Can One Determine Planck's Constant H from the Kinetic Energy Vs

Can One Determine Planck's Constant H from the Kinetic Energy Vs

kinetic energy kinetic frequency Can one determine Planck’s constant h from the kinetic energy vs. frequency observation in the photoelectric effect? (A)Yes, via the intersection with the x-axis (B) Yes, via the slope of curve (C) No, it is not possible. A photon at 300 nm will “kick out” an electron with an amount of kinetic energy, KE 300 . If the wavelength is halved and it is absorbed an electron in the metal that is bound with same energy as the previous electron, the energy of the electron coming out is (A) less than ½ KE 300 . (B) ½ KE 300 (C) = KE 300 Careful: (D) 2 x KE 300 Draw pictures / use formula (E) more than 2 x KE 300 Discuss your answer Use reasoning You initially have blue light shining on metal. If you change the frequency to violet light (at same # of photons per second), what happens to the number of electrons coming out? (A) fewer electrons kicked out Φ (B) same # of electrons (C) more electrons kicked out electron energy energy electronelectron (D) not enough information My first answer is that I need more information: For example, how large is the work function Φ, how much energy does it require to free the most tightly bound electrons? Assuming the photon energy of both blue and violet light is larger than the work function but insufficient to free the most tightly bound electrons, than more electrons are kicked by the violet light (larger photon energy) than by the blue light. If this explanation is too brief, do not hesitate to ask one of the team. Application of photoelectric effect: Photomultiplier big voltage glass vacuum Electron amplifier, enclosure gives pulse of current for each photoelectron Apparatus to detect single photons (eye is incredible good: can detect few photons) Atom models Greek philosophers: ατοµου (atom) – indivisible John Dalton: all matter consists of atoms J.J. Thomson: discovery of electron atoms are made up of smaller particles Cathode rays (J.J. Thomson) E-field: ray consists of charged particles Crossed E&B-fields: charge-to-mass ratio (independent of material of cathode) → same charged particle (electron) Atom model (J.J. Thomson) Following Thomson’s discovery of electron: • Atoms must consist of positively and negatively charged particles • But: How are the charges distributed? - - - - - electrons in - - - positively charged soup - - +- (Plum-pudding model).

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    7 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us