Recurrent Sequences and Cryptography
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POWER FIBONACCI SEQUENCES 1. Introduction Let G Be a Bi-Infinite Integer Sequence Satisfying the Recurrence Relation G If
POWER FIBONACCI SEQUENCES JOSHUA IDE AND MARC S. RENAULT Abstract. We examine integer sequences G satisfying the Fibonacci recurrence relation 2 3 Gn = Gn−1 + Gn−2 that also have the property that G ≡ 1; a; a ; a ;::: (mod m) for some modulus m. We determine those moduli m for which these power Fibonacci sequences exist and the number of such sequences for a given m. We also provide formulas for the periods of these sequences, based on the period of the Fibonacci sequence F modulo m. Finally, we establish certain sequence/subsequence relationships between power Fibonacci sequences. 1. Introduction Let G be a bi-infinite integer sequence satisfying the recurrence relation Gn = Gn−1 +Gn−2. If G ≡ 1; a; a2; a3;::: (mod m) for some modulus m, then we will call G a power Fibonacci sequence modulo m. Example 1.1. Modulo m = 11, there are two power Fibonacci sequences: 1; 8; 9; 6; 4; 10; 3; 2; 5; 7; 1; 8 ::: and 1; 4; 5; 9; 3; 1; 4;::: Curiously, the second is a subsequence of the first. For modulo 5 there is only one such sequence (1; 3; 4; 2; 1; 3; :::), for modulo 10 there are no such sequences, and for modulo 209 there are four of these sequences. In the next section, Theorem 2.1 will demonstrate that 209 = 11·19 is the smallest modulus with more than two power Fibonacci sequences. In this note we will determine those moduli for which power Fibonacci sequences exist, and how many power Fibonacci sequences there are for a given modulus. -
Prime Divisors in the Rationality Condition for Odd Perfect Numbers
Aid#59330/Preprints/2019-09-10/www.mathjobs.org RFSC 04-01 Revised The Prime Divisors in the Rationality Condition for Odd Perfect Numbers Simon Davis Research Foundation of Southern California 8861 Villa La Jolla Drive #13595 La Jolla, CA 92037 Abstract. It is sufficient to prove that there is an excess of prime factors in the product of repunits with odd prime bases defined by the sum of divisors of the integer N = (4k + 4m+1 ℓ 2αi 1) i=1 qi to establish that there do not exist any odd integers with equality (4k+1)4m+2−1 between σ(N) and 2N. The existence of distinct prime divisors in the repunits 4k , 2α +1 Q q i −1 i , i = 1,...,ℓ, in σ(N) follows from a theorem on the primitive divisors of the Lucas qi−1 sequences and the square root of the product of 2(4k + 1), and the sequence of repunits will not be rational unless the primes are matched. Minimization of the number of prime divisors in σ(N) yields an infinite set of repunits of increasing magnitude or prime equations with no integer solutions. MSC: 11D61, 11K65 Keywords: prime divisors, rationality condition 1. Introduction While even perfect numbers were known to be given by 2p−1(2p − 1), for 2p − 1 prime, the universality of this result led to the the problem of characterizing any other possible types of perfect numbers. It was suggested initially by Descartes that it was not likely that odd integers could be perfect numbers [13]. After the work of de Bessy [3], Euler proved σ(N) that the condition = 2, where σ(N) = d|N d is the sum-of-divisors function, N d integer 4m+1 2α1 2αℓ restricted odd integers to have the form (4kP+ 1) q1 ...qℓ , with 4k + 1, q1,...,qℓ prime [18], and further, that there might exist no set of prime bases such that the perfect number condition was satisfied. -
Perfect Gaussian Integer Sequences of Arbitrary Length Soo-Chang Pei∗ and Kuo-Wei Chang† National Taiwan University∗ and Chunghwa Telecom†
