The Structure of Super Line Graphs

The Structure of Super Line Graphs

The structure of super line graphs. Jay Bagga Daniela Ferrero Department of Computer Science Department of Mathematics Ball State University Texas State University Muncie, IN San Marcos, TX [email protected] [email protected] Abstract A graph G on n vertices {v1,...,vn} can be associated with an adjacency matrix, which is the n × n matrix whose For a given graph G =(V,E) and a positive integer k, entries ai,j are given by ai,j =1if there is an edge joining v v G a =0 the super line graph of index k of G is the graph Sk(G) i and j in and i,j otherwise. For a multigraph, which has for vertices all the k-subsets of E(G), and two ai,j is the number of edges between vi and vj.Thecharac- vertices S and T are adjacent whenever there exist s ∈ S teristic polynomial of the graph G, denoted as χ(G, λ),is and t ∈ T such that s and t share a common vertex. In defined as det(A−λI).Theeigenvalues of the graph G are A α the super line multigraph Lk(G) we have an adjacency for those of .Thealgebraic multiplicity of an eigenvalue each such occurrence. is the multiplicity of α as a root of the characteristic poly- A m (α, A) m (α, G) We give a formula to find the adjacency matrix of Lk(G). nomial of and is denoted as a or a .The If G is a regular graph, we calculate all the eigenvalues of geometric multiplicity of an eigenvalue α is the dimension ker(A − αI) m (α, A) m (α, G) Lk(G) and their multiplicities. From those results we give of and is denoted as g or g . an upper bound on the number of isolated vertices. If A is a real symmetric matrix, every eigenvalue α satisfies ma(α, A)=mg(α, A).Thespectrum of G is the set of eigenvalues of G together with their multiplicities as eigen- values of A. The spectrum of a graph provides valuable 1. Introduction information on its topology. More information on this topic can be found in [8] and [11]. In [4] Bagga, Beineke and Varma introduced the concept We refer the reader to [9] and [10] for background on of super line graphs. For a given graph G =(V,E) and graph concepts not included in this Introduction. a positive integer k,thesuper line graph of index k of G is the graph Sk(G) which has for vertices all the k-subsets 2. Spectral properties of E(G), and two vertices S and T are adjacent whenever s ∈ S t ∈ T s t there exist and such that and share a com- Given two positive integers n and k where n ≥ k,let mon vertex. From the definition, it turns out that S1(G) m = n S m × n k . We denote by n,k the binary matrix coincides with the line graph L(G). Properties of super line whose rows are the m strings with exactly k entries equal graphs were presented in [7], [5] and [2], and a good and to 1.ThenifG is a graph with n edges, the rows of the concise summary can be found in [12]. More specifically, matrix Sn,k represent all the possible k-subsets of edges, or 2 some results regarding the super line graph of index were the vertices of the super line multigraph Lk(G). presented in [6] and [2]. Several variations of the super line graph have been considered. A recent survey of line graphs Lemma 2.1 If G is a graph with n edges, for any integer k, and their generalizations is given in [1]. 