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A Classical Approach to the Modeling of Quantum

ARTICLE in JOURNAL OF MODERN · NOVEMBER 2013 DOI: 10.4236/jmp.2013.411A1004

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All in-text references underlined in blue are linked to publications on ResearchGate, Available from: Donald C Chang letting you access and read them immediately. Retrieved on: 07 March 2016 Journal of Modern Physics, 2013, 4, 21-30 Published Online November 2013 (http://www.scirp.org/journal/jmp) http://dx.doi.org/10.4236/jmp.2013.411A1004

A Classical Approach to the Modeling of Quantum Mass

Donald C. Chang Div of LIFS, Hong Kong University of Science and Technology, Hong Kong, China Email: [email protected]

Received September 1, 2013; revised September 29, 2013; accepted October 27, 2013

Copyright © 2013 Donald C. Chang. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

ABSTRACT In modern physics, a particle is regarded as the quantum excitation of a . Then, where does the mass of a particle come from? According to the , a particle acquires mass through its interaction with the Higgs field. The rest mass of a free particle is essentially identified from the Klein-Gordon equation (through its associated Lagrangian density). Recently it was reported that a key feature of this theory (i.e., prediction of Higgs ) is supported by ex- periments conducted at LHC. Nevertheless, there are still many questions about the Higgs model. In this paper, we would like to explore a different approach based on more classical concepts. We think mass should be treated on the same footing as momentum and energy, and the definition of mass should be strictly based on its association with the momentum. By postulating that all particles in nature (including and ) are excitation waves of the vac- uum medium, we propose a simple wave equation for a free particle. We find that the rest mass of the particle is associ- ated with a “transverse wave number”, and the Klein-Gordon equation can be derived from the general wave equation if one considers only the longitudinal component of the excitation wave. Implications of this model and its comparison with the Higgs model are discussed in this work.

Keywords: Mass; Vacuum; Quantum Excitation; Matter Wave; Particle-Wave Duality; Higgs Mechanism

1. Introduction Model! Yet, there are still many questions remaining to be We know the universe is made up of particles; most of answered. It is well aware in the physics community that which have a rest mass (except for and possibly the Standard Model (in the present form) has certain li- neutrinos). In the , a particle is re- garded as an excitation wave of a field. Then, how can a mitations. For example: particle acquire mass? According to the Standard Model  It cannot explain gravitation. (SM), the mass of the particle is acquired through their  Some consider it to be ad hoc in nature, requiring 19 interaction with the Higgs field, the excitation of which numerical constants whose values are arbitrary and is a scalar particle called “the ” [1]. The can only be determined by experiments. Higgs particle has been theorized for a long time but was  The specifics of neutrino mass are still unclear. It is not verified in experiment until very recently. This is due believed that explaining neutrino mass will require an to the very heavy mass of the Higgs particle and thus will additional 7 or 8 constants, which are also arbitrary require a very powerful accelerator to study it. parameters. Experiments to hunt for the Higgs boson was finally  The Standard Model cannot explain the huge amount started at CERN about three years ago using the newly of and dark energy observed in cosmol- built (LHC). On July 2012, two ogy. It also has difficulty to explain the observed experimental groups at LHC reported independently that predominance of matter over anti-matter. they found a new particle with a mass of about 125 GeV, Thus, there is still a long way to go for physicists to which could be the Higgs boson [2,3]. Earlier this year, develop a comprehensive theory that can explain our their report was confirmed by further experimental data physical world from the sub-atomic scale to the cosmos collected at LHC [4]. There was a lot of excitement in scale. There is no wonder why many physicists in recent the physics community about their findings. Their results years are exploring new theories beyond the SM, (e.g., are considered to be a major triumph of the Standard , brane theory, super-, etc.).