Perfect Gaussian Integer Sequences of Arbitrary Length Soo-Chang Pei∗ and Kuo-Wei Chang† National Taiwan University∗ and Chunghwa Telecom† m Objectives N = p or N = p using Legendre N = pq where p and q are coprime Conclusion sequence and Gauss sum To construct perfect Gaussian integer sequences Simple zero padding method: We propose several methods to generate zero au- of arbitrary length N: Legendre symbol is defined as 1) Take a ZAC from p and q. tocorrelation sequences in Gaussian integer. If the 8 2 2) Interpolate q − 1 and p − 1 zeros to these signals sequence length is prime number, we can use Leg- • Perfect sequences are sequences with zero > 1, if ∃x, x ≡ n(mod N) n ! > autocorrelation. = < 0, n ≡ 0(mod N) to get two signals of length N. endre symbol and provide more degree of freedom N > 3) Convolution these two signals, then we get a than Yang’s method. If the sequence is composite, • Gaussian integer is a number in the form :> −1, otherwise. ZAC. we develop a general method to construct ZAC se- a + bi where a and b are integer. And the Gauss sum is defined as N−1 ! Using the idea of prime-factor algorithm: quences. Zero padding is one of the special cases of • A Perfect Gaussian sequence is a perfect X n −2πikn/N G(k) = e Recall that DFT of size N = N1N2 can be done by this method, and it is very easy to implement. sequence that each value in the sequence is a n=0 N taking DFT of size N1 and N2 seperately[14]. -
And Its Properties on the Sequence Related to Lucas Numbers
Mathematica Aeterna, Vol. 2, 2012, no. 1, 63 - 75 On the sequence related to Lucas numbers and its properties Cennet Bolat Department of Mathematics, Art and Science Faculty, Mustafa Kemal University, 31034, Hatay,Turkey Ahmet I˙pek Department of Mathematics, Art and Science Faculty, Mustafa Kemal University, 31034, Hatay,Turkey Hasan Köse Department of Mathematics, Science Faculty, Selcuk University 42031, Konya,Turkey Abstract The Fibonacci sequence has been generalized in many ways, some by preserving the initial conditions, and others by preserving the recur- rence relation. In this article, we study a new generalization {Lk,n}, with initial conditions Lk,0 = 2 and Lk,1 = 1, which is generated by the recurrence relation Lk,n = kLk,n−1 + Lk,n−2 for n ≥ 2, where k is integer number. Some well-known sequence are special case of this generalization. The Lucas sequence is a special case of {Lk,n} with k = 1. Modified Pell-Lucas sequence is {Lk,n} with k = 2. We produce an extended Binet’s formula for {Lk,n} and, thereby, identities such as Cassini’s, Catalan’s, d’Ocagne’s, etc. using matrix algebra. Moreover, we present sum formulas concerning this new generalization. Mathematics Subject Classi…cation: 11B39, 15A23. Keywords: Classic Fibonacci numbers; Classic Lucas numbers; k-Fibonacci numbers; k-Lucas numbers, Matrix algebra. 64 C. Bolat, A. Ipek and H. Kose 1 Introduction In recent years, many interesting properties of classic Fibonacci numbers, clas- sic Lucas numbers and their generalizations have been shown by researchers and applied to almost every …eld of science and art. -
Arxiv:1804.04198V1 [Math.NT] 6 Apr 2018 Rm-Iesequence, Prime-Like Hoy H Function the Theory
CURIOUS CONJECTURES ON THE DISTRIBUTION OF PRIMES AMONG THE SUMS OF THE FIRST 2n PRIMES ROMEO MESTROVIˇ C´ ∞ ABSTRACT. Let pn be nth prime, and let (Sn)n=1 := (Sn) be the sequence of the sums 2n of the first 2n consecutive primes, that is, Sn = k=1 pk with n = 1, 2,.... Heuristic arguments supported by the corresponding computational results suggest that the primes P are distributed among sequence (Sn) in the same way that they are distributed among positive integers. In other words, taking into account the Prime Number Theorem, this assertion is equivalent to # p : p is a prime and p = Sk for some k with 1 k n { ≤ ≤ } log n # p : p is a prime and p = k for some k with 1 k n as n , ∼ { ≤ ≤ }∼ n → ∞ where S denotes the cardinality of a set S. Under the assumption that this assertion is | | true (Conjecture 3.3), we say that (Sn) satisfies the Restricted Prime Number Theorem. Motivated by this, in Sections 1 and 2 we give some definitions, results and examples concerning the generalization of the prime counting function π(x) to increasing positive integer sequences. The remainder of the paper (Sections 3-7) is devoted to the study of mentioned se- quence (Sn). Namely, we propose several conjectures and we prove their consequences concerning the distribution of primes in the sequence (Sn). These conjectures are mainly motivated by the Prime Number Theorem, some heuristic arguments and related computational results. Several consequences of these conjectures are also established. 1. INTRODUCTION, MOTIVATION AND PRELIMINARIES An extremely difficult problem in number theory is the distribution of the primes among the natural numbers. -
