sum of its charged components. Electric charge is conserved by all interactions. A subtle but important issue concerning electric charge is the question of why the charge of the proton is so well 21 matched to that of the electron : |Qp/Qe| = 1.0 to 1 part in 10 . This is a good argument for the Grand Unification idea. In GUTS the lepton and quarks are in the same representations of the larger unified symmetry. Since there are symmetry generators that mix these states, all members of the representations must have the same basic quantum of electrical charge.

Similar additive quantum numbers are baryon number B (and the related quark number) and lepton number L. These numbers simply count the number of baryons (quarks) and leptons minus the number of antibaryons (antiquarks) and antileptons.

Lecture8 10 Physics557Autumn2012 The three known interactions of the Standard Model conserve these quantum numbers. Only the mesons, with zero baryon and quark number can decay entirely into leptons and photons. At present we do not associate this conservation with any underlying symmetry. If the idea of Grand Unification is true, only B-L is conserved when we include the super-weak interactions of the larger symmetry. These interactions allow baryons (quarks) to decay into leptons and protons do eventually decay. Observationally the mode independent lifetime for the proton is bounded below by about 2 x 1029 years. Mode dependent results go as high as 1033 years.

The conserved quark number is also usefully broken down into separate quark flavor numbers, which are separately conserved by the strong (and electromagnetic) interactions but not the weak interactions. Thus we characterize hadronic states by the number of strange quarks, the number of charm quarks, the number of bottom quarks and the number of top quarks. Of course, before quarks became “real” we treated strangeness as a quantum number of the hadrons. (Note that the up and down quarks are be handled separately by the concept of isospin.) There is a similar generation dependent separate conserved lepton quantum number for the electron and electron neutrino, and muon neutrino and and tau neutrino, Le,L and L, respectively. The separate conservation of these numbers is violated by the results.

We are also familiar with conserved vector quantum numbers like 3-momentum and 4-monentum, associated with translational invariance in space and time. Again composite systems have momenta that are simple vector sums of the momenta of the components. We learn in quantum mechanics, however, that the addition of angular momentum is somewhat more complex. Instead of the infinite dimensional, continuous representations that characterize the translation group, spin is quantized and appears in discrete, finite dimensional representations of SU(2) (or SO(3) for orbital angular momentum). This means that the group structure plays a role in the addition process, i.e., the issue is that of adding these finite representations.

Let us a take a moment to review the subject of ladder operators and Clebsch-Gordan coefficients as they help us to add spin. Consider the result of adding two states with   spins J1 and J2 and third components of spin m1 and m2, i.e., the eigenvalues of Jz. We know from the general rules of the addition of angular momentum that the resulting     total angular momentum will lie in the range || J1 |-| J2 || to || J1 |+| J2 ||. We work in the orthonormal basis of the eigenstates of the total angular momentum operator and the third component operator

Lecture8 11 Physics557Autumn2012 2 Jjm, jj  1 jmJjm , ,z , mjm , . (8.22)

The states are normalized as

j,,. m j m  mm (8.23)

Recall that the components of J satisfy the algebra

  JJx,,,,. y  iJJ z  JiJJJ x y z     J (8.24)

It follows that the raising and lowering operators (or ladder operators) do just what their names imply

Jz J j, m  m 1 J j , m . (8.25)

So we define the corresponding coefficients

JjmCjm ,  , 1 , Jjm , 1 Cjm , (8.26) and solve

C  jm, 1 JjmC , ,  jmJjm , , 1

† * (8.27)  j, m 1 J j , m C  C  C , where the last step involves setting the unphysical phase of C+ to zero. We can obtain an explicit expression for C by considering the operator

2 2 2 2 JJ   Jx JiJJJJ y  x y y x  J J z J z , (8.28) which tells us that

2 2  JJjmCjm  , ,  jj  1  mmjm  , . (8.29)

Thus the Clebsch-Gordan coefficients are given by

Lecture8 12 Physics557Autumn2012 Jjm , jj  1  mm  1 jm , 1 Jjj , 0, (8.30) Jjm , jj  1  mm  1 jm , 1 Jjj ,  0.