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In this paper, we will explore a new approach to ex- Equation (6) is similar to Equation (4) if we interpret amine a specific problem in quantum physics. We will the parameter M in Equation (6) as the “mass” of the ask only one question, namely, what is the meaning of excitation wave. In another word, the coefficient associ- particle mass? We will first give a brief review on how ated with the quadratic term Φ†Φ in the Lagrangian den- particle acquires mass according to the Higgs model. We sity as shown in Equation (5) is identified as the square will explain why we need to consider alternative ap- of the rest mass (m2). Thus, in the quantum field theory, proaches. Then, we will present a new model which is the rest mass of a free particle is essentially identified based on more classical concepts. Finally, we will dis- from the Klein-Gordon equation (through its associ- cuss the implications of this model. ated Lagrangian density). Using this as a guide line, one can investigate how a 2. How Do Particles Acquire Mass in the particle may acquire mass in the quantum field theory. Higgs Model? Let us use the as an example to demonstrate this mass-generating mechanism. In the SM, the gauge Let us first review briefly how mass is generated accord- field is introduced solely to allow the Lagrangian density ing to the Standard Model. Classically, mass is defined to be invariant under a local gauge transformation [5]. from its association with momentum. i.e., The excitations of this field are the gauge bosons. The p mv (1) gauge boson (such as ) originally has no mass. This is not exactly how the quantum field theory The gauge boson acquires mass due to its interaction works. In the Standard Model of , mass is with a theoretical Higgs field, under the condition that a property associated with a specific field. The starting the local symmetry of this field is broken. This mecha- point is the energy-momentum relation attributed to the nism was proposed by Higgs, and others in the mid special theory of relativity (STR), 1960s [6-8]. The gauge field mediating the electro- 22224 Epcmc (2) was introduced as a requirement of invariance of a La- To construct the corresponding quantum wave equa- grangian density under local SU(2) transformation as tion, one can use the correspondence principle by con- well as a local U(1) transformation. This approach was verting the energy (E) and momentum (p) of a particle first explored by Yang and Mills in 1954 [9], and was into operators of a field, such that Ei t and later developed into a theory to explain the unification of p i , i.e., the wave equation is electro-weak interaction in by Weinberg and Sa- lem [10-11]. The following is a summary of essential 2 2 2 1  mc steps used in the Higgs mechanism to allow gauge bos- 22  0 . (3) ct  ons to acquire mass: Step 1: First, one may construct a general Lagrangian (Here  is Planck’s constant divided by 2π,  is the density which is Lorentz-invariant and can be renormal- wave function of the field). This equation is called the ized, Klein-Gordon equation. If we use a unit system such   that c = ħ =1, Equation (3) can be simply expressed as L   V  . (7) 2 Here Φ is chosen to be a two-component field, (which 22 m 0 . (4) 2 is sometimes referred to as the Higgs field), i.e. t

 A In the SM, the concept of “field” is being generalized. , (7a) Each type of particle is regarded as the excitation wave B of its own field Φ (which can be a real or complex scalar where both ΦA and ΦB are complex scalar fields, function, a , or a vector field). If one constructs a  ii,. Lagrangian density of this field in the form of  AB12  34

 2  Step 2: If one requires this field to have a local U(1) L M , (5)  symmetry, one needs to introduce a vector gauge field (where μ is the usual summation index representing the Bμ(x), which obeys certain transformation law. This pro- 4-dimenional space), one can easily derive a generalized cedure is analogous to the introduction of the vector po- Klein-Gordon equation using Hamilton’s principle (i.e., tential Aμ into electro-magnetism. If one makes a further by applying the Euler-Lagrange equation), requirement that this field is also invariant under a local

2 SU(2) transformation, one needs to introduce a second 22 vector gauge field, Wμ(x). In order to make the Lagran- 2 –M 0. (6) t gian density to become invariant under the U(1) × SU(2)

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transformation, the ordinary space-time derivative in two parts; L = L1 + L2, where L1 contains the Lagrangian Equation (7) will be replaced by the co-variant operator density representing the free particles, while L2 contains all other parts (which are interpreted as interaction terms). DigBigW  1222    , (8) L1 was shown to be [16] where g and g are coupling constants between the field 1 2 LLLL   L, (15) Φ and the gauge fields associated with U(1) symmetry 1HZEMW and SU(2) symmetry, respectively [12]. The locally where gauge invariant Lagrangian density associated with the 1 field Φ now becomes L hh  22 h, (15a) H 2     L DDV . (9) 1122 2 LZ01ZZggZ    2  Z, (15b) Step 3: Since the gauge fields are now entering the 44 picture, one must also consider their contribution to the Lagrangian density. This dynamic contribution to the 1  LEM  A A , (15c) Lagrangian density associated with the gauge fields is 4 shown to be [13] LW 11 1 L BB  TrWW . (10)       dyn     DW** DW   DW DW . 48 2   

The total Lagrangian density for this system is then a 1 22   gWW sum of two contributions 2 20 

LL Ldyn (11) (15d)

Step 4: One may now consider what the potential en- Here Aμ are components of the new vector gauge field ergy term in the Lagrangian density should look like. In A, while Zμ and Wμ are components of the new vector the Standard Model, V is chosen to be in the following gauge field W/Z; and we define ZZZ  . form (which is sometimes referred to as “the Higgs po- Step 5: Now one can identify the particles and their tential”) [14], mass. Since each of these component Lagrangian densi-

