Worksheet on Number Systems - Read Thoroughly
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Name:______Visual C++ Worksheet on Number Systems - Read thoroughly
CONVERTING TO BASE 10
Base ten has 10 symbols – 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
103 102 101 100 Place Value Thousands Hundreds Tens Ones Numeral 5 2 7 1
Multiply numeral by the place value This number equals five thousand, two hundred, seventy one, 5271
A. FROM BINARY – BASE 2
Base two has 2 symbols – 0 and 1 Multiply numeral by the place value
26 25 24 23 22 21 20 Place Value 64 32 16 8 4 2 1 Numeral 1 0 1 1 0 1 1
Multiply numeral by the place value to get the value in base 10 1 x 64 = 64 0 x 32 = 0 1 x 16 = 16 1 x 8 = 8 0 x 4 = 0 1 x 2 = 2 1 x 1 = 1 ------Then add 9110 base 10 value of 10110112 B. FROM OCTAL – BASE 8
Base eight has 8 symbols – 0, 1, 2, 3, 4, 5, 6, 7 Multiply numeral by the place value
83 82 81 80 Place Value 512 64 8 1 Numeral 3 1 7 4
Multiply numeral by the place value to get the value in base 10 3 x 512 = 1536 1 x 64 = 64 7 x 8 = 56 4 x 1 = 4 ------Then add 166010 base 10 value of 3174 8
C. FROM HEXADECIMAL – BASE 16
Base 16 has 16 symbols– 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F Multiply numeral by the place value
163 162 161 160 Place Value 4096 256 16 1 Numeral A 2 F C
Multiply numeral by the place value to get the value in base 10 A x 4096 = 10 x 4096 = 40960 2 x 256 = 512 F x 16 = 15 x 16 = 240 C x 1 = 12 x 1 = 12 ------Then add 4172410 base 10 value of A2FC 16 CONVERTING FROM BASE 10
D. CONVERT 60010 TO BINARY
METHOD 1 – USING DIVIDENDS – DIVIDE BY 2
600/2 =300 r 0 (r is remainder) 300/2 =150 r 0 150/2 =75 r 0 75/2 =37 r 1 37/2 =18 r 1 18/2 =9 r 0 9/2 =4 r 1 4/2 =2 r 0 2/2 =1 r 0 1/2= 0 r 1 Read remainders from the bottom up 60010 is 10010110002
Check: 29 28 27 26 25 24 23 22 21 20 Place Value 512 256 128 64 32 16 8 4 2 1 Numeral 1 0 0 1 0 1 1 0 0 0
512 + 64 + 16 + 8 = 600 It checks!
METHOD 2 – USING REMAINDERS – DIVIDE BY PLACE VALUE
29 28 27 26 25 24 23 22 21 20 Place Value 512 256 128 64 32 16 8 4 2 1
Choose largest place value that divides into 600 600/512 = 1 r 88 place a 1 in the 512 column cannot divide 88 by 256 or 128 so place 0s in those columns 88/64 = 1 r 24 place a 1 in the 64 column cannot divide 24 by 32 so put a 0 in the 32 column 24/16 = 1 r 8 put a 1 in the 16 column 8/8 = 1 r 0 put a 1 in the 8 column.
Done – no remainder!
29 28 27 26 25 24 23 22 21 20 Place Value 512 256 128 64 32 16 8 4 2 1 Numeral 1 0 0 1 0 1 1 0 0 0 E. CONVERT 60010 TO OCTAL
METHOD 1 – USING DIVIDENDS – DIVIDE BY 8
600/8 = 75 r 0 (r is remainder) 75/8 = 9 r 3 9/8 = 1 r 1 1/8 = 0 r 1
Read remainders from the bottom up 60010 is 11308
Check: 83 82 81 80 Place Value 512 64 8 1 Numeral 1 1 3 0
(1 x 512) + (1 x 64 ) + (3 x 8) = 512 + 64 + 24 = 600 ! It checks!
METHOD 2 – USING REMAINDERS – DIVIDE BY PLACE VALUE
83 82 81 80 Place Value 512 64 8 1
Choose largest place value that divides into 600 600/512 = 1 r 88 place a 1 in the 512 column 88/64 = 1 r 24 place a 1 in the 64 column 24/8 = 3 r 0 place a 3 in the 8 column. Done – no remainder! F. CONVERT 60010 TO HEXADECIMAL
METHOD 1 – USING DIVIDENDS – DIVIDE BY 16
600/16 = 37 r 8 (r is remainder) 37/16 = 2 r 5 2/16 = 0 r 2 Read remainders from the bottom up 60010 is 25816
Check: 162 161 160 Place Value 256 16 1 2 5 8
(2 x 256) + (5 x 16) + (8 x 1) = 512 + 80 + 8 = 600 It checks!
METHOD 2 – USING REMAINDERS – DIVIDE BY PLACE VALUE
162 161 160 Place Value 256 16 1
Choose largest place value that divides into 600 600/256 = 2 r 88 place a 2 in the 512 column 88/16 = 5 r 8 place a 5 in the 16 column 8/1 = 8 r 0 place a 8 in the 1 column.
Done – no remainder! Name:______Visual C++
Use handout for conversion information. Include all work showing how you did the conversion for full credit.
1. Convert each of the following binary numerals to base 10 a) 1001 ______b) 110010 ______c) 1000000 ______d) 111111111111111 (fifteen 1s) ______
2. Convert each of the following octal numerals to base 10 a) 1238 ______b) 27058 ______c) 100008 ______d) 777778 ______
3. Convert each of the following hexadecimal numerals to base 10 a) 1216 ______b) 1AB16 ______c) ABC16 ______d) FFF16 ______
4. Convert each of the following base 10 numbers a) 5810 to binary ______b) 7510 to octal ______c) 41210 to hexadecimal ______