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- Lecture 13

Waves in Insulators

Refractive Index & Impedance • • Absorption • Models of Dispersion & Absorption • The • Example of

1 Maxwell’s Equations in Insulators

Maxwell’s equations are modified by r and µr

- Either put r in front of 0 and µr in front of µ0

- Or remember D = r0E and B = µrµ0H

Solutions are wave equations: ∂2E  µ ∂2E 2E =   µ µ = r r ∇ r 0 r 0 ∂t2 c2 ∂t2

The effect of r and µr is to change the wave velocity: 1 c v = = √r0µrµ0 √rµr

2 &

For non-magnetic materials with µr = 1: c c v = = n = √r √r n The refractive index n is usually slightly larger than 1 Electromagnetic travel slower in

The wave impedance is the ratio of the field amplitudes: Z = E/H in units of Ω = V/A

In vacuo the impedance is a constant: Z0 = µ0c = 377Ω In an the impedance is:

µrµ0c µr Z = µrµ0v = = Z0 √rµr r r

For non-magnetic materials with µr = 1: Z = Z0/n

3 Notes:

Diagrams:

4 Energy Propagation in Insulators

The N = E H measures the energy flux × Energy flux is energy flow per unit time through surface to direction of propagation of wave:

∂U −2 ∂t = A N.dS Units of N are Wm In vacuo the amplitudeR of the Poynting vector is: 1  1 E2 N = E2 0 = 0 0 2 0 µ 2 Z r 0 0 In an insulator this becomes:  1 E2 N = N r = 0 0 µ 2 Z r r The energy flux is proportional to the square of the amplitude, and inversely proportional to the wave impedance

5 Dispersion

Dispersion occurs because the constant r and refractive index n are functions of ω Waves with different propagate with different velocities For a particular frequency the velocity is: ω c v (ω) = = p k n(ω)

For a wavepacket containing a small range of frequencies ∆ω << ω the group velocity is: dω c v (ω) = = g dk (n + ωdn/dω) Energy transmission in a wavepacket is described by !

For most insulators dn/dω > 0, n > 1 and vg < c

6 Absorption

Absorption can be represented by a complex dielectric constant:

 =  i r 1 − 2 The refractive index is also complex:

2 n = (1 i2) = n1 in2 n1 = √1 n2 = − − 2√1 p where we assume that   2  1 Plane wave have a complex k = k ik : 1 − 2 i(ωt−kz) −k2z i(ωt−k1z) E = E0e E = E0e e

The imaginary part of the wavenumber gives an exponential coefficient in the amplitude

7 and Attenutation

The phase velocity of the wave is given by the real parts of the dielectric constant or refractive index: ω c c v = = = k1 n1 √1

The attenuation length of the wave is inversely proportional to the imaginary part of the refractive index: 1 c 2c√ α = = = 1 k2 ωn2 ω2 where we assume the absorption is small   2  1

8 Model

Equation of motion of an in an external electric field: d2x dx m + γ + ω2x = eE e dt2 dt 0 −   where γ is a damping term due to other forces on the electron and ω0 is the natural resonant frequency of the electron An oscillating electric field causes simple harmonic motion:

i(kz−ωt) iωt E = E0e x = x0e eE x = − 0 0 m [(ω2 ω2) + iωγ] e 0 − An oscillating electron can be described by an oscillating electric moment: p = ex = ex eiωtxˆ − − 0

9 Model of Dispersion & Absorption

The oscillating create a P = Nep

The χE is: P N e2 χ = = e E  E m  [(ω2 ω2) + iωγ] 0 e 0 0 − and the dielectric constant is: N e2  (ω) = 1 + e r m  [(ω2 ω2) + iωγ] e 0 0 − The real and imaginary parts are: N e2(ω2 ω2) N e2ωγ  = 1+ e 0 −  = e 1 m  [(ω2 ω2)2 + ω2γ2] 2 m  [(ω2 ω2)2 + ω2γ2] e 0 0 − e 0 0 −

10 The Ionosphere

The ionosphere is a region of the upper atmosphere that contains a of free electrons It can be described by the harmonic oscillator model if we assume ω ω and neglect damping γ = 0:  0 ω2  (ω) = 1 P r − ω2 where the plasma frequency ωP depends on the electron :

2 Nee ωP = sme0

There is a between k and ω: ω2 ω2 k = − P p c

11 Reflection of Waves by the Ionosphere

For frequencies ω < ωP , r < 0 and k is purely imaginary

Waves with ω < ωP do not propagate through the ionosphere The plasma is effectively a conductor and totally reflects the waves

For frequencies ω > ωP , r > 0 and k is real

Waves with ω > ωP propagate with no attenuation

The plasma is effectively an insulator with phase velocity vp > c and group velocity vg < c:

1 c2 v = c v = p (1 ω2 /ω2) g v s − P p

12 Absorption in Molecular Materials

In molecular materials there can be many different resonant frequencies ω0 associated with rotational and vibrational states

At the there is large absorption

The width of a is controlled by the damping term γ

The Q-factor is: ω ω Q = 0 = 0 2 ∆ω γ | 1/2|

13 Example of Polar Dielectric (Water)

Low frequencies ω 1010Hz: •  No resonances. Negligible absorption. Static limit  81. 1 → These conclusions are modified by the presence of conducting in salt water.

Microwaves ω 1011Hz: • ≈ Rotational states lead to large absorption bands. Thermal motion disupts alignment of molcular dipole moments.

1 decreases as a function of ω. ω = 1013 1014Hz: • − Vibrational states lead to large absorption bands. These have narrower widths than rotational states.

1 and 2 vary rapidly.

14 Jackson (Figure 7.9, P.315) - refractive index n = √1 (left) and absorption coefficient α (right) of water as function of ω

15 Visible ω = 4 8 1014Hz: • − × Transparent due to large in absorption coefficient.

Ultraviolet ω = 1015 1016Hz • − Absorption is large due to collective excitations of electrons known as .

Can be modelled by a plasma frequency ωP .

High frequencies ω ω : •  P  1 and absorption is negligible. 1 ≈

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