2 ties (as shown in Equations (15a)-(15d)) looks like the L  2 V    2 , (12) associated with a free particle as shown in Equation (5), 2 0  20 one may interpret them as separated Lagrangian densities associated with different types of free particles. In the where o is a fixed parameter specifying the ground state of the field, and λ is another parameter associated with SM, the excitations associated with the h, Zμ, Aμ and Wμ fields are identified as the Higgs boson, the Z boson, the the coupling of the field to itself. One can now break the +  local SU(2) symmetry by imposing certain restrictions on photon, and the W /W boson, respectively. Also, by the wave function shown in Equation (7a), i.e., by re- comparing Equations (15a)-(15d) with Equation (5), the mass of each particle associated with LH, LZ, LEM, LW quiring A 0 and ΦB is real [15]. The ground state is then can be identified from the coefficient associated with their quadratic term of field strength. The results are 0 summarized in Table 1. ground  (13) 0 Thus, according to the Standard Model, the gauge boson particles (W+, W & Z) acquire their mass solely and the excited state can be written as due to their interaction with the Higgs field. Similar ar- 0 gument can be made on leptons [10,11] and [17],  (14)   hx 2  although the theories involved are more complicated. 0 From the above review, one can easily see that, in the where h(x) is a real function. By combining Equations Higgs model, the rest mass of a particle is just a parame- (9), (10) and (12) into Equation (11), and substituting ter associated with the strength of coupling between the Equation (14) into the combined equation, one can write particle field and the Higgs field. If this is true, we may down L in details in terms of the h(x) field as well as the have a philosophical problem. That is, the physical various components of the two vector gauge fields. By meaning of the rest mass m would be intrinsically differ- recombining the components of the B and W gauge fields ent from energy E or momentum p. This does not seem into two new sets of vector fields A and W/Z, one can to be very satisfactory in view of our traditional under- show that the Lagrangian density can be sorted out into standing of the physics concept.

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Table 1. Theoretical rest mass acquired by different particles under spontaneous breaking of local U(1) × SU(2) symmetry.

Lagrangian density Field Mediating Particle identification Theoretical rest mass

LH Massive Higgs boson M H   2

1 2212 LZ Massive vector gauge field Weak interaction Gauge boson Z MggZ 01 2 2

LEM Massless vector gauge field EM force Photon 0

+/- 1 LW± Massive vector gauge field Weak interaction Gauge boson W MW  g20 2

3. Why Do We Need to Consider an these analogies appears to be satisfactory. In fact, analo- Alternative Approach? gies based on simple resistance to motion are misleading, since the Higgs field does not work by resisting motion In this paper, we would like to explore a different ap- of the particle. proach to explain the origin of particle mass based on a less complicated physical picture. The motivation of do- 4. What Is Our Philosophical Starting Point? ing this is mainly due to the following considerations: First, we think mass should be treated on the same foot- We think a better approach to explain the particle mass ing as E and p. Particularly, the rest mass m should be would be a model that can take into consideration of the associated with some sort of wave property, just like en- following specific points: ergy and momentum. Second, if each type of particle is  Mass should be treated on the same footing as E and regarded as the excitation of one distinct field, it would p. require a large number of fields in the universe. This is  The properties of the fields should be based on well- not very attractive in concept; and will require very con- grounded experimental observations rather than theo- vincing experimental justification. So far, we can only retical (or mathematical) convenience. measure the physical variables of one field, namely, the  The number of fields should be greatly limited. electromagnetic field. All other fields are hypothetical  Properties of the vacuum should be more clearly de- and their properties are not based on experimental ob- fined. servation.  The theory should provide a physical mechanism for Third, it is not clear in the Higgs model what the prop- explaining how particles can be created or annihilated erty of the vacuum is. In the quantum field theory, the in the vacuum. vacuum is regarded as the ground state of all fields. This In order to satisfy the foregoing requirements, we in essence regards the vacuum as an invisible junkyard, would like to explore a new approach to explain the ori- which is used to accommodate all unexplainable pa- gin of particle mass. The starting point of this new model rameters in the theory. This makes the vacuum very is to assume that: complicated. For example, the quantum field theory re- 1) The vacuum is a continuous medium, which can be quires the vacuum to contain the zero-point energy of all excited by an energetic stimulation. The excitation wave particles. This means that, at each point of space-time, can travel within this medium in long distance without the vacuum should contain an infinite amount of energy. energy loss (just like electrons in a superconductor or Does it make sense? In addition, the SM requires the phonons in a superfluid). We may call this physical me- vacuum to contain an infinite number of virtual particle- dium the “V-medium”. pairs (with different E and p) at any given point of space- 2) The excitation waves of the V-medium behave like time. What is the physical basis of that? particles in a macroscopic view. In another word, these Finally, there seems to be a conceptual difficulty in the particles are equivalent to solitons or quasi-particles that Higgs model. It is very difficult to use common-sense were already observed in many physical systems. This ideas to explain to a layman how particle may acquire assumption is inspired by the fact that many particles are mass through the Higgs mechanism. In the last 40 years, known to have a dual property of wave and corpuscle. various analogies have been invented to describe the par- 3) Different excitation waves of the V-medium make ticle’s interaction with the Higgs field, including analo- up different types of particles observed in the physical gies with well known symmetry-breaking effects, such as world. Both fermions and bosons are excitation waves of the formation of rainbow from sunlight, separation of the same vacuum medium. This assumption is based on color using a prism, motion of a charge particle in an the fact that both photons and sub-atomic particles (like electric fields, and resistance affecting some objects electrons and neutrons) behave as physical waves in dif- moving through syrup or snow [18]. However, none of fraction experiments. Also, electron-positron pair and

