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11/22/2019 CIRCUMCEVIAN INVERSION PERSPECTOR A Generalisation of the Center X(35)

SUREN [email protected]

CIRCUMCEVIAN INVERSION PERSPECTOR A Generalization of the X(35)

SUREN [email protected]

ABSTRACT. The triangle center 푋(35) as mentioned in the Kimberling’s Encyclopedia of Triangle Centers, is the point of concurrence of the lines joining the vertices of the triangle to the inverses of the opposite excentres in the circumcircle. In this paper, we obtain a generalization of the same.

NOTATION Let 퐴퐵퐶 be a triangle. We denote its side lengths 퐵퐶, 퐶퐴 and 퐴퐵 by 푎, 푏, 푐 , its by 2푠, 푠 being the , and its by 훥. Its well-known triangle centers are the circumcenter 푂, the 퐼, the orthocenter 퐻 and the 퐺. The nine-point center (푁) is the center of the nine-point and is the of segment 푂퐻.

퐼푎 represents the excenter opposite to 퐴 and define 퐼푏 and 퐼푐 cyclically. The inradius is represented by 푟 and the circumradius by 푅. The Euler is the line on which the circumcenter, the centroid and the orthocenter lie.

푁푎 represents the , i.e. the point of concurrence of the lines joining the vertices of the triangle to the points of tangency of the corresponding excircles to the opposite sides.

(퐴퐵퐶) represents the circumcircle of triangle 퐴퐵퐶. 푃표푤휔(푋) represents the power of the point 푋 wrt the circle ω.

The ordered triple 푥: 푦: 푧 represents the point with barycentric coordinates

푥 푦 푧 ( , , ) 푥 + 푦 + 푧 푥 + 푦 + 푧 푥 + 푦 + 푧

푓(푎, 푏, 푐): 푓(푏, 푐, 푎): 푓(푐, 푎, 푏) can be represented as 푓(푎, 푏, 푐) ∷.

The point 푋(푘) represents the triangle center 푋(푘) as listed in the Kimberling’s Encyclopedia of Triangle Centers.

CONWAY’S NOTATION 2 2 2 (푏 + 푐 − 푎 )⁄ 푆 = 2훥 and 푆퐴 = 2 = 푏푐 cos 퐴.

푆퐵 and 푆퐶 are defined cyclically.

2 ( 2 2) a + b + c ⁄ 푆휔 = 푆 cot 휔 , cot(ω) = 2푆 , where 휔 is the Brocard angle.

Throughout this paper, the above notation shall be used. The symbols have the same meaning as in this section unless specified otherwise.

THE TRIANGLE CENTER 푋(35)

Page | 1 The triangle center 푋(35) as mentioned in the Kimberling’s Encyclopedia of Triangle Centers, is the point of concurrence of the lines joining the vertices of the triangle to the inverses of the opposite excentres in the circumcircle.

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Figure 1. Triangle Center X(35)

THE INCENTER-EXCENTER LEMMA We begin with the well-known Incenter-Excenter Lemma that relates the incenter and excenters of a triangle.

Lemma. Let 퐴퐵퐶 be a triangle. Denote by 퐿 the mid-point of arc 퐵퐶 not containing 퐴. Then, 퐿 is the center of the circle passing through 퐼, 퐼푎, 퐵, 퐶.

Proof. Note that the points 퐴, 퐼, 퐼푎 and 퐿 are collinear (as 퐿 lies on the angle bisector of ∠퐵퐴퐶). We wish to show that 퐿퐵 = 퐿퐼 = 퐿퐶 = 퐿퐼푎.

1 1 First, notice that ∠퐿퐵퐼 = ∠퐿퐵퐶 + ∠퐶퐵퐼 = ∠퐿퐴퐶 + ∠퐶퐵퐼 = ∠퐼퐴퐶 + ∠퐶퐵퐼 = ⁄2 ∠퐴 + ⁄2 ∠퐵 .

