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Heterocyclic compounds

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By Dr. Ghassan Qais Ali Examples on Aromatic Heterocycles:

Look back once again at the definition of , a cyclic, conjugated molecule containing 4n + 2 p .

1) and , for example, are six-membered heterocycles with in their rings. Pyridine is much like in its p structure. Each of the five sp2-hybridized has a p orbital perpendicular to the plane of the ring, and each p orbital contains one p electron. The nitrogen is also sp2-hybridized and has one electron in a p orbital, bringing the total to six p electrons. The nitrogen lone-pair electrons (red in an electrostatic potential map) are in an sp2 orbital in the plane of the ring and are not part of the aromatic p system. Pyrimidine, also shown in Figure below, is a benzene analog that has two nitrogen in a six-membered, unsaturated ring. Both are sp2-hybridized, and each contributes one electron to the aromatic p system. 2) and : are five-membered heterocycles, yet both have six p electrons and are aromatic. In pyrrole, each of the four sp2-hybridized carbons contributes one p electron and the sp2-hybridized nitrogen atom contributes the two from its , which occupies a p orbital. Imidazole, also shown in Figure below, is an analog of pyrrole that has two nitrogen atoms in a five-membered, unsaturated ring. Both nitrogens are sp2- hybridized, but one is in a and contributes only one electron to the aromatic p system while the other is not in a double bond and contributes two from its lone pair. Note that nitrogen atoms have different roles depending on the structure of the molecule. The nitrogen atoms in pyridine and pyrimidine are both in double bonds and contribute only one p electron to the aromatic sextet, just as a atom in benzene does. The nitrogen atom in pyrrole, however, is not in a double bond and contributes two p electrons (its lone pair) to the aromatic sextet. In imidazole, both kinds of nitrogen are present in the same molecule— a double-bonded “pyridine- like” nitrogen that contributes one p electron and a “pyrrole-like” nitrogen that contributes two. 3) Pyrrole, , : 4) Pyrrole and protonated Pyrrole : - The delocalization of the lone pair of Pyrrole pushes electrons from the nitrogen atom into the ring and we expect the ring to be electron-rich and become more nucleophile. Thus, decreased basicity of the nitrogen atom and increased acidity of the NH group as a whole

6  Pyrrole is assumed to be an aromatic molecule. While Its protonated form is not aromatic. Using orbital pictures, explain why?

7 Note: 1) In each of the following, encircle the stronger base :

2) Accounting for the Aromaticity of a Heterocycle If the proton was removed from Pyrrole to give the structure shown below, would it still be considered aromatic? Why or why not? Use pictures in your explanation.

Solution:

9 3) Thiophene, a -containing heterocycle, undergoes typical aromatic substitution reactions rather than addition reactions. Why is thiophene aromatic?

Strategy: Recall the requirements for aromaticity—a planar, cyclic, conjugated molecule with 4n + 2 p electrons—and see how these requirements apply to thiophene. Solution: Thiophene is the sulfur analog of pyrrole. The sulfur atom is sp2-hybridized and has a lone pair of electrons in a p orbital perpendicular to the plane of the ring. Sulfur also has a second lone pair of electrons in the ring plane. 4( Draw an orbital picture of furan to show how the molecule is aromatic.

5( Thiamin, or vitamin B1, contains a positively charged five-membered nitrogen–sulfur heterocycle called a thiazolium ring. Explain why the thiazolium ring is aromatic. Five membered monoheterocyclic or Heterocyclic analogues of cyclopentadiene with one

Cyclic compounds that include an element other than carbon are called

N O S Cyclopentadiene Cyclopentadiene anion H Furan Thiophene Pyrrole

• Pyrrole, furan and thiophene are a five-membered heterocyclic compound, We might expect each of these compounds to have properties of conjugated of an amine , an or sulphide respectively.

12 • On this basis pyrrole , furan and thiophene must be considered to be aromatic, this is proved by NMR spectrum

• these heterocyclic compounds in general undergo electrophilic substitution reaction for example; nitration ,sulphonation, halogenation ,Friedel-craft Acylation and coupling with diazonium salts

• The Heat of combustion indicate stabilization to the extent 22-28 kcal/mole less than the resonance energy of benzene (36kcal/mol)but much greater than of most conjugated diene (about 3 kcal/mol).

(Pyrrole is obtained commercially by treatment of furan with over an alumina catalyst at 400 °C.)

a) Synthesis of :

1- From Acetylene with formaldehyde: 2- From heterocyclic ( furan and succinamide) : 3- Paal-Knorr Synthesis: Mechanism:

R1, R2 = CH3 4- Knorr Synthesis: : Alpha- amino can be obtained by reducing Oxime compound by Zn and HCl as shown bellow: Mechanism: Example:

5- Hantzsch method: By condensation the beta-Ketoester molecule with alpha-chloroketone in presence of ammonia. Example: b) Synthesis of :

1- From and poly-saccharide with dilute mineral acid: Commercially, furan preparation in a large quantities from natural materials containing pentose and poly-saccharide such as bran, straw with dilute mineral acid. - can be prepared by dehydration and cyclization of . Furfural undergoes decarbonylation to give furan Mechanism: 2- From 1,4- Compounds: The Paal-Knorr Synthesis

The Paal-Knorr method for synthesis of furans involves cyclization of 1,4-diketones with acid catalysts such as sulphuric acid, (V) oxide, zinc chloride, acidic ion-exchange resin etc. Mechanism: 3- From α-Halo- carbonyl and 1,3-Dicarbonyl Compounds: The Feist-Benary Synthesis Example 1:

------Example 2 : 4) 3-Substituted furans can be prepared by cyclization of Z-butene-1,4-diols with pyridinium chlorochromate (PCC). c) Synthesis of : 1- From butane, butene and with sulfur vapor : Theophine is commercially available for the continuous heat of the butane, butene or butadiene with sulfur vaper. Where a process of hydrogen displacement and then the closure occurs. 2- From 1,4-Dicarbonyl Compounds and a source of Sulfide: The Paal-Knorr Synthesis

Example:

2,4-bis(4-methoxyphenyl)-1,3,2,4-dithiadiphosphetane 2,4-disulfide

Mechanism:

Anther Example: 3- From Thiodiacetates and 1,2-Dicarbonyl Compounds: The Hinsberg Synthesis

Example: 4- From Thioglycolates and 1,3-Dicarbonyl Compounds 5- From α-Thio-carbonyl Compounds: Problem: 1) Draw an orbital picture of . Assume that both the nitrogen and sulfur atoms are sp2-hybridized, and show the orbitals that the lone pairs occupy.

2) Use the Paal-Knorr method for synthesis 2,5-disubsitunet of furan, pyrrole and thiophene?

Solution: Q1) Draw an orbital picture of thiazole. Assume that both the nitrogen and sulfur atoms are sp2-hybridized, and show the orbitals that the lone pairs occupy.

Q2) Why pyrrole is a weak base ?