Open Access JMP D. C. CHANG 25 photon can be converted between each other. experimental results, however, was very surprising; there 4) The form of the general wave equation describing was no measurable difference between the light speeds of the vacuum is determined solely by the physical proper- the two pathways, regardless how one may orient the ties of the V-medium. Since solutions of this wave equa- interferometer to different directions related to the earth’s tion represent particles of different mass, this equation orbit. The null results of their experiment were widely should not contain the parameter m in it. interpreted as a failure to observe the existence of ether 5) The mass m is more like an eigen value; it should [22]. only emerge in the subsequent wave equation describing If the ether theory was already discredited a long time the motion of a particle with given mass. (This is ana- ago, why would we propose the presence of a vacuum logues to the case that, in the classical quantum theory, medium in this work? There is a major difference be- the energy E is an eigen value. E only appears in the tween our hypothesis and the ether theory. In the 19th time-independent Schrödinger equation, Hψ = Eψ, but century, the ether was hypothesized to carry the light not in the more general time-dependent Schrödinger wave in the vacuum between matters. The ether had equation) [19]. nothing to do with matter itself. In our model, not only Our assumption of a V-medium may remind people of electromagnetic waves (photons), but all particles, in- the “ether” hypothesis proposed in the 19th century, cluding sub-atomic particles that make up matters in the which played a prominent role in the study of radiation universe, are excitation waves of the V-medium. Thus, before the development of quantum physics [20]. Almost when matters (such as a planet) move through the vac- two hundred years ago, many scientists had concluded uum medium, there is no resistance. (This is analogous to that light was made up of oscillating waves. Then, there sound waves travelling through a solid, electrons moving must be a medium that carries this wave of light. This inside a superconductor, or phonons moving through a invisible medium was called “ether”. Some physicists, superfluid.) such as Young and Fresnel, suggested that the ether pos- Then, there is no wonder that any attempt to detect the sesses the power of resisting attempt to distort its shape. earth’s movement through the vacuum medium will fail. In another word, the ether behaves like an elastic solid. This explains the null results of experiments like those Before the 20th century, many prominent physicists (and conducted by Michelson and Morely [21]. mathematicians), including Faraday, Helmholtz, Max- well, Stokes, Cauchy, Poisson, Gauss and Riemann, had 5. Basic Theory of Our Model actively participated in studying various aspects of the Based on the foregoing considerations, we can construct ether theory [20]. a new model to investigate the possible meaning of parti- The concept of ether, however, fell out of favor in the cle mass. As a formal starting point, we can say that our beginning of the 20th century. This was because it could theory is based on two conceptual postulates [23,24]: not overcome two very serious challenges. First, it could 1) All particles found in nature (including fermions not explain how large objects (like planets) can move and bosons) are excitation waves of the vacuum medium through the ether. If ether is like an elastic solid, how can (i.e., the V-medium). planets in their orbital motion travel through the ether at 2) Different types of particles (which make up either immense speed without resistance? Stokes suggested that matter or radiation) are different excitation modes of the ether may behave like shoemaker’s wax; it was rigid same vacuum medium. enough to be capable of elastic vibration, but is yet suffi- The second postulate implies that the equation of mo- ciently plastic to allow other slower bodies to pass it. The tion for all particles should be identical and this equation motion of a planet, of course, is much slower than light. is essentially determined by the physical properties of the This explanation, however, was rather superficial and vacuum medium. In the following, we will outline our was not convincing to most physicists. theoretical approach step by step. Second, a more serious problem was that all attempts Step 1: Determining the wave equation of the vac- to detect the earth’s movement through the ether failed. uum medium The existence of ether was examined in a famous ex- Our first job is to consider how to find the wave equa- periment conducted by Michelson and Morely (1887) tion of the vacuum medium. What does this wave equa- [21]. They developed a very sensitive instrument called tion look like? This is a very difficult question, since we “the Michelson interferometer” to measure the difference have very limited knowledge about the physical proper- of light speeds in two pathways perpendicular to each ties of the V-medium at this point. We can only make other. When this interferometer moves through the hy- reasonable assumptions based on our understanding of pothetical ether, one would expect that the light speed other well known physical systems. As we mentioned along the pathway parallel to the motion of ether should before, the equation of motion of a given system can be be different from the pathway perpendicular to it. The generated based on Hamilton’s principle by constructing

