A.) How Many Moles of Aluminum Were Used? (Density Al = 2.699 G/Cm3)

Stoichiometry, Limiting Leader: Ryan Gale Reactants, and Chapter 4 Course: Chem 177 Supplemental Instruction Instructor: Miller/Bonaccorsi Iowa State University Date: 9/16/12

1.) A piece of aluminum foil 1.00 cm square and 0.550 mm thick is allowed to react with bromine to form aluminum bromide. a.) How many moles of aluminum were used? (density Al = 2.699 g/cm3)

b.) How many grams of aluminum bromide form, assuming the aluminum reacts completely? What type of reaction is this?

2.) Hydrogen sulfide is an impurity in natural gas that must be removed. The Claus process follows 8H2S(g)+ 4O2(g) → S8(l) + 8H2O(g) Under optimal conditions, this process gives 98% yield of S8 from H2S. If you started with 30.0 g of H2S and 50.0 g of O2, how many grams of S8 would be produced, assuming 98% yield?

3.) What kind of reaction are these? (and balance them) a.) N2(g) + H2(g) → NH3(g)

b.) NH4NO3(s) → N2O(g) + H2O(g)

c.) C3H6(g) + O2(g) → CO2(g) + H2O(g)

4.) Define the following terms: a.) Solubility

b.) Saturated solution

Supplemental Instruction 1060 Hixson-Lied Student Success Center v 294-6624 v www.si.iastate.edu c.) Unsaturated solution

d.) Solute

e.) Solvent

f.) Solution = ______+ ______

g.) Strong electrolyte

h.) Weak electrolyte

i.) Nonelectrolyte

5.) If you were to draw diagrams representing aqueous solutions of NiSO4, Ca(NO3)2, Na3PO4, and Al2(SO4)3, how many anions would you show if each diagram contained six (6) cations?

a.) NiSO4

b.) Ca(NO3)2

c.) Na3PO4

d.) Al2(SO4)3

6.) Molarity is the amount of SOLUTE in 1 L of SOLUTION. It represents molar concentration. Units are M = mol/L a.) Calculate the molarity of a solution made by dissolving 23.4 g of sodium sulfate in enough water to form 125 mL of solution.

b.) Calculate the molarity of a solution made by dissolving 5.00 g of glucose (C6H12O6) in sufficient water to form exactly 100 mL of solution.