Honors Benchmark 1 2012

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Honors Benchmark 1 2012

Honors Benchmark 1 2012

Multiple Choice Identify the choice that best completes the statement or answers the question.

____ 1. Which statement is true? a. All quadrilaterals are rectangles. b. All quadrilaterals are squares. c. All rectangles are quadrilaterals. d. All quadrilaterals are parallelograms. ____ 2. Which Venn diagram is NOT correct? a. c.

Rhombuses Quadrilaterals

Squares Kites

b. d.

Squares Parallelograms

Rectangles Rhombuses

____ 3. Lucinda wants to build a square sandbox, but has no way of measuring angles. Explain how she can make sure that the sandbox is square by only measuring length. a. Arrange four equal-length sides so the diagonals bisect each other. b. Arrange four equal-length sides so the diagonals are equal lengths also. c. Make each diagonal the same length as four equal-length sides. d. Not possible; Lucinda has to be able to measure a right angle. ____ 4. Which description does NOT guarantee that a quadrilateral is a parallelogram? a. a quadrilateral with both pairs of opposite sides congruent b. a quadrilateral with the diagonals bisecting each other c. a quadrilateral with consecutive angles supplementary d. quadrilateral with two opposite sides parallel ____ 5. Which description does NOT guarantee that a trapezoid is isoscles? a. congruent diagonals b. both pairs of base angles congruent c. congruent bases d. congruent legs

Short Answer

6. Write the tangent ratios for and . P

29 21

R Q 20

Not drawn to scale

7. Write the tangent ratios for and . Z

85 7

X Y 6

Not drawn to scale

Find the value of x. Round your answer to the nearest tenth.

 7 8. x

Not drawn to scale  x 9. 9

Not drawn to scale

8.9 cm

10. x



Find the value of x to the nearest degree.

19

11 11. x

Not drawn to scale

58 12. 3 x

13. The students in Mr. Collin’s class used a surveyor’s measuring device to find the angle from their location to the top of a building. They also measured their distance from the bottom of the building. The diagram shows the angle measure and the distance. To the nearest foot, find the height of the building. Building

 100 ft

14. A large totem pole in the state of Washington is 100 feet tall. At a particular time of day, the totem pole casts a 249-foot-long shadow. Find the measure of to the nearest degree.

100 ft

A 249 ft

15. Find the value of w, then x. Round lengths of segments to the nearest tenth.

12

  w x

16. Find the missing value to the nearest tenth. tan = 45

17. Write the ratios for sin A and cos A. A

5 4

C B 3

Not drawn to scale Find the value of x. Round to the nearest tenth.

x

18.  11

Not drawn to scale

Find the value of x. Round to the nearest degree.

7

19. 15 x

Not drawn to scale

21

20. x 15

Not drawn to scale

21. Viola drives 170 meters up a hill that makes an angle of 6 with the horizontal. To the nearest tenth of a meter, what horizontal distance has she covered?

Find the value of x. Round the length to the nearest tenth.

 x 200 m

22.

Not drawn to scale 

x

23. 18 yd

Not drawn to scale

24. LMNO is a parallelogram. If NM = x + 15 and OL = 3x + 5 find the value of x and then find NM and OL.

O N

L M

25. Find the values of the variables in the parallelogram. The diagram is not to scale.

29 102

y° z° x°

26. In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 4x – 5, and HE = 2y + 3. Find the values of x and y. The diagram is not to scale.

D E

H

G F

27. Find AM in the parallelogram if PN =9 and AO = 4. The diagram is not to scale. M N

A

P O

28. Find values of x and y for which ABCD must be a parallelogram. The diagram is not to scale.

A B

4x – 2

y + 14

4y – 7

x + 28

D C

29. Based on the information in the diagram, can you prove that the figure is a parallelogram? Explain.

30. Based on the information given, can you determine that the quadrilateral must be a parallelogram? Explain.

Given: and X Y

N

W Z

31. If and find the values of x and y for which LMNO must be a parallelogram. The diagram is not to scale.

O N

L M

32. If find so that quadrilateral ABCD is a parallelogram. The diagram is not to scale.

A B

D C

33. In the rhombus, Find the value of each variable. The diagram is not to scale.

3

2 1

34. DEFG is a rectangle. DF = 5x – 5 and EG = x + 11. Find the value of x and the length of each diagonal.

35. Find the values of a and b.The diagram is not to scale. a° 113°

36° b°

36. The isosceles trapezoid is part of an isosceles triangle with a 46° vertex angle. What is the measure of an acute base angle of the trapezoid? Of an obtuse base angle? The diagram is not to scale.

