PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 135, Number 6, June 2007, Pages 1851–1859 S 0002-9939(07)08693-5 Article electronically published on January 5, 2007

UPPER BOUNDS FOR THE VOLUME AND OF m-DIMENSIONAL SECTIONS OF CONVEX BODIES

JESUS´ BASTERO

(Communicated by N. Tomczak-Jaegermann)

Abstract. In this paper some upper bounds for the volume and diameter of central sections of symmetric convex bodies are obtained in terms of the isotropy constant of the polar body. The main consequence is that every symmetric convex body K in Rn of volume one has a proportional section K ∩ F ,dimF = λn (0 <λ<1), of diameter bounded by Cn3/4 log(n +1) R(K ∩ F ) ≤ , 3 (1 − λ) LK◦ whenever the polar body K◦ is in isotropic position (C>0 is some absolute constant).

1. Introduction, notation and results We consider Rn endowed with the canonical euclidian structure. The set K will be a convex body in Rn, i.e., a compact in Rn having a nonempty interior. We shall say that K is in isotropic position if its centroid is the origin xdx =0 K and there is a constant α>0 such that x, θ2dx = α K for all θ ∈ Sn−1. Every convex body in Rn has a unique, up to orthogonal transfor- mation, isotropic position (by a position of a convex body here we mean any affine transformation of the set, with determinant equal to 1). We recall the definition of the isotropy constant L of a convex body K K 1 (1.1) nL2 |K|2/n =inf |t + Sx|2 dx, K ∈ | | S SL(n) K K t∈Rn

Received by the editors September 14, 2005 and, in revised form, February 8, 2006 and February 14, 2006. 2000 Subject Classification. Primary 46B20, 52A20, 52A40. Key words and phrases. Asymptotic geometric analysis, diameter of sections. The author was partially supported by DGA (Spain), MCYT (Spain) MTM2004-03036 and EU Project MRTN-CT-2004-511953 and is grateful to the Erwin Schr¨odinger Institut in Wien, where part of this work was carried out.

c 2007 American Mathematical Society Reverts to public domain 28 years from publication 1851

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so, if K is in in isotropic position and |K| =1, 2 2 LK = x, θ dx K for all θ ∈ Sn−1. Inthesequelwewillassumethat|K| = 1. It is a major problem in asymptotic convex to prove that the isotropy constant of any convex body K in n R , LK , is bounded from above by an absolute constant (independent even on the ). It is well known that this fact is equivalent to the slicing problem: there exists an absolute constant c>0 with the following property: if K is a convex n body in R there exists a hyperplane H such that |K ∩H|n−1 >c.Thebestknown 1/4 bound for the isotropy constant was given by Bourgain LK ≤ Cn log n (see [Bo1], [Bo2] and also [D] and [Pa1] for the nonsymmetric case). Very recently, using a new concentration inequality of G. Paouris ([Pa2], [Pa3]), B. Klartag has just improved 1/4 Bourgain’s estimate proving that LK ≤ Cn (see [Kl2]). Let us assume that the convex body K of volume one has its centroid in the origin. The circumradius R(K)isthequantity n−1 R(K)=max{|x|; x ∈ K} =max{1/θK ; θ ∈ S }. √ A simple computation shows that C n ≤ R(K). Moreover if K is isotropic ◦ R(K) ≤ n(n +2)LK (cf. [KLS]) and if instead of that, K is in isotropic position, then Cn R(K) ≤ ≤ Cn, LK◦ where C is an absolute constant (see item 3 in the Remarks below). In this paper some upper bounds for the volume and circumradius of sections of symmetric convex bodies with volume one are obtained in terms of the isotropy constant of the polar body. The proof we use in proving the part ii) of Theorem 1.1 is based in the methods appearing in the paper [Bo2] in which Bourgain obtained some sharp estimates for isotropic ψ2-convex bodies. Our result is equivalent to that appearing in [Bo2] (lemma on page 116), at least for high-dimensional sections. However, the approach we use here presents some differences. We use the M-ellipsoid associated to every convex body and sharp estimates on covering numbers given by Pisier (see [Pi]) instead of using the -ellipsoid and Talagrand majoration theorem. The main result we achieve is the following. Theorem 1.1. Let K be a centrally symmetric convex body in Rn with volume |K| =1such that K◦ is in isotropic position. Let E be any m-dimensional subspace, 1 ≤ m ≤ n.Then i) Cn (1.2) |K ∩ E|1/m ≤ , m 3/4 m LK◦ ii) if 0 <δ<1/2 there exists another subspace F ⊂ E, (1 − 2δ)m ≤ dim F ≤ (1 − δ)m such that C log(m +1)n5/4 R(K ∩ F ) ≤ 3 1/2 δ m LK◦ for some absolute constant C>0 (independent of K and of the m, n).

