1.2.SEMINORMEDRINGS 29 January 23, 2020, 3:12pm 1.2. Seminormed rings All rings will be commutative with identity, denoted by 1. All ring homomorphisms take the identity to the identity. If R is a ring, we write R⇥ := R 0 . \{ } 1.2.1. Seminormed rings. A seminorm on a ring A is a seminorm on the underlying abelian group that satisfies 1 1 and is submultiplicative in the sense thatk·kab a b for all a, b A.Thisimplies 1k k=1unless is the zero seminorm. A seminormedk kk ringkis·k ak pair (A, 2), where A is a ringk andk is a seminormk·k on A.Anormed ring is a seminormed ring for whichk·k the seminorm is a norm.k A·kBanach ring is a complete normed ring. A normed field (resp. Banach field) is a normed (resp. Banach) ring that is also a field. Lemma 1.2.1. If is a nonzero seminorm on a ring A, then a =0for all invertible elements a A. As a consequence,k·k a nonzero seminorm on a field is a norm.k k6 2 1 Proof. If a A is invertible, then 1 = 1 a a ,so a = 0. 2 k kk k·k k k k6 ⇤ A morphism of seminormed rings is a bounded ring homomorphism. As in the case of semigroups, there are two natural categories of seminormed rings, using bounded homomorphisms and contractive homomorphisms as morphisms, respectively. Each category has several full subcategories in which the objects are normed or even Banach rings, and/or are non-Archimedean. Some properties of these categories are developed in the exercises. 1.2.2. Power-multiplicative norms and valuations. We often require seminorms to satisfy stronger conditions than being submultiplicative. For instance, we say that a seminorm on A is power-multiplicative if an = a n for n 1. For such norms, we have the following usefulk· criterion.k k k k k Lemma 1.2.2. A power-multiplicative seminorm on a ring A is non-Archimedean i↵ n 1 for all n Z. k·k k k 2 The inequality n 1 can be interpreted as the failure of Archimedes’ axiom. k k Proof. The direct implication is trivial. Now suppose n 1 for all n and pick a, b A. For any n 1wehave k k 2 1/n n n 1/n n j n j a + b = (a + b) = a b k k k k j j=0 ✓ ◆ X 1/n n n j n j 1/n a b (n + 1) max a , b . 0 k j kk k k k 1 {k k k k} j=0 X ✓ ◆ 1/n @ A Since limn (n + 1) = 1, this proves that a + b max a , b . ⇤ !1 k k {k k k k} A seminorm on a ring A is multiplicative if 1 = 1 and ab = a b for a, b A. More generally, ank· elementk a A is multiplicative if abk k= a b kfork all bk kA·.k Ak multiplicative2 seminorm will be called a semivaluation2 .3 k k k k·k k 2 A multiplicative norm on a ring A is called a valuation; we then call (A, )avalued ring. In this case, A must be an integralk·k domain, and extends uniquely to a valuationk·k on the fraction field Frac(A), see Exercise 1.2.7, so (Frac(A), k·)k is therefore a valued field. Valued fields will be studied in 1.3. We shall often denote a valuationk·k on a field by instead of . § |·| k·k 3When is the zero seminorm, the terminology is a bit inconsistent: every element is multiplicative but the k·k seminorm is not multiplicative. . . should address this at some point! 30 1.SEMINORMEDCOMMUTATIVEALGEBRA
Remark 1.2.3. In the literature, valuations are usually assumed non-Archimedean and are often written additively, so that a valuation on a ring A becomes a function v : A⇥ R satisfying v(1) = 0, ! v(a+b) min v(a),v(b) , and v(ab)=v(a)+v(b) for a, b A⇥. To such a function we can associate a valuation (in the{ sense above)} by setting = "v,where"2 (0, 1) is an arbitrary constant. Following Berkovich we shall work multiplicatively,|·| even though, in2 some situations, the additive convention may seem more natural. Remark 1.2.4. It is also possible to consider more general norms and seminorms. Consider an ordered abelian group , with group operation written multiplicatively. Equip 0 with the ordering from together with 0 <