37. are base angles of isosceles trapezoid JKLM. If and

38. and Find The diagram is not to scale. R

U S

T

39. In quadrilateral MNOP, Which of a parallelogram, trapezoid, or rhombus could quadrilateral MNOP be?

40. The vertices of the trapezoid are the origin along with A(4m, 4n), B(4q, 4n), and C(4p, 0). Find the midpoint of the midsegment of the trapezoid. y

A B

(0, 0) C x

41. A highway makes an angle of 6 with the horizontal. This angle is maintained for a horizontal distance of 8 miles. a. Draw and label a diagram to represent this situation. b. To the nearest hundredth of a mile, how high does the highway rise in this 8-mile section? Show the steps you use to find the distance.

42. A forest ranger spots a fire from a 21-foot tower. The angle of depression from the tower to the fire is 12 . a. Draw a diagram to represent this situation. b. To the nearest foot, how far is the fire from the base of the tower? Show the steps you use to find the solution.

43. Find the values of the variables and the lengths of the sides of this rectangle. The diagram is not to scale. 5x

2x + 6 5y

7y + 7

44. What type of quadrilateral has exactly one pair of parallel sides?

45. Isosceles trapezoid ABCD has legs and and base If AB = 4y – 3, BC = 3y – 4, and CD = 5y – 10, find the value of y.

46. Find the lengths of the diagonals of this trapezoid. y

(–b, c) (b, c)

(–a, 0) O (a, 0) x Essay

47. From the top of a 210-foot lighthouse located at sea level, a boat is spotted at an angle of depression of 23 . a. Draw a sketch to represent this situation. b. Use the angle of depression to find the distance from the base of the lighthouse to the boat. Explain your steps in finding the distance. c. Use another angle to verify the distance you found in part (b). Explain your steps in finding the distance and tell why your method works. d. Use the Pythagorean Theorem to find the shortest distance from the top of the lighthouse to the boat. Explain your steps in finding this distance.

48. Use this triangle.

 7 in.



a. Find the length of the hypotenuse using the special relationships for a 45 -45 -90 triangle. Explain the relationships. b. Write the exact value for sin 45 as a fraction in simplest form. c. Use the formula for the area of a triangle given SAS to find the area of the triangle. Explain your steps. d. Use a different method to find the area of the triangle. Explain your steps.

Other

49. Is the quadrilateral a parallelogram? Explain. The diagram is not to scale.

A B 139°

41° 139° C D

50. Give a convincing argument that quadrilateral ABCD with A(–3, –4), B(0, –2), C(6, –2), and D(3, –4) is a parallelogram. Honors Benchmark 1 2012 Answer Section

MULTIPLE CHOICE

1. ANS: C PTS: 1 DIF: L1 REF: 6-1 Classifying Quadrilaterals OBJ: 6-1.1 Classifying Special Quadrilaterals NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 | AL 12 | AL GE VII-4 KEY: reasoning | kite | parallelogram | quadrilateral | rectangle | rhombus | special quadrilaterals MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 2. ANS: B PTS: 1 DIF: L1 REF: 6-1 Classifying Quadrilaterals OBJ: 6-1.1 Classifying Special Quadrilaterals NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 | AL 12 | AL GE VII-4 KEY: reasoning | quadrilateral | Venn Diagram MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 NOT: TC 12, MC, Static. 3. ANS: B PTS: 1 DIF: L2 REF: 6-4 Special Parallelograms OBJ: 6-4.2 Is the Parallelogram a Rhombus or a Rectangle? NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 TOP: 6-4 Example 4 KEY: square | reasoning | Theorem 6-10 | Theorem 6-11 | word problem | problem solving MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 4. ANS: D PTS: 1 DIF: L2 REF: 6-4 Special Parallelograms OBJ: 6-4.2 Is the Parallelogram a Rhombus or a Rectangle? NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 KEY: square | reasoning MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 5. ANS: C PTS: 1 DIF: L3 REF: 6-5 Trapezoids and Kites OBJ: 6-5.1 Properties of Trapezoids and Kites NAT: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 STA: AL 3 | AL 5 | AL 9 KEY: trapezoid | isosceles trapezoid | reasoning MSC: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14