1 1 However, ∠퐵퐼퐿 = ∠퐵퐴퐼 + ∠퐴퐵퐼 = ⁄2 ∠퐴 + ⁄2 ∠퐵 = ∠퐿퐵퐼. Thus, triangle 퐵퐼퐿 is isosceles with 퐿퐵 = 퐿퐼. Similarly, 퐿퐼 = 퐿퐶. Hence, 퐿 is the circumcenter of triangle 퐼퐵퐶. The circle passing through 퐼, 퐵 and 퐶 must pass through 퐼푎 as well (the 퐼퐶퐼푎퐵 is cyclic as the opposite angles add up to 180°). Thus, 퐿 is the center of the circle passing through 퐼, 퐼푎, 퐵, 퐶.

Using this property that relates the excentres and the incenter, we try to obtain a generalization of the triangle center 푋(35).

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Figure 2. The Incenter-Excentre Lemma

THE CIRCUMCEVIAN-INVERSION PERSPECTOR The following theorem is the crux of this paper.

Theorem (Circumcevian-inversion perspector). The triangle formed by the inverses of reflections of a point in the vertices of its circumcevian triangle is perspective to the original triangle at a point called the Circumcevian- inversion perspector of that point with respect to the original triangle.

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Figure 3. The Circumcevian-inversion perspector 푃′

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In simple words, let 푃 be any point in the plane of a triangle 퐴퐵퐶 and the lines 퐴푃, 퐵푃 and 퐶푃 intersect (퐴퐵퐶) again in 퐷, 퐸 and 퐹 respectively. The of 푃 in 퐷, 퐸 and 퐹 are 푋, 푌 and 푍. The inverses of 푋, 푌 and 푍 in (퐴퐵퐶) are the points 푋′, 푌′ and 푍′ respectively. Then the lines 퐴푋′, 퐵푌′ and 퐶푍′ are concurrent at a point which we shall call throughout this paper, the ‘Circumcevian-inversion perspector’ of 푃 . The properties of the Circumcevian-inversion perspector of a point are discussed in the later sections.

Proof. Construct the (퐴푂푋), (퐵푂푌), (퐶푂푍).

푃표푤(퐴푂푋)(푃) = 퐴푃 ∙ 푃푋 = 퐴푃 ∙ 2푃퐷 = 2푃표푤(퐴퐵퐶)(푃)

Similarly, we can prove that 푃표푤(퐵푂푌)(푃) = 푃표푤(퐶푂푍)(푃) = 2푃표푤(퐴퐵퐶)(푃). So, the power of 푃 and 푂 wrt the three circles is equal. This implies that the three circles, (퐴푂푋), (퐵푂푌), (퐶푂푍) are coaxial and their radical axis is the line 푂푃. So, these circles share a second common point (other than 푂), say 퐾.

Define 퐼 as the inversion about the circle (퐴퐵퐶). The image of any point 푋 under this inversion is 퐼(푋). Under the inversion, (퐴푂푋) is mapped to the line 퐴푋′, (퐵푂푌) is mapped to the line 퐵푌′, (퐶푂푍) is mapped to the line 퐶푍′. The lines 퐴푋′, 퐵푌′, and 퐶푍′ share the points 퐼(푂) and 퐼(퐾). Hence the lines 퐴푋′, 퐵푌′, and 퐶푍′ are concurrent at the point 퐼(퐾). (The other common point i.e. 퐼(푂) is a point at infinity).

Remark. 푋, 푌 and 푍 can also be understood as the images of the point 푃 in the homothety with factor −1 centered at the points 퐷, 퐸 and 퐹. If the factor of homothety is changed to some other number, in that case as well, the lines 퐴푋′, 퐵푌′ and 퐶푍′ are concurrent. The above proof with minor modifications works. If the factor of homothety is changed to ℎ then, this perspector is called the ℎ-circumcevian-inversion perspector of 푃 with respect to the original triangle. The (−1) -circumcevian-inversion perspector is simply referred to as the circumcevian-inversion perspector.

It is clear by the incenter-excenter lemma that the triangle center 푋(35) is the Circumcevian-inversion perspector of the incenter. Also, the circumcenter is the Circumcevian-inversion perspector of itself.

PROPERTIES OF THE CIRCUMCEVIAN-INVERSION PERSPECTOR OF A POINT The Circumcevian-inversion perspector of a point displays interesting properties, three of which are listed below. The Circumcevian-inversion perspector opens the windows for many more triangle centers to be discovered.