The two special results verify that the raising and lowering processes truncate at the boundary of the representation and so the representation is of finite size. Consider the simple example of combining spin 1 (3 states) with spin ½ (2 states). We expect that the resulting 6 states will correspond to spin 3/2 (4 states) and spin ½ (2 states), 3 2 4 2. (8.31)

The highest J and Jz states are unique and we can always start with one of them,

1,1 12,12 32,32, (8.32) 1, 112, 12 32, 32.

To find the remaining members of the spin 3/2 multiplet we can just apply J+ or J- to the appropriate starting state (recall that J is additive, i.e., JJJTOT  1  2 )

JJJ 3   1 2 1  2   3 5 3 1 J 32,32    32,12 332,12,  2 2 2 2 1 3 1 1   120   11,012,12       1,112,12 2 2 2 2  (8.33)  21,0 12,12 1,1 12, 12  2 1 32,12 1,012,12 1,112,12. 3 3

Similarly we find 1 2 32,12  1,112,12  1,012,12. (8.34) 3 3

Now what about the corresponding spin ½ state? It has the general form

Lecture8 13 Physics557Autumn2012 12,12  1,112, 12  1,012,12, (8.35) where 2 + 2 = 1. We can proceed by requiring that this state be orthogonal to the previous spin 3/2 state. Alternatively we can require that

J  12,12  1,112,12 2 1,112,12 0 2 1 (8.36)     2     ,  . 3 3

Both procedures yield this same result with an overall sign ambiguity. As usual with such issues, we fix the sign by convention. Here we use the Condon-Shortley convention to agree with the usage in the PDG tables of Clebsch-Gordan coefficients. Using the same order as in Eq.(8.33) to make clear the orthogonality we have

1 2 12,12  1,012,12 1,112,12, 3 3 (8.37) 2 1 12,12   1,112,12  1,012,12. 3 3

The interested student can verify from the PDG table that, as noted above, when adding identical integer spins (bosons) the resulting states with even spin are even under interchange of the two initial spins, while the odd spins are odd.

It should be noted that similar techniques hold for larger symmetry groups, e.g., SU(3), and we will discuss them when they are needed. They will exhibit the added complication that the representations are “higher dimension” than those for SU(2) (SO(3)). For example, SU(3) has “2-D representations” (instead of 1-D) in the sense that we will need two independent ladder operators to explore an entire representation and a 2-D figure to display the representation (the issue is how many generators in the algebra commute – the size, or the rank, of the Abelian subalgebra).

While the role of representations is familiar for transformations in configuration space, it was a major step to recognize the usefulness of symmetry groups in more abstract spaces. The first major application was to the concept of isospin (see Chapter 4.3 in Griffiths and Chapter 6.1 in Rolnick). One of the obvious features of is that the mass of nuclei depends primarily on the total number of nucleons, A, and not separately on the numbers of protons, Z, and . Likewise

Lecture8 14 Physics557Autumn2012 the particles themselves are nearly degenerate, mp = 938.272 MeV while mn = 939.565 MeV (mn – mp = 1.293 MeV). The difference is small both compared to the masses themselves and to the characteristic scale of nuclear physics interactions ~ 100 MeV. These facts suggested that the nuclear (strong) interactions are invariant under a transformation that interchanges protons and neutron. Such a 2-component representation clearly suggests a similarity to ordinary spin and thus to SU(2) symmetry. In the analysis above we simply replace spin S (or J) by isospin I. The structure of states and matrix elements will be the same even though the spaces in which the transformations act are different (i.e., we are rotating the axes in isospin space rather than configuration space). (Remember the words of Richard Feynman, “The same equations have the same solutions.”) Thus we have in isospin space

3 1 p 1 2,1 2 , I2 p p , I p p ; 4z 2 3 1 (8.38) n 1 2, 1 2 , I2 n n , I p  n . 4z 2