SHORT ANSWER

6. ANS: PTS: 1 DIF: L1 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 1 KEY: tangent ratio | tangent | leg opposite angle | leg adjacent to angle MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 7. ANS:

PTS: 1 DIF: L2 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 1 KEY: leg adjacent to angle | leg opposite angle | tangent | tangent ratio MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 8. ANS: 4

PTS: 1 DIF: L1 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 2 KEY: side length using tangent | tangent | tangent ratio MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 9. ANS: 24.7

PTS: 1 DIF: L1 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 2 KEY: side length using tangent | tangent | tangent ratio MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 10. ANS: 6.2 cm

PTS: 1 DIF: L2 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 2 KEY: side length using tangent | tangent | tangent ratio MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 11. ANS: 60

PTS: 1 DIF: L1 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 3 KEY: inverse of tangent | tangent | tangent ratio | angle measure using tangent MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 12. ANS: 22

PTS: 1 DIF: L2 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 3 KEY: inverse of tangent | tangent | tangent ratio | angle measure using tangent MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 13. ANS: 308 ft

PTS: 1 DIF: L1 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 2 KEY: problem solving | word problem | tangent | side length using tangent | tangent ratio MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 14. ANS: 22

PTS: 1 DIF: L2 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 3 KEY: angle measure using tangent | word problem | problem solving | tangent | inverse of tangent | tangent ratio MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 15. ANS: w = 13.3, x = 10.2

PTS: 1 DIF: L2 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 2 KEY: tangent | side length using tangent | tangent ratio | problem solving MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 16. ANS: 49.4

PTS: 1 DIF: L2 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 3 KEY: angle measure using tangent MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 17. ANS:

PTS: 1 DIF: L1 REF: 9-2 Sine and Cosine Ratios OBJ: 9-2.1 Using Sine and Cosine in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-2 Example 1 KEY: sine | cosine | sine ratio | cosine ratio MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 18. ANS: 12.5

PTS: 1 DIF: L1 REF: 9-2 Sine and Cosine Ratios OBJ: 9-2.1 Using Sine and Cosine in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-2 Example 2 KEY: cosine | side length using since and cosine | cosine ratio MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 19. ANS: 28

PTS: 1 DIF: L1 REF: 9-2 Sine and Cosine Ratios OBJ: 9-2.1 Using Sine and Cosine in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-2 Example 3 KEY: inverse of cosine and sine | angle measure using sine and cosine | sine MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 20. ANS: 44

PTS: 1 DIF: L1 REF: 9-2 Sine and Cosine Ratios OBJ: 9-2.1 Using Sine and Cosine in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-2 Example 3 KEY: inverse of cosine and sine | angle measure using sine and cosine | cosine MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 21. ANS: 169.1 m PTS: 1 DIF: L2 REF: 9-2 Sine and Cosine Ratios OBJ: 9-2.1 Using Sine and Cosine in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-2 Example 2 KEY: cosine | word problem | side length using since and cosine | problem solving | cosine ratio MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 22. ANS: 1151.8 m

PTS: 1 DIF: L1 REF: 9-3 Angles of Elevation and Depression OBJ: 9-3.1 Using Angles of Elevation and Depression NAT: NAEP M1k | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 STA: AL 9 | AL 10 | AL GE VII-1 TOP: 9-3 Example 3 KEY: sine | side length using since and cosine | sine ratio | angles of elevation and depression MSC: NAEP M1k | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 23. ANS: 10.4 yd

PTS: 1 DIF: L1 REF: 9-3 Angles of Elevation and Depression OBJ: 9-3.1 Using Angles of Elevation and Depression NAT: NAEP M1k | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 STA: AL 9 | AL 10 | AL GE VII-1 TOP: 9-3 Example 3 KEY: tangent | side length using tangent | tangent ratio | angles of elevation and depression MSC: NAEP M1k | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 24. ANS: x = 5, NM = 20, OL = 20

