Repdigits As Sums of Two Lucas Numbers∗
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Prime Divisors in the Rationality Condition for Odd Perfect Numbers
Aid#59330/Preprints/2019-09-10/www.mathjobs.org RFSC 04-01 Revised The Prime Divisors in the Rationality Condition for Odd Perfect Numbers Simon Davis Research Foundation of Southern California 8861 Villa La Jolla Drive #13595 La Jolla, CA 92037 Abstract. It is sufficient to prove that there is an excess of prime factors in the product of repunits with odd prime bases defined by the sum of divisors of the integer N = (4k + 4m+1 ℓ 2αi 1) i=1 qi to establish that there do not exist any odd integers with equality (4k+1)4m+2−1 between σ(N) and 2N. The existence of distinct prime divisors in the repunits 4k , 2α +1 Q q i −1 i , i = 1,...,ℓ, in σ(N) follows from a theorem on the primitive divisors of the Lucas qi−1 sequences and the square root of the product of 2(4k + 1), and the sequence of repunits will not be rational unless the primes are matched. Minimization of the number of prime divisors in σ(N) yields an infinite set of repunits of increasing magnitude or prime equations with no integer solutions. MSC: 11D61, 11K65 Keywords: prime divisors, rationality condition 1. Introduction While even perfect numbers were known to be given by 2p−1(2p − 1), for 2p − 1 prime, the universality of this result led to the the problem of characterizing any other possible types of perfect numbers. It was suggested initially by Descartes that it was not likely that odd integers could be perfect numbers [13]. After the work of de Bessy [3], Euler proved σ(N) that the condition = 2, where σ(N) = d|N d is the sum-of-divisors function, N d integer 4m+1 2α1 2αℓ restricted odd integers to have the form (4kP+ 1) q1 ...qℓ , with 4k + 1, q1,...,qℓ prime [18], and further, that there might exist no set of prime bases such that the perfect number condition was satisfied. -
Input for Carnival of Math: Number 115, October 2014
Input for Carnival of Math: Number 115, October 2014 I visited Singapore in 1996 and the people were very kind to me. So I though this might be a little payback for their kindness. Good Luck. David Brooks The “Mathematical Association of America” (http://maanumberaday.blogspot.com/2009/11/115.html ) notes that: 115 = 5 x 23. 115 = 23 x (2 + 3). 115 has a unique representation as a sum of three squares: 3 2 + 5 2 + 9 2 = 115. 115 is the smallest three-digit integer, abc , such that ( abc )/( a*b*c) is prime : 115/5 = 23. STS-115 was a space shuttle mission to the International Space Station flown by the space shuttle Atlantis on Sept. 9, 2006. The “Online Encyclopedia of Integer Sequences” (http://www.oeis.org) notes that 115 is a tridecagonal (or 13-gonal) number. Also, 115 is the number of rooted trees with 8 vertices (or nodes). If you do a search for 115 on the OEIS website you will find out that there are 7,041 integer sequences that contain the number 115. The website “Positive Integers” (http://www.positiveintegers.org/115) notes that 115 is a palindromic and repdigit number when written in base 22 (5522). The website “Number Gossip” (http://www.numbergossip.com) notes that: 115 is the smallest three-digit integer, abc, such that (abc)/(a*b*c) is prime. It also notes that 115 is a composite, deficient, lucky, odd odious and square-free number. The website “Numbers Aplenty” (http://www.numbersaplenty.com/115) notes that: It has 4 divisors, whose sum is σ = 144. -
And Its Properties on the Sequence Related to Lucas Numbers
