Section 15.6: Directional Derivatives and Gradients

Section 15.6: Directional Derivatives and Gradients

Section 15.6: Directional Derivatives and Gradients Goals : 1. To calculate the directional derivative of a multivariable function 2. To calculate the gradient of a multivariable function 3. To solve applications involving a gradient Recall : Partial Derivatives allow us to calculate the rate of change of a two-variable function f in the x and y directions. In this section, we will learn how to compute the rate of change of f in any direction. The question of the day is how do we go about measuring the instantaneous rate of change of a two- variable function f in any direction on the domain of f? Well, as you've seen, vectors are very good at pointing in a direction of our choosing. So let u be a unit vector pointing in some pre-specified direction (in the xy -plane). Then a line through some point (x0 , y0 ) in the direction of u = u1,u2 is + = + given in vector form by r = x0 , y0 t u1,u2 (the parametric equations of the line are x x0 tu 1 and = + y y0 tu 2 ). Because u has magnitude 1, the parameter t gives the distance from (x0 , y0 ) to the point (x, y) . Now, if we restrict the domain of f to the points on this line, then z = f (x, y) = + + f (x0 tu 1, y0 tu 2 ) is a curve traced out on the surface corresponding to f. Note that, with this restriction, f is ultimately a function of one variable: t. Thus, we can define the directional derivative using a limit definition in much the same way we did in single variable calculus. Definition : Assume the domain of the function f( x , y ) is restricted as above and u = u1,u2 is a unit vector. Then the directional derivative of f at (x0 , y 0 ) in the direction of u is fxy(,)− fx (, y ) = 0 0 Dfu ( x0 , y 0 ) lim , t→0 t if this limit exists. Notes: 1. Since z = f (x, y) is a one variable function of t on the restricted domain, we can actually find the directional derivative of f as a function of x and y by applying the chain rule, assuming f is differentiable. In this case, the directional derivative of f in the direction of a unit vector u = u1,u2 is dz∂ z dx ∂ z dy D f( x , y ) = = + = f (x, y)u + f (x, y)u . u dt∂ x dt ∂ y dt x 1 y 2 2. We can rewrite the last formula in terms of a dot product as follows: = • Du f (x, y) ( f x (x, y)i + f y (x, y) j) u, where u is a unit vector. The first factor of this dot product is called the gradient . Definition : Suppose z = f (x, y) and first partials exist. Then the gradient of f, denoted ∇f (x, y) , is the vector ∇ = f (x, y) f x (x, y) i + f y (x, y) j Notes : 1. ∇f is read "del f." The symbol del is considered an operator and has no value in and of itself. Another notation for the gradient is grad f (x, y) . 2. The gradient is a vector that lies in the xy -plane, not in space. 3. With the new notation, the directional derivative can be written as = ∇ • Du f (x, y) f (x, y) u (or, using the alternative form of the dot product = ∇ φ φ ∇ Du f (x, y) || f (x, y ||) cos where is the angle between f (x, y) and u). = ∇ φ 4. Using the form Du f (x, y) || f (x, y ||) cos of the directional derivative, we arrive at the properties of the gradient listed below. PROPERTIES OF GRADIENT JUSTIFICTION OF PROPERTY The maximum rate of change of f is ||∇f (x, y ) || OR cos φ = 1 when φ = 0 f increases most rapidly in the direction of the gradient ∇f (x, y) The rate of change of f is 0 when u is orthogonal to ∇ f (x, y) . π OR cos φ = 0 when φ = To stay on a level curve of f, go in an orthogonal 2 direction to ∇f (x, y) . The minimum rate of change of f is − ∇f (x, y) which occurs when u is in the opposite direction of GRAD z . cos φ = −1when φ = π OR f decreases most rapidly in the opposite direction of ∇f (x, y) Note : Directional Derivatives and Gradients generalize to functions of three variables. See page 983. The Tangent Plane (Method 2) Another way to find the equation of a plane is to use a point on the plane and a normal vector (see section 13.5). Suppose a surface is represented by an implicit function of z, say F(, x y , z ) = c. To find a normal vector to the tangent plane, we use the fact that, for a three-variable function of the form = ∇ = w Fxyz(, , ) , the gradient, Fx(0 , y 0 , z 0 ) , is orthogonal to the level surface F(, x y , z ) c at (x0 , y0 , z0 ) and, therefore, normal to the corresponding tangent plane at (x0 , y0 , z0 ) . In other words, we treat an implied function defined by the equation F(, x y , z ) = c as a level surface of a three-variable ∇ function. Thus, Fx(0 , y 0 , z 0 ) is a normal vector to the tangent plane at (x0 , y0 , z0 ) . So, the equation of the tangent plane to a surface at (x0 , y0 , z0 ) is given by −+ −+ −= Fxyzxxx(,,)(000 0 ) Fxyz y (,,)( 000 yy 0 ) Fxyzzz z (,,)( 000 0 )0 Note : This last result only holds if f is differentiable at (x0 , y0 , z0 ) . .

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    2 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us