Notes on Multi-Layer Impedance
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EUROPEAN ORGANIZATION FOR NUCLEAR RESEARCH CERN-AB-2003-093 (ABP) The Impedance of Multi-layer Vacuum Chambers Luc Vos Summary Many components of the LHC vacuum chamber have multi-layered walls : the copper coated cold beam screen, the titanium coated ceramic chamber of the dump kickers, the ceramic chamber of the injection kickers coated with copper stripes, only to name a few. Theories and computer programs are available for some time already to evaluate the impedance of these elements. Nevertheless, the algorithm developed in this paper is more convenient in its application and has been used extensively in the design phase of multi-layer LHC vacuum chamber elements. It is based on classical transmission line theory. Closed expressions are derived for simple layer configurations, while beam pipes involving many layers demand a chain calculation. The algorithm has been tested with a number of published examples and was verified with experimental data as well. Geneva, Switzerland October , 2003 1 Introduction For the LHC it has been necessary to compute the impedance of mult-layered vacuum chambers since a major part of the beam pipe belongs to this family : the copper coated cold beam screen, the titanium coated ceramic chamber of the dump kickers, the ceramic chamber of the injection kickers coated with copper stripes, the copper coated µ-metal pipes of the septum magnets, the copper coated ceramic TDI injection collimators, the copper coated cold-warm transition pieces, the copper coated carbon collimators, the NEG coated warm vacuum pipes. The impedance of multi-layer vacuum chamber walls can be found by solving Maxwell’s equations taking into account the proper boundary conditions. The task is tedious and has been done before[1]. A physically transparent alternative exists which is easy to understand and simple to implement. The basic idea is as follows. A particle beam moving with velocity βc, is accompanied by transverse electric and magnetic fields. In free space these fields tend to infinity while they are simply cut by a perfectly conducting vacuum chamber. Both cases are identical from the point of view of the beam. The situation changes drastically when the vacuum chamber is no longer perfectly conducting or has other propagation properties than those of free space. Fields penetrate the inner surface of the vacuum chamber material. The tangential magnetic field is continuous across the inner boundary. The penetrating magnetic field generates a surface current density which requires a longitudinal electric field in the face of a non-zero surface impedance. This field pair (tangential magnetic field and longitudinal electric field) forms a transverse wave in the vacuum chamber material. The problem at hand consists in finding the longitudinal electric field. The transverse wave is launched in a sequence of layers with different but known characteristics. The situation is essentially that of a transmission line comprising different sections, each with a different but known intrinsic impedance and propagation constant. Hence, the input impedance of this structure, which is the longitudinal impedance, can be found in a straightforward manner. The theory of transmission lines implicitly takes into account Maxwell’s equations with the proper boundary conditions. 2 Basic transmission line parameters [2] Each material can be characterised electro-magnetically by three parameters. They are the electric conductivity σm, the permeability µm and the dielectric constant εm. Both µm and εm can be complex. The intrinsic impedance of the material m is : jωµ m Zm = . (1) jωε m +σ m The other parameters that are required are the propagation constants. Zotter specifies without proof the radial propagation constant [3, page 158] ,[6]: 2 2 ω γ Tm = + jωµ m (σ m + jωε m ). (2) βc The derivation of this quantity goes as follows. Consider a beam travelling in vacuum with a speed βc parallel to a material boundary. The intrinsic propagation constants in vacuum and in the material are known quantities : γ0 and γm. In the most general case one can write the transverse propagation constants as : 2 γ 2 = γ 2 − h 2 T 0 s , (3) 2 2 2 γ Tm = γ m −hsm where γT is the transverse propagation constant and hs the longitudinal propagation constant. From the continuity of the magnetic field across the boundary it follows that hs = hsm. Moreover, there is no transverse propagation in the vacuum such that γT = 0 and γ0 = hs = hsm. Hence: 2 j 2 2 2 ω γ Tm = γ m −γ 0 = jωµ m (σ m + jωεm )− . (4) βc 3 Setting-up the transmission line relations Consider a set of parallel layers numbered n = 1, 2 ... from the first vacuum-material boundary onwards. Each set is characterised by its intrinsic impedance Zn, valid for a unit area, and its transverse propagation constant