Spacetime Trigonometry DRAFT Version: 7/21/2006 1

Spacetime Trigonometry DRAFT Version: 7/21/2006 1

AAPT Topical Conference: Teaching General Relativity to Undergraduates AAPT Summer Meeting 1 Syracuse, NY, July 20-21,22-26 2006 New Ideas for Teaching Relativity: Space-Time Trigonometry Rob Salgado Syracuse University [email protected] Department of Physics In the teaching of Relativity, there are many references to analogues: • – physical concepts in Galilean and Special Relativity – mathematical concepts in Euclidean and Minkowskian geometry There is a known (but not well-known) relationship • among the Euclidean, Galilean and Minkowskian geometries: – They are the “affine Cayley-Klein geometries”. (The de Sitter spacetimes are among the Cayley-Klein geometries.) We exploit this fact to develop a new presentation of relativity, • which may be useful for teaching high-school and college students. eventual Goal: • Introduce some “spacetime intuition” earlier in the curriculum. Goal for this poster: Highlight the foundations of this approach. • What makes this formulation interesting is that • the geometry of Galilean Relativity acts like a • “bridge”from Euclidean geometry to Special Relativity. a faithful visualization of tensor-algebra • can be incorporated a A trigonometric analogy (Yaglom) 2 aI.M. Yaglom, A Simple Non-Euclidean Geometry and Its Physical Basis (1979). Euclidean rotation 1 v t′ = (cos θ)t +( sin θ)y t′ = t + − y − √1+v2 √1+v2 v 1 y′ = ( sin θ)t +( cos θ)y y′ = t + y √1+v2 √1+v2 where v = tan θ. Galilean boost transformation t′ =(cosg θ)t +(0sing θ)y t′ = 1 t y′ =(sing θ)t +( cosg θ)y y′ = v t + 1 y where v = tang θ. θ Yaglom defines cosg θ 1, sing θ θ so that tang θ sing θ. ≡ ≡ ≡ cosg θ ≡ Lorentz boost transformation 1 +v t′ = (cosh θ)t +(+ sinh θ)y t′ = t + y √1 v2 √1 v2 −v −1 y′ = ( sinh θ)t +( cosh θ)y y′ = t + y √1 v2 √1 v2 − − where v = tanh θ. The Cayley-Klein Geometries 3 measure of length between two points elliptic parabolic hyperbolic measure of (η2 = 1) (η2 = 0) (η2 = +1) angle between − two lines elliptic (ǫ2 = 1) Elliptic Euclidean Hyperbolic − parabolic 2 co-Euclidean co-Minkowskian (ǫ = 0) Galilean “anti-Newton-Hooke” “Newton-Hooke” hyperbolic (ǫ2 = +1) anti-De-Sitter Minkowski De-Sitter 2-dimensional manifolds with metric signature (+1, ǫ2) and constant curvature κ = η2 − − 2 a b ds = gab dx dx (1 + η2ǫ2y2)dt2 (1 η2t2)ǫ2dy2 2η2ǫ2ty dt dy = − − − (1 η2(t2 ǫ2y2))2 − − Column η2 =0 are the affine Cayley-Klein geometries. Row ǫ2 = 1 includes the classical non-Euclidean geometries. − Row ǫ2 = +1 are the constant curvature Lorentzian spacetimes. The Metric (Proper Time) 2 We will be concerned with the “η = 0” (or “affine”) geometries. 4 [Observe that Euclid V, the Parallel Postulate, is valid for these geometries.] In this case, the line-element reduces to dS2 = (dt)2 − ǫ2(dy)2 which is a unified (meta-)expression for 2 2 2 2 (ds )Euc = (dt) + (dy) if ǫ = 1 2 2 2 − (ds )Gal = (dt) if ǫ = 0 . 2 2 2 2 (ds ) = (dt) (dy) if ǫ = +1 Min − Upon introducing the metric tensor, the line-element can be written T 2 dt 1 0 dt dS = 2 . dy 0 ǫ dy ! − ! ! Since the Galilean metric is degenerate, one needs to provide an additional metric in order to measure spacelike separations: 1 2 2 2 2 dS if ǫ = 0 dL = −ǫ 6 . 2 2 (dy) if ǫ = 0 The Circle Define the “CIRCLE of radius R” to be the locus of points (t, y) that is a constant 2 positive square-interval R from a common point (t0, y0). 2 2 2 2 R = (t − t0) − ǫ (y − y0) In fact, the unit-circle [generally, unit-sphere] provides a faithful visualization of a symmetric metric tensor. The Pole and the Polar (Visualizing Tensor-Index raising and lowering) 5 A metric tensor is a symmetric tensor that can be used to assign magnitudes to vectors. A metric tensor can also provide a rule to identify a vector with a unique covector. The vector and its covector are [metric-]duals of each other with this metric. Given a a a vector V , in the presence of a metric gab, we can form the combination gabV , which is a covector denoted by Vb. This is known as “index lowering”, a particular move when performing “index gymnastics”. a 2 V “the pole” This construction is due to