Chapter 16 the Tangent Space and the Notion of Smoothness

Chapter 16 the Tangent Space and the Notion of Smoothness

Chapter 16 The tangent space and the notion of smoothness We will always assume K algebraically closed. In this chapter we follow the approach of ˇ n Safareviˇc[S]. We define the tangent space TX,P at a point P of an affine variety X A as ⇢ the union of the lines passing through P and “ touching” X at P .Itresultstobeanaffine n subspace of A .Thenwewillfinda“local”characterizationofTX,P ,thistimeinterpreted as a vector space, the direction of T ,onlydependingonthelocalring :thiswill X,P OX,P allow to define the tangent space at a point of any quasi–projective variety. 16.1 Tangent space to an affine variety Assume first that X An is closed and P = O =(0,...,0). Let L be a line through P :if ⇢ A(a1,...,an)isanotherpointofL,thenageneralpointofL has coordinates (ta1,...,tan), t K.IfI(X)=(F ,...,F ), then the intersection X L is determined by the following 2 1 m \ system of equations in the indeterminate t: F (ta ,...,ta )= = F (ta ,...,ta )=0. 1 1 n ··· m 1 n The solutions of this system of equations are the roots of the greatest common divisor G(t)of the polynomials F1(ta1,...,tan),...,Fm(ta1,...,tan)inK[t], i.e. the generator of the ideal they generate. We may factorize G(t)asG(t)=cte(t ↵ )e1 ...(t ↵ )es ,wherec K, − 1 − s 2 ↵ ,...,↵ =0,e, e ,...,e are non-negative, and e>0ifandonlyifP X L.The 1 s 6 1 s 2 \ number e is by definition the intersection multiplicity at P of X and L. If G(t)is identically zero, then L X and the intersection multiplicity is, by definition, + . ⇢ 1 115 Note that the polynomial G(t)doesn’tdependonthechoiceofthegeneratorsF1,...,Fm of I(X), but only on the ideal I(X)andonL. Definition 16.1.1. The line L is tangent to the variety X at P if the intersection multiplicity of L and X at P is at least 2 (in particular, if L X). The tangent space to ⇢ X at P is the union of the lines that are tangent to X at P ;itisdenotedTP,X. n We will see now that TP,X is an affine subspace of A . Assume that P X: then the 2 polynomials Fi may be written in the form Fi = Li + Gi,whereLi is a homogeneous linear polynomial (possibly zero) and G contains only terms of degree 2. Then i ≥ Fi(ta1,...,tan)=tLi(a1,...,an)+Gi(ta1,...,tan), 2 where the last term is divisible by t .LetL be the line OA,withA =(a1,...,an). We note that the intersection multiplicity of X and L at P is the maximal power of t dividing the greatest common divisor, so L is tangent to X at P if and only if Li(a1,...,an)=0forall i =1,...,m. Therefore the point A belongs to TP,X if and only if L (a ,...,a )= = L (a ,...,a )=0. 1 1 n ··· m 1 n n This shows that TP,X is a linear subspace of A , whose equations are the linear components of the equations defining X. n n Example 16.1.2. (i) TO,An = A ,becauseI(A )=(0). (ii) If X is a hypersurface, with I(X)=(F ), we write as above F = L + G;then n TO,X = V (L): so TO,X is either a hyperplane if L =0,orthewholespaceA if L =0.For 6 3 2 2 2 instance, if X is the affine plane cuspidal cubic V (x y ) A , TO,X = A . − ⇢ Assume now that P X has coordinates (y ,...,y ). With an affine transformation 2 1 n we may translate P to the origin (0,...,0), taking as new coordinates functions on An x y ,...,x y .ThiscorrespondstoconsideringtheK-isomorphism K[x ,...,x ] 1 − 1 n − n 1 n ! K[x y ,...,x y ], which takes a polynomial F (x ,...,x )toitsTaylorexpansion 1 − 1 n − n 1 n G(x y ,...,x y )=F (y ,...,y )+d F + d(2)F + ..., 1 − 1 n − n 1 n P P (i) th where dP F denotes the i di↵erential of F at P :itisahomogeneouspolynomialofdegree i in the variables x y ,...,x y .Inparticularthelineartermis 1 − 1 n − n @F @F dP F = (P )(x1 y1)+ + (P )(xn yn). @x1 − ··· @xn − 116 n We get that, if I(X)=(F1,...,Fm), then TP,X is the affine subspace of A defined by the equations d F = = d F =0. P 1 ··· P m The affine space An,whichmayidentifiedwithKn,canbegivenanaturalstructureof K-vector space with origin P ,soinanaturalwayTP,X