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Marquette University e-Publications@Marquette Mathematics, Statistics and Computer Science Mathematics, Statistics and Computer Science, Faculty Research and Publications Department of
6-1-2015 Free Split Bands Francis Pastijn Marquette University, [email protected]
Justin Albert Marquette University, [email protected]
Accepted version. Semigroup Forum, Vol. 90, No. 3 (June 2015): 753-762. DOI. Β© 2015 Springer International Publishing AG. Part of Springer Nature. Used with permission. Shareable Link. Provided by the Springer Nature SharedIt content-sharing initiative. NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
Free Split Bands
Francis Pastijn Department of Mathematics, Statistics and Computer Science, Marquette University, Milwaukee, WI Justin Albert Department of Mathematics, Statistics and Computer Science, Marquette University, Milwaukee, WI
Abstract: We solve the word problem for the free objects in the variety consisting of bands with a semilattice transversal. It follows that every free band can be embedded into a band with a semilattice transversal.
Keywords: Free band, Split band, Semilattice transversal 1 Introduction
We refer to3 and6 for a general background and as references to terminology used in this paper.
Recall that a band is a semigroup where every element is an idempotent. The Green relation is the least semilattice congruence on a band, and so every band is a semilattice of its -classes; the -classes themselves form rectangular bands.5 We shall be interested in bandsππ S for which the least semilattice congruence splits, that is, there exists a subsemilatticeππ of ππ which intersects each -class in exactly one element. Such a subsemilattice β of will then be called a semilatticeππ transversal of . ππβ ππ ππ ππ ππ ππ Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 1
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
If the band has a semilattice transversal , then we can associate to every the unique which is -related to a. The unary βoperation , is an idempotent - class preservingβ β endomorpππ hism of which inducesππ the -relation on , and inβ particular,ππ β ππ is a ππ β ππ ππ ππ β¦ ππ ππ β¦ ππ ππ retract of . The unary band (( , , )) thus obtained obviously satisfies, apart from the associativeβ law, the identities βππ ππ ππ ππ ππ ππ β , , ,
( ) 2 β , (β )β β . π₯π₯ β π₯π₯ π₯π₯π₯π₯ π₯π₯ β π₯π₯ π₯π₯ π₯π₯π₯π₯ β π₯π₯ (1) β β β β β β β β π₯π₯π₯π₯ β π₯π₯ π¦π¦ β π¦π¦ π₯π₯ π₯π₯ β π₯π₯ One readily verifies that the last identity ( ) follows in fact from the previous ones. It is not difficult to see that if a unary band (( , , )β) satisfiesβ β the identities (1), then = π₯π₯ β π₯π₯ { | } is a semilattice transversal of the bandβ ( , ). For this reason we call the unaryβ bands whichβ satisfy the identities (1) split bands. ππ β ππ ππ ππ β ππ ππ β The variety of bands will be denoted by and the variety of all split bands will be denoted . For a nonempty set , ( ) and ( ) denote the free objects on in ππ and , respectively.β As the abstract indicates, theβ purpose of this paper is to solve the ππ ππ πΉπΉππ ππ πΉπΉππ ππ ππ ππ word problemβ for ( ) and to show that FB(X) can be isomorphically embedded into ππ the multiplicative reductβ of ( ). The solution of the word problem for ( ) is well πΉπΉππ ππ understood and the reader willβ find all the necessary details in Sect 4.5 of3 where ππ ππ appropriate references to1 andπΉπΉ 2 areππ given. Our solution to the word problemπΉπΉ forππ ( ) is similar though slightly more complicated. While is, like , locally finite, for any finiteβ ππ nonempty set the (finite) free object ( ) is muchβ larger than ( ). πΉπΉ ππ β ππ ππ ππ ππ There isππ something more enigmaticπΉπΉ aboutππ all this. It turns outπΉπΉ thatππ if a band has a semilattice transversal then the union of all the -classes [ -classes] in S of the elements of is a left [right]β regular band which is a transversal of the -classes [ππ - classes] of . Thisβ followsππ from a very special applicationβ of Propositionβ 2.3 and Corollary 2.4ππ of8 and below we intend to give a short independent proof βof this fact βin the special circumstancesππ we consider here.
Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 2
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
Result 1.1
Let ( , , ) be a split band with semilattice transversal = { | }. Then = { | } isβ a left [right] regular subband of ( , ) with semilatticeβ transversalβ , and ππ isβ a transversalππ β of the -classes [ -classes] of ( , ). ππ ππ ππ β ππ β πΌπΌ ππππ ππ β ππ ππ β ππ ππ PΞroof β β ππ β
Clearly, for any , the intersection of and the -class of is the the -class of and intersects the -class of in the unique element . It suffices to prove that isβ ππ β ππ πΌπΌππ ππ π·π·ππ ππ β πΏπΏππ a subβsemigroup of , or in particular, that for any , we have thatβ ( )( ) ( ) . In ππ πΌπΌππ β π π ππ ππ ππππ πΌπΌππ any case = = ( ) is -related to ( )( ) in and sinceβ this β-class is aβ ππ ππ ππ β ππ ππππ ππππ β ππππ rectangularβ bandβ it followsβ β that (β )( ) ( β )( β ). Applying the identities (1) we find that ππ ππ ππ ππ ππππ β ππβ β β ππππ βππππ β ππ ππ ππ ππ ππππ ππππ β ππππ ππππ ( )( ) = ( ) β β β β = β β β β
ππ ππ ππππ ππππ = ππβ ππβ ππππβ ππππ = ππβππβππ=ππβ( ) . ππβππβππππ β Thus ( )( ) ( ) as required. ππ ππ ππππ β β β ππTheππ ππ andππ β ππ mentionedππ in Resultβ‘ 1.1 may well serve as a means to coordinatize and one would expect that such a coordinatization would set the stage for a structure ππ ππ theorem of πΌπΌsplit bandsΞ in terms of the left and right regular bands and akin to, but ππ simpler than the construction in II.1 of.6 For a free split band = ( ), it is easy to πΌπΌππ Ξππ characterize the elements of the left [right] regular split band (seeβ Corollary 2.2 and ππ Theorem 2.5). By left-right duality, is anti-isomorphic to πΉπΉ. πΉπΉ ππ ΞπΉπΉ πΉπΉ πΉπΉ The variety of rightπΌπΌ [left] regular split bandsΞ is the subvariety of determined by the additionalβ identityβ . Thus, with the notation ofβ ππππππ ππππππ ππ Result 1.1, and belong to and , respectively. As we shall see, if = π₯π₯π₯π₯π₯π₯ β π¦π¦π¦π¦ π₯π₯π₯π₯π₯π₯ β π₯π₯π₯π₯ ( ) is a free split band, then andβ shouldβ not be assumed to be free on in πΌπΌππ Ξππ ππππππ ππππππ πΉπΉ andβ , respectively. β ππ ππ ππ πΉπΉ ππ β πΌπΌ Ξ ππ ππππππ ππππItππ is time to put our paper in the context of current research. The adequate terminology split band is not of our invention but already occurs in4 where the authors give
Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 3
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
a structure theorem for orthodox semigroups for which the least inverse semigroup congruence splits. Theorem 2 of9 gives a structure theorem for the members of in the manner of Theorem II.1.6 of.6 Combining this result of Yoshida with its dual and withβ Theorem 2 of,7 one obtains a structure theorem for the members of . We would,ππππ ππ however, like to draw the readerβs attention to the all encompassing paperβ 8 which has already been mentioned above, and which in its Example 2.15 introducesππ a variety of unary semigroups (whose members are all regular semigroups) which contains as a subvariety. β ππ 2 Free split bands
In this section we give a solution of the word problem for the free object ( ) in the variety on a nonempty set of variables. β ππ β πΉπΉ ππ We letππ be a set disjoint of ππ and , , a bijection. The elements of will be called lettersβ . The identity of the free monoidβ ( β ) is the empty word 1, thus ( β ππ ππ ππ β¦ ππ π₯π₯ β¦ π₯π₯ ππ βͺ ππ ) = ( ) {1}. For any ( ) we defineβ β the content ( ) of inductivelyβ β by β + β βππ βͺ ππ ππ βͺ ππ ππ βͺ ππ βͺ π€π€ β ππ βͺ ππ ππ π€π€ π€π€ (1) = , ( ) = ( ) = { }, ,
( ππ ) = β ( β ) ( ), ππ π₯π₯ >ππ 1π₯π₯, , β¦π₯π₯, π₯π₯ β ππ. 1 ππβ1 ππ 1 ππβ1 ππ ππ π¦π¦ β― π¦π¦ π¦π¦ ππ π¦π¦ β― π¦π¦ βͺ ππ π¦π¦ β We let be the congruence relation ofππ the freeπ¦π¦ semigroup1 π¦π¦ππ (β ππ βͺ)ππ generated by the pairs β + π½π½ ππ βͺ ππ ( , ), ( ) , ( , 2), ( , ), β + , π€π€( π€π€β , β )π€π€,β ββ ππ, βͺ ππ . π₯π₯ π₯π₯π₯π₯ π₯π₯ π₯π₯ π₯π₯ π₯π₯π₯π₯ π₯π₯ β ππ (2) β β β β π₯π₯ π¦π¦ π¦π¦ π₯π₯ π₯π₯ π¦π¦ β ππ One readily verifies that ( )/ is a band generated by the elements of the form or , and Greenβs -relation on this bandβ is given by β ππ βͺ ππ π½π½ π₯π₯π₯π₯ π₯π₯ π½π½ ππ ( ) = ( ).
