Star Products from Commutative String Theory

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Star Products from Commutative String Theory hep-th/0108072 TIFR/TH/01-28 Star Products from Commutative String Theory Sunil Mukhi Tata Institute of Fundamental Research, Homi Bhabha Rd, Mumbai 400 005, India ABSTRACT A boundary-state computation is performed to obtain derivative corrections to the Chern-Simons coupling between a p-brane and the RR gauge potential Cp−3. We work to quadratic order in the gauge field strength F , but all orders in derivatives. In a certain limit, which requires the presence of a constant B-field background, it is found that these corrections neatly sum up into the product of (commutative) gauge fields. The result ∗2 is in agreement with a recent prediction using noncommutativity. arXiv:hep-th/0108072v1 10 Aug 2001 August 2001 Introduction In a recent paper[1] it was shown that the noncommutative formulation of open-string theory can actually give detailed information about ordinary commutative string theory. Once open Wilson lines are included in the noncommutative action, one has exact equality of commutative and noncommutative actions including all α′ corrections on both sides. As a result, a lot of information about α′ corrections on the commutative side is encoded in the lowest-order term (Chern-Simons or DBI) on the noncommutative side, and can be extracted explicitly. The predictions of Ref.[1] were tested against several boundary-state computations in commutative open-string theory performed in Ref.[2], and impressive agreement was found. The latter calculations were restricted to low-derivative orders, largely because the boundary-state computation becomes rather tedious when we go to high derivative order. However, in some specific cases, particularly when focusing on Chern-Simons couplings in the Seiberg-Witten limit[3], the predictions from noncommutativity in Ref.[1] are simple and elegant to all derivative orders as long as we work with weak field strengths (quadratic order in F ). This suggests that the boundary state computation can be performed for these special cases, and in the given limits, to all derivative orders. In this short note, we perform precisely such a calculation, using techniques and formulae already established in Ref.[2]. It will turn out that the derivative corrections neatly sum up and give rise to a product[4] between a pair of commutative field strengths: ∗2 1 pq sin( 2 ←−∂p θ −→∂q ) Fij(x), Fkl(x) ∗ Fij(x) Fkl(x) (1) h i 2 ≡ 1 pq 2 ←−∂p θ −→∂q The expression obtained in this way for the derivative corrections agrees perfectly with a prediction from noncommutativity that was made in Ref.[1]. Besides verifying this prediction, the calculation described here suggests that deriva- tive corrections to brane actions in commutative string theory, even away from the Seiberg- Witten limit, might have a novel underlying mathematical structure. We will comment on this at the end. Chern-Simons Corrections: RR 6-form In this section, we compute the corrections to the term 1 (6) SCS = C F F (2) 2 RR ∧ ∧ Z 1 on a Euclidean D9-brane of type IIB string theory with noncommutativity along all 10 directions. Here C6 is the Ramond-Ramond 6-form potential. The computation is per- formed to all orders in the derivative expansion, but keeping only terms of order (F 2). The use of D9-branes is purely a convenience, the same calculation can be trivially applied to Dp-branes and their coupling to the RR form C(p−3). The computation of corrections will be done in the boundary-state formalism. Useful background on how to compute derivative corrections in this formalism may be found in Ref.[2]. The formalism itself was developed in Ref.[5], and has been reviewed recently in Ref.[6]. Earlier work on derivative corrections can be found in Refs.[7]. Let us denote the sum of all derivative corrections to SCS as ∆SCS. Our starting point is the expression i µ − ′ dσdθDφ A (φ) 2πα µ SCS +∆SCS = C e B R (3) R where C represents the RR field, and B R is the Ramond-sector boundary state for zero | i | i field strength. We are using superspace notation, for example φµ = Xµ + θψµ and D is the supercovariant derivative. Combining Eqs.