Some Combinatorics of Factorial Base Representations
1 2 Journal of Integer Sequences, Vol. 23 (2020), 3 Article 20.3.3 47 6 23 11 Some Combinatorics of Factorial Base Representations Tyler Ball Joanne Beckford Clover Park High School University of Pennsylvania Lakewood, WA 98499 Philadelphia, PA 19104 USA USA [email protected] [email protected] Paul Dalenberg Tom Edgar Department of Mathematics Department of Mathematics Oregon State University Pacific Lutheran University Corvallis, OR 97331 Tacoma, WA 98447 USA USA [email protected] [email protected] Tina Rajabi University of Washington Seattle, WA 98195 USA [email protected] Abstract Every non-negative integer can be written using the factorial base representation. We explore certain combinatorial structures arising from the arithmetic of these rep- resentations. In particular, we investigate the sum-of-digits function, carry sequences, and a partial order referred to as digital dominance. Finally, we describe an analog of a classical theorem due to Kummer that relates the combinatorial objects of interest by constructing a variety of new integer sequences. 1 1 Introduction Kummer’s theorem famously draws a connection between the traditional addition algorithm of base-p representations of integers and the prime factorization of binomial coefficients. Theorem 1 (Kummer). Let n, m, and p all be natural numbers with p prime. Then the n+m exponent of the largest power of p dividing n is the sum of the carries when adding the base-p representations of n and m. Ball et al. [2] define a new class of generalized binomial coefficients that allow them to extend Kummer’s theorem to base-b representations when b is not prime, and they discuss connections between base-b representations and a certain partial order, known as the base-b (digital) dominance order. -
My Favorite Integer Sequences
My Favorite Integer Sequences N. J. A. Sloane Information Sciences Research AT&T Shannon Lab Florham Park, NJ 07932-0971 USA Email: [email protected] Abstract. This paper gives a brief description of the author's database of integer sequences, now over 35 years old, together with a selection of a few of the most interesting sequences in the table. Many unsolved problems are mentioned. This paper was published (in a somewhat different form) in Sequences and their Applications (Proceedings of SETA '98), C. Ding, T. Helleseth and H. Niederreiter (editors), Springer-Verlag, London, 1999, pp. 103- 130. Enhanced pdf version prepared Apr 28, 2000. The paragraph on \Sorting by prefix reversal" on page 7 was revised Jan. 17, 2001. The paragraph on page 6 concerning sequence A1676 was corrected on Aug 02, 2002. 1 How it all began I started collecting integer sequences in December 1963, when I was a graduate student at Cornell University, working on perceptrons (or what are now called neural networks). Many graph-theoretic questions had arisen, one of the simplest of which was the following. Choose one of the nn−1 rooted labeled trees with n nodes at random, and pick a random node: what is its expected height above the root? To get an integer sequence, let an be the sum of the heights of all nodes in all trees, and let Wn = an=n. The first few values W1; W2; : : : are 0, 1, 8, 78, 944, 13800, 237432, : : :, a sequence engraved on my memory. I was able to calculate about ten terms, but n I needed to know how Wn grew in comparison with n , and it was impossible to guess this from so few terms. -
