Natural Logarithm and Natural Exponential

Natural Logarithm and Natural Exponential

Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries exp(x) = inverse of ln(x) Last day, we saw that the function f (x) = ln x is one-to-one, with domain (0; 1) and range (−∞; 1). We can conclude that f (x) has an inverse function which we call the natural exponential function and denote (temorarily) by f −1(x) = exp(x), The definition of inverse functions gives us the following: y = f −1(x) if and only if x = f (y) y = exp(x) if and only if x = ln(y) The cancellation laws give us: f −1(f (x)) = x and f (f −1(x)) = x exp(ln x) = x and ln(exp(x)) = x : Annette Pilkington Natural Logarithm and Natural Exponential Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Graph of exp(x) We can draw the graph of y = exp(x) by reflecting the graph of y = ln(x) in the line y = x. have that the graph y = exp(x) is one-to-one and continuous with 20 domain (−∞; 1) and range (0; 1). Note that exp(x) > 0 for all values of x. We see that x 15 y = expHxL = e exp(0) = 1 since ln 1 = 0 exp(1) = e since ln e = 1; exp(2) = e2 since ln(e2) = 2; 10 exp(−7) = e−7 since ln(e−7) = −7: 2 H2, e L In fact for any rational number r, we have 5 exp(r) = er since ln(er ) = r ln e = H1, eL = H L y ln x r; 2 H-7, e-7L H0, 1L He , 2L He, 1L by the laws of Logarithms. H L -5 1, 0 5 10 -5 He-7Annette, -7L Pilkington Natural Logarithm and Natural Exponential -10 We Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Definition of ex . Definition When x is rational or irrational, we define ex to be exp(x). ex = exp(x) Note: This agrees with definitions of ex given elsewhere (as limits), since the definition is the same when x is a rational number and the exponential function is continuous. Restating the above properties given above in light of this new interpretation of the exponential function, we get: When f (x) = ln(x), f −1(x) = ex and ex = y if and only if ln y = x eln x = x and ln ex = x Annette Pilkington Natural Logarithm and Natural Exponential I Applying the exponential function to both sides of the equation ln(x + 1) = 5, we get eln(x+1) = e5 ln u I Using the fact that e = u, (with u = x + 1 ), we get x + 1 = e5; or x = e5 − 1 : I Applying the natural logarithm function to both sides of the equation ex−4 = 10, we get ln(ex−4) = ln(10) u I Using the fact that ln(e ) = u, (with u = x − 4) , we get x − 4 = ln(10); or x = ln(10) + 4: Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Solving Equations We can use the formula below to solve equations involving logarithms and exponentials. eln x = x and ln ex = x Example Solve for x if ln(x + 1) = 5 Example Solve for x if ex−4 = 10 Annette Pilkington Natural Logarithm and Natural Exponential ln u I Using the fact that e = u, (with u = x + 1 ), we get x + 1 = e5; or x = e5 − 1 : I Applying the natural logarithm function to both sides of the equation ex−4 = 10, we get ln(ex−4) = ln(10) u I Using the fact that ln(e ) = u, (with u = x − 4) , we get x − 4 = ln(10); or x = ln(10) + 4: Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Solving Equations We can use the formula below to solve equations involving logarithms and exponentials. eln x = x and ln ex = x Example Solve for x if ln(x + 1) = 5 I Applying the exponential function to both sides of the equation ln(x + 1) = 5, we get eln(x+1) = e5 Example Solve for x if ex−4 = 10 Annette Pilkington Natural Logarithm and Natural Exponential I Applying the natural logarithm function to both sides of the equation ex−4 = 10, we get ln(ex−4) = ln(10) u I Using the fact that ln(e ) = u, (with u = x − 4) , we get x − 4 = ln(10); or x = ln(10) + 4: Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Solving Equations We can use the formula below to solve equations involving logarithms and exponentials. eln x = x and ln ex = x Example Solve for x if ln(x + 1) = 5 I Applying the exponential function to both sides of the equation ln(x + 1) = 5, we get eln(x+1) = e5 ln u I Using the fact that e = u, (with u = x + 1 ), we get x + 1 = e5; or x = e5 − 1 : Example Solve for x if ex−4 = 10 Annette Pilkington Natural Logarithm and Natural Exponential u I Using the fact that ln(e ) = u, (with u = x − 4) , we get x − 4 = ln(10); or x = ln(10) + 4: Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Solving Equations We can use the formula below to solve equations involving logarithms and exponentials. eln x = x and ln ex = x Example Solve for x if ln(x + 1) = 5 I Applying the exponential function to both sides of the equation ln(x + 1) = 5, we get eln(x+1) = e5 ln u I Using the fact that e = u, (with u = x + 1 ), we get x + 1 = e5; or x = e5 − 1 : Example Solve for x if ex−4 = 10 I Applying the natural logarithm function to both sides of the equation ex−4 = 10, we get ln(ex−4) = ln(10) Annette Pilkington Natural Logarithm and Natural Exponential Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Solving Equations We can use the formula below to solve equations involving logarithms and exponentials. eln x = x and ln ex = x Example Solve for x if ln(x + 1) = 5 I Applying the exponential function to both sides of the equation ln(x + 1) = 5, we get eln(x+1) = e5 ln u I Using the fact that e = u, (with u = x + 1 ), we get x + 1 = e5; or x = e5 − 1 : Example Solve for x if ex−4 = 10 I Applying the natural logarithm function to both sides of the equation ex−4 = 10, we get ln(ex−4) = ln(10) u I Using the fact that ln(e ) = u, (with u = x − 4) , we get x − 4 = ln(10); or x = ln(10) + 4: Annette Pilkington Natural Logarithm and Natural Exponential I As it stands, this limit has an indeterminate form since both numerator and denominator approach infinity as x ! 1 I We modify a trick from Calculus 1 and divide (both Numertor and denominator) by the highest power of ex in the denominator. ex ex =ex lim = lim x!1 10ex − 1 x!1 (10ex − 1)=ex I 1 1 = lim = x!1 10 − (1=ex ) 10 Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Limits From the graph we see that lim ex = 0; lim ex = 1: x→−∞ x!1 ex Example Find the limit limx!1 10ex −1 . Annette Pilkington Natural Logarithm and Natural Exponential I We modify a trick from Calculus 1 and divide (both Numertor and denominator) by the highest power of ex in the denominator. ex ex =ex lim = lim x!1 10ex − 1 x!1 (10ex − 1)=ex I 1 1 = lim = x!1 10 − (1=ex ) 10 Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Limits From the graph we see that lim ex = 0; lim ex = 1: x→−∞ x!1 ex Example Find the limit limx!1 10ex −1 . I As it stands, this limit has an indeterminate form since both numerator and denominator approach infinity as x ! 1 Annette Pilkington Natural Logarithm and Natural Exponential I 1 1 = lim = x!1 10 − (1=ex ) 10 Natural Logarithm Function Graph of Natural Logarithm Algebraic Properties of ln(x) Limits Extending the antiderivative of 1=x Differentiation and integration Logarithmic differentiation Exponentials Graph ex Solving Equations Limits Laws of Exponentials Derivatives Derivatives Integrals summaries Limits From the graph we see that lim ex = 0; lim ex = 1: x→−∞ x!1 ex Example Find the limit limx!1 10ex −1 .

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