A Window Into Zeta and Modular Physics MSRI Publications Volume 57, 2010
Basic zeta functions and some applications in physics
KLAUS KIRSTEN
1. Introduction It is the aim of these lectures to introduce some basic zeta functions and their uses in the areas of the Casimir effect and Bose–Einstein condensation. A brief introduction into these areas is given in the respective sections; for recent monographs on these topics see [8; 22; 33; 34; 57; 67; 68; 71; 72]. We will con- sider exclusively spectral zeta functions, that is, zeta functions arising from the eigenvalue spectrum of suitable differential operators. Applications like those in number theory [3; 4; 23; 79] will not be considered in this contribution. There is a set of technical tools that are at the very heart of understanding analytical properties of essentially every spectral zeta function. Those tools are introduced in Section 2 using the well-studied examples of the Hurwitz [54], Epstein [38; 39] and Barnes zeta function [5; 6]. In Section 3 it is explained how these different examples can all be thought of as being generated by the same mechanism, namely they all result from eigenvalues of suitable (partial) differential operators. It is this relation with partial differential operators that provides the motivation for analyzing the zeta functions considered in these lectures. Motivations come for example from the questions “Can one hear the shape of a drum?”, “What does the Casimir effect know about a boundary?”, and “What does a Bose gas know about its container?” The first two questions are considered in detail in Section 4. The last question is examined in Section 5, where we will see how zeta functions can be used to analyze the phenomenon of Bose–Einstein condensation. Section 6 will point towards recent developments for the analysis of spectral zeta functions and their applications.
101 102 KLAUS KIRSTEN
2. Some basic zeta functions In this section we will construct analytical continuations of basic zeta func- tions. From these we will determine the meromorphic structure, residues at singular points and special function values. 2.1. Hurwitz zeta function. We start by considering a generalization of the Riemann zeta function
X1 1 R.s/ : (2-1) D ns n 1 D DEFINITION 2.1. Let s ރ and 0 < a < 1. Then for Re s > 1 the Hurwitz zeta 2 function is defined by
X1 1 H .s; a/ : D .n a/s n 0 D C Clearly, H .s; 1/ R.s/. Results for a 1 b > 1 follow by observing D D C X1 1 1 H .s; 1 b/ H .s; b/ : C D .n 1 b/s D bs n 0 D C C In order to determine properties of the Hurwitz zeta function, one strategy is to express it in term of ’known’ zeta functions like the Riemann zeta function.
THEOREM 2.2. For 0 < a < 1 we have
1 X1 k .s k/ k H .s; a/ . 1/ C a R.s k/: D as C .s/k! C k 0 D PROOF. Note that for z < 1 we have the binomial expansion j j X1 .s k/ .1 z/ s C zk : D .s/k! k 0 D So for Re s > 1 we compute
k 1 X1 1 1 1 X1 1 X1 k .s k/ aÁ H .s; a/ s . 1/ C D as C ns 1 a D as C ns .s/k! n n 1 n n 1 k 0 D C D D 1 X1 .s k/ X1 1 . 1/k C ak D as C .s/k! ns k k 0 n 1 C D D 1 X1 k .s k/ k . 1/ C a R.s k/: D as C .s/k! C k 0 D BASIC ZETA FUNCTIONS AND SOME APPLICATIONS IN PHYSICS 103
From here it is seen that s 1 is the only pole of H .s; a/ with Res H .1; a/ 1. D D In determining certain function values of H .s; a/ the following polynomials will turn out to be useful.
DEFINITION 2.3. For x ރ we define the Bernoulli polynomials Bn.x/ by the 2 equation xz ze X1 Bn.x/ zn; where z < 2: (2-2) ez 1 D n! j j n 0 D 1 Examples are B0.x/ 1 and B1.x/ x . The numbers Bn.0/ are called D D 2 Bernoulli numbers and are denoted by Bn. Thus
z X1 Bn zn; where z < 2: (2-3) ez 1 D n! j j n 0 D LEMMA 2.4. The Bernoulli polynomials satisfy Pn n n k (1) Bn.x/ k 0 k Bk x ; D D n 1 (2) Bn.x 1/ Bn.x/ nx if n 1; C n D n 1 (3) . 1/ Bn. x/ Bn.x/ nx ; D n C (4) Bn.1 x/ . 1/ Bn.x/: D EXERCISE 1. Use relations (2-2) and (2-3) to show assertions (1)–(4).