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a proper Lagrangian density, which is defined as citation wave of the EM field, L2 is most likely to be relevant only for the weak and strong interactions. That L  TV– . (16) means that it must be very short-ranged. Second, L2 is where T is the kinetic energy and V is the potential en- mainly responsible for interactions between different ergy. Like in most physical systems, we may separate L particles. We know that, in the absence of an external into two parts field, a free particle can travel for a long distance in vac- uum at a straight line, without altering its energy and LLL12 (17) momentum. This motion is essentially described by the where is the Lagrangian density describing the motion L1 wave equation generated from L1 alone. So L2 is likely to of excitation waves representing free particles, while L2 be responsible for the interaction between particles. represents the interaction terms. What should be the Based on the above considerations, one can treat L2 as a proper forms of L1 and L2 for the vacuum medium? We perturbation term, which is expected to be very small and can make some educated guesses by considering several can be ignored if we consider only the asymptotic be- well-known facts and reasonable conjectures. First, the havior of a free particle. wave equation of the V-medium must be isotropic, since Thus, under the condition that the system contains there is no preferred direction in the universe. Second, only one free particle (i.e., no particle-particle interaction) we already know the wave equation of at least one type and we consider only the asymptotic behavior of the ex- of particle, namely, the photon. This can provide a very citation wave (in spatial dimensions larger than an atom- useful hint. Third, we know that the Klein-Gordon equa- ic nucleus), we can hypothesize that the wave equation of tion cannot be the general wave equation of the V-me- a free particle in the vacuum medium is essentially in the dium, since it contains the parameter m. But, we also form of Equation (19). Here, the wave function  is not know that the electron theory of Dirac is highly success- limited to be a scalar function; it could represent different ful; and Dirac’s theory is based on the Klein-Gordon types of physical fields (which are different modes of equation [25]. So, the general wave equation of the vac- stress of the V-medium). The mathematical representa- uum must be capable to give the Klein-Gordon equation tion of these fields could be a scalar, a vector, a pseudo- when the concerned wave function is reduced to describ- vector (like a spinor), or even a tensor. ing only one specific type of particle (such as an elec- In summary, one may justify our hypothesis based on tron). several considerations. First, the proposed wave Equation Based on the above considerations, we can greatly nar- is isotropic. Second, Equation (19) is valid for at least row our choice for the wave equation of the V-medium. one type of particle, namely, the photon. Third, this We speculate that L1 must be in the form equation can be derived directly from the Maxwell equa-   tions, which accurately describe the electro-magnetic L1    . (18) properties of the vacuum based on experimental observa- This is a very common Lagrangian density used to de- tions. (Here, the light velocity c is determined directly scribe the elastic wave of an isotropic medium. Here, the from the dielectric constant and the permeability of the kinetic energy is represented by the time derivative part, vacuum medium.) Forth, according to our second postu- while the space derivative part represents the potential late, different particles are just different excitation modes energy, which arises solely due to the stretching or com- of the same vacuum medium. If this is true, the motion of pressing of the physical medium. By substituting L1 into particles other than photon should also obey the same the Euler-Lagrange equation, we can obtain the wave wave equation. equation for a free particle, which is We may call Equation (19) as the 4-dimensional La-  0 , (19) place equation. It is probably the most general form of wave equation found in many isotropic physical sys- 1 2 where 2  is the wave operator. Interest- tems. Besides the propagation of EM fields, the same ct22 equation can be used to describe sound wave propagation ingly, this is exactly the wave equation of a photon, if  in an elastic solid; one can simply replace the light speed is taken as a component of the vector potential (A) of the with the speed of sound (which depends on the mechani- electro-magnetic field. cal properties of the medium). In the 19th century, many What is the form of L2 in Equation (17)? This is not physicists and mathematicians had devoted great efforts exactly known at this point, but we can have some rough to study the elastic properties of ether and came up with ideas. First, it must be extremely short-ranged. In quan- various models to explain the optical effects. Some of tum physics, one considers mainly three : the EM them also had derived similar equations as Equation (19). force, the weak interaction and the . For example, MacCullagh developed a dynamic theory in Since we already shown that L1 can give entirely the ex- 1848 by considering the rotational elasticity of the vac-

Open Access JMP D. C. CHANG 27 uum medium [20]. He derived a wave equation which The left-hand side of this equation is a function only of looks exactly like Equation (19). kxˆ  and t , while the right-hand side of this equation Step 2: Solutions of the proposed wave equation is a function only of kxˆ  . Equation (23) holds only if We can now solve the wave equation of the vacuum both sides eq ual a constant, which we can denote it as and examine the properties of the wave function. For 2 . Then, Eq uation (23) can be broken down into two reason of simplicity, hereafter we will treat the wave simultaneous equations function in Equation (19) as a scalar function. 1 2 The simplest solution of Equation (19) is a plane wave 22kxˆ ,,(24)tt  kxˆ  22 LL  ct ikx t  ~e , (20)  22 k kxˆˆ kx (25)  TT  where k and  are the wave vector and frequency, which can be solved separately for  L and  T . The respectively. This plane wave solution is commonly used solution of Equation (25) is to represent a photon. It, however, does not seem to be ˆ in appropriate in describing a particle with nonzero rest  Tnkx Jr e , (26) mass, since such a particle would behave like a mass point in the classical limit. A massive particle must have where Jn is the Bessel function of the first kind, and n a limited cross-section. Then, the wave representing the is an integer or half integer; r and  represent the radial particle should not be uniform in the transverse plane. distance and the azimuthal angle of the space v ec tor in (That is, the probability of finding the particle is ex- the transverse plane. The solution of Equation (24) is a pected to be highest at its trajectory). This expectation plane wave suggests that the wave function of a free particle should ˆ ikxt  L kx,et (27) depend not only on the spatial coordinate parallel to its trajectory (i.e., kxˆ  ), but also on the coordinates in the where kk k ˆ is a vector parallel to kˆ and ˆ transverse plane kx . 2212 Furthermore, since the trajectory of a free particle is a  kc . (28) straight line, only one direction (i.e. the direction of mo- By combining Equations (21), (26), and (27), the wave ˆ tion, k ) is specified. The wave function must have a function of the V-medium thus becomes cylindrical symmetry. Thus, one can assume that the i kx ωt ψ x,t  aJr eeinθ  (29) general wave function representing a free particle must kˆ n  have the form (where a is a normalizing constant). As expected, the xk,,ttˆ xkˆ x, (21) wave functio n of a free particle behaves like a travelling kˆ  LT wave moving along the direction of its trajectory. But because of an added phase factor n , the particle wave where  L is the longitudinal component of the wave function which describes the travelling wave along the actually pro pagates in a helical fashion. The wave func- tion as a w hole thus behaves like a vortex. Also, due to particle’s trajectory, and  T is the transverse compo- the presen ce of the Bessel function, varies in a di- nent of the wave function whi ch determines the probabil-  kˆ ity density of the particle at the transverse plane. Substi- minishing oscillating manner in the directions perpen- tuting Equation (21) into Equation (19), one has dicular to the particle’s trajectory. Step 3: Finding the physical meaning of the wave 2 kxˆ kxˆ ,t parameters in the classical limit TL The wave function of Equation (29) contains four pa- . (22) ˆ 2  T kx  rameters, ω, k,  and n. What are their physical mean-  kxˆ ,t 0 ct22 L  ings? From the correspondence principle [26], the energy (E) and momentum (p) of a particle in the classical limit After expanding the 2 term (keeping in mind that can be obtained from the expectation values of the