Rational Tree Morphisms and Transducer Integer Sequences: Definition and Examples
1 2 Journal of Integer Sequences, Vol. 10 (2007), 3 Article 07.4.3 47 6 23 11 Rational Tree Morphisms and Transducer Integer Sequences: Definition and Examples Zoran Suni´cˇ 1 Department of Mathematics Texas A&M University College Station, TX 77843-3368 USA [email protected] Abstract The notion of transducer integer sequences is considered through a series of ex- amples (the chosen examples are related to the Tower of Hanoi problem on 3 pegs). By definition, transducer integer sequences are integer sequences produced, under a suitable interpretation, by finite transducers encoding rational tree morphisms (length and prefix preserving transformations of words that have only finitely many distinct sections). 1 Introduction It is known from the work of Allouche, B´etr´ema, and Shallit (see [1, 2]) that a squarefree sequence on 6 letters can be obtained by encoding the optimal solution to the standard Tower of Hanoi problem on 3 pegs by an automaton on six states. Roughly speaking, after reading the binary representation of the number i as input word, the automaton ends in one of the 6 states. These states represent the six possible moves between the three pegs; if the automaton ends in state qxy, this means that the one needs to move the top disk from peg x to peg y in step i of the optimal solution. The obtained sequence over the 6-letter alphabet { qxy | 0 ≤ x,y ≤ 2, x =6 y } is an example of an automatic sequence. We choose to work with a slightly different type of automata, which under a suitable interpretation, produce integer sequences in the output. -
Arxiv:1606.08690V5 [Math.NT] 27 Apr 2021 on Prime Factors of Mersenne
On prime factors of Mersenne numbers Ady Cambraia Jr,∗ Michael P. Knapp,† Ab´ılio Lemos∗, B. K. Moriya∗ and Paulo H. A. Rodrigues‡ [email protected] [email protected] [email protected] [email protected] paulo [email protected] April 29, 2021 Abstract n Let (Mn)n≥0 be the Mersenne sequence defined by Mn = 2 − 1. Let ω(n) be the number of distinct prime divisors of n. In this short note, we present a description of the Mersenne numbers satisfying ω(Mn) ≤ 3. Moreover, we prove that the inequality, (1−ǫ) log log n given ǫ> 0, ω(Mn) > 2 − 3 holds for almost all positive integers n. Besides, a we present the integer solutions (m, n, a) of the equation Mm+Mn = 2p with m,n ≥ 2, p an odd prime number and a a positive integer. 2010 Mathematics Subject Classification: 11A99, 11K65, 11A41. Keywords: Mersenne numbers, arithmetic functions, prime divisors. 1 Introduction arXiv:1606.08690v5 [math.NT] 27 Apr 2021 n Let (Mn)n≥0 be the Mersenne sequence defined by Mn = 2 − 1, for n ≥ 0. A simple argument shows that if Mn is a prime number, then n is a prime number. When Mn is a prime number, it is called a Mersenne prime. Throughout history, many researchers sought to find Mersenne primes. Some tools are very important for the search for Mersenne primes, mainly the Lucas-Lehmer test. There are papers (see for example [1, 5, 21]) that seek to describe the prime factors of Mn, where Mn is a composite number and n is a prime number. -
Fast Tabulation of Challenge Pseudoprimes
Fast Tabulation of Challenge Pseudoprimes Andrew Shallue Jonathan Webster Illinois Wesleyan University Butler University ANTS-XIII, 2018 1 / 18 Outline Elementary theorems and definitions Challenge pseudoprime Algorithmic theory Sketch of analysis Future work 2 / 18 Definition If n is a composite integer with gcd(b, n) = 1 and bn−1 ≡ 1 (mod n) then we call n a base b Fermat pseudoprime. Fermat’s Little Theorem Theorem If p is prime and gcd(b, p) = 1 then bp−1 ≡ 1 (mod p). 3 / 18 Fermat’s Little Theorem Theorem If p is prime and gcd(b, p) = 1 then bp−1 ≡ 1 (mod p). Definition If n is a composite integer with gcd(b, n) = 1 and bn−1 ≡ 1 (mod n) then we call n a base b Fermat pseudoprime. 