Mathematica Aeterna, Vol. 2, 2012, no. 1, 63 - 75 On the sequence related to Lucas numbers and its properties Cennet Bolat Department of Mathematics, Art and Science Faculty, Mustafa Kemal University, 31034, Hatay,Turkey Ahmet I˙pek Department of Mathematics, Art and Science Faculty, Mustafa Kemal University, 31034, Hatay,Turkey Hasan Köse Department of Mathematics, Science Faculty, Selcuk University 42031, Konya,Turkey Abstract The Fibonacci sequence has been generalized in many ways, some by preserving the initial conditions, and others by preserving the recur- rence relation. In this article, we study a new generalization {Lk,n}, with initial conditions Lk,0 = 2 and Lk,1 = 1, which is generated by the recurrence relation Lk,n = kLk,n−1 + Lk,n−2 for n ≥ 2, where k is integer number. Some well-known sequence are special case of this generalization. The Lucas sequence is a special case of {Lk,n} with k = 1. Modified Pell-Lucas sequence is {Lk,n} with k = 2. We produce an extended Binet’s formula for {Lk,n} and, thereby, identities such as Cassini’s, Catalan’s, d’Ocagne’s, etc. using matrix algebra. Moreover, we present sum formulas concerning this new generalization. Mathematics Subject Classi…cation: 11B39, 15A23. Keywords: Classic Fibonacci numbers; Classic Lucas numbers; k-Fibonacci numbers; k-Lucas numbers, Matrix algebra. 64 C. Bolat, A. Ipek and H. Kose 1 Introduction In recent years, many interesting properties of classic Fibonacci numbers, clas- sic Lucas numbers and their generalizations have been shown by researchers and applied to almost every …eld of science and art. -
On Repdigits As Product of Consecutive Fibonacci Numbers1
Rend. Istit. Mat. Univ. Trieste Volume 44 (2012), 393–397 On repdigits as product of consecutive Fibonacci numbers1 Diego Marques and Alain Togbe´ Abstract. Let (Fn)n≥0 be the Fibonacci sequence. In 2000, F. Luca proved that F10 = 55 is the largest repdigit (i.e. a number with only one distinct digit in its decimal expansion) in the Fibonacci sequence. In this note, we show that if Fn ··· Fn+(k−1) is a repdigit, with at least two digits, then (k, n) = (1, 10). Keywords: Fibonacci, repdigits, sequences (mod m) MS Classification 2010: 11A63, 11B39, 11B50 1. Introduction Let (Fn)n≥0 be the Fibonacci sequence given by Fn+2 = Fn+1 + Fn, for n ≥ 0, where F0 = 0 and F1 = 1. These numbers are well-known for possessing amaz- ing properties. In 1963, the Fibonacci Association was created to provide an opportunity to share ideas about these intriguing numbers and their applica- tions. We remark that, in 2003, Bugeaud et al. [2] proved that the only perfect powers in the Fibonacci sequence are 0, 1, 8 and 144 (see [6] for the Fibono- mial version). In 2005, Luca and Shorey [5] showed, among other things, that a non-zero product of two or more consecutive Fibonacci numbers is never a perfect power except for the trivial case F1 · F2 = 1. Recall that a positive integer is called a repdigit if it has only one distinct digit in its decimal expansion. In particular, such a number has the form a(10m − 1)/9, for some m ≥ 1 and 1 ≤ a ≤ 9. -
Product of Consecutive Tribonacci Numbers with Only One Distinct Digit
1 2 Journal of Integer Sequences, Vol. 22 (2019), 3 Article 19.6.3 47 6 23 11 Product of Consecutive Tribonacci Numbers With Only One Distinct Digit Eric F. Bravo and Carlos A. G´omez Department of Mathematics Universidad del Valle Calle 13 No 100 – 00 Cali Colombia [email protected] [email protected] Florian Luca School of Mathematics University of the Witwatersrand Johannesburg South Africa and Research Group in Algebraic Structures and Applications King Abdulaziz University Jeddah Saudi Arabia and Department of Mathematics University of Ostrava 30 Dubna 22, 701 03 Ostrava 1 Czech Republic [email protected] Abstract Let (Fn)n≥0 be the sequence of Fibonacci numbers. Marques and Togb´eproved that if the product Fn ··· Fn+ℓ−1 is a repdigit (i.e., a number with only distinct digit 1 in its decimal expansion), with at least two digits, then (ℓ,n)=(1, 10). In this paper, we solve the same problem with Tribonacci numbers instead of Fibonacci numbers. 1 Introduction A positive integer is called a repdigit if it has only one distinct digit in its decimal expansion. The sequence of numbers with repeated digits is included in Sloane’s On-Line Encyclopedia of Integer Sequences (OEIS) [11] as sequence A010785. In 2000, Luca [6] showed that the largest repdigit Fibonacci number is F10 = 55 and the largest repdigit Lucas number is L5 = 11. Motivated by the results of Luca [6], several authors have explored repdigits in general- izations of Fibonacci numbers and Lucas numbers. For instance, Bravo and Luca [1] showed 1 (3) that the only repdigit in the k-generalized Fibonacci sequence , is F8 = 44. -