 TL vanishes) and dividing the whole equation Ei t and p i operators, i.e., by  TL , one can rearrange Equation (22) to obtain  3 2 Ei d x, (30A) 112  ˆ t   L kx,t ˆ ct22  and  L kx ,t  . (23)  p d3 x . (30B) 1 2 ˆ   T kx i  kxˆ  T  Substituting Equation (29) into Equation (30A), one

Open Access JMP 28 D. C. CHANG can easily show that and (39), one can obtain the other “relativistic relations”, E   , (31) i.e. pv  m , (40) which, of course, is identical to the Planck’s relation. Similarly, by substituting Equation (29) into Equation M   m (41) (30B), one can obtain and pk  , (32) Emc  2 , (42)

12 which is identical to the de Broglie relation. These results where  1 vc22 . By combining Equations (41) are very encouraging. But what is the physical meaning of  in the classical limit? From Equation (28), we and (42), we have know  is closely related to ω and k. By combining EMc 2 , (43) Equations (28), (31), and (32), one can obtain which is the well-known “Einstein’s relation” of mass Ecp22222 . (33) and energy. Hence, from Equations (29) and (37), one can see that It is well known in wave mechanics that the particle the rest mass of a particle is associated with the oscil- velocity (v) is determined by the group velocity of the lation periodicity of the wave function in the trans- wave packet [27], that is, verse plane (which is perpendicular to the direction of  E movement of the particle). In short, among the four pa- v  (34) kp rameters found in the wave function as shown in Equa- tion (29), we can identify each of them to a physical Combining Equations (33) and (34), one can solve for property of the particle in the classical limit. Namely, the p and obtain wave vector k is associated with momentum p, the fre-  quency ω is associated with energy E, and the transverse  c  wave number  is associated with the rest mass m. Fi- pv 12 . (35) 1 vc22 nally, one may ask what could be the physical meaning  of the parameter n. It appears that n is likely to be associ- In the classical limit, the momentum (p) is equal to the ated with the helicity of the free particle. Since n is a mass (M) times the velocity (v). Hence, we can identify quantum number conjugate to the angular coordinate  , the quantity within the bracket on the right-hand side of dimensional analysis suggests that n is associated with Equation (35) as mass, that is, some sort of angular momentum. The helicity operator  c can be regarded as equivalent to an angular momentum M  (36) operator about an axis of the particle’s trajectory (in di- 2212 1 vc rection kˆ ). In our case the eigen value of this operator is n . Because of the phase factor n , Equation (29) At v = 0, M equals the rest mass, m. Equation (36) then suggests that the excitation wave representing a free par- implies that ticle generally propagates in a helical fashion.  Step 4: Interpretation of the Klein-Gordon equation m  (37) c From the above analysis, it is strongly suggested that the rest mass of a particle is associated with the periodic This indicates that the parameter  is associated with oscillation of the wave function in the transverse plane. the rest mass of the particle! This result appears to make This result appears to make good sense. First, such iden- good sense, since when we substitute Equation (37) into tification can directly lead to the well-known relativistic Equation (33), we have relations which are well supported by experiments. Sec- Ep22cmc224 (38) ond, one can easily see that mass is associated with a wave property of the excitation wave. This is very pleas- which agrees exactly with the energy-m omentum rela- ing in consideration of the wave-particle duality. Third, tionship obtained from the classical treatment of STR from Equation (29), one can see that m is associated with [28]. Furthermore, by substituting Equation (35) into the inverse of an oscillation wavelength, since the Bessel Equation (33), one can solve for E and obtain function approximates a cosine function in the asymp- c totic limit, i.e., E  12 (39) 1 vc22 12  Jn rrr cos . By substituting Equation (37) into Equations (35), (36), Thus, m is associated with the curvature of the field