We now establish elementary properties of H .s; a/.
THEOREM 2.5. For Re s > 1 we have Z at 1 1 s 1 e H .s; a/ t dt: (2-4) D .s/ 1 e t 0 Furthermore, for k ގ0 we have 2 Bk 1.a/ H . k; a/ C : D k 1 C PROOF. We use the definition of the gamma function and have Z Z 1 s 1 u s 1 s 1 t .s/ u e du t e dt: (2-5) D 0 D 0 This shows the first part of the theorem, Z Z X1 1 1 s 1 t.n a/ 1 1 s 1 X1 t.n a/ H .s; a/ t e C dt t e C dt D .s/ 0 D .s/ 0 n 0 n 0 D D 1 Z e at 1 t s 1 dt: D .s/ 1 e t 0 104 KLAUS KIRSTEN
Furthermore we have Z ta 1 1 s 2 te H .s; a/ t dt D .s/ 1 e t 0 1 Z 1 . t/e ta 1 Z . t/e ta t s 2 dt 1 t s 2 dt: D .s/ e t 1 C .s/ e t 1 0 1 The integral in the second term is an entire function of s. Given that the gamma function has singularities at s k, k ގ0, only the first term can possibly D 2 contribute to the properties H . k; a/ considered. We continue and write Z 1 ta Z 1 1 s 2 . t/e 1 s 2 X1 Bn.a/ n t t dt t . t/ dt .s/ 0 e 1 D .s/ 0 n! n 0 D n 1 X1 Bn.a/ . 1/ ; D .s/ n! s n 1 n 0 D C which provides the analytical continuation of the integral to the complex plane. From here we observe again
Res H .1; a/ B0.a/ 1: D D Furthermore the second part of the theorem follows:
k 1 1 Bk 1.a/ . 1/ C H . k; a/ lim C D " 0 . k "/ .k 1/! " ! C C k 1 k Bk 1.a/ . 1/ C Bk 1.a/ lim . 1/ k!" C C : D " 0 .k 1/! " D k 1 ! C C The disadvantage of the representation (2-4) is that it is valid only for Re s > 1. This can be improved by using a complex contour integral representation. The starting point is the following representation for the gamma function [46].
LEMMA 2.6. For z ޚ we have … Z 1 z 1 t .z/ . t/ e dt; D 2i sin.z/ C where the anticlockwise contour C consists of a circle C3 of radius " < 2 and straight lines C1, respectively C2, just above, respectively just below, the x-axis; see Figure 1.
PROOF. Assume Re z > 1. As the integrand remains bounded along C3, no contributions will result as " 0. Along C1 and C2 we parametrize as given in ! BASIC ZETA FUNCTIONS AND SOME APPLICATIONS IN PHYSICS 105
6 t-plane
t e i u D C C 3 1- C2 nnn - t ei u D
Figure 1. Contour in Lemma 2.6.
Figure 1 and thus for Re z > 1 Z Z 0 Z z 1 t i.z 1/ z 1 u 1 i.z 1/ z 1 u lim . t/ e dt e u e du e u e du " 0 C D C 0 ! 1Z 1 z 1 u iz izÁ u e e e du D 0 Z 1 z 1 u 2i sin.z/ u e du; D 0 which implies the assertion by analytical continuation. This representation for the gamma function can be used to show the following result for the Hurwitz zeta function.
THEOREM 2.7. For s ރ, s ގ, we have 2 … Z s 1 ta .1 s/ . t/ e H .s; a/ dt; D 2i 1 e t C with the contour C given in Figure 1.
PROOF. We follow the previous calculation to note Z . t/s 1e ta Z e ta dt 2i sin.s/ 1 t s 1 dt; 1 e t D 1 e t C 0 and we use [46] sin.s/ .s/ D .1 s/ to conclude the assertion. 106 KLAUS KIRSTEN
From here, properties previously given can be easily derived. For s ޚ the 2 integrand does not have a branch cut and the integral can easily be evaluated using the residue theorem. The only possible singularity enclosed is at t 0 D and to read off the residue we use the expansion
ta . t/e X1 Bn.a/ . t/s 2 . t/s 2 . t/n: e t 1 D n! n 0 D 2.2. Barnes zeta function. The Barnes zeta function is a multidimensional generalization of the Hurwitz zeta function.
