2 Homework Solutions 18.335 " Fall 2004

2 Homework Solutions 18.335 " Fall 2004

2 Homework Solutions 18.335 - Fall 2004 2.1 Count the number of ‡oating point operations required to compute the QR decomposition of an m-by-n matrix using (a) Householder re‡ectors (b) Givens rotations. 2 (a) See Trefethen p. 74-75. Answer: 2mn2 n3 ‡ops. 3 (b) Following the same procedure as in part (a) we get the same ‘volume’, 1 1 namely mn2 n3: The only di¤erence we have here comes from the 2 6 number of ‡opsrequired for calculating the Givens matrix. This operation requires 6 ‡ops (instead of 4 for the Householder re‡ectors) and hence in total we need 3mn2 n3 ‡ops. 2.2 Trefethen 5.4 Let the SVD of A = UV : Denote with vi the columns of V , ui the columns of U and i the singular values of A: We want to …nd x = (x1; x2) and such that: 0 A x x 1 = 1 A 0 x2 x2 This gives Ax2 = x1 and Ax1 = x2: Multiplying the 1st equation with A 2 and substitution of the 2nd equation gives AAx2 = x2: From this we may conclude that x2 is a left singular vector of A: The same can be done to see that x1 is a right singular vector of A: From this the 2m eigenvectors are found to be: 1 v x = i ; i = 1:::m p2 ui corresponding to the eigenvalues = i. Therefore we get the eigenvalue decomposition: 1 0 A 1 VV 0 1 VV = A 0 p2 U U 0 p2 U U 3 2.3 If A = R + uv, where R is upper triangular matrix and u and v are (column) vectors, describe an algorithm to compute the QR decomposition of A in (n2) time. O The matrix A is of the form u2v1 0 1 . u3v1 u3v2 . A = B C B .C Bu4v1 u4v2 u4v3 .C B C B . C B . .. C B C Bunv1 unv2 ::: unvn 1 C B C @ A We exploit the fact that the matrix uv is rank one. By applying a sequence of Givens rotations starting from the bottom row, we notice that the rotation that zeroes the entry Ak;1 also zeroes out all the entries Ak;2;Ak;3; :::Ak;2n k 2: Thus the n 1 Givens rotations that kill the …rst column also kill all the entries below the …rst subdiagonal: 0 .1 0 . B C B . .C B . .. .. .. .C B C B 0 0 C B C @ A Thus we need another n 1 Givens rotations to kill the …rst subdiagonal entries (shown with ’sabove). We have a total cost 2n 2 rotations at no more than 6n operations per Givens rotation. Hence this algorithm requires n2 ‡ops. O 1 1 2.4 Given the SVD of A, compute the SVD of (AA) ; (AA) A; 1 1 A(AA) ;A(AA) A in terms of U , and V . Answers: 1 2 (AA) = V V 1 1 (AA) A = V U 1 1 A(AA) = U V 1 A(AA) A = UU (note that UU may not be equal to I; unless U is square in the reduced SVD) 4.

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