Property 1. The Circumcevian-inversion perspector of the point 푃 wrt triangle 퐴퐵퐶 lies on the line 푃푂, 푂 being the circumcenter of 퐴퐵퐶.

Proof. Since the point 퐾 lies on the line 푃푂, 퐼(퐾) must lie on 푃푂 as well.

′ 푃푃′ Property 2. If the distance 푃푂 = 푑, and 푃 is the Circumcevian-inversion perspector of 푃, then ⁄푃′푂 = 1 − 2 푑 ⁄ 푅2.

Proof.

2 2 푃표푤(퐴퐵퐶)(푃) = 푅 − 푑 = 퐴푃 ∙ 푃퐷

2 2 푃표푤(퐴푂푋)(푃) = 퐴푃 ∙ 푃푋 = 2퐴푃 ∙ 푃퐷 = 2( 푅 − 푑 ) = 푂푃 ∙ 푃퐾

2(푅2 − 푑2) 2푅2 − 푑2 푃퐾 = ⟹ 푂퐾 = 푑 푑

Page | 4 푅2푑 푂푃 2푅2 − 푑2 푃푃′ 푑2 푂퐾 ∙ 푂푃′ = 푅2 ⟹ 푂푃′ = ⟹ = ⟹ = 1 − 2푅2 − 푑2 푂푃′ 푅2 푃′푂 푅2

Property 3. P′ and 퐼(푃) = 푄 are harmonic conjugates wrt the points 푂 and 푃.

Proof.

푅2 푅2 − 푑2 푃푄 푅2 − 푑2 푑2 푃푄 푃푃′ 푂푃 ∙ 푂푄 = 푅2 ⟹ 푂푄 = ⟹ 푃푄 = ⟹ = = 1 − ⟹ = 푑 푑 푂푄 푅2 푅2 푂푄 푂푃′

Remark. The converse of property 3 is also easy to prove.

BARYCENTRIC COORDINATES OF THE CIRCUMCEVIAN-INVERSION PERSPECTOR OF A TRIANGLE CENTER In this section, we find the barycentric coordinates of the Circumcevian-inversion perspector of a point by using Property 2 discussed in the last section.

Consider the point 푃 = (푝, 푞, 푟). Note that here, we are considering the normalized barycentric coordinates of the point. The result can be denormalized later.

2 푎 푆퐴⁄ The circumcenter 푂 has normalized barycentric coordinates ( 2푆2 , _, _) and the coordinates of 푃 are (푝, 푞, 푟). We use the barycentric distance formula to find the distance 푑 = 푃푂. Now, we use property 3.

2 2 푏 푆푏 푐 푆푐 푑2 = 푃푂2 = − ∑ 푎2 ( − 푞) ( − 푟) 2푆2 2푆2 푐푦푐

2 2 2 푏 푆푏 푐 푆푐 ′ 2 ∑ 푎 ( − 푞) ( − 푟) 푃푃 푑 푐푦푐 2푆2 2푆2 = 1 − = 1 + 푃′푂 푅2 푅2

6 2 4 2 2 2 2 2 2 2 푃′ = 8푆 푅 푝 + (4푆 푅 + ∑(푎 (푏 푆퐵 − 2푞푆 )(푐 푆퐶 − 2푟푆 )))푎 푆퐴 ∷ 푐푦푐

After algebraic manipulations and denormalization, we get

푃′ = 푝(푝 + 푞 + 푟)푎2푏2푐2 + 푎2(푏2 + 푐2 − 푎2)(푎2푞푟 + 푏2푝푟 + 푐2푝푞) ∷

It should be noted that the above expression is valid for all points 푝: 푞: 푟 instead of only for (푝, 푞, 푟) as we have denormalised the expression.