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Remarks. 1. The bound (1.2) for the high dimensions gives the better known bound for the isotropy constant. In fact, it is clear for m = n simply by taking E = Rn. A similar situation happens for m = n(1 − f(n)) whenever f(n)=O(1/ log n). Indeed, as a consequence of Hensley inequalities (cf. [H]) or Ball’s result (cf. [B2], Lemma 6) we know that | ∩ |1/(n−m) ≥ LK E K m C whenever that K is a symmetric convex body in Rn of |K| = 1 in isotropic position, E is any m-dimensional subspace of Rn and C>0 is a numerical constant. Then if the convex body K is not assumed to be in isotropic position the inequality before is true at least for one m-dimensional subspace E and so, taking into account (1.2) we have (n−m)/m C1 ≤| ∩ |1/m ≤ C2n K E m 3/4 , LK m LK◦ ≤ and√ by using the rough estimates for the isotropy constant (for instance, LK C n), we would have − C (n m)/m C n √1 ≤ 2 . 3/4 n m LK◦ When m = n(1 − f(n)) the inequality gives the better known estimate for the isotropy constant. 2. Apart from random estimates obtained recently by different authors (see, for instance, Giannopoulos and Milman in [GM1], [GM2] and [GM3], Giannopoulos, Milman and Tsolomitis in [GMT], Litvak and Tomczak-Jaegermann in [LT] and Klartag in [Kl1]) the most recent result in this is that by Bourgain, Klartag and Milman (see [BKM]) who proved that if Kn is an isotropic convex body of

volume one such that LKn is the worst possible constant in dimension n,thenfor − | ∩ |1/m ≤ any subspace F of dimension n m, Kn F n−m C, for some absolute constant 0 C. In our situation, if K is a symmetric convex body such that LK = LKn ,then ≤ | ∩ |1/m ≤ n by using the fact that Lm CLn,wehavethat K E m C m . 3. It is clear that no upper bounds for the circumradius of a general symmetric convex body can exist without fixing a position. However if K◦ is in isotropic position, then the expression (1.2) for m =1givesR(K) ≤ Cn. We can also give a shorter proof using the reverse Blaschke-Santal´o’s inequality (see [BM]). Indeed, ◦ ◦ 1/n since the convex body K is in isotropic position and its volume is |K |n ∼ 1/n, the isotropic constant satisfies 2 ∼ n | |2 (1.3) LK◦ | ◦| x dx, K n K◦ according to (1.1). Then we have 2 2 ≤ n 2 ≤ 2 2 LK◦ C | ◦| x, θ dx Cn θ K . K K◦ n (·K represents the norm in R whose unit ball is K.) If K is a general convex body in Rn with its centroid in the origin, using K ⊂ K − K and Rogers-Shephard’s inequality there exists a position of K,sayK˜ ,for which R(K˜ ) ≤ Cn. 4. We can improve the above estimate on the circumradius only for high- dimensional sections of convex bodies of volume one, whose polars are in isotropic

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position. For instance, given 0 <λ<1, by taking m = n and δ =(1− λ)/2in Theorem 1.1, we obtain that for any convex body K satisfying this hypothesis there exists some λn-dimensional section for a subspace F such that

3/4 ∩ ≤ Cn log(n +1) R(K F ) 3 . (1 − λ) LK◦ Taking polars and renormalizating volumes we can express this result in terms of the polar body in the following way: If K is an isotropic symmetric convex body in Rn with volume one, then given 0 <λ<1 there exists some orthogonal projection on the subspace F of Rn such that L n1/4 P (K) ⊇ C(1 − λ)3 K D , F log(1 + n) λn

where Dλn denotes the Euclidean unit ball in dimension λn.

n Let us eventually introduce some notation. We represent 2 the normed space Rn with the Euclidean norm. Note that |·|will represent the Euclidian norm and also the volume |K| = |K|n (if we want to emphasise the dimension). By C, c we will represent absolute constants which can vary from line to line. The expression ∼ denotes equivalence of two quantities up to an absolute factor.