is a vector subspace (with origin n P ). The functions x y ,...,x y form a basis of the dual space (K )⇤ and their 1 − 1 n − n restrictions generate TP,X⇤ . Note moreover that dim TP,X =dimTP,X⇤ = k if and only if n k is the maximal number of polynomials linearly independent among d F ,...,d F . − P 1 P m If dP F1,...,dP Fn k are these polynomials, then they form a basis of the orthogonal TP,X? of − n the vector space TP,X in (K )⇤,becausetheyvanishonTP,X. 16.2 Zariski tangent space Let us define now the di↵erential of a regular function. Let f (X)bearegularfunction 2O on X.Wewanttodefinethedi↵erentialoff at P .SinceX is closed in An, f is induced by a polynomial F K[x ,...,x ]aswellasbyallpolynomialsoftheformF + G with 2 1 n G I(X). Fix P X:thend (F + G)=d F + d G so the di↵erentials of two polynomials 2 2 P P P inducing the same function f on X di↵er by the term d G with G I(X). By definition, P 2 dP G is zero along TP,X,sowemaydefinedpf as a regular function on TP,X,thedi↵erential of f at P :itisthefunctiononTP,X induced by dP F .SincedP F is a linear combination of x y ,...,x y , d f can also be seen as an element of T ⇤ . 1 − 1 n − n p P,X There is a natural map d : (X) T ⇤ ,whichsendsf to d f.Becauseoftherules p O ! P,X p of derivation, it is clear that dP (f + g)=dP f + dP g and dP (fg)=f(P )dP g + g(P )dP f.In particular, if c K, d (cf)=cd f.Sod is a linear map of K-vector spaces. We denote 2 p P p again by dP the restriction of dP to IX (P ), the maximal ideal of the regular functions on X which are zero at P .Sinceclearlyf = f(P )+(f f(P )) then d f = d (f f(P )), so this − P P − restriction doesn’t modify the image of the map. 2 Proposition 16.2.1. The map dP : IX (P ) TP,X⇤ is surjective and its kernel is IX (P ) . 2 ! Therefore T ⇤ I (P )/I (P ) as K-vector spaces. P,X ' X X n Proof. Let ' T ⇤ be a linear form on T . ' is the restriction of a linear form on K : 2 P,X P,X λ (x y )+...+ λ (x y ), with λ ,...,λ K.LetG be the polynomial of degree 1 1 1 − 1 n n − n 1 n 2 λ (x y )+...+ λ (x y ): the function g induced by G on X is zero at P and coincides 1 1 − 1 n n − n with its own di↵erential, so ' = dP g and dP is surjective. 117 Let now g IX (P )suchthatdpg =0,g induced by a polynomial G. Note that dP G may 2 n be interpreted as a linear form on K which vanishes on TP,X,henceasanelementofTP,X? . So dP G = c1dpF1 + ...+ cmdpFm (c1,...,cm suitable elements of K). Let us consider the polynomial G c F ... c F :sinceitsdi↵erentialatP is zero, it doesn’t have any term − 1 1 − − m m of degree 0 or 1 in x y ,...,x y ,soitbelongstoI(P )2.SinceG c F ... c F 1 − 1 n − n − 1 1 − − m m defines the function g on X,weconcludethatg I (P )2. 2 X ⇤ 2 Corollary 16.2.2. The tangent space TP,X is isomorphic to (IX (P )/IX (P ) )⇤ as an abstract K-vector space. Corollary 16.2.3. Let ' : X Y be an isomorphism of affine varieties and P X, ! 2 Q = '(P ). Then the tangent spaces TP,X and TQ,Y are isomorphic. Proof. ' induces the comorphism '⇤ : (Y ) (X), which results to be an isomorphism O2 !O2 such that '⇤IY (Q)=IX (P )and'⇤IY (Q) = IX (P ) .Sothereisaninducedhomomorphism I (Q)/I (Q)2 I (P )/I (P )2. Y Y ! X X which is an isomorphism of K-vector spaces. By dualizing we get the claim. ⇤ The above map from TP,X to TQ,Y is called the di↵erential of ' at P and is denoted by dP '. Now we would like to find a “more local” characterization of TP,X.Tothisendweconsider the local ring of P in X: .Werecallthenaturalmap (X) = (X) ,the OP,X O !OP,X O IX (P ) last one being the localization. It is natural to extend the map d : (X) T ⇤ to P O ! P,X OP,X setting f g(P )d f f(P )d g d = P − P . P g g(P )2 ⇣ ⌘ As in the proof of Proposition 16.2.1 one proves that the map dP : P,X TP,X⇤ induces 2 O ! an isomorphism P,X/ P,X TP,X⇤ ,where P,X is the maximal ideal of P,X.Soby M M ! 2 M O duality we have: T ( / )⇤.ThisprovesthatthetangentspaceT is a local P,X ' MP,X MP,X P,X invariant of P in X.

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