Trigonometry in the Hyperbolic Plane
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Analytic Geometry
Guide Study Georgia End-Of-Course Tests Georgia ANALYTIC GEOMETRY TABLE OF CONTENTS INTRODUCTION ...........................................................................................................5 HOW TO USE THE STUDY GUIDE ................................................................................6 OVERVIEW OF THE EOCT .........................................................................................8 PREPARING FOR THE EOCT ......................................................................................9 Study Skills ........................................................................................................9 Time Management .....................................................................................10 Organization ...............................................................................................10 Active Participation ...................................................................................11 Test-Taking Strategies .....................................................................................11 Suggested Strategies to Prepare for the EOCT ..........................................12 Suggested Strategies the Day before the EOCT ........................................13 Suggested Strategies the Morning of the EOCT ........................................13 Top 10 Suggested Strategies during the EOCT .........................................14 TEST CONTENT ........................................................................................................15 -
Algebra/Geometry/Trigonometry App Samples
Algebra/Geometry/Trigonometry App Samples Holt McDougal Algebra 1 HMH Fuse: Algebra 1- HMH Fuse is the first core K-12 education solution developed exclusively for the iPad. The portability of a complete classroom course on an iPad enables students to learn in the classroom, on the bus, or at home—anytime, anywhere—with engaging content that provides an individually-tailored learning experience. Students and educators using HMH Fuse: will benefit from: •Instructional videos that teach or re-teach all key concepts •Math Motion is a step-by-step interactive demonstration that displays the process to solve complex equations •Homework Help provides at-home support for intricate problems by providing hints for each step in the solution •Vocabulary support throughout with links to a complete glossary that includes audio definitions •Tips, hints, and links that enable students to acquire the help they need to understand the lessons every step of the way •Quizzes that assess student’s skills before they begin a concept and at strategic points throughout the chapters. Instant, automatic grading of quizzes lets students know exactly how they have performed •Immediate assessment results sent to teachers so they can better differentiate instruction. Sample- Cost is Free, Complete App price- $59.99 Holt McDougal HMH Fuse: Geometry- Following our popular HMH Fuse: Algebra 1 app, HMH Fuse: Geometry is the newest offering in the HMH Fuse series. HMH Fuse: Geometry will allow you a sneak peek at the future of mobile geometry curriculum and includes a FREE sample chapter. HMH Fuse is the first core K-12 education solution developed exclusively for the iPad. -
Section 6.7 Hyperbolic Functions 3
Section 6.7 Difference Equations to Hyperbolic Functions Differential Equations The final class of functions we will consider are the hyperbolic functions. In a sense these functions are not new to us since they may all be expressed in terms of the exponential function and its inverse, the natural logarithm function. However, we will see that they have many interesting and useful properties. Definition For any real number x, the hyperbolic sine of x, denoted sinh(x), is defined by 1 sinh(x) = (ex − e−x) (6.7.1) 2 and the hyperbolic cosine of x, denoted cosh(x), is defined by 1 cosh(x) = (ex + e−x). (6.7.2) 2 Note that, for any real number t, 1 1 cosh2(t) − sinh2(t) = (et + e−t)2 − (et − e−t)2 4 4 1 1 = (e2t + 2ete−t + e−2t) − (e2t − 2ete−t + e−2t) 4 4 1 = (2 + 2) 4 = 1. Thus we have the useful identity cosh2(t) − sinh2(t) = 1 (6.7.3) for any real number t. Put another way, (cosh(t), sinh(t)) is a point on the hyperbola x2 −y2 = 1. Hence we see an analogy between the hyperbolic cosine and sine functions and the cosine and sine functions: Whereas (cos(t), sin(t)) is a point on the circle x2 + y2 = 1, (cosh(t), sinh(t)) is a point on the hyperbola x2 − y2 = 1. In fact, the cosine and sine functions are sometimes referred to as the circular cosine and sine functions. We shall see many more similarities between the hyperbolic trigonometric functions and their circular counterparts as we proceed with our discussion. -