(3) Semigroup forum, Vol. 90, No. 3 (June 2015): pg.π£π£π£π£ 753ππ-762π€π€. DOIπ€π€. Thisβ articleππ isπ£π£ Β© Springerππ andπ€π€ permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 4
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
Also, the element of the form ( β¦ ) , 1, , β¦ , , constitute a subsemilattice which intersects every β-classβ exactly once. Given ( ) with content π₯π₯1 π₯π₯ππ π½π½ ππ β₯ π₯π₯1 π₯π₯ππ β ππ ( ) = { , β¦ } we let ( ) be the unique element ( ) of this semilatticeβ + which is ππ π€π€ β ππ βͺ ππ -related to in ( ) / β : the mapping ( β ) yieldsβ an idempotent ππ π€π€ π₯π₯1 π₯π₯ππ π€π€π€π€ π₯π₯1 β― π₯π₯ππ π½π½ endomorphism which inducesβ +the -relation. The unary band thusβ obtained will be denoted by . ππ π€π€π€π€ ππ βͺ ππ π½π½ π€π€π€π€ β π€π€π€π€ For the sake of simplicityππ we drop the notation and we use β=β to denote equalityπΉπΉ in . Thus for , ( ) we write = (in ) instead of . We shall reserve β β for the equality in ( β )+ . We shall denote the π½π½semilattice transversal of consistingπΉπΉ of theπ£π£ π€π€elementsβ ππ βͺ ππβ¦β β , 1, π£π£ , β¦π€π€ πΉπΉ , by . Clearlyπ£π£π£π£π£π£ is a model of β‘ ( ): if : , thenππ forβͺ βππ everyβ and every mapping β : , there existsπΉπΉ a π₯π₯1 π₯π₯ππ ππ β₯ π₯π₯1 π₯π₯ππ β ππ πΉπΉ πΉπΉ (unique)β homomorphism of unary bands β : such that = . If is finite then so is ππ πΉπΉ ππ , andππ ππthereforeβ πΉπΉ is also finite,ππ β sinceππ finitely generated bandsππ ππ βareππ finite. In other ππ ππππ words,β the variety is locally finite. Fromππ thisπΉπΉ β it followsππ that there existsππ an algorithm ππ βͺ ππ πΉπΉ + which decides whetherβ for given , , ( ) we have that = in F. We shall give an algorithm whichππ is transparent enough to beβ useful. The algorithm which we set out to describe is similar to the algorithmπ£π£ π£π£ givenπ€π€ β inππ2βͺ forππ free bands. π£π£ π€π€
We shall need some invariants. In our context, a property of a word which belongs to ( ) is called an invariant if whenever = in and satisfies this property, then so doesβ + . To βhave the same contentβ is such an invariant: recall that for , , ππ βͺ ππ+ π£π£ π€π€ πΉπΉ π£π£ ( ) , ( ) = ( ) if and only if in , or if and only if in . β π€π€ π£π£ π£π£ π€π€ β ππ βͺ ππFor anyππ π£π£ (ππ π€π€ ) we defineπ£π£ π£π£π£π£ πΉπΉ to be the word obtainedπ£π£π£π£π£π£ fromπΉπΉ by deleting first every occurrence of an β β in when precededβ somewhere in by or , and then π€π€ β ππ βͺ ππ π€π€πΏπΏ β ππ π€π€ deleting every occurrence of any . Thus for instance, for , , , β π₯π₯ β ππβ π€π€ β π€π€ π₯π₯ π₯π₯ π¦π¦( β ππ ) 1π₯π₯, π¦π¦ π§π§ β ππ