DEFINITION 2.8. Let s ރ with Re s > d and c ޒ , r ޒd . The Barnes 2 2 C E 2 zeta function is defined as C X 1 B.s; c r/ : (2-6) jE D .c m r/s m ގd CE E E 2 0 If c 0 it is understood that the summation ranges over m 0. D E ¤ E For r 1 .1; 1;:::; 1; 1/, the Barnes zeta function can be expanded in terms E D Ed WD of the Hurwitz zeta function.
EXAMPLE 2.9. Consider d 2 and r .1; 1/. Then D E D X 1 X1 k 1 X1 k c 1 c B.s; c 12/ s C s C C s jE D .c m1 m2/ D .c k/ D .c k/ m ގ2 C C k 0 C k 0 C E 2 0 D D H .s 1; c/ .1 c/H .s; c/: D C .d/ EXAMPLE 2.10. Let ek be the number of possibilities to write an integer k as a sum over d non-negative integers. We then can write
X 1 X1 .d/ 1 B.s; c 1d / s ek s : jE D .c m1 md / D .c k/ m ގd C C C k 0 C E 2 0 D .d/ The coefficient ek can be determined for example as follows. Consider  à  à 1 1 1 X1 X1 xl1 xld .1 x/d D 1 x 1 x D l1 0 ld 0 D D X1 X1 X1 .d/ xl1 ld e xk : D CC D k l1 0 ld 0 k 0 D D D BASIC ZETA FUNCTIONS AND SOME APPLICATIONS IN PHYSICS 107
On the other side, using the binomial expansion  à 1 X1 .d k/ X1 .d k 1/! X1 d k 1 C xk C xk C xk : .1 x/d D .d/k! D .d 1/!k! D d 1 k 0 k 0 k 0 D D D This shows  à X1 d k 1 1 B.s; c 1 / C ; jEd D d 1 .c k/s k 0 C D which, once the dimension d is specified, allows to write the Barnes zeta func- tion as a sum of Hurwitz zeta functions along the lines in Example 2.9.
It is possible to obtain similar formulas for ri rational numbers [27; 28]. For some properties of the Barnes zeta function the use of complex contour integral representations turns out to be the best strategy.
THEOREM 2.11. We have the following representations: 1 Z e ct .s; c r/ 1 t s 1 dt B d jE D .s/ Q rj t 0 j 1 .1 e / D .1 s/ Z e ct . t/s 1 dt; d D 2i Q rj t C j 1 .1 e / D with the contour C given in Figure 1.
EXERCISE 2. Use equation (2-5), and again Lemma 2.6, to prove Theorem 2.11. The residues of the Barnes zeta function and its values at non-positive integers are best described using generalized Bernoulli polynomials [70]. .d/ DEFINITION 2.12. We define the generalized Bernoulli polynomials Bn .x r/ jE by the equation
xt d n d e . 1/ X1 . t/ B.d/.x r/: d d n Q rj t D Q n! jE j 1 .1 e / j 1 rj n 0 D D D Using Definition 2.12 in Theorem 2.11 one immediately obtains the following properties of the Barnes zeta function.
THEOREM 2.13. d z . 1/ C .d/ (1) Res B.z; c r/ B .c r/; z 1; 2;:::; d; jE D Qd d z jE D .z 1/!.d z/! j 1 rj D d . 1/ n! .d/ (2) B. n; c r/ B .c r/: jE D Qd d n jE .d n/! j 1 rj C C D 108 KLAUS KIRSTEN
EXERCISE 3. Use the first representation of B.s; c r/ in Theorem 2.11 together jE with Definition 2.12 to show Theorem 2.13. Follow the steps of the proof in Theorem 2.5.
EXERCISE 4. Use the second representation of B.s; c r/ in Theorem 2.11 to- jE gether with Definition 2.12 and the residue theorem to show Theorem 2.13. 2.3. Epstein zeta function. We now consider zeta functions associated with sums of squares of integers [38; 39].
DEFINITION 2.14. Let s ރ with Re s > d=2 and c ޒ , r ޒd : The Epstein 2 2 C E 2 zeta function is defined as C X 1 E .s; c r/ : 2 2 2 s jE D .c r1m r2m rd m / m ޚd C 1 C 2 C C d E 2 If c 0 it is understood that the summation ranges over m 0. D E ¤ E LEMMA 2.15. For Re s > d=2, we have
1 Z 2 2 1 s 1 X t.r1m rd m c/ E .s; c r/ t e 1CC d C dt: jE D .s/ 0 m ޚd E 2 PROOF. This follows as before from property (2-5) of the gamma function. As we have noted in the proof of Theorem 2.5, it is the small-t behavior of the integrand that determines residues of the zeta function and special function values. The way the integrand is written in Lemma 2.15 this t 0 behavior is ! not easily read off. A suitable representation is obtained by using the Poisson resummation [53].