Open Access JMP D. C. CHANG 29

(distortion in the V-medium) in the transverse plane erally travel through space in a straight line in a helical caused by the excitation wave. By comparing Equation fashion. Only (such as photon) travels (37) with Equations (31) and (32), one can easily see that as a plane wave. the physical meaning of m is very similar to that of en- The physical meaning of particle mass is explored in ergy and momentum, since all of them are related to the this work. Our definition of mass is based on its associa- curvature of the field. Thus, our result stro ngly suggests tion with momentum, just like what we learned in classi- that the mass m can indeed be treated on th e same theo- cal mechanics. We found that the rest mass of a particle retical basis as E and p. is associated with a transverse wave number  , which is After demonstrating that  is connected with m, we related to the periodic oscillation of the excitation wave can now identify the origin of the Klein-Gordon equation. in a plane perpendicular to the movement of the particle. By substituting Equation (37) into Equation (24), one can Our finding appears to make good sense. It satisfies our obtain requirement that the mass m should be treated on the 2 mc same footing as E and p. It is well known that mass m is LL 0 , (44) a particle property; our model is able to naturally connect  this particle property with a wave property of the excita- which is identical to the “Klein-Gordon equation” shown tion wave. This is highly satisfactory and consistent with in Equation (3). One should notice that, by comparing the fact that all particles have the property of particle- Equations (3) and (44), the wave function described by wave duality. the Klein-Gordon equation is just the longitudinal com- Our results can also provide a useful basis for ex- ponent of the travelling wave; it does not represent the plaining the origin of the Klein-Gordon equation, which entire wave function of a free particle. comes out naturally from our model. We show that it is a In conclusion, the results of our analysis have several simplified wave equation of the vacuum for a particle of implications. First, by successfully deriving the Klein- specific m. This equation describes only the longitudinal Gordon equation, we can reconcile our model with that component of the excitation wave. Once the Klein- of the quantum field theory, even though our starting Gordon equation is derived, one can then easily obtain point is more classical. Second, the fact that we can re- the to describe the motion of electron [29]. produce the Planck’s relation and the de Broglie relation Furthermore, based on the Dirac equation, the Schrö- suggest that our proposed wave equation for the vacuum dinger equation can be derived under the condition when medium is very reasonable. In another word, the free the Coulomb potential energy and kinetic energy are Lagrangian density constructed by us (i.e., Equation (18)) small in comparison to the rest mass of the particle. This must be a good choice. Third, by following the derivation procedure had been shown elsewhere [30]. of Equation (44), it is clear that the Klein-Gordon equa- Finally, the well-known relativistic relations between tion is not a general wave equation of the vacuum me- energy, momentum and mass also emerge naturally in dium; it can only describe the motion of a particle with a this model. But, we must point out that we did not use specific mass (i.e., when the parameter  is already STR as the start point. Our proposed wave equation for chosen). Forth, according to Equation (44), the wave the V-medium is based on the Maxwell equations (and function described by the Klein-Gordon equation,  , L the wave equation of an elastic solid). We obtain the only represents the longitudinal part of the excitation relativistic relations because the wave equation chosen wave. This part of the wave function contains mainly the by us happens to be Lorentz invariant. Since the wave positional information of the particle along its pathway; equation of a free particle comes from the Lagrangian it does not describe the actual physical wave of the vac- density L1 alone, our choice only requires L1 to be Lor- uum medium. Thus, the Klein-Gordon equation is mainly entz invariant. At this point we know very little about L2, useful for describing the trajectory of the part icle. the Lagrangian density responsible for particle interac- tions. There is no guarantee that the full Lagrangian den- 6. Discussions sity of the vacuum medium as shown in Equation (17) is The starting point of this work is that particles are re- Lorentz invariant. So, our requirement at this point is less garded as quantum excitation waves of the vacuum me- stringent than the STR. dium (i.e., the V-medium). Thus, the equation of motion In summary, this work suggests that the vacuum is not for all particles is determined by the physical properties an empty space with nothing in it. Instead, it is made of a of the vacuum. Based on a few general considerations, physical medium that can propagate different sorts of we proposed a wave equation for the V-medium under a elastic waves. This medium may appear to be invisible, simplified condition, i.e., when the vacuum contains only because visibility requires photons, which appear only a single free particle. Solution of this wave equation when the medium is in the excited state. We hypothesize suggests that, free particles with non-zero rest mass gen- that different types of particles observed in nature are just