( β β β β ) . πΏπΏ π₯π₯β π¦π¦ π₯π₯βπ₯π₯βπ§π§ π¦π¦π¦π¦β β‘ The letters of such words π₯π₯ π¦π¦π¦π¦ (if any)π₯π₯ π¦π¦ belongπ§π§π§π§π§π§ to πΏπΏ andβ‘ areπ¦π¦π¦π¦ necessarily distinct. If 1, then the last letter of will be denoted by ( ). We can then uniquely write π€π€πΏπΏ ππ π€π€πΏπΏ β’ ( ) ( ) for some prefix ( ) of where ( ) ( ( )) and some suffix . Here ( ) or π€π€πΏπΏ ππ π€π€ π€π€ β‘ may well be empty. Thus, for instance, ππ π€π€ ππ π€π€ π’π’ ππ π€π€ π€π€ ππ π€π€ β ππ ππ π€π€ π’π’ ππ π€π€ π’π’
Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 5
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
( ) =
( β β β β) = . ππ π₯π₯βπ¦π¦π¦π¦π₯π₯βπ¦π¦βπ§π§π§π§π§π§β π§π§ β β β If = 1, it will beππ convenientπ₯π₯ π¦π¦π¦π¦π₯π₯ π¦π¦to putπ§π§π§π§ π§π§( ) (π₯π₯)π¦π¦π¦π¦1π₯π₯. π¦π¦ πΏπΏ Inπ€π€ a left-right dual way we define, forππ π€π€ β‘( ππ π€π€ β‘) , the word and, whenever 1, the variable ( ) and the suffix ( )β ofβ . Then if 1β, π π ( ) ( ) in ( ) for some prefix .π€π€ If β ππ βͺ1 ππwe put ( ) π€π€ ( β)ππ 1. π π π π π€π€ β’ β β ππ π€π€ ππ π€π€ π€π€ π€π€ β’ π€π€ β‘ π π π£π£Lemmaππ π€π€ ππ 2.1π€π€ ππ βͺ ππ π£π£ π€π€ β‘ ππ π€π€ β‘ ππ π€π€ β‘
For ( ) with ( ) = { , β¦ , }, β + π€π€ β ππ βͺ ππ ππ π€π€ =π₯π₯1 π₯π₯ππ in F if 1,
β β = (β ) (β ) in F otherwise. π€π€ βπ€π€π₯π₯1 β― π₯π₯ππ π₯π₯1 β― π₯π₯ππ π€π€πΏπΏ β‘ ππππππ β β β β Proof π€π€ βπ€π€π₯π₯1 β― π₯π₯ππ ππ π€π€ ππ π€π€ π₯π₯1 β― π₯π₯ππ
If ( ) with ( ) = { , β¦ , }, then or whereβ + and for+ some . β¦ , β¦ , 1 , ππβ¦ ( ) 1 β π€π€ ββ ππ βͺ ππ ππ π€π€ βπ₯π₯ π₯π₯ π₯π₯ β ππ π€π€ β‘ 0 1 1 ππ ππ 0 ππ 1 ππ π€π€ π¦π¦ π€π€Firstπ¦π¦ weπ€π€ assume thatπ€π€ π€π€ 1β. Thenππ canπ¦π¦ beπ¦π¦ writtenβ ππ π€π€as = ππ β₯ , 1, where ( ) = { , β¦ , } such that, for every 1 , we have thatβ ( )β πΏπΏ 1 1 ππ ππ { , β¦ , }. We prove by inductionπ€π€ β‘ that forπ€π€ all 1 we haveπ€π€ thatπ¦π¦ π€π€ =β― π¦π¦ π€π€ ππ β₯ in ππ π€π€ π¦π¦1 π¦π¦ππ β€ ππ β€ ππ ππ π€π€ππ β . This is obviously true for = 1. Suppose that for < we have that β β π¦π¦1 π¦π¦ππ β€ ππ β€ ππ π€π€ π¦π¦1 β― π¦π¦ππ π€π€ πΉπΉ = ππ= ππ ππ . β β β β β β β β β Since π€π€ π¦π¦1 β― π¦π¦ππ π€π€ π¦π¦1 β― π¦π¦ππ π¦π¦1π€π€1π¦π¦2π€π€2 β― π¦π¦ππ π€π€πππ¦π¦ππ+1 β― π¦π¦πππ€π€ππ ( ) = , β¦ , = ( ), β β β β β β it follows that ππ π¦π¦1 β― π¦π¦ππ π¦π¦1π€π€1 β― π¦π¦ππ π€π€ππ π¦π¦1 π¦π¦ππ ππ π¦π¦1 β― π¦π¦ππ
β β β β β β in . Therefore π¦π¦1 β― π¦π¦ππ βπ¦π¦1 β― π¦π¦ππ π¦π¦1π€π€1 β― π¦π¦ππ π€π€ππ πΉπΉ Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 6
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
=