2. Proof of the theorem Proof. i) The case m = n is just the estimate for the isotropy constant. We only consider 1 ≤ m ≤ n − 1. By using Bourgain-Milman’s reverse Blaschke-Santal´o’s inequality (see [BM]) we have that C |K ∩ E|1/m ≤ m ◦ 1/m m|(K ∩ E) |m C = ◦ 1/m m|PE(K )|m and also using Fubini’s theorem and Brunn-Minkowski inequality | ◦|1/n ≤| ◦ ∩ ⊥|1/n | ◦ |1/n K n K E n−m PE(K ) m . Then

1/m C ◦ ⊥ 1/m |K ∩ E| ≤ |K ∩ E | − . m m|K◦|1/m n m Now we use a fact which can be deduced from a well-known result by Milman-Pajor (cf. [MP], Proposition 3.11) (this result can be found implicit in K. Ball ([B1])): if T in Rn is an isotropic symmetric convex body, then

| ∩ ⊥|1/m ≤ Lm | |(n−m)/nm T E n−m C T n , LT

where C is an absolute constant and Lm is the supremun of the isotropy constants of all m-dimensional convex bodies. Hence, we apply this result to T = K◦,takinginto ◦ 1/n account that |K |n ∼ C/n by reverse Blaschke-Santal´o’s inequality. Eventually the better known estimate for the isotropy constant gives the result.

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◦ ◦ 1/n ii) Since the convex body K is in isotropic position and its volume is |K |n ∼ 1/n, the isotropic constant L = LK◦ satisfies 2 ∼ n | |2 (2.4) L | ◦| x dx, K n K◦

according to (1.1). Let E be any m-dimensional subspace of Rn.WedenotebyX the m-dimensional normed space X =(E,·K∩E), where ·K∩E is the norm on E whose unit ball is K ∩ E. WedenotebyB the polar set of K ∩ E in E so the dual space is ∗ ◦ X =(E,·B), and it is well known that B = PE(K ), where PE denotes the orthogonal projection on E. We consider the M-ellipsoid associated to the symmetric convex body (in E), ∩ m → K E (see [Pi]), i.e. given any 0

for some absolute constant C>0andforallk =1,...,m,wherethedk,ck,ek’s are the corresponding Kolmogorov, Gelfand and entropy numbers. Furthermore

∗ (2.6) max {log N(u(Dm),tK∩ E), log N(u (B),tDm), (2.7) log N(K ∩ E,tu(D )), log N(D ,tu∗(B))} m m C p m (2.8) ≤ √ 2 − p tp √ for all t ≥ C/ 2 − p ,whereC>0 is an absolute constant (see, for instance, [Pi], Theorem 7.13 and Corollaries 7.15 and 7.16). We can assume that the isomorphism u has a diagonal expression if we take { }m m { }m the canonical basis εi i=1 in 2 and some orthogonal basis ei i=1 (with respect n to the euclidian structure of R )inE such that u(εi)=λiei,forsomeλi > 0, 1 ≤ i ≤ m in such a way that λ1 ≤ λ2 ≤···≤λm.Let1≤ k

(see (2.5)), by definition of the Gelfand numbers, there exists a subspace F1 ⊆ E with dim F1 >m− k, such that C m 1/p |u−1(x)|≤√ x 2 − p k K

for all x ∈ F1.LetF2 =span{e1,...,em−k}. It is clear that F = F1 ∩ F2 verifies that m − 2k

License or copyright restrictions may apply to redistribution; see https://www.ams.org/journal-terms-of-use 1856 J. BASTERO m−k ∈ for all x = i=1 xiei F .So, 1/p | |≤ √ C m   x λm−k − x K 2 p k m 1 C m 1/p ≤ λ √ x k i 2 − p k K i=m−k+1 1 m C m 1/p ≤ λ √ x k i 2 − p k K i=1

for all x ∈ F . We will assume the following. Claim. m Cn(3/2−1/2p)m1/p λ ≤ √ . i L 2 − p i=1 We first finish the proof. If we assume that k = δm,forsome0<δ<1/2, then C n3/2−1/2p |x|≤ (2 − p)δ1+1/p Lm1−1/p for all x ∈ F ∩ K, and we achieve the result, by taking p =2− 1/ log m. 

