Linear Algebra Midterm Exam, April 5, 2007 Write Clearly, with Complete

Linear Algebra Midterm Exam, April 5, 2007 Write Clearly, with Complete

Mathematics 110 Name: GSI Name: Linear Algebra Midterm Exam, April 5, 2007 Write clearly, with complete sentences, explaining your work. You will be graded on clarity, style, and brevity. If you add false statements to a correct argument, you will lose points. Be sure to put your name and your GSI’s name on every page. 1. Let V and W be finite dimensional vector spaces over a field F . (a) What is the definition of the transpose of a linear transformation T : V → W ? What is the relationship between the rank of T and the rank of its transpose? (No proof is required here.) Answer: The transpose of T is the linear transformation T t: W ∗ → V ∗ sending a functional φ ∈ W ∗ to φ ◦ T ∈ V ∗. It has the same rank as T . (b) Let T be a linear operator on V . What is the definition of a T - invariant subspace of V ? What is the definition of the T -cyclic subspace generated by an element of V ? Answer: A T -invariant subspace of V is a linear subspace W such that T w ∈ W whenever w ∈ W . The T -cyclic subspace of V generated by v is the subspace of V spanned by the set of all T nv for n a natural number. (c) Let F := R, let V be the space of polynomials with coefficients in R, and let T : V → V be the operator sending f to xf 0, where f 0 is the derivative of f. Let W be the T -cyclic subspace of V generated by x2 + 1. Compute the characteristic polynomial of T|W . Answer T (x2 + 1) = 2x2 and T (2x2) = 4x2. Thus W has a basis (x2 + 1, 2x2, and the matrix for T with respect to this basis is 0 0 . Hence the characteristic polynomial of T is x2 − 2x. 1 2 |W Mathematics 110 Name: GSI Name: 2. Let V be a finite dimensional vector space over a field F . (a) What is the definition of the dual space V ∗ of V ? If α is an or- dered basis for V , what is the definition of the dual basis of V ∗ corresponding to α? Answer: The dual space to V is the vector space of all linear transformations from V to F . If α = (v1, . , vn), then its dual is the sequence (φ1, . , φn), where φi is the unique linear transfor- mation V → F such that φi(vj) = δij. (b) Let Pn be the space of polynomials of degree at most n with coef- ficients in F . Assume that F has at least n + 1 distinct elements, c0, . , cn. For 0 ≤ i ≤ n, let φi: Pn → F denote evaluation of f at ci. Show, using properties of polynomials discussed in class and/or the book, that each φi lies in the dual space to Pn. Prove that (φ0, . , φn) is a basis for this dual space. Hint: For 0 ≤ j ≤ n, Q let fj := k6=j(x − ck) ∈ Pn. Answer: First of all φi is linear because if f, g ∈ Pn and a, b ∈ F , then φi(af + bg) = (af + bg)(ci) = af(ci) + bg(ci) = aφi(f) + bφi(g). Q Now we compute that φi(fj) = k6=j(cj − ck) = 0 iff and only if P P i 6= j. Hence if aiφi = 0, aiφi(fj) = ajφj(fj), and if it follows that aj = 0. This shows that the sequence (φ0, . φn) is linearly ∗ independent. Since we know that the dimension of Pn is n + 1, it must be a basis. (c) If F = R and in the situation of (b), c0 = −1c1 = 0, and c2 = 1, find the basis for P2 whose dual is (φ0, φ1, φ2). Answer: In fact we almost have the answer already from the hint above: f0 = x(x − 1), f1 = (x + 1)(x − 1), and f2 = (x + 1)x. These almost work, but have to be fixed by rescaling, and we find the dual basis is: x((1 − x)/2, (1 − x2), (x2 + x)/2). Mathematics 110 Name: GSI Name: 3. Let V be a vector space over a field F and let T be a linear operator on V . (a) Define the concepts of eigenvectors and eigenvalues of T . Answer: An element v ∈ V is an eigenvector of T if there exists a λ ∈ F such that T (v) = λv. An element a ∈ F is an eigenvalue of T if there is some v ∈ V with v 6= 0 such that T (v) = λv. (b) Find the eigenvalues and bases for the eigenspaces of the linear 11 −30 operator corresponding to the matrix . 4 −11 Answer: The characteristic polyonomial of T is x2 − 1, so the eigenvalues are 1 and −1. The 1-eigenspace is the nullspace of 10 −30 , which is spanned by (3, 1). The −1-eigenspace is 4 −12 12 30 the nullspace of which is spanned by (5, 2). 4 −10 (c) Find T 200, where T is the operator in the previous part. Answer: By the Cayley-Hamilton theorem, T 2 = id, so T 200 = id. 4. Let T be a linear operator on a finite dimensional vector space V over a field F . (a) What does it mean to say that T is diagonalizable? Answer: T is diagonalizable if V has a basis consisting of eigen- vectors for T . (b) Give an example of a T whose characteristic polynomial splits but which is not diagonalizable, or prove that no such example exists. 0 1 Answer: The operator corresponding to the matrix is 0 0 such an example. (c) Suppose that W is a T -invariant subspace of V . Suppose that v1 + v2 ∈ W , where v1 and v2 are eigenvectors of T corresponding to distinct eigenvalues. Prove that v1 and v2 both belong to W . Answer: Let w := v1 + v2 ∈ W . Then T (w) = λ1v1 + λ2v2 ∈ W , since W is T -invariant. We also have λ1w = λ1v1 + λ1v2 ∈ W and hence T (w) − λ1w = (λ2 − λ1)v2 ∈ W , since W is a linear subspace. Since (λ2 − λ1) 6= 0, it follows that v2 ∈ W . Since v1 = w − v2, v1 ∈ W . 4.

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    4 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us