Plane Trigonometry - Lecture 16 Section 3.2: the Law of Cosines
Plane Trigonometry - Lecture 16 Section 3.2: The Law of Cosines Summary: http://www.math.ksu.edu/~gerald/math150/sum16.pdf Course page: http://www.math.ksu.edu/~gerald/math150/ Gerald Hoehn April 1, 2019 Law of cosines Theorem Let ∆ABC any triangle, then c2 = a2 + b2 − 2ab cos γ b2 = a2 + c2 − 2ac cos β a2 = b2 + c2 − 2bc cos α We may reformulate the statement also in word form. Theorem In any triangle, the square of the length of a side equals the sum of the squares of the length of the other two sides minus twice the product of the length of the other two sides and the cosine of the angle between them. Solving Triangles For solving triangles ∆ABC one needs at least three of the six quantities a, b, and c and α, β, γ. One distinguishes six essential different cases forming three classes: I AAA case: Three angles given. I AAS case: Two angles and a side opposite one of them given. I ASA case: Two angles and the side between them given. I SSA case: Two sides and an angle opposite one of them given. I SAS case: Two sides and the angle between them given. I SSS case: Three sides given. The case AAA cannot be solved. The cases AAS, ASA and SSA are solved by using the law of sines. The cases SAS, SSS are solved by using the law of cosines. Solving Triangles: the SAS case For the SAS case a unique solution always exists. Three steps: 1. Use the law of cosines to determine the length of the third side opposite to the given angle. -
Squaring the Circle a Case Study in the History of Mathematics the Problem
Squaring the Circle A Case Study in the History of Mathematics The Problem Using only a compass and straightedge, construct for any given circle, a square with the same area as the circle. The general problem of constructing a square with the same area as a given figure is known as the Quadrature of that figure. So, we seek a quadrature of the circle. The Answer It has been known since 1822 that the quadrature of a circle with straightedge and compass is impossible. Notes: First of all we are not saying that a square of equal area does not exist. If the circle has area A, then a square with side √A clearly has the same area. Secondly, we are not saying that a quadrature of a circle is impossible, since it is possible, but not under the restriction of using only a straightedge and compass. Precursors It has been written, in many places, that the quadrature problem appears in one of the earliest extant mathematical sources, the Rhind Papyrus (~ 1650 B.C.). This is not really an accurate statement. If one means by the “quadrature of the circle” simply a quadrature by any means, then one is just asking for the determination of the area of a circle. This problem does appear in the Rhind Papyrus, but I consider it as just a precursor to the construction problem we are examining. The Rhind Papyrus The papyrus was found in Thebes (Luxor) in the ruins of a small building near the Ramesseum.1 It was purchased in 1858 in Egypt by the Scottish Egyptologist A. -
Circumference and Area of Circles 353
Circumference and 7-1 Area of Circles MAIN IDEA Find the circumference Measure and record the distance d across the circular and area of circles. part of an object, such as a battery or a can, through its center. New Vocabulary circle Place the object on a piece of paper. Mark the point center where the object touches the paper on both the object radius and on the paper. chord diameter Carefully roll the object so that it makes one complete circumference rotation. Then mark the paper again. pi Finally, measure the distance C between the marks. Math Online glencoe.com • Extra Examples • Personal Tutor • Self-Check Quiz in. 1234 56 1. What distance does C represent? C 2. Find the ratio _ for this object. d 3. Repeat the steps above for at least two other circular objects and compare the ratios of C to d. What do you observe? 4. Graph the data you collected as ordered pairs, (d, C). Then describe the graph. A circle is a set of points in a plane center radius circumference that are the same distance from a (r) (C) given point in the plane, called the center. The segment from the center diameter to any point on the circle is called (d) the radius. A chord is any segment with both endpoints on the circle. The diameter of a circle is twice its radius or d 2r. A diameter is a chord that passes = through the center. It is the longest chord. The distance around the circle is called the circumference. -
“An Introduction to Hyperbolic Functions in Elementary Calculus” Jerome Rosenthal, Broward Community College, Pompano Beach, FL 33063