Open Access JMP 30 D. C. CHANG different modes of quantum excitations of this medium. [13] W. N. Cottingham and D. A. Greenwood, “An Introduc- At this point, the physical properties of the vacuum me- tion to the Standard Model of Particle Physics,” Cam- dium are not exactly known. It could behave like an elas- bridge University Press, Cambridge, 1998, pp. 105-106. tic solid or a superfluid. How to find the detailed proper- [14] J. Goldstone, “Field Theories with ‘Superconductor’ So- ties of the vacuum medium will be a major challenge in lutions,” Il Nuovo Cimento, Vol. 19, 1961, pp. 154-164. http://dx.doi.org/10.1007/BF02812722 the future. [15] G. S. Guralnik, International Journal of Modern Physics A, Vol. 24, 2009, pp. 2601-2627. 7. Acknowledgements http://dx.doi.org/10.1142/S0217751X09045431 I am grateful to Profs. John Wheeler and H. E. Rorschach [16] W. N. Cottingham and D. A. Greenwood, “An Introduc- for their encouragement during the early stage of this tion to the Standard Model of Particle Physics,” Cam- work. I thank Profs. Zhaoqing Zhang and Xiangrong bridge University Press, Cambridge, 1998, pp. 107-109. Wang for their comments. I also thank Mr. Wenbin Cao [17] W. N. Cottingham and D. A. Greenwood, “An Introduc- for his assistance. A preliminary version of this work was tion to the Standard Model of Particle Physics,” Cam- presented in the Joint APS/AAPT Meeting (1984) in bridge University Press, Cambridge, 1998, pp. 131-139. USA [31] and in the 8th International CASYS Confer- [18] J. Ellis, “What Is the Higgs Boson?” ence (2007) held in Liege, Belgium. http://lybio.net/tag/john-ellis-what-is-the-higgs-boson-qu otes/ [19] A. Messiah, “,” John Wiley & Sons, REFERENCES New York, 1965, pp. 59-72. [1] G. Z. Liu, G. Cheng, Physical Review B, Vol. 65, 2002, p. [20] E. Whittaker, “A History of the Theories of Aether and 13. Electricity,” Thomas Nelson and Sons Ltd., London, 1951. [2] ATLAS Collaboration, Physical Review B, Vol. 716, 2012, p. 1. [21] A. A. Michelson and E. W. Morley, “On the Relative Motion of the Earth and the Luminiferous Ether,” Ameri- [3] CMS Collaboration, Physical Review B, Vol. 716, 2012, p. can Journal of Science, Vol. 34, 1887, pp. 333-345. 30. http://dx.doi.org/10.2475/ajs.s3-34.203.333 [4] ATLAS Collaboration, Physics Letters B, 2013. [22] A. P. French, “,” Nelsen, London, 1968. arXiv:1307.1427 [hep-ex] [23] D. C. Chang, “What Is Rest Mass in the Wave-Particle [5] R. Oerter, “The Theory of Almost Everything: The Stan- Duality? A Proposed Model,” 2004. dard Model, the Unsung Triumph of Modern Physics,” ArXiv: physics/0404044 Penguin Group, 2006. [24] D. C. Chang, “On the Wave Nature of Matter,” 2005. [6] F. Englert and R. Brout, Physical Review Letters, Vol. 13, ArXiv: physics/0505010 1964, pp. 321-323. http://dx.doi.org/10.1103/PhysRevLett.13.321 [25] P. A. M. Dirac, “The Principles of Quantum Mechanics,” 4th Edition, Oxford University Press, Oxford, 1981. [7] P. W. Higgs, Physical Review Letters, Vol. 13, 1964, pp. 508-509. http://dx.doi.org/10.1103/PhysRevLett.13.508 [26] A. Messiah, “Quantum Mechanics,” John Wiley & Sons, New York, 1965, pp. 56-59. [8] G. S. Guralnik, C. R. Hagen and T. W. B. Kibble, Physi- cal Review Letters, Vol. 13, 1964, pp. 585-587. [27] S. Nettel, “Wave Physics,” 3rd Edition, Springer, Berlin, http://dx.doi.org/10.1103/PhysRevLett.13.585 2003, pp. 221-223. http://dx.doi.org/10.1007/978-3-662-05317-1 [9] C. N. Yang and R. Mills, Physical Review, Vol. 96, 1954, pp. 191-195. http://dx.doi.org/10.1103/PhysRev.96.191 [28] A. Einstein, “Relativity. The Special and the General Theory,” Three River Press, New York, 1961, pp. 1-64. [10] S. Weinberg, Physical Review Letters, Vol. 19, 1967, pp. 1264-1266. [29] J. J. Sakurai, “Advanced Quantum Mechanics,” Addison- http://dx.doi.org/10.1103/PhysRevLett.19.1264 Wesley, Reading, 1973, pp. 78-89. [11] A. Salam, “ Physics: Relativistic [30] W. N. Cottingham and D. A. Greenwood, “An Introduc- Groups and Analyticity,” In: N. Svartholm, Ed., Eighth tion to the Standard Model of Particle Physics,” Cam- Nobel Symposium, Almquvist and Wiksell, Stockholm, bridge University Press, Cambridge, 1998, p. 72. 1968. [31] D. C. Chang, Bulletin of the American Physical Society, [12] W. N. Cottingham and D. A. Greenwood, “An Introduc- Vol. 29, 1984, p. 6. tion to the Standard Model of Particle Physics,” Cam- bridge University Press, Cambridge, 1998, pp. 103-105.

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