Representation Theory and Quantum Mechanics Tutorial a Little Lie Theory

Representation Theory and Quantum Mechanics Tutorial a Little Lie Theory

Representation theory and quantum mechanics tutorial A little Lie theory Justin Campbell July 6, 2017 1 Groups 1.1 The colloquial usage of the words \symmetry" and \symmetrical" is imprecise: we say, for example, that a regular pentagon is symmetrical, but what does that mean? In the mathematical parlance, a symmetry (or more technically automorphism) of the pentagon is a (distance- and angle-preserving) transformation which leaves it unchanged. It has ten such symmetries: 2π 4π 6π 8π rotations through 0, 5 , 5 , 5 , and 5 radians, as well as reflection over any of the five lines passing through a vertex and the center of the pentagon. These ten symmetries form a set D5, called the dihedral group of order 10. Any two elements of D5 can be composed to obtain a third. This operation of composition has some important formal properties, summarized as follows. Definition 1.1.1. A group is a set G together with an operation G × G ! G; denoted by (x; y) 7! xy, satisfying: (i) there exists e 2 G, called the identity, such that ex = xe = g for all x 2 G, (ii) any x 2 G has an inverse x−1 2 G satisfying xx−1 = x−1x = e, (iii) for any x; y; z 2 G the associativity law (xy)z = x(yz) holds. To any mathematical (geometric, algebraic, etc.) object one can attach its automorphism group consisting of structure-preserving invertible maps from the object to itself. For example, the automorphism group of a regular pentagon is the dihedral group D5. For another example, let n ≥ 0 and consider Rn as a vector space over R. Linear maps Rn ! Rn can be thought of as n × n matrices with coefficients in R, a space we denote by Matn×n(R). Composition of linear maps goes over to matrix multiplication. The linear automorphism group of Rn is GLn(R) := fA 2 Matn×n(R) j A is invertibleg; the nth general linear group over R. Recall a square matrix A is invertible if and only if det A 6= 0. We also make frequent use of the related nth special linear group over R SLn(R) := fA 2 Matn×n(R) j det A = 1g: 1 1.2 Next we consider a geometrical figure more symmetrical than a regular pentagon, namely a circle 1 2 2 2 S := f(x; y) 2 R j x + y = 1g: We call it more symmetrical because it has infinitely many symmetries, given by the second orthogonal group > > O2(R) := fA 2 GL2(R) j AA = A A = Ig: 2 Equivalently, one can define O2(R) to consist of those A 2 O2(R) which preserve the dot product on R , meaning 2 O2(R) = fA 2 GL2(R) j (Av) · (Aw) = v · w for all v; w 2 R g: This explains the term \orthogonal," because the length of and angle between vectors can be expressed in terms of the inner product using the formulas p v · w jvj = v · v and cos θ = : jvjjwj This means that O2(R) is precisely the group of linear transformations of the plane which preserve distance and angle, the basic quantities in Euclidean geometry. Any symmetry of a regular pentagon centered at (0; 0) is also a symmetry of the circle, so we have an inclusion D5 ⊂ O2(R) which realizes the former group as a subgroup of the latter. A physicist might say that the pentagon breaks the symmetry of the circle, reducing it from an infinite group to a group with ten elements. ∼ 4 Since the group O2(R) is infinite and it comes as a subset of Mat2×2(R) = R , we ought to think of it as a geometric figure in its own right, rather than an unstructured jumble of points. In fact, it consists of a disjoint union of two circles, which can be parameterized as cos θ − sin θ cos θ sin θ θ 7! and θ 7! : sin θ cos θ sin θ − cos θ The first circle is the subgroup SO2(R) := SL2(R) \ O2(R) consisting of those A 2 O2(R) satisfying det A = 1, and the other component (which is not a subgroup) consists of A 2 O2(R) such that det A = −1. More geometrically, SO2(R) consists of all rotations about (0; 0), while a matrix in the other component of O2(R) is a reflection over a line through (0; 0). 