“An Introduction to Hyperbolic Functions in Elementary Calculus” Jerome Rosenthal, Broward Community College, Pompano Beach, FL 33063 Mathematics Teacher, April 1986, Volume 79, Number 4, pp. 298–300. Mathematics Teacher is a publication of the National Council of Teachers of Mathematics (NCTM). The primary purpose of the National Council of Teachers of Mathematics is to provide vision and leadership in the improvement of the teaching and learning of mathematics. For more information on membership in the NCTM, call or write: NCTM Headquarters Office 1906 Association Drive Reston, Virginia 20191-9988 Phone: (703) 620-9840 Fax: (703) 476-2970 Internet: http://www.nctm.org E-mail: [email protected] Article reprint with permission from Mathematics Teacher, copyright April 1986 by the National Council of Teachers of Mathematics. All rights reserved. he customary introduction to hyperbolic functions mentions that the combinations T s1y2dseu 1 e2ud and s1y2dseu 2 e2ud occur with sufficient frequency to warrant special names. These functions are analogous, respectively, to cos u and sin u. This article attempts to give a geometric justification for cosh and sinh, comparable to the functions of sin and cos as applied to the unit circle. This article describes a means of identifying cosh u 5 s1y2dseu 1 e2ud and sinh u 5 s1y2dseu 2 e2ud with the coordinates of a point sx, yd on a comparable “unit hyperbola,” x2 2 y2 5 1. The functions cosh u and sinh u are the basic hyperbolic functions, and their relationship to the so-called unit hyperbola is our present concern. The basic hyperbolic functions should be presented to the student with some rationale. -
Inverse Hyperbolic Functions
INVERSE HYPERBOLIC FUNCTIONS We will recall that the function eex − − x sinh x = 2 is a 1 to 1 mapping.ie one value of x maps onto one value of sinhx. This implies that the inverse function exists. y =⇔=sinhxx sinh−1 y The function f(x)=sinhx clearly involves the exponential function. We will now find the inverse function in its logarithmic form. LET y = sinh−1 x x = sinh y THEN eey − − y x = 2 (BY DEFINITION) SOME ALGEBRAIC MANIPULATION GIVES yy− 2xe=− e MULTIPLYING BOTH SIDES BY e y yy2 21xe= e − RE-ARRANGING TO CREATE A QUADRATIC IN e y 2 yy 02=−exe −1 APPLYING THE QUADRATIC FORMULA 24xx± 2 + 4 e y = 2 22xx± 2 + 1 e y = 2 y 2 exx= ±+1 SINCE y e >0 WE MUST ONLY CONSIDER THE ADDITION. y 2 exx= ++1 TAKING LOGARITHMS OF BOTH SIDES yxx=++ln2 1 { } IN CONCLUSION −12 sinhxxx=++ ln 1 { } THIS IS CALLED THE LOGARITHMIC FORM OF THE INVERSE FUNCTION. The graph of the inverse function is of course a reflection in the line y=x. THE INVERSE OF COSHX The function eex + − x fx()== cosh x 2 Is of course not a one to one function. (observe the graph of the function earlier). In order to have an inverse the DOMAIN of the function is restricted. eexx+ − fx()== cosh x , x≥ 0 2 This is a one to one mapping with RANGE [1, ∞] . We find the inverse function in logarithmic form in a similar way. y = cosh −1 x x = cosh y provided y ≥ 0 eeyy+ − xy==cosh 2 2xe=+yy e− 02=−+exeyy− 2 yy 02=−exe +1 USING QUADRATIC FORMULA −24xx±−2 4 e y = 2 y 2 exx=± −1 TAKING LOGS yxx=±−ln2 1 { } yxx=+−ln2 1 is one possible expression { } APPROPRIATE IF THE DOMAIN OF THE ORIGINAL FUNCTION HAD BEEN RESTRICTED AS EXPLAINED ABOVE. -
Old-Fashioned Relativity & Relativistic Space-Time Coordinates
Relativistic Coordinates-Classic Approach 4.A.1 Appendix 4.A Relativistic Space-time Coordinates The nature of space-time coordinate transformation will be described here using a fictional spaceship traveling at half the speed of light past two lighthouses. In Fig. 4.A.1 the ship is just passing the Main Lighthouse as it blinks in response to a signal from the North lighthouse located at one light second (about 186,000 miles or EXACTLY 299,792,458 meters) above Main. (Such exactitude is the result of 1970-80 work by Ken Evenson's lab at NIST (National Institute of Standards and Technology in Boulder) and adopted by International Standards Committee in 1984.) Now the speed of light c is a constant by civil law as well as physical law! This came about because time and frequency measurement became so much more precise than distance measurement that it was decided to define the meter in terms of c. Fig. 4.A.1 Ship passing Main Lighthouse as it blinks at t=0. This arrangement is a simplified model for a 1Hz laser resonator. The two lighthouses use each other to maintain a strict one-second time period between blinks. And, strict it must be to do relativistic timing. (Even stricter than NIST is the universal agency BIGANN or Bureau of Intergalactic Aids to Navigation at Night.) The simulations shown here are done using RelativIt. Relativistic Coordinates-Classic Approach 4.A.2 Fig. 4.A.2 Main and North Lighthouses blink each other at precisely t=1. At p recisel y t=1 sec. -