β β β β β = β β β β β β , 1 ππ 1 1 ππ ππ ππ+1 ππ+1 1 ππ 1 1 ππ ππ ππ+1 π¦π¦ β― π¦π¦ π¦π¦ π€π€ β― π¦π¦ π€π€ π¦π¦ π¦π¦β π¦π¦ ββ―βπ¦π¦ π¦π¦β π€π€ β― π¦π¦β π€π€ π¦π¦β since the elements of which are -related to anπ¦π¦ element1 β― π¦π¦ ππofπ¦π¦ theππ+ 1semilatticeπ¦π¦1π€π€1 β― transversalπ¦π¦ππ π€π€πππ¦π¦ππ+ 1 of form a right regular band by Result 1.1. It follows that = . Using inductionβ and πΉπΉ β πΉπΉ πΉπΉ the fact that = we find that = β . Sinceβ β in , we thus π€π€ π¦π¦1 β― π¦π¦ππ π¦π¦ππ+1π€π€ have that β β =β β = β β. β β 1 ππ 1 ππ 1 ππ 1 ππ π₯π₯ β―βπ₯π₯ β π¦π¦ β―βπ¦π¦ β β π€π€β π₯π₯β β― π₯π₯β π€π€ π€π€π€π€π₯π₯ β― π₯π₯ πΉπΉ Weπ€π€ nextβπ€π€ π₯π₯consider1 β― π₯π₯ππ the π₯π₯case1 β― whereπ₯π₯πππ€π€π₯π₯ 1 β― π₯π₯1ππ. Thenπ₯π₯1 thereβ― π₯π₯ππ exists ( ) such that ( ) ( ) for some ( ), ( ) . If ( ) = { , , }, we may as well assume π€π€πΏπΏ β’ ππ π€π€ β ππ π€π€ β‘ that ( ( ) ( )) = { , , } for someβ β . Then ππ π€π€ ππ π€π€ π’π’ ππ π€π€ π’π’ β ππ βͺ ππ ππ π€π€ π₯π₯1 β― π₯π₯ππ ππ ππ =π€π€ ππ( π€π€) ( )(π₯π₯1( β―) (π₯π₯ππ )) ( ) ππ( β€)ππ (since ( ) ( ) ( ( ) ( )) in ) = ( ) ( ) ( )β ( ) β π€π€ ππ π€π€ ππ π€π€ ππ π€π€ ππ π€π€ ππ π€π€ ππ π€π€ π’π’ ππ π€π€ ππ π€π€ ππ ππ π€π€ ππ π€π€ πΉπΉ = ( ) ( ) β β ππ π€π€ ππ π€π€ π₯π₯1 β― π₯π₯ππ ππ π€π€ ππ π€π€ π’π’ where ππ π€π€ ππ π€π€( π£π£) ( ) is such that = 1 and ( ) = { , β¦ , } = ( ). By the β β first part of the proof, = β¦ and thus = ( ) ( ) . Since and π£π£ β‘ π₯π₯1 β― π₯π₯ππ ππ π€π€ ππ π€π€ π’π’ π£π£πΏπΏ ππ π£π£ π₯π₯1 π₯π₯ππ ππ π€π€ ( ) ( ) have theβ sameβ content, they must then be -relatedβ β in . Further, π£π£ π₯π₯1 π₯π₯πππ£π£ π€π€ ππ π€π€ ππ π€π€ π₯π₯1 β― π₯π₯πππ£π£ π€π€ β β = and so = ( ) ( ) . ππ π€π€ ππ π€π€ π₯π₯1 β― π₯π₯ππ β πΉπΉ β β β β β β β β β β ππ ππ ππ ππ ππ π₯π₯1 β― π₯π₯Fromπ£π£π₯π₯1 β―Lemmaπ₯π₯ 2.1π₯π₯1 andβ― π₯π₯ its dual weπ€π€π₯π₯ have1 β― π₯π₯ the following.ππ π€π€ ππ π€π€ π₯π₯1 β― π₯π₯ β‘
Corollary 2.2
Let ( ) , ( ) = { , β¦ , }. β + 1 ππ If π€π€ β1ππ βͺ ππ, thenππ π€π€ π₯π₯ π₯π₯
πΏπΏ π π π€π€ β’ β’(π€π€) ( ) ( ) ( ) β β β β β β and = π€π€( ) β( ππ) π€π€ ππ π€π€ (π₯π₯1)β―( π₯π₯)ππ. βπ₯π₯1 β― π₯π₯ππβπ₯π₯1 β― π₯π₯ππππ π€π€ ππ π€π€ βπ€π€ β β If π€π€ 1ππ π€π€ ππ ,π€π€ thenπ₯π₯1 β― π₯π₯ππππ π€π€ ππ π€π€ π€π€=πΏπΏ β’( )β‘( π€π€)π π .. β β β β π€π€ ππ π€π€ ππ π€π€ π₯π₯1 β― π₯π₯ππβπ₯π₯1 β― π₯π₯ππ Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 7
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
If 1 , then
π€π€=πΏπΏ β‘ β’ π€π€π π ( ) ( ) . β β β β π€π€If π₯π₯1 1β― π₯π₯ππππ π€π€, thenππ π€π€ =βπ₯π₯1 β― π₯π₯ππ . β β πΏπΏ π π 1 ππ Thatπ€π€ theβ‘ ,β‘Β―, π€π€ and yieldπ€π€ invariantsπ₯π₯ β― π₯π₯ follows from the following sequence of results.
