The Limit Point of the Pentagram Map and Infinitesimal Monodromy,” International Mathematics Research Notices, Vol
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Limits Involving Infinity (Horizontal and Vertical Asymptotes Revisited)
Limits Involving Infinity (Horizontal and Vertical Asymptotes Revisited) Limits as ‘ x ’ Approaches Infinity At times you’ll need to know the behavior of a function or an expression as the inputs get increasingly larger … larger in the positive and negative directions. We can evaluate this using the limit limf ( x ) and limf ( x ) . x→ ∞ x→ −∞ Obviously, you cannot use direct substitution when it comes to these limits. Infinity is not a number, but a way of denoting how the inputs for a function can grow without any bound. You see limits for x approaching infinity used a lot with fractional functions. 1 Ex) Evaluate lim using a graph. x→ ∞ x A more general version of this limit which will help us out in the long run is this … GENERALIZATION For any expression (or function) in the form CONSTANT , this limit is always true POWER OF X CONSTANT lim = x→ ∞ xn HOW TO EVALUATE A LIMIT AT INFINITY FOR A RATIONAL FUNCTION Step 1: Take the highest power of x in the function’s denominator and divide each term of the fraction by this x power. Step 2: Apply the limit to each term in both numerator and denominator and remember: n limC / x = 0 and lim C= C where ‘C’ is a constant. x→ ∞ x→ ∞ Step 3: Carefully analyze the results to see if the answer is either a finite number or ‘ ∞ ’ or ‘ − ∞ ’ 6x − 3 Ex) Evaluate the limit lim . x→ ∞ 5+ 2 x 3− 2x − 5 x 2 Ex) Evaluate the limit lim . x→ ∞ 2x + 7 5x+ 2 x −2 Ex) Evaluate the limit lim . -
Section 8.8: Improper Integrals
Section 8.8: Improper Integrals One of the main applications of integrals is to compute the areas under curves, as you know. A geometric question. But there are some geometric questions which we do not yet know how to do by calculus, even though they appear to have the same form. Consider the curve y = 1=x2. We can ask, what is the area of the region under the curve and right of the line x = 1? We have no reason to believe this area is finite, but let's ask. Now no integral will compute this{we have to integrate over a bounded interval. Nonetheless, we don't want to throw up our hands. So note that b 2 b Z (1=x )dx = ( 1=x) 1 = 1 1=b: 1 − j − In other words, as b gets larger and larger, the area under the curve and above [1; b] gets larger and larger; but note that it gets closer and closer to 1. Thus, our intuition tells us that the area of the region we're interested in is exactly 1. More formally: lim 1 1=b = 1: b − !1 We can rewrite that as b 2 lim Z (1=x )dx: b !1 1 Indeed, in general, if we want to compute the area under y = f(x) and right of the line x = a, we are computing b lim Z f(x)dx: b !1 a ASK: Does this limit always exist? Give some situations where it does not exist. They'll give something that blows up. -
13 Limits and the Foundations of Calculus
13 Limits and the Foundations of Calculus We have· developed some of the basic theorems in calculus without reference to limits. However limits are very important in mathematics and cannot be ignored. They are crucial for topics such as infmite series, improper integrals, and multi variable calculus. In this last section we shall prove that our approach to calculus is equivalent to the usual approach via limits. (The going will be easier if you review the basic properties of limits from your standard calculus text, but we shall neither prove nor use the limit theorems.) Limits and Continuity Let {be a function defined on some open interval containing xo, except possibly at Xo itself, and let 1 be a real