W. Burke, 1.5 Applied Differential Geometry y y1 through the pole, draw the tangents to the conic 0.5 g Va = V ±1 ±0.50 0.5 1t ab b t “the polar [hyperplane]” gab ±0.5 metric tensor ±1 the number of polar hyperplanes of V b square-norm of the vector V a pierced by the vector V a = g V aV b (number of “bongs of bell”) ab ! In Minkowski spacetime: a timelike vector and a lightlike vector and their metric-duals. a draft of The Trilogy of the Surveyors the Trilogy is available 2 2 y y 6 Euclidean 1 1 ±2 ±1 1 2 ±2 ±1 1 2 t t ±1 ±1 ±2 ±2 2 2 y y Here, where the tangents Galilean 1 1 coincide, “simultaneity” is absolute. ±2 ±1 1 2 ±2 ±1 1 2 t t ±1 ±1 ±2 ±2 2 2 y y Minkowskian 1 1 ±2 ±1 1 2 ±2 ±1 1 2 t t ±1 ±1 ±2 ±2 Family of surveyors of a two-dimensional plane: From this point, travel in all possible directions. Stop when your odometer reads 1 mi. This “calibration curve” defines a circle, with perpendicular as “tangent to the circle”. Family of observers of a two-dimensional spacetime: From this event, travel with all possible velocities. Stop when your wristwatch reads 1s. This “calibration curve” defines a “circle”, with simultaneous as “tangent to the circle”. The Angle (Rapidity) 7 Define the “ANGLE-measure between two future-timelike lines ℓ1 and ℓ2”: CIRCULAR arc-LENGTH L intercepted by ℓ1 and ℓ2 Θ = radius R of the CIRCLE centered at o 2 1.8 1.6 1.4 ℓ2 1.2 −1 θg = tang v 1 A A 0.8 −1 −1 A θm = tanh v θe = tan v P AU 0.6 P PPPq 0.4 0.2 −1 Θ = TANH v ℓ1 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 t Use the [spacelike] square-interval to measure the spacelike arc-length along the circle t2 ǫ2y2 = R2: − 1 Θ = dL R Z 8 For ǫ2 = 0 cases, 6 1 1 dy 1 1 Θ = dy2 dt2 = = sinh− (ǫy/R) s 2 2 2 2 R Z − ǫ Z √R + ǫ y ǫ Thus, ǫy = R sinh(ǫΘ) t = R cosh(ǫΘ). Euclidean case (ǫ2 = 1) Minkowskian case (ǫ2 = +1) − y = R sin(θe) y = R sinh(θm) t = R cos(θe) t = R cosh(θm) For the Galilean case (ǫ2 = 0), 1 1 y θg = dL = dy = . R Z R Z R Thus, y = Rθg = R sing(θg) t = R = R cosg(θg) where cosg(θg) = 1 and sing(θg) = θg We can write the results for the three cases as y = R SINH Θ t = R COSH Θ the connecting relation (“velocity = tangent(rapidity)”) y v = = tan θ = tang θ = tanh θ t e g m Hypercomplex Numbers? 9 (Maximum Signal Speed) 2 2 Physically, ǫ = (clight/cmax) 2 Minkowskian cmax = clight (finite): ǫ = 1 [but ǫ = 1](double numbers) 2 6 Galilean cmax = (infinite): ǫ = 0 [but ǫ = 0](dual numbers) Euclidean c = ic∞ (finite, imaginary): ǫ2 = 1 (complex6 numbers) max light − It is convenient (but not necessary) to introduce the following “generalized complex”or “hypercomplex” number systems. Consider quantities of the form z = a + ǫb, where a and b are real-numbers and ǫ is the “generalized imaginary number”. These quantities can be given a matrix representation: 1 0 a 0 real 1 = a = 0 1 ! 0 a ! 0 1 a b complex ǫ = − a + ǫb = − Euclidean 1 0 ! b a ! 0 0 a 0 dual (ǫ2 = 0 [ǫ = 0]) ǫ = a + ǫb = Galilean 6 1 0 ! b a ! 0 1 a b double (ǫ2 = 1 [ǫ = 1]) ǫ = a + ǫb = Minkowskian 6 1 0 ! b a ! (these number systems have “divisors of zero”) Dual (ǫ2 = 0 [ǫ = 0]): Double (ǫ2 = 1 [ǫ = 1]): 6 6 1/ǫ implies ǫx = 1 1/(1 + ǫ) implies (1 + ǫ)x = 1 ǫ2x = ǫ (1 ǫ2)x = 1 ǫ − − 0 = ǫ 0 = 1 ǫ − impossible! impossible! Note: One can easily proceed with formal calculations in which ǫ is treated algebraically but never evaluated until the last step. 2 It appears all physical quantities involve ǫ . The Circular Functions (The Relativistic “Factors”) 10 Let Θ be a real number. EXP Θ exp(ǫΘ) ≡ (ǫΘ)2 (ǫΘ)3 (ǫΘ)4 = 1 + (ǫΘ) + + + + 2! 3! 4! ··· (ǫΘ)2 (ǫΘ)4 = 1 + + + " 2! 4! ···# (ǫΘ)3 (ǫΘ)5 + (ǫΘ) + + + " 3! 5! ···# = cosh (ǫΘ) + sinh (ǫΘ) Θ2 Θ4 = 1 + ǫ2 + ǫ4 + " 2! 4! ···# Θ3 Θ5 +ǫ Θ + ǫ2 + ǫ4 + " 3! 5! ···# = COSH Θ + ǫ SINH Θ sinh(ǫΘ) ǫ SINH Θ ǫ TANH Θ tanh(ǫΘ) = = ≡ cosh(ǫΘ) COSH Θ Differential Identities Algebraic Identities d 2 2 2 1 = COSH Θ ǫ SINH Θ EXP Θ = ǫ EXP Θ − dΘ d TANH Θ1 + TANH Θ2 COSH Θ = ǫ2 SINH Θ TANH (Θ1 + Θ2) = 2 1 + ǫ TANH Θ1 TANH Θ2 dΘ 2 2 1 2 d COSH Θ = (1 ǫ TANH Θ)− / SINH Θ = COSH Θ − dΘ d 2 TANH Θ = 1 ǫ2 TANH Θ dΘ − Every vector can be thought of as the HYPOTENUSE of some RIGHT triangle.

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