(2.3),(2.6),(2.13) of Ref.[2], we can rewrite this as: ∞ i 1 k+1 ν µ λ λ ′ dσdθ Dφ φ φ 1 ···φ k ∂λ ...∂λ Fµν (x) SCS +∆SCS = C e 2πα k=0 (k+1)! k+2 1 k ∞ × (4) i µ ν µ ν 1 λ λ ′ dσR[Ψ ψ +Pψ ψ ] X 1 ···X k ∂λ ...∂λ Fµν (x) e 2πα 0 0 0 k=0 k! 1 k B e e e e R R P where nonzero modes have a tildee on them, while thee zeroe modes are explicitly indicated. Since we are looking for couplings to the RR 6-form C(6), and working to order F 2, we only need terms with the structure ∂...∂F ∂...∂F . For such terms, two F ’s and ∧ 4 ψ0’s must be retained. Thus we can drop the first exponential factor in Eq.(4) above, µ ν as well as the first fermion bilinear Ψ ψ0 in the second exponential. Then, expanding the exponential to second order, we get: e ∞ ∞ 2 2π 2π 1 i 1 µ ν 1 α β SCS +∆SCS = dσ dσ C ψ ψ ψ ψ 2 2πα′ 1 2 2 0 0 2 0 0 × n=0 p=0 Z0 Z0 X X 1 1 (5) Xλ1 (σ ) Xλn (σ ) Xρ1 (σ ) Xρp (σ ) n! 1 ··· 1 p! 2 ··· 2 × ∂ ...∂ F x ∂ ...∂ F x B λ1e λn µν (e) ρ1 ρep αβ( ) eR 2 Now we need to evaluate the 2-point functions of the X. The relevant contributions have non-logarithmic finite parts[2] and come from propagators for which there is no self- e contraction. This requires that n = p. Then we get a combinatorial factor of n! from the n n number of such contractions in X(σ1) X(σ2) . The result is: ∞ i 2e 2π e 2π 1 1 λ1ρ1 λnρn SCS +∆SCS = dσ dσ D (σ σ ) D (σ σ ) 2 n! 2πα′ 1 2 1 − 2 ··· 1 − 2 × n=0 0 0 X Z Z 1 1 ∂ ...∂ F (x) ∂ ...∂ F (x) C ψµψν ψαψβ B λ1 λn µν ρ1 ρn αβ 2 0 0 2 0 0 R (6) The fermion zero mode expectation values are evaluated using the recipe: 1 µ ν ′ ψ ψ Fµν ( iα )F (7) 2 0 0 → − where the F on the right hand side is a differential 2-form. The justification for this can be found below Eq.(B.3) of Ref.[2]. Thus we are led to: λ1...λn; ρ1...ρn SCS +∆SCS = T ∂λ ...∂λ F ∂ρ ...∂ρ F (8) 1 n ∧ 1 n where i 2 2π 2π λ1...λn; ρ1...ρn 1 1 ′ 2 λ1ρ1 λnρn T ′ ( iα ) dσ1 dσ2 D (σ1 σ2) D (σ1 σ2) ≡ 2 n! 2πα − 0 0 − ··· − Z Z (9) Now we insert the expression for the propagator: ∞ −ǫm ′ e − − − Dµν (σ σ ) = α hµν eim(σ2 σ1) + hνµe im(σ2 σ1) (10) 1 − 2 m m=1 X where ǫ is a regulator, and 1 hµν (11) ≡ g +2πα′(B + F ) As is well known, the propagator is no longer symmetric when a B-field background is turned on. We now find that: ∞ ∞ −ǫ(m +···m ) 1 1 ′ e 1 n T λ1...λn; ρ1...ρn = (α )n 2 n! ··· m ...mn × m =1 m =1 1 X1 Xn (12) 2π 2π n dσ1 dσ2 − − − hλiρi eimi(σ2 σ1) + hρiλi e imi(σ2 σ1) 2π 2π 0 0 i=1 Z Z Y 3 It is convenient to define (h+)µν hµν , (h−)µν hνµ ≡ ≡ which allows us to write: − − − ± ± − hµν eim(σ2 σ1) + hνµe im(σ2 σ1) = (h )µν e im(σ2 σ1) ± X and we find that 2π n ∞ −ǫm 1 1 ′ dσ ± e ± T λ1...λn; ρ1...ρn = (α )n (h )λiρi e imσ (13) 2 n! 2π m 0 i=1 ± m=1 Z Y X X After evaluating the sum over m, the result, depending on the regulator ǫ, is 2π n 1 1 ′ dσ ± − ± T λ1...λn; ρ1...ρn = (α )n (h )λiρi ln(1 e ǫ iσ) (14) 2 n! 2π − − 0 i=1 ± ! Z Y X At this point it proves difficult to proceed further without introducing some simplifi- cation. The integral above, for general hµν , can only be performed explicitly for n = 2, as has in fact been done in Ref.[2]. However, if we take a limit where ′ gµν δ, Bµν fixed, α √δ (15) ∼ ∼ ∼ with δ 0, a simplification occurs. This is indeed just the Seiberg-Witten limit[3]. In → this limit, the “metric” hµν becomes antisymmetric: θµν hµν (16) → 2πα′ where 1 µν θµν (17) ≡ B and hence we find: e−ǫ+iσ ± λiρi −ǫ±iσ 1 λiρi 1 (h ) ln(1 e ) = ′ θ ln − −ǫ−iσ ± − 2πα 1 e X − (18) 1 = i (σ π) θλiρi 2πα′ − 4 The integrand has simplified considerably and the integral can now be done. Also, we have now taken the regulator ǫ to 0, as it is no longer needed. It follows that: 1 1 i n 2π dσ T λ1...λn; ρ1...ρn = θλ1ρ1 ...θλnρn (σ π)n 2 n! −2π 0 2π − n n Z 1 1 i π λ1ρ1 λnρn (19) 2 n! 2π n+1 θ ...θ (even n) = − 0 (odd n) Inserting this back in Eq.(8), it follows that keeping all derivative orders, but restrict- ing to quadratic order in F , and in the Seiberg-Witten limit, SCS +∆SCS ∞ 1 (6) j 1 λ1ρ1 λ2j ρ2j = C ( 1) θ ...θ ∂λ ...∂λ F ∂ρ ...∂ρ F 2 ∧ − 22j(2j + 1)! 1 2j ∧ 1 2j j=0 Z X 1 (6) = C F F ∗ 2 ∧h ∧ i 2 Z (20) where the product was defined in Eq.(1).
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