3 / 18 Lucas Sequences Definition Let P, Q be integers, and let D = P2 − 4Q (called the discriminant). Let α and β be the two roots of x 2 − Px + Q. Then we have an integer sequence Uk defined by αk − βk U = k α − β called the (P, Q)-Lucas sequence. Definition Equivalently, we may define this as a recurrence relation: U0 = 0, U1 = 1, and Un = PUn−1 − QUn−2. 4 / 18 Definition If n is a composite integer with gcd(n, 2QD) = 1 such that Un−(n) ≡ 0 (mod n) then we call n a (P, Q)-Lucas pseudoprime. An Analogous Theorem Theorem Let the (P, Q)-Lucas sequence be given, and let (n) = (D|n) be the Jacobi symbol. If p is an odd prime and gcd(p, 2QD) = 1, then Up−(p) ≡ 0 (mod p) 5 / 18 An Analogous Theorem Theorem Let the (P, Q)-Lucas sequence be given, and let (n) = (D|n) be the Jacobi symbol. -
ON NUMBERS N DIVIDING the Nth TERM of a LINEAR RECURRENCE
Proceedings of the Edinburgh Mathematical Society (2012) 55, 271–289 DOI:10.1017/S0013091510001355 ON NUMBERS n DIVIDING THE nTH TERM OF A LINEAR RECURRENCE JUAN JOSE´ ALBA GONZALEZ´ 1, FLORIAN LUCA1, CARL POMERANCE2 AND IGOR E. SHPARLINSKI3 1Instituto de Matem´aticas, Universidad Nacional Autonoma de M´exico, CP 58089, Morelia, Michoac´an, M´exico ([email protected]; fl[email protected]) 2Mathematics Department, Dartmouth College, Hanover, NH 03755, USA ([email protected]) 3Department of Computing, Macquarie University, Sydney, NSW 2109, Australia ([email protected]) (Received 25 October 2010) Abstract We give upper and lower bounds on the count of positive integers n x dividing the nth term of a non-degenerate linearly recurrent sequence with simple roots. Keywords: linear recurrence; Lucas sequence; divisibility 2010 Mathematics subject classification: Primary 11B37 Secondary 11A07; 11N25 1. Introduction Let {un}n0 be a linear recurrence sequence of integers satisfying a homogeneous linear recurrence relation un+k = a1un+k−1 + ···+ ak−1un+1 + akun for n =0, 1,..., (1.1) where a1,...,ak are integers with ak =0. In this paper, we study the set of indices n which divide the corresponding term un, that is, the set Nu := {n 1: n|un}. But first, some background on linear recurrence sequences. To the recurrence (1.1) we associate its characteristic polynomial m k k−1 σi fu(X):=X − a1X −···−ak−1X − ak = (X − αi) ∈ Z[X], i=1 c 2012 The Edinburgh Mathematical Society 271 272 J. J. Alba Gonz´alez and others where α1,...,αm ∈ C are the distinct roots of fu(X) with multiplicities σ1,...,σm, respectively. -
Repdigits As Sums of Two Lucas Numbers∗
Applied Mathematics E-Notes, 20(2020), 33-38 c ISSN 1607-2510 Available free at mirror sites of http://www.math.nthu.edu.tw/ amen/ Repdigits As Sums Of Two Lucas Numbers Zafer ¸Siary, Refik Keskinz Received 11 Feburary 2019 Abstract Let (Ln) be the Lucas sequence defined by Ln = Ln 1 +Ln 2 for n 2 with initial conditions L0 = 2 ≥ and L1 = 1. A repdigit is a nonnegative integer whose digits are all equal. In this paper, we show that if Ln + Lm is a repdigit, then Ln + Lm = 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 77, 333. 1 Introduction Let (Fn)n 0 be the Fibonacci sequence satisfying the recurrence relation Fn+2 = Fn+1 + Fn with initial ≥ conditions F0 = 0 and F1 = 1. Let (Ln)n 0 be the Lucas sequence following the same recursive pattern as ≥ th the Fibonacci sequence, but with initial conditions L0 = 2 and L1 = 1.Fn and Ln are called n Fibonacci number and nth Lucas number, respectively. It is well known that n n F = and L = n + n, (1) n n where 1 + p5 1 p5 = and = , 2 2 which are the roots of the characteristic equation x2 x 1 = 0. Also, the following relation between nth Lucas number Ln and is well known: n 1 n Ln 2 (2) ≤ ≤ for n 0. The inequality (2) can be proved by induction. A≥ repdigit is a nonnegative integer whose digits are all equal. Recently, some mathematicians have investigated the repdigits which are sums or products of any number of Fibonacci numbers, Lucas numbers, and Pell numbers.