Crystal structure and scattering experiments Chris J. Pickard How can we tell where the atoms are? ² We have see the rich variety of bonding and structures that collections of atoms can adopt ² But how can we ever know where the atoms actually are? ² We must experimentally probe the Amphibole structural information Possible Experimental Probes Hit something and see what it, or the probe, does Scattering ² Probe atomic structure by \bouncing" particles o® it, and measuring changes in momentum etc. ² May be X-ray, neutron or electron scattering and elastic or inelastic A scattering experiment: The ² X-ray and neutron facilities European Synchrotron Radiation are massive pieces of scienti¯c Facility infrastructure Crystal Lattices ² In order to interpret the scattering experiments we need a model of where the atoms might be ² There are simply too many atoms in a solid for each's coordinates to be determined ² For crystalline solids we introduce the concept of a Bravais lattice The Bravais Lattice A ² The Bravais lattice describes the underlying periodic structure: not the crystal structure itself B a2 ² An in¯nite array which looks identical a1 if viewed from any point ² R = i niai, ni are all integers, and ai arePnot in the same plane A 2D Bravais Lattice A = a1 + 2a2 and B = ¡a1 + a2 ² The primitive vectors ai generate or span the lattice Finite Crystals ² All point are equivalent in a Bravais lattice: it must be in¯nite, but real crystals are ¯nite ² Finite size e®ects, or surface e®ects, may not be important: the Bravais lattice is a useful approximation ² It can be useful to consider a ¯nite Gold crystallite portion: R = i niai; 0 · ni < Ni P Coordination Number ² The Bravais lattice points closest to a given point are the nearest neighbours ² Because the Bravais lattice is periodic, all points have the same number of Diamond: 4 Simple Cubic: 6 nearest neighbours or coordination number. It is a property of the lattice ² Can be extended to arrays of points that are not Bravais lattices (the diamond lattice is not a Bravais BCC: 8 FCC: 12 lattice) Primitive Unit Cell ² Volume which when translated by all vectors in Bravais lattice just ¯lls space ² Not uniquely de¯ned ² The set of points r = x1a1 + x2a2 + x3a3, 0 · xi < 1 is an obvious choice ² Does not display the full symmetry of Two choices the lattice The Conventional Unit Cell ² A unit cell just ¯lls space when translated through a subset of Bravais lattice vectors ² The conventional unit cell is chosen to be larger than the primitive cell, but with the full symmetry of the Bravais lattice ² The size of the conventional cell is given by the lattice constants { a FCC Bravais lattice single a in this case The Wigner-Seitz Primitive Cell ² The Wigner-Seitz cell is a primitive cell with the full symmetry of the Bravais lattice ² Constructed by selecting a lattice point and taking the volume closer to that point than any others Wigner-Seitz cell for a 2D lattice ² Algorithm: draw lines from the lattice point to all others, bisect each line with a plane and take the smallest polyhedron containing the point The Wigner-Seitz Primitive Cell BCC FCC Wigner-Seitz cells for BCC and FCC 3D lattices Crystal structure ² A crystal structure is a basis, or physical unit, translated by each vector of the Bravais lattice ² Also known as a \lattice with a basis" ² A monatomic Bravais lattice has a basis consisting of a single atom 2D Bravais lattice with ² A Bravais lattice is a lattice with two point basis a basis when a non-primitive cell is chosen The Diamond Structure ² Two interpenetrating FCC Bravais lattices, displaced by 1/4 length of body diagonal ² FCC cubic lattice with two-point a/4(x+y+z) basis: 0 and a/4(x+y+z) z x ² The diamond lattice is not a Bravais a y lattice Conventional cubic cell ² Zincblende structure with two species Hexagonal Close Packing ² The hexagonal close packed (HCP) structure is not a Bravais lattice ² Many pure elements (about 30) a3 crystallise in this way ² The HCP structure consists of two interpenetrating simple hexagonal a2 1/3a1+1/3a2+1/2a3 a1 Bravais lattices Hexagonal close packed crystal structure ² Other stackings are possible: ...ABCABC... is FCC The Reciprocal Lattice ² The reciprocal lattice arises from the relationship between the Bravais a2 £ a3 ik¢r b1 = 2¼ lattice and plane waves, e a1 ¢ (a2 £ a3) ² For certain k the plane waves will have a3 £ a1 b2 = 2¼ the periodicity of the lattice. These a1 ¢ (a2 £ a3) are the points of the reciprocal lattice ¢ a1 £ a2 K and eiK R = 1 b3 = 2¼ a1 ¢ (a2 £ a3) ² The reciprocal lattice is a Bravais lattice, and the reciprocal lattice of the reciprocal lattice is the original b ¢ a = 2¼± i j ij direct lattice Some Examples a a a a1 = ax^; a2 = ay^; a3 = az^ a1 = (y^+z^); a1 = (z^+x^); a1 = (x^+y^) 2 2 2 2¼ 2¼ 4¼ 1 4¼ 1 b1 = x^; b2 = y^ b1 = (y^+z^¡x^); b2 = (z^+x^¡y^) a a a 2 a 2 2¼ 4¼ 1 b3 = z^ b3 = (x^ + y^ ¡ z^) a a 2 The Simple Cubic Bravais Lattice The FCC Bravais Lattice