Enciclopedia Matematica a Claselor De Numere Întregi
THE MATH ENCYCLOPEDIA OF SMARANDACHE TYPE NOTIONS vol. I. NUMBER THEORY Marius Coman INTRODUCTION About the works of Florentin Smarandache have been written a lot of books (he himself wrote dozens of books and articles regarding math, physics, literature, philosophy). Being a globally recognized personality in both mathematics (there are countless functions and concepts that bear his name), it is natural that the volume of writings about his research is huge. What we try to do with this encyclopedia is to gather together as much as we can both from Smarandache’s mathematical work and the works of many mathematicians around the world inspired by the Smarandache notions. Because this is too vast to be covered in one book, we divide encyclopedia in more volumes. In this first volume of encyclopedia we try to synthesize his work in the field of number theory, one of the great Smarandache’s passions, a surfer on the ocean of numbers, to paraphrase the title of the book Surfing on the ocean of numbers – a few Smarandache notions and similar topics, by Henry Ibstedt. We quote from the introduction to the Smarandache’work “On new functions in number theory”, Moldova State University, Kishinev, 1999: “The performances in current mathematics, as the future discoveries, have, of course, their beginning in the oldest and the closest of philosophy branch of nathematics, the number theory. Mathematicians of all times have been, they still are, and they will be drawn to the beaty and variety of specific problems of this branch of mathematics. Queen of mathematics, which is the queen of sciences, as Gauss said, the number theory is shining with its light and attractions, fascinating and facilitating for us the knowledge of the laws that govern the macrocosm and the microcosm”. -
On Repdigits As Sums of Fibonacci and Tribonacci Numbers
S S symmetry Article On Repdigits as Sums of Fibonacci and Tribonacci Numbers Pavel Trojovský Department of Mathematics, Faculty of Science, University of Hradec Králové, 500 03 Hradec Králové, Czech Republic; [email protected]; Tel.: +42-049-333-2860 Received: 17 September 2020; Accepted: 21 October 2020; Published: 26 October 2020 Abstract: In this paper, we use Baker’s theory for nonzero linear forms in logarithms of algebraic numbers and a Baker-Davenport reduction procedure to find all repdigits (i.e., numbers with only one distinct digit in its decimal expansion, thus they can be seen as the easiest case of palindromic numbers, which are a “symmetrical” type of numbers) that can be written in the form Fn + Tn, for some n ≥ 1, where (Fn)n≥0 and (Tn)n≥0 are the sequences of Fibonacci and Tribonacci numbers, respectively. Keywords: Diophantine equations; repdigits; Fibonacci; Tribonacci; Baker’s theory MSC: 11B39; 11J86 1. Introduction A palindromic number is a number that has the same form when written forwards or backwards, i.e., of the form c1c2c3 ... c3c2c1 (thus it can be said that they are “symmetrical” with respect to an axis of symmetry). The first 19th palindromic numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99 and clearly they are a repdigits type. A number n is called repdigit if it has only one repeated digit in its decimal expansion. More precisely, n has the form ! 10` − 1 n = a , 9 for some ` ≥ 1 and a 2 [1, 9] (as usual, we set [a, b] = fa, a + 1, .. -
Arxiv:1606.08690V5 [Math.NT] 27 Apr 2021 on Prime Factors of Mersenne