1 ≤ k ≤ n, the adjacency matrix of the multigraph Lk(G) In this paper we study the super line multigraph which is A(L (G)) = S A(S )t is defined as follows. For a given graph G =(V,E) and a k n,k n,k k k positive integer ,thesuper line multigraph of index of where A = A(L(G)) is the adjacency matrix of L(G). G is the multigraph Lk(G) whose vertices are the k-subsets of E(G), and two vertices S and T are joined by as many edges as pairs of edges s ∈ S and t ∈ T share a common Corollary 2.2 If G is a graph with n edges, for any inte- vertex. ger k, 1 ≤ k ≤ n, the adjacency matrix of the multigraph Proceedings of the 8th International Symposium on Parallel Architectures, Algorithms and Networks (ISPAN’05) 1087-4089/05 $20.00 © 2005 IEEE t Lk(G) is Obviously, Sn,1 Sn,1 = I. However, if k>1, t Sn,k Sn,k still has a particular pattern. In what follows, for A(L (G)) = S BtB(S )t − 2S (S )t k n,k n,k n,k n,k any matrix X, let us denote by (X)ij the entry in the row i and column j in the matrix X. where B = B(L(G)) is the incidence matrix of G. Lemma 2.4 For an integer n ≥ 2 and an integer k, 1 ≤ Notice that if k>|E| then S (G) has no vertices and if k k<n, let b and c be defined by k = |E|, Sk(G) is a trivial graph with one vertex. For this 1 ≤ k<|E| reason, we focus our attention to the case . n − 2 n − 1 b = and c = Proposition 2.3 Let G be a graph with n edges, k an inte- k − 2 k − 1 1 ≤ k<n A L(G) ger, , and the adjacency matrix of . Let Then m = n k ; then t Sn,k Sn,k = bJ +(c − b)I, χ(S AS t; λ)=(−λ)m−nχ(S tS A; λ). n,k n,k n,k n,k where J is the all-one’s matrix. t Proof: For any eigenvalue α of S AS , define r = t n,k n,k α Proof: S S is a n × n matrix whose entries are m (α, S ASt ) α = n,k n,k a n,k n,k . We first show that for eigenvalues 0 of S ASt , (n) n,k n,k (S tS ) = k (S )t (S ) n,k n,k ij k=1 n,k ik n,k kj r = m (α, S ASt ) (n) α g n,k n,k = k (S ) (S ) k=1 n,k ki n,k kj ≤ m (α, St S A) g n,k n,k ≤ m (α, St S A) Therefore if i = j, (Sn,k)ki and (Sn,k)kj coincide in a n,k n,k n−1 i = j n−2 exactly k−1 positions, and if , in exactly k−2 t S tS The first equality is clear since Sn,kAS is real and positions. Thus the entries of the matrix n,k n,k are all n,k −2 −1 α =0 S ASt b = n , except in the diagonal where all are c = n . symmetric. Suppose is an eigenvalue of n,k n,k. k−2 k−1 v ,...,v Let 1 rα be a basis for the eigenspace corresponding α v v ,...,v to . For any nonzero linear combination of 1 rα , t t t t χ(S tS A; λ) we must have S v =0and S Sn,kAS v = αS v. From Lemma 2.4 we shall obtain n,k n,k , and n,k n,k n,k n,k t m (α, S ASt ) ≤ m (α, St S A) therefore χ(Sn,n−1ASn,n−1 ; λ), for regular graphs. Therefore g n,k n,k g n,k n,k and (λ − α)rα |χ(St S A; λ) n,k n,k . Now consider α =0, let E0 be the eigenspace of S ASt N(St ) n,k n,k corresponding to eigenvalue 0, and let n,k 3. Regular graphs St St n be the null space of n,k. The rank of n,k is , since it is n n e +e easy to see that the linearly independent -vectors i n, In this section we consider a d-regular graph G with n 1 ≤ i ≤ n − 1 e + ···+ e for , and 1 n are in its column edges which has 2(d − 1)-regular line graph L(G).IfA N(St ) m − n space. Therefore the dimension of n,k is . is the adjacency matrix of L(G), then A has eigenvalues t Clearly, N(S ) ⊆ E0. Let v1,...,v ,v − ,...,v n,k mN m n r0 α1 =2(d−1),α2,...,αn with corresponding eigenvectors be a basis for E0 extended from v1,...,v − , a basis m n φ1 = 1,φ2,...,φn. N(St ) v for n,k . Thus any nonzero linear combination v ,...,v St v of m−n+1 r0 yields a nonzero eigenvector n,k Proposition 3.1 Let G be a d-regular graph with n ≥ 2 St S A λr0−m+n|χ(St S A; λ) of n,k n,k , giving that n,k n,k . edges, k an integer, 1 ≤ k<n, and A the adjacency matrix χ(S ASt ; λ)|λm−nχ(St S A; λ) Therefore n,k n,k n,k n,k , and of L(G). Let α1,...,αn be the eigenvalues of A and φi we have equality up to a sign because the polynomials are an eigenvector corresponding to the eigenvalue αi, for i = monic and the degrees are equal.

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