6.2 Law of Cosines
6.2 Law of Cosines The Law of Sines can’t be used directly to solve triangles if we know two sides and the angle between them or if we know all three sides. In this two cases, the Law of Cosines applies. Law of Cosines: In any triangle ABC , we have a2 b 2 c 2 2 bc cos A b2 a 2 c 2 2 ac cos B c2 a 2 b 2 2 ab cos C Proof: To prove the Law of Cosines, place triangle so that A is at the origin, as shown in the Figure below. The coordinates of the vertices BC and are (c ,0) and (b cos A , b sin A ) , respectively. Using the Distance Formula, we have a2( c b cos) A 2 (0 b sin) A 2 =c2 2bc cos A b 2 cos 2 A b 2 sin 2 A =c2 2bc cos A b 2 (cos 2 A sin 2 A ) =c22 2bc cos A b =b22 c 2 bc cos A Example: A tunnel is to be built through a mountain. To estimate the length of the tunnel, a surveyor makes the measurements shown in the Figure below. Use the surveyor’s data to approximate the length of the tunnel. Solution: c2 a 2 b 2 2 ab cos C 21222 388 2 212 388cos82.4 173730.23 c 173730.23 416.8 Thus, the tunnel will be approximately 417 ft long. Example: The sides of a triangle are a5, b 8, and c 12. Find the angles of the triangle. -
Downloaded from Bookstore.Ams.Org 30-60-90 Triangle, 190, 233 36-72
Index 30-60-90 triangle, 190, 233 intersects interior of a side, 144 36-72-72 triangle, 226 to the base of an isosceles triangle, 145 360 theorem, 96, 97 to the hypotenuse, 144 45-45-90 triangle, 190, 233 to the longest side, 144 60-60-60 triangle, 189 Amtrak model, 29 and (logical conjunction), 385 AA congruence theorem for asymptotic angle, 83 triangles, 353 acute, 88 AA similarity theorem, 216 included between two sides, 104 AAA congruence theorem in hyperbolic inscribed in a semicircle, 257 geometry, 338 inscribed in an arc, 257 AAA construction theorem, 191 obtuse, 88 AAASA congruence, 197, 354 of a polygon, 156 AAS congruence theorem, 119 of a triangle, 103 AASAS congruence, 179 of an asymptotic triangle, 351 ABCD property of rigid motions, 441 on a side of a line, 149 absolute value, 434 opposite a side, 104 acute angle, 88 proper, 84 acute triangle, 105 right, 88 adapted coordinate function, 72 straight, 84 adjacency lemma, 98 zero, 84 adjacent angles, 90, 91 angle addition theorem, 90 adjacent edges of a polygon, 156 angle bisector, 100, 147 adjacent interior angle, 113 angle bisector concurrence theorem, 268 admissible decomposition, 201 angle bisector proportion theorem, 219 algebraic number, 317 angle bisector theorem, 147 all-or-nothing theorem, 333 converse, 149 alternate interior angles, 150 angle construction theorem, 88 alternate interior angles postulate, 323 angle criterion for convexity, 160 alternate interior angles theorem, 150 angle measure, 54, 85 converse, 185, 323 between two lines, 357 altitude concurrence theorem, -
Developing Creative Thinking in Mathematics: Trigonometry
Secondary Mathematics Developing creative thinking in mathematics: trigonometry Teacher Education through School-based Support in India www.TESS-India.edu.in http://creativecommons.org/licenses/ TESS-India (Teacher Education through School-based Support) aims to improve the classroom practices of elementary and secondary teachers in India through the provision of Open Educational Resources (OERs) to support teachers in developing student-centred, participatory approaches. The TESS-India OERs provide teachers with a companion to the school textbook. They offer activities for teachers to try out in their classrooms with their students, together with case studies showing how other teachers have taught the topic and linked resources to support teachers in developing their lesson plans and subject knowledge. TESS-India OERs have been collaboratively written by Indian and international authors to address Indian curriculum and contexts and are available for online and print use (http://www.tess-india.edu.in/). The OERs are available in several versions, appropriate for each participating Indian state and users are invited to adapt and localise the OERs further to meet local needs and contexts. TESS-India is led by The Open University UK and funded by UK aid from the UK government. Video resources Some of the activities in this unit are accompanied by the following icon: . This indicates that you will find it helpful to view the TESS-India video resources for the specified pedagogic theme. The TESS-India video resources illustrate key pedagogic techniques in a range of classroom contexts in India. We hope they will inspire you to experiment with similar practices. They are intended to complement and enhance your experience of working through the text-based units, but are not integral to them should you be unable to access them.