On prime factors of Mersenne numbers Ady Cambraia Jr,∗ Michael P. Knapp,† Ab´ılio Lemos∗, B. K. Moriya∗ and Paulo H. A. Rodrigues‡ [email protected] [email protected] [email protected] [email protected] paulo [email protected] April 29, 2021 Abstract n Let (Mn)n≥0 be the Mersenne sequence defined by Mn = 2 − 1. Let ω(n) be the number of distinct prime divisors of n. In this short note, we present a description of the Mersenne numbers satisfying ω(Mn) ≤ 3. Moreover, we prove that the inequality, (1−ǫ) log log n given ǫ> 0, ω(Mn) > 2 − 3 holds for almost all positive integers n. Besides, a we present the integer solutions (m, n, a) of the equation Mm+Mn = 2p with m,n ≥ 2, p an odd prime number and a a positive integer. 2010 Mathematics Subject Classification: 11A99, 11K65, 11A41. Keywords: Mersenne numbers, arithmetic functions, prime divisors. 1 Introduction arXiv:1606.08690v5 [math.NT] 27 Apr 2021 n Let (Mn)n≥0 be the Mersenne sequence defined by Mn = 2 − 1, for n ≥ 0. A simple argument shows that if Mn is a prime number, then n is a prime number. When Mn is a prime number, it is called a Mersenne prime. Throughout history, many researchers sought to find Mersenne primes. Some tools are very important for the search for Mersenne primes, mainly the Lucas-Lehmer test. There are papers (see for example [1, 5, 21]) that seek to describe the prime factors of Mn, where Mn is a composite number and n is a prime number. -
Prime and Perfect Numbers
Chapter 34 Prime and perfect numbers 34.1 Infinitude of prime numbers 34.1.1 Euclid’s proof If there were only finitely many primes: 2, 3, 5, 7, ...,P, and no more, consider the number Q = (2 3 5 P ) + 1. · · ··· Clearly it is divisible by any of the primes 2, 3,..., P , it must be itself a prime, or be divisible by some prime not in the list. This contradicts the assumption that all primes are among 2, 3, 5,..., P . 34.1.2 Fermat numbers 2n The Fermat numbers are Fn := 2 + 1. Note that 2n 2n−1 2n−1 Fn 2 = 2 1= 2 + 1 2 1 = Fn 1(Fn 1 2). − − − − − − By induction, Fn = Fn 1Fn 2 F1 F0 + 2, n 1. − − ··· · ≥ From this, we see that Fn does not contain any factor of F0, F1, ..., Fn 1. Hence, the Fermat numbers are pairwise relatively prime. From this,− it follows that there are infinitely primes. 1 1 It is well known that Fermat’s conjecture of the primality of Fn is wrong. While F0 = 3, F1 = 5, 32 F2 = 17, F3 = 257, and F4 = 65537 are primes, Euler found that F5 = 2 + 1 = 4294967297 = 641 6700417. × 1202 Prime and perfect numbers 34.2 The prime numbers below 20000 The first 2262 prime numbers: 10 20 30 40 50 60 70 80 90 100 bbbbbb bb bbb b bb bb b bb b bb bb bb b b b b bb b b b b b b b b b b b b b b b bb b b b b b b b b b b b b b b b b bb b b b b bb b b b b b bb b b b b b b b b b b b b b b b b b b bb b b b b b b b b bb b b b bb b b b b b b b b b b b b bb b b b b b b b b b bb b b b b b b b b b b b b b b b b b b bb b b bb b b b b bb b b b b b b b b b b b b b 100 b b bb b bb b bb b b b b bb b b b b b bb b b b b b b b bb b bb b b b b b bb b b b -
Tribonacci Numbers That Are Concatenations of Two Repdigits
TRIBONACCI NUMBERS THAT ARE CONCATENATIONS OF TWO REPDIGITS MAHADI DDAMULIRA Abstract. Let (Tn)n≥0 be the sequence of Tribonacci numbers defined by T0 = 0, T1 = T2 = 1, and Tn+3 = Tn+2 + Tn+1 + Tn for all n ≥ 0. In this note, we use of lower bounds for linear forms in logarithms of algebraic numbers and the Baker- Davenport reduction procedure to find all Tribonacci numbers that are concatenations of two repdigits. 