Lemma 2.3ππ ππ ππ ππ
Let , ( ) be such that = in . Then 1 if and only if 1. If this is the case, then ( β) + ( ) and either ( ) 1 ( ) or ( ) = ( ) in . π£π£ π€π€ β ππ βͺ ππ π£π£ π€π€ πΉπΉ π£π£πΏπΏ β’ π€π€πΏπΏ β’ Proof ππ π£π£ β‘ ππ π€π€ ππ π£π£ β‘ β‘ ππ π€π€ ππ π£π£ ππ π€π€ πΉπΉ
If = in then can be transformed into w by using a finite sequence of transformations of the form where , ( ) and where ( , ) or ( , ) is oneπ£π£ ofπ€π€ the pairsπΉπΉ listedπ£π£ in (2). It therefore suffices to proveβ β the statement of the theorem for the special case ππππππwhereβ ππππππ andππ ππ β ππ βͺ whereππ ( , ) is any π π ofπ‘π‘ the pairs listedπ‘π‘ π π in (2). The proof is not much harder than the corresponding verification for free bands as in the proof of Lemma 4.5.1π£π£ ofβ‘.3ππππππ π€π€ β‘ ππππππ π π π‘π‘
Using an inductive argument we thusβ‘ have the following.
Corollary 2.4
If , ( ) are such that = in , then . β + πΏπΏ πΏπΏ It π£π£willπ€π€ beβ convenientππ βͺ ππ to denote by π£π£ theπ€π€ unaryπΉπΉ bandπ£π£ withβ‘ π€π€ an identity 1 adjoined. The unary operation of can be extended to1 by putting 1 = 1. From Corollaries 2.2 and 2.4, Lemma 2.3 and their duals, we concludeπΉπΉ 1 the following.πΉπΉβ πΉπΉ πΉπΉ Theorem 2.5
For , ( ) we have: if = in , then β + π£π£ π€π€ β ππ (βͺ ππ) = ( ), π£π£ π€π€ πΉπΉ , ,
and ππ π£π£ ππ π€π€ π£π£πΏπΏ β‘ π€π€πΏπΏ π£π£π π β‘ π€π€π π Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 8
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
( ) = ( ) in if 1,
( ) = ( ) 1 1. in if πΏπΏ πΏπΏ ππ π£π£ ππ π€π€ πΉπΉ1 π£π£ β‘ π€π€ β’ Conversely, if ( ) = ππ( π£π£), then ππ= π€π€ in ifπΉπΉ eitherπ£π£ oneπ π β‘of theπ€π€π π followingβ’ occur:
1. (i) ππ π£π£ ππ1π€π€, π£π£ π€π€1, (πΉπΉ) = ( ) in and ( ) = ( ) in , 1 1 πΏπΏ πΏπΏ π π π π (ii)π£π£ β‘ π€π€ β’ 1π£π£, β‘ π€π€ β’ 1ππ, andπ£π£ ( ππ)π€π€= (πΉπΉ) in ππ, π£π£ ππ π€π€ πΉπΉ 1 (iii)π£π£ πΏπΏ β‘ π€π€πΏπΏ β‘ 1,π£π£ π π β‘ π€π€π π β’ 1, andππ (π£π£) = ππ(π€π€) in πΉπΉ , 1 (iv) π£π£πΏπΏ β‘ π€π€πΏπΏ β’1 π£π£π π β‘ π€π€π π β‘. ππ π£π£ ππ π€π€ πΉπΉ π£π£πΏπΏ β‘ π€π€πΏπΏ β‘ β‘ π£π£π π β‘ π€π€π π
β‘ We remark here that the task for testing whether = in is, by Theorem 2.5, reduced to a similar task for words of smaller content. Proceeding inductively, Theorem 2.5 thus allows us to verify whether = in in a finite numberπ£π£ π€π€ of steps.πΉπΉ We shall be more explicit in the following. π£π£ π€π€ πΉπΉ Let { , } be the free monoid on the set containing the symbols and , and again let 1 stand for the identityβ element of { , } . For { , } and ( ) , we define ( ) inductively by:ππ ππ β β ππ β βππ ππ ππ ππ β ππ ππ π€π€ β ππ βͺ ππ ππ π€π€ 1( ) =
andπ€π€ for π€π€= with , β¦ , { , }, 1, ( ) =ππ (ππ1 β―β¦ππππ ( ))ππ. 1 ππππ β ππ ππ ππ β₯ ππ π€π€ Theππ 1followingππ2 ππ ππfollowsπ€π€ from Theorem 2.5 using induction. For { , } , we let | | be the length of , and, for a set , we let | | be the cardinality of . β ππ β ππ ππ ππ Theoremππ 2.6 π΄π΄ π΄π΄ π΄π΄
For , ( ) we have that = in if and only if ( ) = ( ) and for any { , } with | | |β (+ )| = | ( )|, π£π£βπ€π€ β ππ βͺ ππ π£π£ π€π€ πΉπΉ ππ π£π£ ππ π€π€ ππ β ππ ππ ππ β€ ππ π£π£ ππ π€π€
Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 9
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( ( )) = ( ( )),
( ) ( ) and ( ) ( ) . ππ ππ π£π£ ππ ππ π€π€ ππ π£π£ πΏπΏ β‘ ππ π€π€ πΏπΏ ππ π£π£ π π β‘ ππ π€π€ π π β‘ From Theorem 2.6 and the solution of the word problem for the free band ( ) on the set (see [2] or Section 4.5 in [3]) it follows that for , , and represent the ππ same element of the free band ( ) if and only if = in . We+ can state this asπΉπΉ inππ the followingππ corollary. π£π£ π€π€ β ππ π£π£ π€π€ πΉπΉππ ππ π£π£ π€π€ πΉπΉ Corollary 2.7
Let be a nonempty set. Then the mapping , , can be extended to an embedding of the free band ( ) as a subband of = β ( ). ππ ππ β¦ ππ βͺ ππ βπ₯π₯ β¦ π₯π₯ ππ ππ In other words, any free bandπΉπΉ canππ be isomorphicallyπΉπΉ embeddedπΉπΉ ππ into a band which has a semilattice transversal. Therefore, the free objects in the quasivariety consisting of the bands which can be embedded into some band which has a semilattice transversal, are the familiar free bands.