number. There are two defmitions of the· state ment lim{(x) = 1 x-+xo Condition 1 1. Given any number CI < l, there is an interval (al> b l ) containing Xo such that CI <{(x) ifal <x < b i and x ;6xo. 2. Given any number Cz > I, there is an interval (a2, b2) containing Xo such that Cz > [(x) ifa2 <x< b 2 and x :;Cxo. Condition 2 Given any positive number €, there is a positive number 0 such that If(x) -11 < € whenever Ix - x 0 I< 5 and x ;6 x o. Depending upon circumstances, one or the other of these conditions may be easier to use. The following theorem shows that they are interchangeable, so either one can be used as the defmition oflim {(x) = l. X--->Xo 180 LIMITS AND CONTINUITY 181 Theorem 1 For any given f. -
Two Fundamental Theorems About the Definite Integral
Two Fundamental Theorems about the Definite Integral These lecture notes develop the theorem Stewart calls The Fundamental Theorem of Calculus in section 5.3. The approach I use is slightly different than that used by Stewart, but is based on the same fundamental ideas. 1 The definite integral Recall that the expression b f(x) dx ∫a is called the definite integral of f(x) over the interval [a,b] and stands for the area underneath the curve y = f(x) over the interval [a,b] (with the understanding that areas above the x-axis are considered positive and the areas beneath the axis are considered negative). In today's lecture I am going to prove an important connection between the definite integral and the derivative and use that connection to compute the definite integral. The result that I am eventually going to prove sits at the end of a chain of earlier definitions and intermediate results. 2 Some important facts about continuous functions The first intermediate result we are going to have to prove along the way depends on some definitions and theorems concerning continuous functions. Here are those definitions and theorems. The definition of continuity A function f(x) is continuous at a point x = a if the following hold 1. f(a) exists 2. lim f(x) exists xœa 3. lim f(x) = f(a) xœa 1 A function f(x) is continuous in an interval [a,b] if it is continuous at every point in that interval. The extreme value theorem Let f(x) be a continuous function in an interval [a,b]. -
Calculus Terminology
AP Calculus BC Calculus Terminology Absolute Convergence Asymptote Continued Sum Absolute Maximum Average Rate of Change Continuous Function Absolute Minimum Average Value of a Function Continuously Differentiable Function Absolutely Convergent Axis of Rotation Converge Acceleration Boundary Value Problem Converge Absolutely Alternating Series Bounded Function Converge Conditionally Alternating Series Remainder Bounded Sequence Convergence Tests Alternating Series Test Bounds of Integration Convergent Sequence Analytic Methods Calculus Convergent Series Annulus Cartesian Form Critical Number Antiderivative of a Function Cavalieri’s Principle Critical Point Approximation by Differentials Center of Mass Formula Critical Value Arc Length of a Curve Centroid Curly d Area below a Curve Chain Rule Curve Area between Curves Comparison Test Curve Sketching Area of an Ellipse Concave Cusp Area of a Parabolic Segment Concave Down Cylindrical Shell Method Area under a Curve Concave Up Decreasing Function Area Using Parametric Equations Conditional Convergence Definite Integral Area Using Polar Coordinates Constant Term Definite Integral Rules Degenerate Divergent Series Function Operations Del Operator e Fundamental Theorem of Calculus Deleted Neighborhood Ellipsoid GLB Derivative End Behavior Global Maximum Derivative of a Power Series Essential Discontinuity Global Minimum Derivative Rules Explicit Differentiation Golden Spiral Difference Quotient Explicit Function Graphic Methods Differentiable Exponential Decay Greatest Lower Bound Differential -