1. Introduction A repdigit is a positive integer R that has only one distinct digit when written in its decimal expansion. That is, R is of the form 10` − 1 (1) R = d ··· d = d ; | {z } 9 ` times for some positive integers d; ` with ` ≥ 1 and 0 ≤ d ≤ 9. The sequence of repdigits is sequence A010785 on the On-Line Encyclopedia of Integer Sequences (OEIS) [6]. Consider the sequence (Tn)n≥0 of Tribonacci numbers given by T0 = 0;T1 = 1;T2 = 1; and Tn+3 = Tn+2 + Tn+1 + Tn for all n ≥ 0: The sequence of Tribonacci numbers is sequence A000073 on the OEIS. The first few terms of this sequence are given by (Tn)n≥0 = 0; 1; 1; 2; 4; 7; 13; 24; 44; 81; 149; 274; 504; 927; 1705; 3136; 5768; 10609; 19513;:::: 2. Main Result In this paper, we study the problem of finding all Tribonacci numbers that are concate- nations of two repdigits. More precisely, we completely solve the Diophantine equation 10`1 − 1 10`2 − 1 `2 (2) Tn = d1 ··· d1 d2 ··· d2 = d1 × 10 + d2 ; | {z } | {z } 9 9 `1 times `2 times in non-negative integers (n; d1; d2; `1; `2) with n ≥ 0, `1 ≥ `2 ≥ 1, and 0 ≤ d2 < d1 ≤ 9. -
Repdigits As Sums of Two Generalized Lucas Numbers
Turkish Journal of Mathematics Turk J Math (2021) 45: 1166 – 1179 http://journals.tubitak.gov.tr/math/ © TÜBİTAK Research Article doi:10.3906/mat-2011-59 Repdigits as sums of two generalized Lucas numbers Sai Gopal RAYAGURU1;∗, Jhon Jairo BRAVO2 1Department of Mathematics, National Institute of Technology Rourkela, Odisha, India 2Department of Mathematics, University of Cauca, Popayán, Colombia Received: 18.11.2020 • Accepted/Published Online: 20.03.2021 • Final Version: 20.05.2021 Abstract: A generalization of the well–known Lucas sequence is the k -Lucas sequence with some fixed integer k ≥ 2. The first k terms of this sequence are 0;:::; 0; 2; 1, and each term afterwards is the sum of the preceding k terms. In this paper, we determine all repdigits, which are expressible as sums of two k -Lucas numbers. This work generalizes a prior result of Şiar and Keskin who dealt with the above problem for the particular case of Lucas numbers and a result of Bravo and Luca who searched for repdigits that are k -Lucas numbers. Key words: Generalized Lucas number, repdigit, linear form in logarithms, reduction method 1. Introduction For an integer k ≥ 2, let the k -generalized Fibonacci sequence (or simply, the k -Fibonacci sequence) F (k) := (k) (Fn )n≥2−k be defined by the linear recurrence sequence of order k (k) (k) (k) ··· (k) ≥ Fn = Fn−1 + Fn−2 + + Fn−k for all n 2; (k) (k) ··· (k) (k) with initial conditions F−(k−2) = F−(k−3) = = F0 = 0 and F1 = 1. The above sequence is one among the several generalizations of the Fibonacci sequence (Fn)n≥0 . -
Arxiv:2001.11839V1 [Math.CO] 30 Jan 2020 Ihiiilvalues Initial with Ubr Aebcm N Ftems Oua Eune Ostudy by to Denoted Sequences Numbers, Combinatorics
SOME RESULTS ON AVERAGE OF FIBONACCI AND LUCAS SEQUENCES DANIEL YAQUBI AND AMIRALI FATEHIZADEH Abstract. The numerical sequence in which the n-th term is the average (that is, arithmetic mean) of the of the first n Fibonacci numbers may be found in the OEIS (see A111035 ). An interesting question one might pose is which terms of the sequences n ∞ n ∞ 1 1 Fi and Li (0.1) n i=1 n=1 n i=1 n=1 X X are integers? The average of the first three Fibonacci sequence, (1 + 1 + 3)/3=4/3, is not whereas the 24 Pi=1 Fi average of the first 24 Fibonacci sequence, 24 = 5058 is. In this paper, we address this question and also present some properties of average Fibonacci and Lucas numbers using the Wall-Sun-Sun prime conjecture. 1. Introduction Fibonacci numbers originally arose in a problem in Liber Abaci, published in 1202, which was one of the first texts to describe the Hindu-Arabic numeral system. Since then Fibonacci numbers have become one of the most popular sequences to study, appearing in a wealth of problems not only in enumerative combinatorics. The Fibonacci numbers, denoted by F ∞ , are defined by the following recurrence relation { n}n=0 Fn+1 = Fn + Fn 1, (1.1) − with initial values F0 = 0 and F1 = 1 . The first elements of this sequence are given in (A000045 ), as 0 1 1 2 3 5 8 13 21 .... arXiv:2001.11839v1 [math.CO] 30 Jan 2020 The Fibonacci numbers are closely related to binomial coefficients; it is a well-known fact that they are given by the sums of the rising diagonal lines of Pascal’s triangle (see [1]) n ⌊ 2 ⌋ n i F = − .