SHINAGAWA COEFFICIENTS OF THE CIRCUMCEVIAN-INVERSION PERSPECTOR OF A TRIANGLE CENTER ON THE Suppose that 푋 is a triangle center on the Euler line given by barycentric coordinates 푓(푎, 푏, 푐) ∶ 푓(푏, 푐, 푎) ∶ 푓(푐, 푎, 푏). The Shinagawa coefficients of 푋 are the functions 퐺(푎, 푏, 푐) and 퐻(푎, 푏, 푐) such that 푓(푎, 푏, 푐) = 2 퐺(푎, 푏, 푐) ∙ 푆 + 퐻(푎, 푏, 푐) ∙ 푆퐵푆퐶.

Many a times, Shinagawa coefficients of a triangle center can be conveniently expressed in terms of the following,

Page | 5 2 (푆퐵 + 푆퐶)(푆퐶 + 푆퐴)(푆퐴 + 푆퐵)⁄ 푎푏푐 2 퐸 = 푆2 = ( ⁄푆) = 4푅 2 2 2 푆퐴푆퐵푆퐶⁄ (푎 + 푏 + 푐 )⁄ 2 2 퐹 = 푆2 = 2 − 4푅 = 푆휔 − 4푅

Let the Shinagawa coefficients of a triangle center 푃 on the Euler line be (푘, 푙). By property 1, the Circumcevian- inversion perspector of 푃 i.e. 푃′ lies on the Euler line as well. We try to find the Shinagawa coefficients of 푃′. 푂 and 퐻 are circumcenter and orthocenter respectively of the reference triangle.

2 푃 has Shinagawa coefficients (푘, 푙). Thus, 푃 = 푘푆 + 푙푆퐵푆퐶 ∷. 푟 If 푂푃⁄ = 1⁄ , then 푃 = 푟 푆2 + (2푟 − 푟 )푆 푆 ∷. Comparing the barycentric coordinates for 푃 in the two 푃퐻 푟2 2 2 1 퐵 퐶 푂푃 푘 + 푙 cases, we get ⁄푃퐻 = ⁄2푘.

(푘 + 푙)(푂퐻) 푂푃 = 3푘 + 푙

Now, we use property 3 of the Circumcevian-inversion perspector of a point.

푃푃′ 푑2 (푘 + 푙)2(푂퐻)2 (푘 + 푙)2(퐸 − 8퐹) (3푘 + 푙)2퐸 − (푘 + 푙)2(퐸 − 8퐹) = 1 − = 1 − = 1 − = 푃′푂 푅2 (3푘 + 푙)2(푅)2 (3푘 + 푙)2퐸 (3푘 + 푙)2퐸

The barycentric section formula gives the Shinagawa coefficients (after cancelling out any common factors) of 푃′ as

(2푘(3푘 + 푙)퐸 + (3푘 + 푙)2퐸 − (푘 + 푙)2(퐸 − 8퐹), 2푙(3푘 + 푙)퐸 − (3푘 + 푙)2퐸 + (푘 + 푙)2(퐸 − 8퐹))

This formula can be used to find the Shinagawa coefficients of the Circumcevian-inversion perspector of any triangle center lying on the Euler line. Note that this formula is applicable because 푘 and 푙 have the same degree of homogeneity in 푎, 푏, 푐 for any triangle center on the Euler line.

We find the Shinagawa coefficients of the Circumcevian-inversion perspector of the Nine Point Center and the .

Example 1. Nine Point Center i.e. 푋(5) has the Shinagawa coefficients (1,1). So, its Circumcevian-inversion perspector has the shinagawa coefficients (5퐸 + 8퐹, −퐸 − 8퐹).

This is now 푋(34864)Kimberling’s Encyclopedia of Triangle Centers.

Example 2. De Longchamps Point i.e. 푋(20) has the Shinagawa coefficients (1, −2). So, its Circumcevian- inversion perspector has the shinagawa coefficients (퐸 + 4퐹, −2퐸 − 4퐹). Thus, the Circumcevian-inversion perspector of the triangle center 푋(20) i.e. the De Longchamps Point is the triangle center 푋(7488).

OTHER CIRCUMCEVIAN-INVERSION PERSPECTORS CIRCUMCEVIAN-INVERSION PERSPECTOR OF THE CENTROID (푋(2)) According to the Kimberling’s Encyclopedia of Triangle Centers,

푋(7496)= 푋(2), 푋(3)- harmonic conjugate of 푋(23)

Barycentrics (Pending)

푋(23) is the inverse-in-circumcircle of 푋(2).