γTn = γn (drop subscript T since only transverse waves are dealt with from this moment onwards) and its length or thickness. The last layer, which can be of any nature (vacuum, conductor, insulator) has infinite length. No reflections occur in this part of the transmission line, hence it loads the previous section with its characteristic impedance. This allows the computation in a piecewise fashion of the input impedance and transfer impedance of each preceding line section. The input impedance of the first section (inverse order, last in computation!) is simply the surface impedance experienced by the beam. The classical formulae for the transfer and input impedances are : Ztn = Zin+1 cosh(γ nsn )+ Zn sinh(γ nsn ) Ztn , (5) Zin = Zn Zn cosh()γ nsn + Zin+1 sinh()γ nsn where Zin, Ztn are the input and transfer impedances of section n and Zin+1, Ztn+1 are the input and transfer impedances of section n+1. The length of section n is sn. The penetration of the electro-magnetic fields through the different layers is defined by the transfer impedances and the input impedances as will be shown below. Consider a flat beam travelling through vacuum between two planar perfect conductors. The electro-magnetic fields travel with a speed βc, no reflections occur. Interrupt the perfect conductors and insert a piece of material with known electro-magnetic and geometric properties and which length is unity. The primary fields that accompany the beam are not altered, namely the tangential magnetic field. Its interaction with the input impedance of the insertion generates a longitudinal electric field. The input impedance is the longitudinal impedance of the vacuum chamber insert. The equivalent transmission line diagram for three consecutive layers is shown in Fig 1. The last layer is always infinitely thick, in this case layer three, and serves as load impedance of the previous section. Since we work with fields, impedances are surface impedances. The magnetic field at the entry of the first transmission line section is given by Ampere’s law : Hi = Hi1 = Jb , (6) 3 where Jb is the planar beam current density . transverse transmission lines Hi1 Z1, γ1, Z2, γ2, Ei1 Z3 Figure 1 : Equivalent transmission line circuit of a vacuum chamber consisting of three layers. The transverse wave will be partially reflected and transmitted at each transmission line junction except at the last one since it is infinitely long. The effect of the partial reflections and transmissions is duly taken into account in the formulae of the input and transfer impedances (Eq.5). The computation proceeds backwards and yields the input impedance Zi1. When needed, the penetration of the magnetic field through the various layers can be found with the transfer impedances Ztn. Indeed, Ei1 Hi1 = , Zi1 Ei1 Zi1 Hi2 = = Hi1 , (7) Zt1 Zt 1 Zi1 Zi 2 Hi3 = Hi1 . Zt1 Zt 2 4 Cylindrical geometry versus planar geometry The input magnetic field in cylindrical geometry is given by : i H = b , (8) i1 2πb where ib is beam intensity and b the radius of the pipe. The beam is located in the center. In free space the magnetic field decreases as r-1, where r is the increasing distance from the beam. Consider two consecutive layers. If the area of the first is unity,then the area of the second is unity increased by ∆1/b, ∆1 being the thickness (length of equivalent transmission line) of the first layer. The increased cross-section of the second layer increases in a similar way the inductance, the capacitance and the conductivity. Hence the characteristic impedance is not changed and the transmission constant increases with ∆1/b. For subsequent layers the transmission constant increases by ∆2/(b+∆1), etc. Obviously, this effect is only 4 significant when ∆1/b is not too small. In practice it turns out that the simple planar geometry is a good approximation for most cylindrical cases. 5 Special cases A few cases with a small number of layers lead to relatively simple closed formulae. 5.1 A single metallic layer with infinite thickness The input impedance is the intrinsic impedance of the metal : jωρ Z1 = Z0 ≈ jωµρ , (9) jωρ + Z 0c where Z0 is the impedance of free space and ρ =1/σ. Eq. 9 is the classical skin depth formula. The approximation is valid for radian frequencies ω c << Z0 ρ . 5.2 A single metallic layer with finite thickness The impedance of the outer layer is Z0. The metal layer has resistivity ρ, thickness s1, and the usual free space value for permeability µ and dielectric constant ε. The intrinsic impedance and the propagation constant are for β = 1: jωρ Z1 = Z0 jωρ + Z 0c . (10) jωµ γ = 1 ρ This yields the following surface impedance : jωρ jωµ 1+ tanh s1 jωρ + Z0c ρ Z = Z . (11) i1 0 jωρ + Z c 0 jωµ 1+ tanh s1 jωρ ρ For ω = 0 the impedance is real and corresponds to a parallel circuit formed by the impedance of vacuum (Z0) and the surface impedance of the metal wall ρ/s1.