P-Groups with All the Elements of Order P in the Center∗ Daniela Bubboloni Gabriella Corsi Tani DIMAD Universita’ Di Firenze Via C

P-Groups with All the Elements of Order P in the Center∗ Daniela Bubboloni Gabriella Corsi Tani DIMAD Universita’ Di Firenze Via C

View metadata, citation and similar papers at core.ac.uk brought to you by CORE provided by Florence Research Algebra Colloquium 11:2 (2004) 181{190 Algebra Colloquium °c AMSS CAS 2004 p-Groups with All the Elements of Order p in the Center¤ Daniela Bubboloni Gabriella Corsi Tani DIMAD Universita' di Firenze via C. Lombroso 6/17, I-50134 Firenze, Italy E-mail: [email protected]¯.it [email protected]¯.it Received 26 April 2001 Communicated by C.K. Gupta Abstract. Resting on a suitable base of the quotients of the ¸i-series for the free groups on r generators, we get, for p odd, a class of TH-p-groups (the groups n in the title) Gr with arbitrary large derived length. We prove that every TH-p- n n group G with r generators and exponent p is a quotient of Gr and a product m of m cyclic groups, where p = j­1(G)j: At last we describe the TH-p-groups of exponent p2: 2000 Mathematics Subject Classi¯cation: 20D15 Keywords: p-groups, central series, free groups 1 Introduction Let G be a p-group and p an odd prime. We denote by ­i(G) the subgroup of G generated by the elements of order dividing pi, and we call G a TH- p-group if all its elements of order p are central, i.e., ­1(G) · Z(G): This name was introduced by the authors in [2] in acknowledgment to Thompson who ¯rst obtained some classical results for the number of generators of these groups (see [4, III, 12.2]). In [2], it was shown that several properties of the regular p-groups hold also for the class of TH-p-groups. There we 2 characterized the TH-p-groups G with j­1(G)j = p and exhibited some other examples of TH-p-groups obtaining only metabelian groups. In this paper, following a suggestion of C.M. Scoppola, we construct a n class of TH-p-groups Gr (see De¯nition 3.1) with arbitrary large derived length (see Theorems 3.2 and 3.3). This construction rests on the properties of the central series ¸i(Fr) of the free group Fr on r generators and on the behaviour of a particular base ¤Supported by M.U.R.S.T. and C.N.R. 182 D. Bubboloni, G. Corsi Tani of the elementary abelian quotients ¸i(Fr)=¸i+1(Fr) (see Theorem 2.5(c)). The explicit determination of a base for ¸i(Fr)=¸i+1(Fr) has interest in itself and we devote Section 2 to this, resting on methods and results in [5] and [1]. Similar goals for the central series ·n(Fr); the Jennings{Lazard{Zassen- haus series of G, were reached by C.M. Scoppola in [6] (compare Lemma 1.11 and Proposition 2.5 in [6] with (a) and (c) of Theorem 2.5). In Section 4, we observe that each TH-p-group with r generators and n n exponent p is a quotient of the group Gr (Theorem 4.1). Moreover, we obtain some new general result about the structure of TH-p-groups which turn out to be a suitable product of cyclic groups (Theorem 4.3). Finally, in Section 5, we describe the TH-p-groups of exponent p2: The notation is standard. We indicate by γi(G) the i-th term of the lower central series of a group G: Throughout this paper, p will be always an odd prime. 