The First Brillouin Zone ² The ¯rst Brillouin zone is the Wigner- Seitz primitive cell of the reciprocal lattice ² Higher Brillouin zones exist, and are important in the theory of electronic FCC levels in a periodic potential ² Take care: the ¯rst BZ of a FCC BCC lattice is the Wigner-Seitz primitive The ¯rst Brillouin zone cell of the BCC lattice (and vice versa) Lattice Planes ² Families of lattice planes can be classi¯ed in terms of the reciprocal lattice ² For any reciprocal lattice vector K there is a family of planes normal to K and separated by a distance d Two families of lattice planes in a ² The length of the shortest reciprocal 2¼ simple cubic Bravais lattice lattice vector parallel to K is d Miller Indices ² The reciprocal lattice provides a a3 a3 convienient way to label lattice planes a1 a1 ² The Miller indices are the a2 a2 (010) (110) coordinates of the shortest reciprocal a3 lattice vector normal to the plane a1 ² A plane with Miller indices h,k,l is a2 normal to K = hb1 + kb2 + lb3 (111) Lattice planes and Miller indices in a simple cubic Bravais lattice ² h,k,l are integers with no common factor Specifying Directions: some conventions ² Lattice planes: (h; k; l) ! (hkl) with a3 a3 ¡n ! n¹ e.g. (2; ¡1; 4) ! (21¹4) a1 a1 ² Directions in the direct lattice: use a2 a2 (010) (110) square brackets e.g. [111] a3 ² Planes equivalent by symmetry: a1 (100), (010), and (001) are equivalent a2 in a cubic crystal, and we write f100g (111) Lattice planes and Miller indices in a simple cubic Bravais lattice ² For directions: [100], [010], [001], [100]¹ , [010]¹ , [001¹] ! h100i Beyond Translational Symmetry in Crystals ² There can be other symmetries in addition to translational symmetry ² The subject of crystallography systematises the classi¯cation of these di®erent symmetries The symmetries of a cube are identical ² The number of possibilities can be to an octahedron, but not a shown to be ¯nite for crystals, and tetrahedron have been ennumerated Seven Crystal Systems and Fourteen Bravais Lattices Cubic a Hexagonal Tetragonal a a Cubic a Trigonal Orthorhombic a a Trigonal c Monoclinic c Triclinic a c a a b Tetragonal Monoclinic Hierarchy of Symmetries a a a Hexagonal c c ² e.g. the cubic crystal system includes a b a Triclinic the simple cubic, BCC and FCC b Orthorhombic The Seven Crystal Systems Bravais lattices Point and Space Groups of Bravais Lattices and Crystal Structures Bravais Lattice Crystal Structure (basis of spherical symmetry) (basis of arbitary symmetry) Number of 7 32 point groups (crystal systems) (crystallographic point groups) Number of 14 230 space groups (Bravais lattices) (space groups) ² Adding a basis considerably complicates the situation ² Nonsymmorphic groups account for many of the 230: these contain screw axes and glide planes ² SchÄonflies (e.g. D6h) and International (e.g. 6=mmm) notations exist Structure Determination by X-ray Diffraction ² Atoms are separated by distances of the order of Angstroms (10¡8cm): the wavelength must be comparable hc ² We need X-rays: ¹h! = 10¡8cm12:3 £ 103eV ² We now consider how the scattering of X-rays from rigid periodic arrays of ions reveals their structure λ The Bragg Formulation ² W.L. Bragg considered crystals to be made up of parallel planes of atoms θ θ ² The di®raction peak occurs if 1) θ θ d d sin θ d sin θ X-rays reflect specularly from the atoms in a plane and 2) the X-rays from successive planes constructively interfere ² The di®raction condition is n¸ = 2dsinθ, and n is the order of the Bragg reflection reflection The von Laue Formulation ² The crystal is considered to be made up of identical microscopic objects at O R, which reradiate in all directions 1/2 K 1/2 K k K ² The Laue condition: constructive k' interference occurs if K = k ¡ k0 is a reciprocal lattice vector The Laue Condition ² No assumption that crystal contains lattice planes is made or that the ² The von Laue picture is equivalent to reflection is specular the Bragg picture The Ewald Sphere ² Given an incident wave vector k, draw a sphere centered on the origin O ² If a reciprocal lattice vector K lies on k k' the surface, a di®raction peak will be O 0 K observed, and k is the Bragg reflected ray ² In general, this is not the case (hence The Ewald Construction \peak") Experimental Methods ² Laue { The direction of k is varied by { Use a non-monochromatic beam rotating the crystal (from ¸0 to ¸1) { All K between the two Ewald ² Powder or Debye-Scherrer spheres will be seen { The randomly oriented crystallites ² Rotating Crystal e®ectively rotate the crystal, and { A monochromatic beam is used vary the axis of rotation Structure and Atomic Form Factors 1 iK¢r fj(K) = ¡ dre ½(r) n e Z iK¢dj SK = e The Atomic Form Factor Xj=1 The Structure Factor ² Modulates the intensities of the di®raction peaks ² There can be forbidden reflections for lattices with a basis ² Can be used analytically n iK¢dj SK = fj(K)e ² Some species are more visible than Xj=1 others.