By property 3, we can claim that 푋(7496) is the Circumcevian-inversion perspector of 푋(2) i.e. the centroid.

Page | 6 Barycentric formula gives the barycentric coordinates of 퐺′ as (3푎2푏2푐2 + 푎2(푎2 + 푏2 + 푐2)(푏2 + 푐2 − 푎2) ∷ ).

CIRCUMCEVIAN-INVERSION PERSPECTOR OF THE ORTHOCENTER (푋(4)) We claim that the triangle center 푋(3520) is the Circumcevian-inversion perspector of the orthocenter i.e. 푋(4). 푋(186) is the inverse-in-circumcircle of the orthocenter (퐻). If we denote the Circumcevian-inversion perspector of 퐻 by 퐻′, then 푋(4), 푋(3); 퐻′, 푋(186) is a harmonic bundle by property 3. 푋(4) = (tan 퐴 ∷) and 푋(3) = (sin 2퐴 ∷) . 푋(186) = (sin 퐴 (4 cos 퐴 − sec 퐴) ∷) = (2 sin 2퐴 − tan 퐴 ∷). By basic properties of barycentric coordinates in a harmonic bundle, we get 퐻′ = (2 sin 2퐴 + tan 퐴 ∷) = (sin 퐴 (4 cos 퐴 + sec 퐴) ∷) = 푋(3520).

CIRCUMCEVIAN-INVERSION PERSPECTOR OF THE POINT (푋(6)) According to the Kimberling’s Encyclopedia of Triangle Centers,

푋(6) = inverse-in-circumcircle of 푋(187)

푋(574) = inverse-in-Brocard-circle of 푋(187)

Brocard circle of a triangle is the circle with the circumcenter and symmedian point of the triangle as its diametric ends.

This shows that 푋(6), 푋(3); 푋(574), 푋(187) is in fact a harmonic bundle. By property 3, 푋(574) is the Circumcevian-inversion perspector of the symmedian point.

CIRCUMCEVIAN-INVERSION PERSPECTOR OF THE NAGEL POINT (푋(8)) We take a different approach here, rather than just using the barycentric formula for circumcevian-inversion perspector.

It is known that the incenter is the complement of the Nagel point. Also, the nine-point center (푁) of the triangle 푅 is the circumcenter of the . By Feuerbach’s Theorem, we have, 푁퐼 = ⁄2 − 푟.

Due to homothety of the triangle with its medial triangle, it follows that 푂푁푎 = 2 ∙ 푁퐼 = 푅 − 2푟.

Now, it is only a matter of using property 2 to find the barycentric coordinates 푁푎′ i.e. the Circumcevian- inversion perspector of 푁푎.

푁푎푁푎′ 푑2 4푅푟 − 4푟2 = 1 − = 푁푎′푂 푅2 푅2

푂 = 푋(3) = (sin 2퐴 ∷)

푁푎 = 푋(8) = (푏 + 푐 − 푎 ∷)

푁푎′ = (푏 + 푐 − 푎 + 4 ∙ sin 2퐴 (푅 − 푟) ∷)

This is now 푋(34866) in Kimberling’s Encyclopedia of Triangle Centers.

KNOWN CIRCUMCEVIAN-INVERSION PERSPECTORS Circumcevian- Triangle Center inversion perspector Incenter 푋(35)

Page | 7 Centroid 푋(7496) Circumcenter Circumcenter Orthocenter 푋(3520) Symmedian Point 푋(574) De Longchamps Point 푋(7488)

REFERENCES

Kimberling, C. (n.d.). Encyclopedia of Triangle Centers. Retrieved from http://faculty.evansville.edu/ck6/encyclopedia/ETC.html

Weisstein, E. W. (n.d.). Circumcenter. Retrieved from MathWorld--A Wolfram Web Resource: http://mathworld.wolfram.com/Circumcenter.html

Suren: 156, Prem Nagar, Hisar, Haryana – 125001, India (Landmark - Back of Kumhar Dharamshala)

Email: [email protected]

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