When we combine a neutron and proton we expect to find both an I = 1 state and an I = 0 state. However, only the antisymmetric (in isospace) I = 0 np state of the deuteron is bound, i.e., a stable nucleus. The symmetric pp, np, nn I = 1 states are not bound. Similarly the u and d quarks form a doublet under isospin. In fact, the masses of the u and d quarks are nearly degenerate (mu ~ 1.7 to 3.1 MeV, md ~ 4.1 to 5.7 MeV). The observed isospin symmetry of the non-strange hadrons arises from the fact that mu and md are much smaller than the scale of the strong interactions (QCD ~ 200 MeV) and not from their near equality. The quark mass difference, md > mu, however, does help to explain the mass splitting mn > mp, which is very important to our existence, i.e., so that the neutron, and not the proton, decays weakly. Combining a quark and antiquark yields both isovectors (’s and ’s, spin 0 and 1, respectively) and isoscalars (’s and ’s, again spin 0 and 1). (Note that the antiquarks are members of doublets just like the quarks, i.e., an “anti-doublet” is just like a doublet except for the issue of phases. This similarity of representations for “things” with representations for “anti-things” will not carry over to larger symmetries.) For the 3 quarks in a baryon we combine 3 isospin ½ objects to find isospin 3/2, the ’s, and isospin ½, the nucleons. The global SU(2) of isospin described here is the so-called strong isospin (and there are no corresponding gauge bosons). The isospin corresponding to the local SU(2) symmetry of the weak interactions is slightly different (e.g., it has gauge bosons) and will be described later in a more detailed discussion of the weak interactions.

Lecture8 15 Physics557Autumn2012 Note another difference from the application of SU(2) to (real) spin. In the latter case it is easy to appreciate what we mean by a rotated reference frame or observer. In isospace such an observer sees a mixed state of a neutron and a proton. This clearly does not conserve electric charge (electromagnetic interactions violate isospin invariance) but does make sense quantum mechanically. However, we will seldom use such concepts. The real value of the idea of isospin invariance is the prediction that hadrons must appear in complete (and approximately mass degenerate) multiplets of SU(2) and that the strong interactions themselves should be isoscalars. This latter constraint will provide information on relative couplings of different channels. Consider the following processes

1)p p D   , (8.39) 2)p n D  0 , where D is the deuteron. As noted above the deuteron is I = 0 while the pion is I = 1. Thus the final state is I = 1 for both reactions. On the other hand the initial state for the first process is pure I = 1 while the second process has a 50/50 mixture of I = 1 and I = 0, p n n p p n n p 1,0 ; 0,0 . (8.40) 2 2

The isospin invariance of the strong interactions says that the initial isospin and the final isospin must be identical and thus only the I = 1 component of the initial state can contribute. We have

2 2 D  H pp IIII1, 1 1, 1 1 s z z  2 2 o  2 D Hs pn IIIIII1,z 0  1, z 0  0, z  0 2 1 2 (8.41)  2  2, 1 2 as is observed experimentally.

Before proceeding to the discussion of the particles, we should introduce two more quantities. First note that we can expect that there is some relationship between isospin and electric charge. (It is already clear that the electric charge operator cannot

Lecture8 16 Physics557Autumn2012 commute with the isospin ladder operators.) Conventionally this relationship for the electric charges of hadrons is expressed as (where I here is the strong isospin)

Y QI  . (8.42) z 2

We have introduced a new additive quantum, Y, the hypercharge, which will eventually be associated with a local U(1) symmetry. Initially Y was observed to be equal to the baryon number, Y = B, i.e., 1 for the proton and neutron and 0 for the mesons. Thus the charge of the proton is ½ + ½ = 1, while the neutron is – ½ + ½ = 0. Likewise for the u and d quarks with baryon number 1/3 and hypercharge 1/6, we have charges ½ + 1/6 = 2/3 and – ½ + 1/6 = - 1/3, respectively. For the mesons, the electric charge is just the Iz value, e.g., +1, 0 and –1 for the three components of the pion isovector. (When we include strangeness, we will find that Y = B + S, in the (historical) context of strong isospin where strangeness is an isospin singlet. In the modern context of quarks and the local SU(2) symmetry of the weak interactions, where all quarks are in doublets, Y = B. The above expression about for Q stays the same throughout.)