On Generalizations of the Pentagram Map: Discretizations of Agd Flows
ON GENERALIZATIONS OF THE PENTAGRAM MAP: DISCRETIZATIONS OF AGD FLOWS GLORIA MAR´I BEFFA Abstract. In this paper we investigate discretizations of AGD flows whose projective realizations are defined by intersecting different types of subspaces m in RP . These maps are natural candidates to generalize the pentagram map, itself defined as the intersection of consecutive shortest diagonals of a convex polygon, and a completely integrable discretization of the Boussinesq equation. We conjecture that the r-AGD flow in m dimensions can be discretized using one (r − 1)-dimensional subspace and r − 1 different (m − 1)-dimensional m subspaces of RP . 1. Introduction The pentagram map is defined on planar, convex N-gons, a space we will denote by CN . The map T takes a vertex xn to the intersection of two segments: one is created by joining the vertices to the right and to the left of the original one, xn−1xn+1, the second one by joining the original vertex to the second vertex to its right xnxn+2 (see Fig. 1). These newly found vertices form a new N-gon. The pentagram map takes the first N-gon to this newly formed one. As surprisingly simple as this map is, it has an astonishingly large number of properties, see [16, 17, 18], [19], [14] for a thorough description. The name pentagram map comes from the following classical fact: if P 2 C5 is a pentagon, then T (P ) is projectively equivalent to P . Other relations seem to be 2 also classical: if P 2 C6 is a hexagon, then T (P ) is also projectively equivalent to P . -
Notes Chapter 4(Integration) Definition of an Antiderivative
1 Notes Chapter 4(Integration) Definition of an Antiderivative: A function F is an antiderivative of f on an interval I if for all x in I. Representation of Antiderivatives: If F is an antiderivative of f on an interval I, then G is an antiderivative of f on the interval I if and only if G is of the form G(x) = F(x) + C, for all x in I where C is a constant. Sigma Notation: The sum of n terms a1,a2,a3,…,an is written as where I is the index of summation, ai is the ith term of the sum, and the upper and lower bounds of summation are n and 1. Summation Formulas: 1. 2. 3. 4. Limits of the Lower and Upper Sums: Let f be continuous and nonnegative on the interval [a,b]. The limits as n of both the lower and upper sums exist and are equal to each other. That is, where are the minimum and maximum values of f on the subinterval. Definition of the Area of a Region in the Plane: Let f be continuous and nonnegative on the interval [a,b]. The area if a region bounded by the graph of f, the x-axis and the vertical lines x=a and x=b is Area = where . Definition of a Riemann Sum: Let f be defined on the closed interval [a,b], and let be a partition of [a,b] given by a =x0<x1<x2<…<xn-1<xn=b where xi is the width of the ith subinterval. -
Calculus Formulas and Theorems
Formulas and Theorems for Reference I. Tbigonometric Formulas l. sin2d+c,cis2d:1 sec2d l*cot20:<:sc:20 +.I sin(-d) : -sitt0 t,rs(-//) = t r1sl/ : -tallH 7. sin(A* B) :sitrAcosB*silBcosA 8. : siri A cos B - siu B <:os,;l 9. cos(A+ B) - cos,4cos B - siuA siriB 10. cos(A- B) : cosA cosB + silrA sirrB 11. 2 sirrd t:osd 12. <'os20- coS2(i - siu20 : 2<'os2o - I - 1 - 2sin20 I 13. tan d : <.rft0 (:ost/ I 14. <:ol0 : sirrd tattH 1 15. (:OS I/ 1 16. cscd - ri" 6i /F tl r(. cos[I ^ -el : sitt d \l 18. -01 : COSA 215 216 Formulas and Theorems II. Differentiation Formulas !(r") - trr:"-1 Q,:I' ]tra-fg'+gf' gJ'-,f g' - * (i) ,l' ,I - (tt(.r))9'(.,') ,i;.