Charged Plane for a Charged Plane, the Only Direction in the Problem Is the Normal ˆn, Which Is a O Vector ⇒ E ∝ ˆn

Charged Plane for a Charged Plane, the Only Direction in the Problem Is the Normal ˆn, Which Is a O Vector ⇒ E ∝ ˆn

1 Unit 2-6: Symmetry Under Parity Transformation: vector vs pseudovector i Right Handed Left Handed coordinate systems A Parity transformation inverts all the Cartesian axes, and takes one from a right handed to a left handed coordinate system. Under a parity transformation, the coordinates of the position vector change sign, r = (x; y; z) ) (−x; −y: − z) (2.6.1) If P is the parity operator, we can write P(r) = −r, and we say that r is odd under parity (i.e. it changes sign). Any vector-like quantity that is odd under a parity transformation we will call a vector. examples of vectors: position r dr velocity v = , since r is vector and t is a scalar under parity, P(t) = t dt dv acceleration a = , since v is a vector and t is a scalar dt Force F = ma, since a is a vector and m is a scalar momentum p = mv, since v is a vector and m is a scalar electric field E = F=q, since F is a vector and q is a scalar P current j = i qiviδ(r − ri), since vi is a vector and qi and δ(r) are scalars In contrast, any vector-like quantity that is even (i.e. does not change sign) under parity is called a pseudovector. angular momentum L = r × p, since under parity r ! −r and p ! −p, then L ! L under parity. L is even under parity, so L is a pseudovector! v magnetic field F = q × B, since F and v are vectors, and q is a scalar, B must be a pseudovector. c A cross product of any two vectors is a pseudovector. A cross product of any vector with a pseudovector is a vector. When solving for E, it can only be made up of other vectors that exist in the problem. When solving for B, it can only be made up of other pseudovectors that exist in the problem. charged plane For a charged plane, the only direction in the problem is the normal ^n, which is a o vector ) E / ^n For a planar surface current, the only directions in the problem are the vectors surface current ^n and K. But B is a pseudovector and can only be made up of pseudovectors ) B / (K × ^n).

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    1 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us