PTS: 1 DIF: L1 REF: 6-2 Properties of Parallelograms OBJ: 6-2.1 Properties: Sides and Angles NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 TOP: 6-2 Example 2 KEY: parallelogram | algebra | Theorem 6-1 MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.16 25. ANS:

PTS: 1 DIF: L1 REF: 6-2 Properties of Parallelograms OBJ: 6-2.1 Properties: Sides and Angles NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 KEY: parallelogram | opposite angles | consectutive angles | transversal MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.16 26. ANS: x = 3, y = 2

PTS: 1 DIF: L1 REF: 6-2 Properties of Parallelograms OBJ: 6-2.2 Properties: Diagonals and Transversals NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 TOP: 6-2 Example 3 KEY: transversal | diagonal | parallelogram | Theorem 6-3 | algebra MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.16 27. ANS: 4

PTS: 1 DIF: L1 REF: 6-2 Properties of Parallelograms OBJ: 6-2.2 Properties: Diagonals and Transversals NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 KEY: parallelogram | diagonal | Theorem 6-3 MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.16 28. ANS: x = 10, y = 7

PTS: 1 DIF: L1 REF: 6-3 Proving That a Quadrilateral is a Parallelogram OBJ: 6-3.1 Is the Quadrilateral a Parallelogram? NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 STA: AL 3 | AL 5 | AL 9 | AL GE VII-1 TOP: 6-3 Example 1 KEY: algebra | parallelogram | Theorem 6-5 | diagonal MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 29. ANS: Yes; opposite angles are congruent.

PTS: 1 DIF: L1 REF: 6-3 Proving That a Quadrilateral is a Parallelogram OBJ: 6-3.1 Is the Quadrilateral a Parallelogram? NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 STA: AL 3 | AL 5 | AL 9 | AL GE VII-1 TOP: 6-3 Example 2 KEY: opposite angles | parallelogram | Theorem 6-8 MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 30. ANS: Yes; opposite sides are congruent.

PTS: 1 DIF: L1 REF: 6-3 Proving That a Quadrilateral is a Parallelogram OBJ: 6-3.1 Is the Quadrilateral a Parallelogram? NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 STA: AL 3 | AL 5 | AL 9 | AL GE VII-1 TOP: 6-3 Example 2 KEY: parallelogram | opposite sides | Theorem 6-7 MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 31. ANS: 5 x = 9, y = 2

PTS: 1 DIF: L1 REF: 6-3 Proving That a Quadrilateral is a Parallelogram OBJ: 6-3.1 Is the Quadrilateral a Parallelogram? NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 STA: AL 3 | AL 5 | AL 9 | AL GE VII-1 KEY: algebra | parallelogram | Theorem 6-7 | opposite sides MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 32. ANS: 139

PTS: 1 DIF: L1 REF: 6-3 Proving That a Quadrilateral is a Parallelogram OBJ: 6-3.1 Is the Quadrilateral a Parallelogram? NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 STA: AL 3 | AL 5 | AL 9 | AL GE VII-1 KEY: opposite angles | parallelogram | Theorem 6-8 MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 33. ANS: x = 6, y = 84, z = 10

PTS: 1 DIF: L1 REF: 6-4 Special Parallelograms OBJ: 6-4.1 Diagonals of Rhombuses and Rectangles NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 TOP: 6-4 Example 1 KEY: algebra | diagonal | rhombus | Theorem 6-13 MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 34. ANS: x = 4, DF = 15, EG = 15

PTS: 1 DIF: L1 REF: 6-4 Special Parallelograms OBJ: 6-4.1 Diagonals of Rhombuses and Rectangles NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 TOP: 6-4 Example 2 KEY: rectangle | algebra | Theorem 6-11 | diagonal MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 35. ANS:

PTS: 1 DIF: L1 REF: 6-5 Trapezoids and Kites OBJ: 6-5.1 Properties of Trapezoids and Kites NAT: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 STA: AL 3 | AL 5 | AL 9 TOP: 6-5 Example 1 KEY: trapezoid | base angles | Theorem 6-15 MSC: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 36. ANS: 67°; 113°

PTS: 1 DIF: L1 REF: 6-5 Trapezoids and Kites OBJ: 6-5.1 Properties of Trapezoids and Kites NAT: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 STA: AL 3 | AL 5 | AL 9 TOP: 6-5 Example 2 KEY: trapezoid | isosceles trapezoid | base angles | isosceles triangle MSC: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 37. ANS: 151