LEMMA 2.16. Let r ރ with Re r > 0 and t ޒ , then 2 2 C r 2 X1 trl2 X1 l2 e e r t : D tr l l D 1 D 1 EXERCISE 5. If F.x/ is continuous such that Z 1 F.x/ dx < ; j j 1 1 then we define its Fourier transform by Z F.u/ 1 F.x/e 2ixu dx: O D 1 If Z 1 F.u/ du < ; j O j 1 1 BASIC ZETA FUNCTIONS AND SOME APPLICATIONS IN PHYSICS 109 then we have the Fourier inversion formula Z F.x/ 1 F.u/ e2ixu du: D O 1 Show the following Theorem: Let F L1.ޒ/. Suppose that the series 2 X F.n v/ C n ޚ 2 converges absolutely and uniformly in v, and that X F.m/ < : j O j 1 m ޚ 2 Then X X F.n v/ F.n/e2inv: C D O n ޚ n ޚ 2 2 Hint: Note that X G.v/ F.n v/ D C n ޚ 2 is a function of v of period 1.
EXERCISE 6. Apply Exercise 5 with a suitable function F.x/ to show the Pois- son resummation formula Lemma 2.16. In Lemma 2.16 it is clearly seen that the only term on the right hand side that is not exponentially damped as t 0 comes from the l 0 term. Using the ! D resummation formula for all d sums in Lemma 2.15, after resumming the m 0 E D E term contributes Z d=2 0 1 1 s 1 ct E.s; c r/ t e dt E d=2 jE D .s/ 0 t pr1 r d d=2 Z d=2 s d 1 t s d=2 1e ct dt 2 : s d=2 D pr1 r .s/ D pr1 r .s/c d 0 d All other contributions after resummation are exponentially damped as t 0 ! and can be given in terms of modified Bessel functions [46].
DEFINITION 2.17. Let Re z2 > 0. We define the modified Bessel function K.z/ by Z z2 1 z Á 1 t 1 K.z/ e 4t t dt: D 2 2 0 Performing the resummation in Lemma 2.15 according to Lemma 2.16, with Definition 2.17 one obtains the following representation of the Epstein zeta function valid in the whole complex plane [34; 78]. 110 KLAUS KIRSTEN
THEOREM 2.18. We have
d d 2s d=2 s 4 s 2 d s 2 c E .s; c r/ c 2 jE D pr1 rd .s/ C .s/pr1 rd 1 d 1 Â 2 2 Ã2 .s 2 / Â Â 2 2 Ã2 Ã X n1 nd n1 nd K d s 2pc : r1 C C rd 2 r1 C C rd n ޚd = 0 E2 fEg
EXERCISE 7. Show Theorem 2.18 along the lines indicated.
From Definition 2.17 it is clear that the Bessel function is exponentially damped for large Re z2. As a result the representation above is numerically very effective as long as the argument of Kd=2 s is large. The terms involving the Bessel functions are analytic for all values of s, the first term contains poles. As an immediate consequence of the properties of the gamma function one can show the following properties of the Epstein zeta function.
d d THEOREM 2.19. For d even, E .s; c r/ has poles at s 2 ; 2 1;:::; 1, whereas d jEd 1 2lD 1 for d odd they are located at s ; 1;:::; ; , l ގ0. Furthermore, D 2 2 2 2C 2
d j j d j . 1/ 2 2 c 2 Res .j ; c r/ C ; E d jE D pr1 r .j / j 1 d 2 C 8 ˆ 0 for d odd; <ˆ d d d p . 1/ 2 p! 2 c 2 E . p; c r/ C for d even: jE D ˆ d Á :ˆ pr1 rd p 1 2 C C
EXERCISE 8. Use Theorem 2.18 and properties of the gamma function to show Theorem 2.19.
This concludes the list of examples for zeta functions to be considered in what follows. A natural question is what the motivations are to consider these zeta functions. Before we describe a few aspects relating to this question let us mention how all these zeta functions, and many others, result from a common principle.