1 1 In particular, for any v 2 S , the map SO2(R) ! S given by A 7! Av is bijective. We also remark that our parameterization cos θ − sin θ θ 7! sin θ cos θ of SO2(R) sends addition of angles to matrix multiplication, i.e. cos(θ + ') − sin(θ + ') cos θ − sin θ cos ' − sin ' = : sin(θ + ') cos(θ + ') sin θ cos θ sin ' cos ' 1.3 Although the group GL2(R) is nonabelian, its subgroup SO2(R) consisting of rotations in the plane is abelian. On the other hand, rotations in three-dimensional space form a nonabelian group. First we introduce the third orthogonal group > > O3(R) := fA 2 GL3(R) j AA = A A = Ig: As in the case of O2(R), a matrix A 2 O3(R) satisfies det A = ±1, and we put SO3(R) := SL3(R) \ O3(R): Note that reflection through a plane containing (0; 0; 0) has determinant −1, while a rotation about a line containing (0; 0; 0) has determinant 1. If L is an oriented line (meaning it has a distinguished positive L direction) then we write Rθ 2 SO3(R) for the rotation about L through θ radians, counterclockwise with respect to the given orientation of L according to the right-hand rule. 2 L Proposition 1.3.1 (Euler). Any element of SO3(R) has the form Rθ for some oriented line L through (0; 0; 0) and some angle 0 ≤ θ < 2π. Proof. Fix A 2 SO3(R), and let χA(λ) = det(λI − A) be its characteristic polynomial. Being a polynomial in three variables with real coefficients, χA necessarily has a real zero (reason: its three complex roots are permuted by complex conjugation, so there can be at most one pair of conjugate non-real roots). We claim that A fixes a nonzero vector, i.e. it has 1 as an eigenvalue. If v is an eigenvector of A with real eigenvalue λ, then jvj = jAvj = jλvj = jλjjvj implies that λ = ±1. Now if A has three real eigenvalues λ, µ, ν, then since det A = 1, either λ = µ = ν = 1, or −1 occurs with multiplicity two and 1 appears once. In either case one of the eigenvalues is 1. In the remaining case, A has one real eigenvalue λ = ±1 and two complex conjugate eigenvalues µ, µ. Then λjµj = λµµ = det A = 1 implies that λ = 1. Let L be the line spanned by an eigenvector of A with eigenvalue 1, i.e. A acts as the identity on L. Since A is orthogonal, it preserves the plane H ⊂ R3 through (0; 0; 0) perpendicular to L. Moreover, since ∼ 2 det A = 1 and det AjL = 1, we must have det LjH = 1. Thus LjH is a linear transformation of H = R which preserves the dot product and has determinant one, i.e. a rotation. In words, Euler's proposition says that SO3(R) is precisely the subgroup of O3(R) consisting of rotations. It follows that any element of SO3(R) can be written as a composition Rx Ry Rz ; θ1 θ2 θ3 where we use Rx to denote rotation counterclockwise around the x-axis, etc. Thus, in a sense we have not rigorously defined, the group SO3(R) is three-dimensional. We can explicitly write 21 0 0 3 2 cos θ 0 sin θ3 2cos θ − sin θ 03 x y z Rθ = 40 cos θ − sin θ5 ;Rθ = 4 0 1 0 5 ;Rθ := 4sin θ cos θ 05 : 0 sin θ cos θ − sin θ 0 cos θ 0 0 1 2 Lie algebras 2.1 The group SO3(R) is geometrically somewhat complicated. It is useful to have a \linear approximation" to such a group, and the appropriate object is defined as follows. Definition 2.1.1. A Lie algebra over R is a vector space g over R equipped with a bilinear operation [ ; ]: g × g ! g called the Lie bracket, which is required to satisfy (i) skew-symmetry, meaning for any x; y 2 g we have [x; y] = −[x; y], (ii) the Jacobi identity, which says that for any x; y; z 2 g we have [x; [y; z]] + [z; [x; y]] + [y; [z; x]] = 0: The most trivial example of a Lie algebra is a vector space g with the bracket which is identically zero. Such a Lie algebra is called abelian. For any n ≥ 1, one can equip Matn×n(R) with the commutator bracket [A; B] := AB − BA: 3 th The Lie algebra gln(R) so defined is called the n general linear Lie algebra; it is nonabelian for n > 1. We now explain the sense in which gln(R) is a \linear approximation" of GLn(R). First, since GLn(R) is an open subset of the vector space Matn×n(R) = gln(R), it is natural to view gln(R) as the tangent space of GLn(R) at any point, and we may as well take that point to be the identity matrix I 2 GLn(R). To reiterate, gln(R) = TI (GLn(R)) where the notation on the right side indicates the tangent space of GLn(R) at I.

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