Feynman Rules for QED

Feynman Rules for QED

Feynman rules for QED The Feynman Rules for QED Setting up Amplitudes Casimir's Trick Trace Theorems Slides from Sobie and Blokland Physics 424 Lecture 16 Page 1 2 Page and ¢ ¥ ¨ © § ¨ © and © ¦ positrons £¥¤ equations § ¦ £¥¤ § 16 Dirac ¨ © e ¤ and ¢ the Lectur and ¦ satisfy £ satisfy § ¦ © § £ § spin) § = § © § Electrons (s § and ¦ ¦ £¥¤ £¥¤ and § and ¢ ¦ ¦ © £ £¥¤ and ¢ ¢ ¢ ¦ ¦ ¤ £¥¤ £ ¢ ¨ © spinors ¢ adjoints ¢ orthogonality ¢ normalization ¢ completeness ¡ ¡ ¡ ¡ ¡ 424 Physics 3 Page ¨ $ % "! # 16 e - * Lectur ¨ Photons ¨ * , ) +* ¦ & £¥¤ % ( ¨ % ' gauge ¦ condition ¦ and £ £¥¤ ¨ % entz % ¦ % & & ¤ ¥ £ Lor orthogonality normalization Coulomb Completeness % % % % ¡ ¡ ¡ ¡ ¡ 424 Physics The Feynman Rules for QED The Feynman rules provide the recipe for constructing an amplitude . from a Feynman diagram. ¡ Step 1: For a particular process of interest, draw a Feynman diagram with the minimum number of vertices. There may be more than one. 1 2/ 4 3 / © 1 0/ / Physics 424 Lecture 16 Page 4 The Feynman Rules for QED ¡ Step 2: For each Feynman diagram, label the four-momentum of each line, enforcing four-momentum conservation at every vertex. Note that arrows are only present on fermion lines and they represent particle flow, not momentum. 1 2/ 4 3 / © 1 2/ / Physics 424 Lecture 16 Page 5 Step 3: The amplitude depends on 1. Vertex factors 2. Propagators for internal lines 3. Wavefunctions for external lines Physics 424 Lecture 16 Page 6 Vertex Factors 5 Every QED vertex, 6 5 < 798;: contributes a factor of 6 . 8 : is a dimensionless coupling constant and is related to the ? fine-structure constant by 8 : = > @ A Physics 424 Lecture 16 Page 7 Propagators 798 < 6 Each internal photon connects two vertices of the form : 798 B 6 and : , so we should expect the photon propagator to contract the indices C and D . 7 8 E < B ? Photon propagator: F Internal fermions have a more complicated propagator, K G 7 HJI /F ? ? Fermion propagator: F I E The sign of F matters here — we take it to be in the same direction as the fermion arrow. Physics 424 Lecture 16 Page 8 External Lines Since both the vertex factor and the fermion propagators @ @ involve L matrices, but the amplitude must be a scalar, the external line factors must sit on the outside. Work backwards along every fermion line using: N N M M 6 6 5 in 5 out 5 in 5 out in out T P PRQ O Q O S S < < Physics 424 Lecture 16 Page 9 Matrix elements I G K G K < U 798 V follow fermion lines backward to give O 6 O 5 6 5 Physics 424 Lecture 16 Page 10 11 Page the in [ Q_^ K ents B 6 ? ^ curr \ \ 798 : G II N N ` ` ? P Q W 5 5 two ? the K B X < to \ 6 E 798 E 16 e Z elements G]\ Lectur [ OYZ X Z oportional \ \ K < pr Ma` Ma` 6 5 5 is Matrix 798 : G OYX P . W element below matrix The diagram 424 Physics And Finally... Step 4: The overall amplitude is the coherent sum of the individual amplitudes for each diagram: b b b H Hdc > Z ? c c ? ? f f f f b b b H H e > Z ? c c c Step 4a: Antisymmetrization. Include a minus sign between diagrams that differ only in the exchange of two identical fermions. Physics 424 Lecture 16 Page 12 Examples There are only a handful of ways to make tree-level diagrams in QED. Today, we will construct amplitudes for Bhabha scattering N N G K G K M M g g 5 6 5 6 5 5 5 5 and Compton scattering . Next week, we will undertake thorough calculations for Mott N G K G K h h M g g 5 5 6 6 scattering 5 5 , pair annihilation . You will P N G K i i M g examine fermion pair-production via 5 5 for your assignment. Physics 424 Lecture 16 Page 13 14 ? ^ Page \ \ [ [ N N ` ` Qn^ OnZ 5 5 K K B B 6 6 798 : 798 : 6 G G ? ? P Q PRQ W W ? ? K K B ? B X bml < < \ \ E H X Z 798 798 E E \ \ E Scattering Z Z ` ` M M G]\ G]\ 5 5 bkj [ [ O Z Q ^ 16 ? > e b ^ K K < < \ \ 6 6 N N ` ` Lectur Bhabha e 5 5 798 798 : : G G X X O O P P W W 7 7 6 > > Example: b j l b X Z \ \ ` ` M M 5 5 Antisymmetrization 424 Physics B < 15 ? ? S ^ S ? Page < B \ T T \ ` M S S X X 6 ` 5 p p OYZ OJZ K K B B 6 6 798 798 : : G G ? b ? ? K K H I I E E H H I I X Z