PTS: 1 DIF: L2 REF: 6-5 Trapezoids and Kites OBJ: 6-5.1 Properties of Trapezoids and Kites NAT: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 STA: AL 3 | AL 5 | AL 9 KEY: algebra | isosceles trapezoid | base angles | trapezoid | Theorem 6-15 MSC: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 38. ANS: 70

PTS: 1 DIF: L1 REF: 6-5 Trapezoids and Kites OBJ: 6-5.1 Properties of Trapezoids and Kites NAT: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 STA: AL 3 | AL 5 | AL 9 KEY: kite | sum of interior angles MSC: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 39. ANS: any of the three

PTS: 1 DIF: L2 REF: 6-5 Trapezoids and Kites OBJ: 6-5.1 Properties of Trapezoids and Kites NAT: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 STA: AL 3 | AL 5 | AL 9 KEY: quadrilateral | rectangle | rhombus | trapezoid | parallelogram | reasoning MSC: NAEP G3f | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.CP | S9.TSK2.GM | S10.TSK2.GM | TV.LV20.13 | TV.LV20.14 40. ANS: (m + q + p, 2n)

PTS: 1 DIF: L2 REF: 6-7 Proofs Using Coordinate Geometry OBJ: 6-7.1 Building Proofs in the Coordinate Plane NAT: NAEP G4d | NAEP G5a | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.14 | TV.LV20.17 | TV.LV20.52 STA: AL 9 KEY: algebra | coordinate plane | isosceles trapezoid | midsegment MSC: NAEP G4d | NAEP G5a | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.17 | TV.LV20.52 41. ANS: a. x  8 mi

b. = Use the tangent ratio.

x = Solve for x. x 0.84 The rise is about 0.84 miles.

PTS: 1 DIF: L2 REF: 9-1 The Tangent Ratio OBJ: 9-1.1 Using Tangents in Triangles NAT: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 STA: AL 9 | AL 10 | AL GE VI-1 | AL GE VII-4 TOP: 9-1 Example 2 KEY: problem solving | word problem | tangent | side length using tangent | tangent ratio | multi-part question MSC: NAEP M1m | CAT5.LV20.45 | CAT5.LV20.46 | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.DP | IT.LV16.FR | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.47 42. ANS: a. Ranger  21 ft

Fire x

b. = Use the tangent ratio.

x = Solve for x.

x 99 The fire is about 99 feet from the base of the tower.

PTS: 1 DIF: L2 REF: 9-3 Angles of Elevation and Depression OBJ: 9-3.1 Using Angles of Elevation and Depression NAT: NAEP M1k | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 STA: AL 9 | AL 10 | AL GE VII-1 TOP: 9-3 Example 2 KEY: side length using tangent | word problem | multi-part question | problem solving | tangent | angles of elevation and depression | tangent ratio MSC: NAEP M1k | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 43. ANS: x = 7, y = 4; 20, 35

PTS: 1 DIF: L2 REF: 6-1 Classifying Quadrilaterals OBJ: 6-1.1 Classifying Special Quadrilaterals NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 | AL 12 | AL GE VII-4 TOP: 6-1 Example 3 KEY: algebra | rectangle MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 44. ANS: trapezoid

PTS: 1 DIF: L1 REF: 6-1 Classifying Quadrilaterals OBJ: 6-1.1 Classifying Special Quadrilaterals NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 | AL 12 | AL GE VII-4 KEY: quadrilateral | reasoning | algebra | trapezoid | rhombus | square | parallelogram MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 45. ANS: 7

PTS: 1 DIF: L1 REF: 6-1 Classifying Quadrilaterals OBJ: 6-1.1 Classifying Special Quadrilaterals NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL 3 | AL 5 | AL 9 | AL 12 | AL GE VII-4 KEY: isosceles trapezoid | algebra MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 46. ANS: Each diagonal has length .