[tyt.rt) l'' d, \ (sttt rrJ .* ('oqI' .7, tJ, \ . ./ stll lr dr. l('os J { 1a,,,t,:r) - .,' o.t "11'2 1(<,ot.r') - (,.(,2.r' Q:T rl , (sc'c:.r'J: sPl'.r tall 11 ,7, d, - (<:s<t.r,; - (ls(].]'(rot;.r fr("'),t -.'' ,1 - fr(u") o,'ltrc ,l ,, 1 ' tlll ri - (l.t' .f d,^ --: I -iAl'CSllLl'l t!.r' J1 - rz 1(Arcsi' r) : oT Il12 Formulas and Theorems 2I7 III. Integration Formulas 1. ,f "or:artC 2. [\0,-trrlrl *(' .t "r 3. [,' ,t.,: r^x| (' ,I 4. In' a,,: lL , ,' .l 111Q 5. In., a.r: .rhr.r' .r r (' ,l f 6. sirr.r d.r' - ( os.r'-t C ./ 7. /.,,.r' dr : sitr.i'| (' .t 8. tl:r:hr sec,rl+ C or ln Jccrsrl+ C ,f'r^rr f 9. -
Math 220 GW 7 SOLUTIONS 1. Using the Limit Definition of Derivative, Find the Derivative Function, F (X), of the Following Funct
Math 220 GW 7 SOLUTIONS 1. Using the limit definition of derivative, find the derivative function, f 0(x), of the following functions. Show all your beautiful algebra. (a) f(x) = 2x f(x + h) − f(x) 2(x + h) − 2x lim = lim h!0 h h!0 h 2x + 2h − 2x = lim h!0 h 2h = lim h!0 h 2: (b) f(x) = −x2 + 2x f(x + h) − f(x) −(x + h)2 + 2(x + h) + x2 − 2x lim = lim h!0 h h!0 h −x2 − 2xh − h2 + 2x + 2h + x2 − 2x = lim h!0 h −2xh − h2 + 2h = lim h!0 h = lim(−2x − h + 2) h!0 = −2x + 2: 1 2. You are told f(x) = 2x3 − 4x, and f 0(x) = 6x2 − 4. Find f 0(3) and f 0(−1) and explain, in words, how to interpret these numbers. f 0(3) = 6(3)2 − 4 = 50: f 0(1) = 6(1)2 − 4 = 2: These are the slopes of f(x) at x = 3 and x = 1. Both are positive, thus f is increasing at those points. Also, 50 > 2, so f is increasing faster at x = 3 than at x = 1. Example Find the derivative of f(x) = 3=x2. f(x + h) − f(x) f 0(x) = lim h!0 h 3 3 2 − 2 = lim (x+h) x h!0 h x2 3 3 (x+h)2 2 ∗ 2 − 2 ∗ 2 = lim x (x+h) x (x+h) h!0 h 3x2−3(x+h)2 2 2 = lim x (x+h) h!0 h 1 3x2 − 3(x + h)2 1 = lim ∗ h!0 x2(x + h)2 h 3x2 − 3(x2 + 2xh + h2) = lim h!0 hx2(x + h)2 3x2 − 3x2 − 6xh + h2 = lim h!0 hx2(x + h)2 h(−6x + h) = lim h!0 hx2(x + h)2 h −6x + h = lim ∗ h!0 h x2(x + h)2 −6x + h = lim h!0 x2(x + h)2 −6x + 0 = x2(x + 0)2 −6x = x4 −6 = x3 3. -
Pentagram Map, Twenty Years After
Pentagram map, twenty years after Stony Brook, March 2014 1 Part 1. A survey of older results Pentagram Map of Richard Schwartz: P P T(P) T(P) A good reference (among many others): http://en.wikipedia. org/wiki/Pentagram_map 2 Example: if n=5 then T (P ) = P . (t1−t2)(t3−t4) Cross-ratio: [t1; t2; t3; t4] = : (t1−t3)(t2−t4) A D’ C’ B E A’ D C Exercise: if n = 6 then T 2(P ) = P . Let's watch an animation 3 Relevant moduli spaces: Cn, space of projective equivalence classes of closed n-gons in RP2 ; dim = 2n − 8; Pn, space of projective equivalence classes of twisted n-gons in RP2; dim = 2n: φ : Z ! RP2 s:t: φ(k + n) = M ◦ φ(k); 8k: M is the monodromy. 4 Theorem (OST 2010) The Pentagram Map is completely inte- grable on the space of twisted n-gons Pn: 1). There are 2[n=2] + 2 algebraically independent integrals; 2). There is an invariant Poisson structure of corank 2 if n is odd, and corank 4 if n is even, such that the integrals Poisson commute. In both cases, dim Pn − corank = 2(number of integrals − corank). 5 Arnold-Liouville integrability (Poisson set-up) Let Mp+2q have independent Poisson commuting `integrals' f1; : : : ; fp; fp+1; : : : ; fp+q where f1; : : : ; fp are Casimirs. One has the symplectic foliation given by f1 = const; f2 = const; : : : ; fp = const; and the Lagrangian subfoliation Fq given by fp+1 = const; fp+2 = const; : : : ; fp+q = const: The leaves carry a flat structure given by the commuting fields H ;:::;H : fp+1 fp+q If a (discrete or continuous time) dynamical system on M pre- serves all this, then the motion on the leaves is a parallel trans- lation. -