2 The ¸i-Series of the Free Groups We recall the construction of the central series ¸i(G) of a group G and the properties of this series which we intend to use, collecting them from [5] and [1]. De¯nition 2.1. For any group G, put pi¡1 pi¡2 ¸i(G) := γ1(G) γ2(G) ¢ ¢ ¢ γi(G)(i ¸ 1): Thus, ¸i(G) is a characteristic subgroup of G and G = ¸1(G) ¸ ¸2(G) ¸ ¢ ¢ ¢ ¸ ¸n(G) ¸ ¢ ¢ ¢ : Theorem 2.2. [5, 1] For any i 2 N; the following properties hold: (a) [¸i(G); ¸j(G)] · ¸i+j(G); p (b) ¸i(G) = [¸i¡1(G);G] ¸i¡1(G) ; pi¡1 (c) [¸i(G);G] = γ2(G) ¢ ¢ ¢ γi+1(G); pi¡j (d) if G/γj(G) is torsion free, then ¸i(G) \ γj(G) = γj(G) ¢ ¢ ¢ γi(G); pj (e) ¸i(G) · ¸i+j(G); (f) the ¸i-series is central and ¸i(G)=¸i+1(G) is an elementary abelian p-group. De¯nition 2.3. Let Fr be the free group on r free generators x1; x2; : : : ; xr, p and A = (a1; a2; : : : ; an) be an ordered subset of Fr. We denote by A the p p p p ordered subset A = (a1; a2; : : : ; an). Moreover, if H £ Fr, we denote with A mod H the ordered subset (a1H; a2H; : : : ; anH) of Fr=H. For brevity, we will often write ¸i and γi instead of ¸i(Fr) and γi(Fr), respectively. p-Groups with Elements of Order p in Center 183 Lemma 2.4. Let a1; a2; : : : ; an 2 ¸i¡1 (i ¸ 2): Then p p p p (a1a2 ¢ ¢ ¢ an) ´ (a1 a2 ¢ ¢ ¢ an ) mod ¸i+1: Proof. Let a1; a2 2 ¸i¡1: By the Hall{Petrescu formula, there exist elements ck 2 γk(¸i¡1)(k = 2; : : : ; p) such that (p) p p p p 2 (p¡1) a1 a2 = (a1a2) c2 ¢ ¢ ¢ cp¡1 cp: Since i; k ¸ 2, we get ¸k(i¡1) · ¸i, and by (a) and (e) of Theorem 2.2, we p obtain γk(¸i) · ¸ki and ¸i · ¸i+1; so whenever k · p ¡ 1; we get (p) p p p ck k 2 γk(¸i¡1) · ¸k(i¡1) · ¸i · ¸i+1: For k = p, since i ¸ 2 and p ¸ 3 imply p(i ¡ 1) ¸ i + 1, we get cp 2 γp(¸i¡1) · ¸p(i¡1) · ¸i+1: Hence, p p p a1 a2 ´ (a1a2) mod ¸i+1: Now by induction on n; the lemma follows at once. 2 Theorem 2.5. (a) ¸i¡1=¸i may be embedded into ¸i=¸i+1: Moreover, there exists a base p Ai¡1 mod ¸i of ¸i¡1=¸i such that Ai¡1 mod ¸i+1 is independent in ¸i=¸i+1. (b) For each i, let Ai mod γi+1 be a base of γi/γi+1: Then pi¡1 pi¡2 (A1 [A2 [ ¢ ¢ ¢ [ Ai) mod ¸i+1 is a base for ¸i=¸i+1: (c) Let Ci denote the set of the basic commutators of weight i in a ¯xed sequence, then pi¡1 pi¡2 Bi := (C1 [C2 [ ¢ ¢ ¢ [ Ci) mod ¸i+1 is a base of ¸i=¸i+1: p (d) The map 'i : ¸i¡1 ! ¸i=¸i+1 de¯ned by x'i = x ¸i+1 is a homomor- phism and ker 'i = ¸i. Proof. (a) By a well-known result of Blackburn [5, VIII, 1.9b)], since p is odd, there is an isomorphism γ1 γi ®i : p £ ¢ ¢ ¢ £ p ¡! ¸i=¸i+1 γ1 γ2 γi γi+1 184 D. Bubboloni, G. Corsi Tani pi¡1 pi¡2 given by (¹a1; a¹2;:::; a¹i)®i = a1 a2 ¢ ¢ ¢ ai¸i+1: If ¹ is the natural im- γ1 γi¡1 γ1 γi mersion of p £ ¢ ¢ ¢ £ p into p £ ¢ ¢ ¢ £ p , then the map γ1 γ2 γi¡1 γi γ1 γ2 γi γi+1 ¡1 ¼i = ®i¡1 ¹®i : ¸i¡1=¸i ¡! ¸i=¸i+1 is a monomorphism. γj Leta ¹j 2 p and x = (1;:::; 1; a¹j; 1;:::; 1)®i¡1 2 ¸i¡1=¸i: Then γj γj+1 pi¡j¡1 x = aj ¸i and we have pi¡j x¼i = aj ¸i+1 2 ¸i=¸i+1: p p Now if Cj mod γj γj+1 is a base of γj/γj γj+1; then i[¡1 i[¡1 p pi¡1¡j ((Cj mod γj γj+1)®i¡1) = (Cj mod ¸i) j=1 j=1 is a base, say Ai¡1 mod ¸i of ¸i¡1=¸i: Hence, we obtain that i[¡1 pi¡j p (Ai¡1 mod ¸i)¼i = (Cj mod ¸i+1) = Ai¡1 mod ¸i+1 j=1 is a base of Im ¼i. (b) First of all, we observe that if Ai mod γi+1 is a base of γi/γi+1, p since γi/γi+1 is a torsion-free abelian group, Ai mod γi γi+1 is a base of p the elementary abelian group γi/γi γi+1. p p Next the base (A1 mod γ1 γ2) [ ¢ ¢ ¢ [ (Ai mod γi γi+1) of γ1 γi p £ ¢ ¢ ¢ £ p γ1 γ2 γi γi+1 i¡1 p pi¡2 is taken onto the base (A1 [A2 [ ¢ ¢ ¢ [ Ai) mod ¸i+1 of ¸i=¸i+1 by the isomorphism ®i which we mentioned in the proof of (a). (c) By the well-known Hall's basis theorem, Ci mod γi+1 is a base of γi/γi+1 (see [3, Chapter 11]). Thus, (c) follows from (b). ¸i p (d) By Lemma 2.4, the map 'i : ¸i¡1 ! given by x'i = x ¸i+1 is ¸i+1 a homomorphism. We prove ker 'i = ¸i. Clearly, ¸i · ker 'i, and we only need to show p that for x 2 ¸i¡1, the condition x 2 ¸i+1 implies x 2 ¸i. By (a), we can choose a base Ai¡1 mod ¸i for ¸i¡1=¸i with Ai¡1 = (a1; a2; : : : ; at) p ®1 ®2 ®t such that Ai¡1 mod ¸i+1 is independent in ¸i=¸i+1.

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    10 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us