Finally the concept of G-parity, which combines isospin and charge conjugation, was found to be useful in analyzing the strong interactions (see Chapter 4.4.2 in Griffiths and Appendix G of Rolnick). In our discussion of C we noted that it was conserved by the strong (and electromagnetic) interactions but that electrically charged states, or, in fact, states with any nonzero value for one of the additive quantum numbers cannot be eigenstates. G-parity was introduced to study states that have zero internal scalar additive quantum numbers, except possibly Iz, i.e., states with “meson-like” quantum numbers. Such states have Y = 0 and thus Q = Iz. Since C changes the sign of Q, we have the operator statement

CIz  I z C. (8.43)

As expected, C and I do not commute. Consider instead the G-parity operator defined as G Cei I y , (8.44) which first rotates a state by  (you will see both choices + and - in the literature – it does not matter) about the Iy axis and then performs charge conjugation. Since the two factors separately are conserved by the strong

Lecture8 17 Physics557Autumn2012 interactions, this is an invariance of the strong interactions. Due to the isospin transformation, G-parity it is not an invariance of the electromagnetic (or weak) interactions. We can understand the result of the isospin rotation by thinking about what happens to spins under a rotation about the y-axis (remember the words of Feynman), ,,,        (8.45) i.e., the directions of both the x-axis and z-axis have flipped. Consider first neutral states with Iz = 0. We know from our earlier discussion of parity (and the Ylm’s) that the transformation above has the following impact on a state with Iz = 0 (Yl0 is independent of ), I GII,0 C  1 ,0 , (8.46) where C is the C quantum number of the state. So for our friend the 0, with C = +1 and I = 1, we find G = -1. Now, if Iz  0 for the state of interest, the isospin rotation will flip the sign of Iz. Then C will just flip it back (recall Iz is the only nonzero internal scalar additive quantum), adding at most an overall phase. This phase that arises when C is applied to a charged state is undefined and can be chosen so that entire isospin multiplet has the same G-parity quantum number,

C I GIIII,z  1 , z , (8.47)

C with  the same as for the Iz = 0 component (i.e., the eigenstate of C). Thus for the pion multiplet, +, -, 0 all members have G = -1. In the restricted space of such “nearly” neutral states we have  GI,  0 (8.48) and G-parity is useful for analyzing strong decays between the mesons, as we shall see. Note that, like the photons with the operator C, we have

n GG  1 , n   1  . (8.49)

You will sometimes see this information for the quantum number information of the pion multiplet summarized as JPC IG = 0-+ 1-.

Lecture8 18 Physics557Autumn2012 Clearly, since we were really discussing quark-antiquark pairs above, we can also apply G-parity to the nucleon-antinucleon channel. From our study of the C properties of such states we have

l S I GNNlSI , ,   1 NNlSI , , . (8.50)

Combining our various discussions, we find a useful relationship for any pair of identical particles, or for any two particles from the same isospin multiplet,

l S I Y 1 2  1. (8.51)

Such states containing pairs of identical particles must satisfy the spin statistics connection: the interchange of two identical fermions must produce an overall –1 (the state is antisymmetric and no two identical fermions can be in the same state); the interchange of two bosons must produce a +1 (the state is symmetric and bosons “want” to all be in the same state). This result is encoded in the above formula. For example, if we look at the two pion state with S = Y = 0, we must have l + I = even. This means that odd angular momentum (the antisymmetric spatial wave function) goes with odd isospin and even with even. This constraint guarantees that the isospin wave function that is odd under interchange of the two pions goes with the spatial wave function that is also odd and even isospin wave functions go with even spatial wave functions. (For integer isospin the symmetry structure of the isospin wave function is just like that for integer angular momentum – the same equations have the same solutions.) The result is an overall wave function that is even under interchange of the pions as required.

Lecture8 19 Physics557Autumn2012 We summarize the various symmetries of the three Standard Model interactions in the following table.

Conservation Summary:

Interaction Conserved quantity Strong Electromagnetic Weak Additive Energy-momentum Yes Yes Yes Electric charge Yes Yes Yes Baryon number Yes Yes Yes Lepton number Yes Yes Yes Angular Momentum Yes Yes Yes Isospin - I Yes No No Multiplicative Parity - P Yes Yes No Charge Conjugation - C Yes Yes No Time Reversal – T or CP Yes Yes ~ 10-3 viol CPT Yes Yes Yes G - parity Yes No No

Lecture8 20 Physics557Autumn2012