Scattering ? ? Z \ \ b ? K K X 6 ` ` M ? / / \ \ X H E 5 \ \ H E > b Z Z / / \ \ G G Z Z 16 7 7 e \ \ G G ^ ? e \ \ ` M Lectur K K 6 < < ` 5 Compton 6 6 7 7 8 8 : : G G ^ ^ O O P P o o 7 7 > > Example: ? X Z Z b b antisymmetrization \ \ 6 ` ` M 5 No 424 Physics Polarized Particles A typical QED amplitude might look something like W [ < brq s P OnZ Q S ? X < The Feynman rules won't take us any further, but to get a number for b we will need to substitute explicit forms for the P O Q StX Z ? wavefunctions of the external particles: , , and < . If all external particles have a known polarization, this might be a reasonable way to calculate things. More often, though, we are interested in unpolarized particles. Physics 424 Lecture 16 Page 16 Spin-Averaged Amplitudes If we do not care about the polarizations of the particles then we need to 1. Average over the polarizations of the initial-state particles 2. Sum over the polarizations of the final-state particles ? f f in the squared amplitude b . We call this the spin-averaged amplitude and we denote it by u v ? f f b Note that the averaging over initial state polarizations involves summing over all polarizations and then dividing by the u v ? f f number of independent polarizations, so b involves a sum over the polarizations of all external particles. Physics 424 Lecture 16 Page 17 18 Page have we z that OYZ y z 6 x x OYZ z s ? x O T y y | [ s 6 6 ? OYZ suppose O x y y [ s 6 6 s ? P s O ? ? x x x ? O O O Z s O P O Z P W and w w w { O Z P [ [ [ [ [ W ? ? ? ? ? O O O O O s s s s s Sums 16 q b OYZ OYZ OYZ OnZ OYZ e P P P P P W W W W W further Lectur Spin even q q q q q ? f b things f simplify Let's Then 424 Physics 19 Page the over | OnZ s P K K ? | OYZ (summing s P H I H I ? O P ? [ { OJZ / \ G / \ G [ s ? above O s OnZ P > O Z P W { O P l } OYZ P elation W r 16 e O l } ? q q Lectur ? Z q ~ f b ? f ed-amplitude l } b f f 2), l squar completeness the the paticle in ? O P of ? O spins Applying to 424 Physics 20 that Page can the so we esent again, epr r indices, [ K K once [ we K Z O Z K if G [ OYZ P K over H I O Z P OYZ OYZ P but G OYZ Z elation OYZ , G / \ G r W K G W OYZ P W G number 16 summations e a > > > > q ? f [ b Lectur OYZ just f with completeness is OYZ P W l the side apply as we it multiplication , right-hand get ewrite we r matrix The Finally 424 Physics In total, we have W [ b s P OYZ O q ? V u v ? { | P G G K f f K b s s HJI H e \ \ I q Z Z ? ? U / / Z The factor of ? is from the averaging over initial spins, O O assuming exactly one of Z and ? corresponds to an initial-state particle. If they are both in the initial state (e.g., Z pair annihilation), the factor is ^ . If neither is in the initial state (e.g., pair production), the factor is V . Physics 424 Lecture 16 Page 21 22 | K Page use in HJI we / \ G ? sum, s P K amplitudes spin K I H the I rick. E / \ G T in Z s 's / rick G \ { elation T r esent > s ' spin-averaged PRQ l } pr > 16 T Casimir e e [ Q l } ar O as ? K ? Q Lectur s G Z ~ O P W l } completeness calculating Casimir [ known O of is Z s spinors e O; P W traces esponding ocedur of pr corr antiparticle This If terms the 424 Physics 23 Page K ourselves G K find G to > K H -matrices. 6 K K K going G G G G e = 16 we'r e races involving T traces: > > > > Lectur rick, K K K K T = H 's traces G about G of G G lot a Casimir of identities Because General calculating 424 Physics 24 Page similar a build In to . B der 8 K @ B or 6 B K < in > < 6 6 6 L < E 6 G B 6 B 6 < B B < need 6 < 6 @ e E E 8 < B 8 @ 6 U 6 ar G U B B will 6 6 < Blocks U E 6 U U > > we and 16 B e @ < B 6 > > > > that 8 B identities > Lectur < < < < ` 6 6 6 < 8 B 6 6 trace < Building 6 that identities that find major we show complicated can two e ou mor fashion, The Y 424 Physics 25 Page odd any U B K < of 8 6 < B 6 8 H H trace U K K B B B 6 the < G V < 8 6 is < B 8 @ G < B G U < 8 as E 8 > K @ 8 o, G V Identities zer 8 B > > > > < is K 16 B 8 is: e 6 race < @ 6 T Lectur G matrix > K 6 6 identity 6 B 6 single < trace 6 a -matrices.

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