PTS: 1 DIF: L2 REF: 6-6 Placing Figures in the Coordinate Plane OBJ: 6-6.1 Naming Coordinates NAT: NAEP G4d | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.17 | TV.LV20.52 STA: AL 9 | AL 12 | AL GE VI-1 | AL GE VII-4 KEY: algebra | coordinate plane | isosceles trapezoid | trapezoid | diagonal MSC: NAEP G4d | CAT5.LV20.50 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.12 | TV.LV20.14 | TV.LV20.17 | TV.LV20.52

ESSAY

47. ANS: [4] a.

b. = Use the tangent ratio. = 210 Multiply each side by x.

= Divide each side by tan 23 . x 494.7 Use a calculator. The distance from the base of the lighthouse to the boat is about 494.7 feet. c. Since the measures of the acute angles of a right triangle add to 90 , you can use the other angle in the triangle to find the distance. The measure of the other acute angle is 90 – 23 , or 67 .

tan 67 = Use the tangent ratio. x = 210(tan 67 ) Multiply each side by 210. x 494.7 Use a calculator. d. The shortest distance from the top of the lighthouse to the boat is the hypotenuse of the right triangle with legs of length 210 feet and 494.7 feet. = Pythagorean Theorem = Substitute. 44,100 + 244,728 = Simplify. 288,828 = Simplify. 537.4 c Use a calculator. The shortest distance from the top of the lighthouse to the boat is about 537.4 feet. [3] one mathematical error or correct answers with incomplete explanations [2] two mathematical errors or correct answers with errors in explanation [1] correct answers with no explanation

PTS: 1 DIF: L3 REF: 9-3 Angles of Elevation and Depression OBJ: 9-3.1 Using Angles of Elevation and Depression NAT: NAEP M1k | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 STA: AL 9 | AL 10 | AL GE VII-1 KEY: extended response | word problem | side length using tangent | multi-part question | problem solving | rubric-based question | tangent | angles of elevation and depression | writing in math | tangent ratio MSC: NAEP M1k | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 48. ANS: [4] a. In a 45 -45 -90 triangle, the length of the hypotenuse is the length of the short leg times , so the length of the hypotenuse is 7 in. b. The exact value of sin 45 is = = .

c. Area of a triangle =

= b = 7, c = 7 , A = 45

= Simplify. = 24.5 The area of the triangle is 24.5 in. . d. Another formula for the area of a triangle if the base length and height are known is . For this triangle, b = 7 and h = 7 since they are the legs of a right triangle. A =

= b = 7, h = 7 = Simplify.

= 24.5 The area of the triangle is 24.5 in. . one mathematical error or correct answers with incomplete explanations two mathematical errors or correct answers with errors in explanation correct answers with no explanation

PTS: 1 DIF: L2 REF: 9-5 Trigonometry and Area OBJ: 9-5.2 Finding the Area of a Triangle NAT: NAEP M1h | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 STA: AL GE IV-1 TOP: 9-5 Example 3 KEY: 45-45-90 triangle | area | area of a triangle | extended response | multi-part question | problem solving | rubric-based question | sine | writing in math MSC: NAEP M1h | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16

OTHER

49. ANS: Yes. is supplementary to both and since 41 + 139 = 180. So and ABCD is a parallelogram.

PTS: 1 DIF: L2 REF: 6-3 Proving That a Quadrilateral is a Parallelogram OBJ: 6-3.1 Is the Quadrilateral a Parallelogram? NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 STA: AL 3 | AL 5 | AL 9 | AL GE VII-1 KEY: parallelogram | reasoning | writing in math MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 50. ANS: 2 Slope of is . 3 2 Slope of is . 3 Slope of is 0. Slope of is 0.

and . Therefore ABCD is a parallelogram.

PTS: 1 DIF: L2 REF: 6-3 Proving That a Quadrilateral is a Parallelogram OBJ: 6-3.1 Is the Quadrilateral a Parallelogram? NAT: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18 STA: AL 3 | AL 5 | AL 9 | AL GE VII-1 KEY: parallelogram | coordinate plane | algebra | slope | writing in math MSC: NAEP G3f | CAT5.LV20.50 | CAT5.LV20.55 | CAT5.LV20.56 | IT.LV16.AM | IT.LV16.CP | IT.LV16.PS | S9.TSK2.GM | S9.TSK2.PRA | S10.TSK2.GM | S10.TSK2.PRA | TV.LV20.13 | TV.LV20.14 | TV.LV20.16 | TV.LV20.17 | TV.LV20.18

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