3. Boundary value problems and associated zeta functions
In this section we explain how the considered zeta functions, and others, are all associated with eigenvalue problems of (partial) differential operators. BASIC ZETA FUNCTIONS AND SOME APPLICATIONS IN PHYSICS 111
EXAMPLE 3.1. Let M Œ0; L be some interval and consider the Dirichlet D boundary value problem. @2 Pn.x/ n.x/ nn.x/; n.0/ n.L/ 0: WD @x2 D D D The solutions to the boundary value problem have the general form p p n.x/ A sin. nx/ B cos. nx/: D C Imposing the Dirichlet boundary condition shows we need p n.0/ B 0; n.L/ A sin.L n/ 0; D D D D which implies n22 n ; n ގ: D L2 2 We only need to consider n ގ because non-positive integers lead to linearly 2 dependent eigenfunctions. The zeta function P .s/ associated with this bound- ary value problem is defined to be the sum over all eigenvalues raised to the power . s/, namely X1 s 1 P .s/ ; Re s > : D n 2 n 1 D So here the associated zeta function is a multiple of the zeta function of Riemann,
1 Á 2s Á2s X n L P .s/ R.2s/: D L D n 1 D EXAMPLE 3.2. The previous example can be easily generalized to higher di- mensions. We consider explicitly two dimensions; for the higher dimensional situation see [1]. Let M .x; y/ x Œ0; L1; y Œ0; L2 : We consider the D f j 2 2 g boundary value problem with Dirichlet boundary conditions on M , that is  @2 @2 à Pn;m.x; y/ c n;m.x; y/ n;mn;m.x; y/; D @x2 @y2 C D n;m.0; y/ n;m.L1; y/ n;m.x; 0/ n;m.x; L2/ 0: D D D D Using the process of separation of variables, eigenfunctions are seen to be Ânx à Âmy à n;m.x; y/ A sin sin ; D L1 L2 with the eigenvalues Ân Ã2 Âm Ã2 n;m c; n; m ގ: D L1 C L2 C 2 112 KLAUS KIRSTEN
The associated zeta function therefore is ÄÂ Ã2 Â Ã2 s X1 X1 n m P .s/ c ; D L1 C L2 C n 1 m 1 D D which can be expressed in terms of the Epstein zeta function given in Definition 2.14 as follows: Â ˇ Â Á2 Á2ÃÃ 1 ˇ P .s/ 4 E s; c ; D ˇ L1 L2 Â ˇ Á2Ã Â ˇ Á2Ã 1 ˇ 1 ˇ 1 s 4 E s; c 4 E s; c 4 c : (3-1) ˇ L1 ˇ L2 C
EXAMPLE 3.3. Similarly one can consider periodic boundary conditions instead of Dirichlet boundary conditions, this means the manifold M is given by M D S 1 S 1. In this case the eigenfunctions have to satisfy @ @ n;m.0; y/ n;m.L1; y/; n;m.0; y/ n;m.L1; y/; D @x D @x @ @ n;m.x; 0/ n;m.x; L2/; n;m.x; 0/ n;m.x; L2/: D @y D @y This shows that
i2nx=L1 i2my=L2 n;m.x; y/ Ae e ; D which implies for the eigenvalues
2 2 2nÁ 2mÁ 2 n;m c;.n; m/ ޚ : D L1 C L2 C 2 The associated zeta function therefore is Á Â2 Á2 2 Á2Ã P .s/ E s; c r ; r ; : D jE E D L1 L2 Clearly, in d dimensions one finds
Á Â2 Á2 2 Á2Ã P .s/ E s; c r ; r ;:::; : D jE E D L1 Ld
EXAMPLE 3.4. As a final example we consider the Schrodinger¨ equation of atoms in a harmonic oscillator potential. In this case M ޒ3, and the eigen- D value equation reads BASIC ZETA FUNCTIONS AND SOME APPLICATIONS IN PHYSICS 113
 2 à m 2 2 2 „ !1x !2y !3z n ;n ;n .x; y; z/ 2m C 2 C C 1 2 3 n ;n ;n n ;n ;n .x; y; z/: D 1 2 3 1 2 3 This differential equation is augmented by the condition that eigenfunctions 2 3 must be square integrable, n ;n ;n .x; y; z/ L .ޒ /: As is well known, this 1 2 3 2 gives the eigenvalues