Example 1
The -classes of = ( ) are much larger than the corresponding -classes of the free band ( ). Thus, if andβ are distinct elements of , then the -class of in ππ consistsππ of the 11πΉπΉ elementsπΉπΉ ππ , , , , , ππ β ,β , ππ πΉπΉ , ππ , π₯π₯ π¦π¦, βandβ β β β . Thereforeβ β βππ theβ β-classββ ofβ β inπ₯π₯ β π¦π¦ βcontainsβ πΉπΉ β β exactlyβ β 121 elements.β β β Theβ βπ₯π₯-classπ¦π¦ π₯π₯ π₯π₯ β π¦π¦in theβπ¦π¦ βπ₯π₯ freeπ₯π₯ π¦π¦ bandπ¦π¦ π¦π¦π¦π¦ π₯π₯( π¦π¦) containsπ¦π¦π₯π₯ π¦π¦ π₯π₯onlyπ¦π¦π₯π₯ theπ¦π¦ 4π₯π₯ elementsπ₯π₯π₯π₯π₯π₯ π¦π¦ π₯π₯π₯π₯,π₯π₯ π¦π¦ ,π₯π₯π₯π₯ , π¦π¦andπ₯π₯ π¦π¦ π¦π¦π¦π¦. π₯π₯ π¦π¦ π¦π¦π¦π¦ π₯π₯π₯π₯ π¦π¦ ππ π₯π₯π₯π₯ πΉπΉ ππ π₯π₯π₯π₯ πΉπΉππ ππ π₯π₯π₯π₯ π₯π₯π₯π₯π₯π₯If π¦π¦π¦π¦= { ,π¦π¦π¦π¦π¦π¦} then the 11 elements listed above, together with , , , and form the left regular band which is a transversal of the -classes of β( ). βTheβ 6-elementβ ππ π₯π₯ π¦π¦ π₯π₯ π₯π₯π₯π₯ π¦π¦ π¦π¦π¦π¦ free band ( ) is a normal band, whereas the 129-element free split βband ( ) is not: β πΉπΉππ ππ ( ) is not a semilattice, but a 9-element (square) rectangular band withβ an πΉπΉππ ππ πΉπΉππ ππ identityβ β adjoined.β If is the smallest fully invariant congruence on ( ) which identifies π₯π₯ πΉπΉππ ππ π₯π₯ these 9 elements, then separates the elements of ( ): the free normalβ band ( ) is ππ embeddable into theππ split band ( )/ , which is a normal band.πΉπΉ ππ ππ ππ ππ β πΉπΉ ππ πΉπΉ ππ ππ Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 7πΉπΉ53-762ππ. DOI. Thisππ article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 10
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3 Normal forms
We continue to use the notation introduced in the first few paragraphs of the previous section. Thus is the congruence relation on ( ) generated by the pairs in (2), and as we have seen ( ) / yields the free split bandβ + ( ) on the set . We π½π½ ππ βͺ ππ would like to find a subset of ( β + ) which is a cross section of theβ -classes. The ππ elements of this subset areππ thenβͺ ππ calledβπ½π½ of+ normal form, and every πΉπΉ ππ( ) isππ related to a unique element of ππnormalβͺ ππ form, called the normal form of wπ½π½. We wouldβ + like to do all this in such a way that, given any ( ) , there existsπ€π€ β an ππalgorithmβͺ ππ whichπ½π½ produces the normal form of . After this is accomplished,β + we have a concrete model of ( ) at hand. π€π€ β ππ βͺ ππ β π€π€ ππ πΉπΉ ππ In order to be able to find a normal form for the elements of ( ), we shall assume that there exists a total order on the set of generators. For anyβ finite nonempty ππ set of , say = { , β¦ , } with < β¦ < for the total order,πΉπΉ ππ we let be the uniquely defined word of ( ) . In particular,ππ if ( ) , then (β ) 1 ππ 1 2 ππ ( πΆπΆ) isππ uniquelyπΆπΆ definedπ₯π₯ β andπ₯π₯ β ( ( π₯π₯β) +) =π₯π₯ ( ). π₯π₯ β + πΆπΆ β 1 ππ β + π₯π₯ β― π₯π₯ ππ β π€π€ β ππ βͺ ππ ππ π€π€ β ππ From the results of the previousππ ππ π€π€ section,ππ π€π€ the following holds.
