Algebraic Surfaces Sep
Algebraic surfaces Sep. 17, 2003 (Wed.) 1. Comapct Riemann surface and complex algebraic curves This section is devoted to illustrate the connection between compact Riemann surface and complex algebraic curve. We will basically work out the example of elliptic curves and leave the general discussion for interested reader. Let Λ C be a lattice, that is, Λ = Zλ1 + Zλ2 with C = Rλ1 + Rλ2. Then an ⊂ elliptic curve E := C=Λ is an abelian group. On the other hand, it’s a compact Riemann surface. One would like to ask whether there are holomorphic function or meromorphic functions on E or not. To this end, let π : C E be the natural map, which is a group homomorphism (algebra), holomorphic function! (complex analysis), and covering (topology). A function f¯ on E gives a function f on C which is double periodic, i.e., f(z + λ1) = f(z); f(z + λ2) = f(z); z C: 8 2 Recall that we have the following Theorem 1.1 (Liouville). There is no non-constant bounded entire function. Corollary 1.2. There is no non-constant holomorphic function on E. Proof. First note that if f¯ is a holomorphic function on E, then it induces a double periodic holomorphic function on C. It then suffices to claim that a a double periodic holomorphic function on C is bounded. To do this, consider := z = α1λ1 + α2λ2 0 αi 1 . The image of f is f(D). However, D is compact,D f so is f(D) and hencej ≤f(D)≤ is bounded.g By Liouville theorem, f is constant and hence so is f¯.
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