Fundamental Theorem of Calculus, Riemann Sums, Substitution

Fundamental Theorem of Calculus, Riemann Sums, Substitution

Fundamental Theorem of Calculus, Riemann Sums, Substitution Integration Methods 104003 Differential and Integral Calculus I Technion International School of Engineering 2010-11 Tutorial Summary – February 27, 2011 – Kayla Jacobs Indefinite vs. Definite Integrals A calc student upset as could be • Indefinite integral: That his antiderivative didn't agree Ȅ ͚ʚͬʛ ͬ͘ With the one in the book E'en aft one more look. The function F(x) that answers question: Oh! Seems he forgot to write the "+ C". “What function, when differentiated, gives f(x)?” -Anonymous • Definite integral: Ȅ ͚ʚͬʛ ͬ͘ o The number that represents the area under the curve f(x) between x=a and x=b o a and b are called the limits of integration . o Forget the +c. Now we’re calculating actual values . Fundamental Theorem of Calculus (Relationship between definite & indefinite integrals) If Î and f is continuous, then F is differentiable and ɑ . ¢ʚÎʛ Ȭ Ȅ ¼ʚÊʛ ºÊ ¢ ʚÎʛ Ɣ ¼ʚÎʛ · Important Corollary: For any function F whose derivative is f (i.e., ), ̀ ’ʚͬʛ Ɣ ͚ʚͬʛ ¸ ǹ ¼ʚÎʛ ºÎ Ɣ ¢ʚ¸ʛ Ǝ ¢ʚ·ʛ · This lets you easily calculate definite integrals! Definite Integral Properties • Ȅ ͚ʚͬʛ ͬ͘ Ɣ 0 • Ȅ ͚ʚͬʛ ͬ͘ Ɣ Ǝ Ȅ ͚ʚͬʛ ͬ͘ • whether or not Ȅ ͚ʚͬʛ ͬ͘ Ɣ Ȅ ͚ʚͬʛ ͬ͘ ƍ Ȅ ͚ʚͬʛ ͬ͘ ͗ Ǩ ʞ͕, ͖ʟ Area in [a,b] Bounded by Curve f(x) Case 1: Curve entirely above x-axis. Really easy! Area = Ȅ ͚ʚͬʛ ͬ͘ Case 2: Curve entirely below x-axis. Easy! Area = | | = - Ȅ ͚ʚͬʛ ͬ͘ Ȅ ͚ʚͬʛ ͬ͘ Case 3: Curve sometimes below, sometimes above x-axis. Sort of easy! Break up into sections. Average Value The average value of function f(x) in region [a,b] is: Ȅ ͚ʚͬʛ ͬ͘ average Ɣ ͖ Ǝ ͕ Calculus – Tutorial Summary – February 27 , 2011 2 Riemann Sum Let [a,b] = closed interval in the domain of function f Partition [a,b] into n subdivisions: { [x 0,x 1], [x 1,x 2], [x 2,x 3], … , [x n-1,x n]} where a = x 0 < x 1 < … < x n-1 < x n = b The Riemann sum of function f over interval [a,b] is: ) ͍ Ɣ ȕ ͚ʚͭ$ʛ · ʚͬ$ Ǝ ͬ$ͯͥʛ $Ͱͥ th where yi is any value between x i-1 and x i. Note (xi – xi-1) is the length of the i subdivision [x i-1, x i]. If for all i: then… yi = x i-1 S = Left Riemann sum yi = x i S = Right Riemann sum yi = (x i + x i-1)/2 S = Middle Riemann sum f(yi) = ( f(x i-1) + f(x i) )/2 S = Trapezoidal Riemann sum f(y i) = maximum of f over [x i-1, x i] S = Upper Riemann sum f(y i) = minimum of f over [x i-1, x i] S = Lower Riemann sum As , S converges to the value of the definite integral of f over [ a,b]: ͢ Ŵ ∞ lim )ŴϦ ͍ Ɣ ͚ʚͬʛ ͬ͘ Ȅ Ex: Riemann sum methods of f(x) = x3 over interval [ a, b] = [0, 2] using 4 equal subdivisions of 0.5 each: (1) Left Riemann sum: (2) Right Riemann sum: (4) Middle Riemann sum: (3) Trapezoidal Riemann sum: Calculus – Tutorial Summary – February 27, 2011 3 Integration Method: u-substitution 0ʚʛ ǹ ͚ʚͩʚͬʛʛ · ͩɑʚͬʛ ͬ͘ Ɣ ǹ ͚ʚͩʚͬʛʛ ͩ͘ 0ʚʛ …where (because ). ͩ͘ Ɣ ͩ’ʚͬʛͬ͘ ͩ’ʚͬʛ Ɣ ͩ͘/ͬ͘ Notes: • This is basically derivative chain rule in reverse. • The hard part is figuring out what a good u is. • If it’s a definite integral , don’t forget to change the limits of integration! , ͕ Ŵ ͩʚ͕ʛ ͖ Ŵ ͩʚ͖ʛ • If it’s an indefinite integral, don’t forget to change back to the original variable at the end, and +c . Basic Trigonometric Derivatives and Indefinite Integrals From trigonometric identities and u-substitution: Calculus – Tutorial Summary – February 27, 2011 4 Integration Method: Trigonometric Substitution for Rational Functions of Sine and Cosines To integrate a rational function of sin(x) and cos(x), try the substitution: ͬ 2 ͨ Ɣ tan ʚ ʛ ͬ͘ Ɣ ͦ ͨ͘ 2 1 ƍ ͨ Use the following trig identities to transform the function into a rational function of t: ͬ ʛ 2 tan ʚ2 2ͨ sin ʚͬʛ Ɣ ͬ Ɣ ͦ 1 ƍ tan ͦʚ ʛ 1 ƍ ͨ 2 ͦ ͬ ͦ 1 Ǝ tan ʠ2ʡ 1 Ǝ ͨ cos ʚͬʛ Ɣ ͬ Ɣ ͦ 1 ƍ tan ͦ ʠ ʡ 1 ƍ ͨ 2 ͬ 2 tan ʠ ʡ 2ͨ tan ʚͬʛ Ɣ 2 Ɣ ͦ ͬ 1 Ǝ ͨͦ 1 Ǝ tan ʠ2ʡ Integration Method: Trigonometric Substitution If the integral involves… … then substitute… … and use the trig identity… ͦ ͦ ·̋ Ǝ Ë̋ ͩ Ɣ ͕ · sin 1 Ǝ sin Ɣ cos ͦ ͦ ·̋ ƍ Ë̋ ͩ Ɣ ͕ · tan 1 ƍ tan Ɣ sec ͦ ͦ Ë̋ Ǝ ·̋ ͩ Ɣ ͕ · sec sec Ǝ 1 Ɣ tan Steps: 1. Notice that the integral involves one of the terms above. 2. Substitute the appropriate u. Make sure to change the dx to a du (with relevant factor). 3. Simplify the integral using the appropriate trig identity. 4. Rewrite the new integral in terms of the original non-Ѳ variable (draw a reference right-triangle to help). 5. Solve the (hopefully now much easier) integral, .

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