Lemma 3.1
For any ( ) , = ( ) ( ) ( ) ( ) ( ). β + β It followsπ€π€ thatβ weππ can,βͺ ππ in a uniqueπ€π€ ππway,π€π€ parseππ π€π€ ππeveryπ€π€ ππ π€π€(ππ π€π€ ) following the rule given by Lemma 3.1. We may visualize our parsing of by considering a βtree+ with a root labeled , π€π€ β ππ βͺ ππ and where every node labeled ( ) is expanded as in Fig. 1. β + π€π€ π€π€ π£π£ β ππ βͺ ππ
Fig. 1 Expansion of node
Semigroup forum, Vol. 90, No. 3 (Junπ£π£e 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 11
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
We shall, however, not consider such a further expansion if , 1 or ( ) . In the latter case we rewrite as ( ) . When parsing any ( ) we thus obtainβ + a labeled tree whose leaves are labeledβ with either 1, or a letterπ£π£ β ofππ π£π£, orβ‘ aβ word+ π£π£ βof (ππ ) . π£π£ ππ π£π£ π€π€ β ππ βͺ ππ β + ππ ππ By way of example, we give the parsing tree for the word with < < < < < in X: see Fig. 2. The corresponding π€π€ β‘ normalβ βformβ for β mayβ then be calculated, using Lemma 3.1, as π¦π¦π₯π₯ π¦π¦ππ π₯π₯π π π¦π¦π¦π¦π¦π¦π‘π‘ π§π§ π π ππ π π π‘π‘ π₯π₯ π¦π¦ π§π§ = [ π€π€ ] ( ) [ ] = 1 β (β β ) β [β β ]β β β( β )β β [ ] π€π€ π¦π¦π₯π₯( π¦π¦ππ π₯π₯βπ π βπ¦π¦)β β βπ§π§ β [ππ π π π‘π‘β] π₯π₯ π¦π¦ π§π§ β β π₯π₯ββ βπ π βπ¦π¦π¦π¦π¦π¦β βπ‘π‘ π§π§ π π β = 1 β π¦π¦ β β (βππ βπ π π₯π₯β π¦π¦ ) β π₯π₯ββ βπ π π¦π¦ β π§π§( β ππ)π π π‘π‘ π₯π₯1π¦π¦ π§π§ (β π₯π₯ β π π π¦π¦ β ) π§π§ β π π π‘π‘(π¦π¦β π§π§β )β β π¦π¦β β 1π‘π‘ π§π§ βπ π ( β β) ( ) β (β β β β) β 1. ββ π¦π¦ β ππ βπ π βπ₯π₯ π¦π¦ β π₯π₯ β π π β π¦π¦β β β π π β π¦π¦β β π¦π¦ β ββ π§π§β β ππ π π π‘π‘βπ₯π₯β π¦π¦β π§π§ β π₯π₯ β Here theπ π β squareπ¦π¦ β π π bracketsπ¦π¦ β π¦π¦ indicateβ β π§π§ thatβ π π furtherπ‘π‘ π¦π¦ π§π§ expansionβ π¦π¦ β π‘π‘ isπ§π§ required,β π π β andπ π π‘π‘ dotsπ§π§ suggestβ π π β that some branching in the parsing tree is involved.
Fig. 2 Parsing of the word w
References
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Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 12
NOT THE PUBLISHED VERSION; this is the authorβs final, peer-reviewed manuscript. The published version may be accessed by following the link in the citation at the bottom of the page.
7Saito, T.: A note on regular semigroups with inverse transversals. Semigroup Forum 33, 149β152 (1986) 8Tang, X.: LRT-biordered sets. Semigroup Forum 73, 377β394 (2006) 9Yoshida, R.: Right regular bands with semilattice transversals; In: Proceedings of the 8th Symposium on Semigroups, Shimane University, Matsue, Pp. 26β31 (1984)
Semigroup forum, Vol. 90, No. 3 (June 2015): pg. 753-762. DOI. This article is Β© Springer and permission has been granted for this version to appear in e-Publications@Marquette. Springer does not grant permission for this article to be further copied/distributed or hosted elsewhere without the express permission from Springer. 13