m n Proof of the Claim. We consider 2 canonically embedded in 2 , and we denote by { }n { }m εi i=1 its canonical basis; in the same way, we extend the orthogonal basis ei i=1 n n from E to all R .LetPE : R → E be the orthogonal projection on E. ⊆ n Let K1 2 be the convex set defined by n n { ∈ n ∈ ◦} K1 = x = xiεi 2 ; xiei K . i=1 i=1 ◦ K1 is an orthogonal copy of K , therefore they have the same volume and isotropy constant, and hence, by (2.4), C 1 L2 ≤ x2dx 2 | | i n K1 n K1 for an absolute constant and for all 1 ≤ i ≤ n. Hence C m 1 m (2.9) L2 λ ≤ λ x2 dx 2 i | | i i n K1 n K i=1 1 i=1 n m 1 ∗ (2.10) = | | xiεi,u xiei dx K1 n K 1 i=1 i=1 n 1 ∗ (2.11) = x, u ◦ PE xiei dx |K1|n K1 i=1 1 (2.12) ≤ max x, z dx | | z∈ u∗(B) K1 n K1 ◦ since B, which is the polar of K ∩ E in E, can be expressed as B = PE(K )and ∗ · → m u :(E, B) 2 .

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Now we follow the method appearing in [D], [Gi], [Pa1] in order to estimate from ∗ above the last integral. If we assume that u (B) ⊂ RDm,forsomeR>0 large enough, we use the Dudley-Fernique’s technique. Let N ∈ N (to be chosen later). By using (2.8), it is clear that for every j =1,...,N there exist points y(j),...,y(j) 1 Nj such that N j R u∗(B) ⊂ y(j) + D , i 2j m i=1 where C p m2jp log N ≤ √ . j 2 − p Rp Therefore, for every z ∈ u∗(B)and1≤ j ≤ N we choose the points y(j) such that |z − y(j)|≤R/2j . Hence

z =0+(y(1) − 0) + (y(2) − y(1))+···+(y(N) − y(N−1))+(z − y(N))

= w1 + ···+ wN + w,

where 3R |w |≤|y(j) − z| + |z − y(j−1)|≤ , j 2j R |w| = |z − y(N))|≤ . 2N

Each vector wj belongs to a finite set Fj of cardinality |Fj|≤NjNj−1,so C p m2jp log |F |≤2 √ . j 2 − p Rp

Therefore

N max x, z dx ≤ max x, wjdx + max x, wdx. ∈ ∗ ∈F R z u (B) wj j w∈ Dm K1 j=1 K1 K1 2N

Since K1 is in isotropic position, the last summand verifies 1 R 1 max x, wdx ≤ |x|dx | | R N | | K1 n w∈ Dm 2 K1 n K1 2N K1 R 1 1/2 ≤ |x|2dx N | | 2 K1 n K1 CR L ≤ by (2.4) ≤ √ . 2N n

We use the following well-known fact (which is a consequence of Borell’s lemma; see [MS]): if K˜ is an isotropic convex body with volume |K˜ |n =1,then N | | ≤ N | | (2.13) max x, yi dx CLK˜ log N max yi K˜ i=1 i=1

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for any finite family of unit vectors {y1,...,yN },whereC>0 is an absolute constant. Then we get that −1/n n |K1|n max |x, wj|dx ≤ C max |x, wj|dx | | wj ∈Fj | | wj ∈Fj K1 n K1 K1 n K1 ≤ C1L log |Fj | max |wj| ∈F wj j C p m2jp 3R ≤ C L 2 √ 1 2 − p Rp 2j CC Lm 2j(p−1) ≤ 1 . (2 − p)p/2 Rp−1 Taking into account (2.12) and (2.13) we have ⎛ ⎞ m R √ CC m N 2j(p−1) L λ ≤ Cn⎝ n + 1 ⎠ i 2N (2 − p)p/2 Rp−1 i=1 j=1 p−1 R √ CC m 2N ≤ Cn n + 1 . 2N (2 − p)p/2(p − 1) R

We optimize by taking R CC m 1/p = √ 1 , 2N n(2 − p)p/2 and hence the claim holds.

Acknowledgment The author is very indebted to Bo’az Klartag for permitting the inclusion of this version and proof of part i) of the theorem, which very much improved an earlier version.

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Departamento de Matematicas,´ Facultad de Ciencias, Universidad de Zaragoza, 50009 Zaragoza, Spain E-mail address: [email protected]

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