Dynamics of the Pentagram Map Supervised by Dr
Introduction Ergodicity Parametrization Unifying the Maps Conclusion Dynamics of the Pentagram Map Supervised by Dr. Xingping Sun H. Dinkins, E. Pavlechko, K. Williams Missouri State University July 28th, 2016 H. Dinkins, E. Pavlechko, K. Williams MSU The Pentagram Map July 28th, 2016 1 / 45 Finite Fourier Transforms Coefficients of ergodicity Elementary geometry Introduction Ergodicity Parametrization Unifying the Maps Conclusion Review Midpoint Iteration Problem of midpoint iterations FIGURE – Basic midpoint iteration on a heptagon H. Dinkins, E. Pavlechko, K. Williams MSU The Pentagram Map July 28th, 2016 2 / 45 Coefficients of ergodicity Elementary geometry Introduction Ergodicity Parametrization Unifying the Maps Conclusion Review Midpoint Iteration Problem of midpoint iterations Finite Fourier Transforms FIGURE – Basic midpoint iteration on a heptagon H. Dinkins, E. Pavlechko, K. Williams MSU The Pentagram Map July 28th, 2016 2 / 45 Elementary geometry Introduction Ergodicity Parametrization Unifying the Maps Conclusion Review Midpoint Iteration Problem of midpoint iterations Finite Fourier Transforms Coefficients of ergodicity FIGURE – Basic midpoint iteration on a heptagon H. Dinkins, E. Pavlechko, K. Williams MSU The Pentagram Map July 28th, 2016 2 / 45 Introduction Ergodicity Parametrization Unifying the Maps Conclusion Review Midpoint Iteration Problem of midpoint iterations Finite Fourier Transforms Coefficients of ergodicity Elementary geometry FIGURE – Basic midpoint iteration on a heptagon H. Dinkins, E. Pavlechko, K. Williams -
Math Handbook of Formulas, Processes and Tricks Calculus
Math Handbook of Formulas, Processes and Tricks (www.mathguy.us) Calculus Prepared by: Earl L. Whitney, FSA, MAAA Version 4.9 February 24, 2021 Copyright 2008‐21, Earl Whitney, Reno NV. All Rights Reserved Note to Students This Calculus Handbook was developed primarily through work with a number of AP Calculus classes, so it contains what most students need to prepare for the AP Calculus Exam (AB or BC) or a first‐year college Calculus course. In addition, a number of more advanced topics have been added to the handbook to whet the student’s appetite for higher level study. It is important to note that some of the tips and tricks noted in this handbook, while generating valid solutions, may not be acceptable to the College Board or to the student’s instructor. The student should always check with their instructor to determine if a particular technique that they find useful is acceptable. Why Make this Handbook? One of my main purposes for writing this handbook is to encourage the student to wonder, to ask “what about … ?” or “what if … ?” I find that students are so busy today that they don’t have the time, or don’t take the time, to find the beauty and majesty that exists within Mathematics. And, it is there, just below the surface. So be curious and seek it out. The answers to all of the questions below are inside this handbook, but are seldom taught. What is oscillating behavior and how does it affect a limit? Is there a generalized rule for the derivative of a product of multiple functions? What’s the partial derivative shortcut to implicit differentiation? What are the hyperbolic functions and how do they relate to the trigonometric functions? When can I simplify a difficult definite integral by breaking it into its even and odd components? What is Vector Calculus? Additionally, ask yourself: Why … ? Always ask “why?” Can I come up with a simpler method of doing things than I am being taught? What problems can I come up with to stump my friends? Those who approach math in this manner will be tomorrow’s leaders.