Simple Derivation of Electromagnetic Waves from Maxwell's Equations

Simple Derivation of Electromagnetic Waves from Maxwell's Equations

Simple Derivation of Electromagnetic Waves from Maxwell’s Equations By Lynda Williams, Santa Rosa Junior College Physics Department Assume that the electric and magnetic fields are constrained to the y and z directions, respectfully, and that they are both functions of only x and t. This will result in a linearly polarized plane wave travelling in the x direction at the speed of light c. Ext( , ) Extj ( , )ˆ and Bxt( , ) Bxtk ( , ) ˆ We will derive the wave equation from Maxwell’s Equations in free space where I and Q are both zero. EB 0 0 BE EB με tt00 iˆˆ j kˆ E Start with Faraday’s Law. Take the curl of the E field: E( x , t )ˆ j = kˆ x y z x 0E ( x , t ) 0 EB Equating magnitudes in Faraday’s Law: (1) xt This means that the spatial variation of the electric field gives rise to a time-varying magnetic field, and visa-versa. In a similar fashion we derive a second equation from Ampere-Maxwell’s Law: iˆˆ j kˆ BBE Take the curl of B: B( x , t ) kˆ = ˆ j (2) x y z x x00 t 0 0B ( x , t ) This means that the spatial variation of the magnetic field gives rise to a time-varying electric field, and visa-versa. Take the partial derivative of equation (1) with respect to x and combining the results from (2): 22EBBEE 22 = 0 0 0 0 x x t t x t t t 22EE (3) xt2200 22BB In a similar manner, we can derive a second equation for the magnetic field: (4) xt2200 Both equations (3) and (4) have the form of the general wave equation for a wave (,)xt traveling in 221 the x direction with speed v: . Equating the speed with the coefficients on (3) and (4) x2 v 2 t 2 we derive the speed of electric and magnetic waves, which is a constant that we symbolize with “c”: 1 8 c 2.997 x 10 m / s 00 The simplest solutions to the differential equations (3) and (4) are sinusoidal wave functions: E( x , t ) Emax cos( kx t ) (5) B( x , t ) Bmax cos( kx t ) (6) where k = 2π/λ is the wavenumber , ω = 2πƒ is the angular frequency, λ is the wavelength, f is the frequency and /.k f v c . Taking partial derivatives of E and B and substituting into (1): EB kEsin( kx t ) and Bsin( kx t ) xtmax max kEmaxsin( kx t ) B max sin( kx t ) Emax B max cB max k E c. B At every instant, the ratio of the electric field to the magnetic field in an electromagnetic wave equals the speed of light. The rate of energy transfer by an electromagnetic wave is described by the Poynting vector, S, defined as the rate at which energy passes through a unit surface area perpendicular to the direction of 1 wave propagation (W/m2): SEB. For a plane electromagnetic wave: 0 EB E22 cB S . The time average of S over one or more cycles is called the wave intensity, I, 0 0c 0 which gives the very important result that the intensity of a light wave is proportional to the square of the amplitude of the electric or magnetic fields: 22 EBmax max ISave 2200cc (The ½ comes from averaging the cosine squared terms.) Intensity is a measureable “real” quantity that has primary significance in all wave phenomena. Intensity is the loudness of a sound or the brightness of a light. Intensity will serve as an important conceptual analog in our study of quantum physics in the following way: “Intensity is to the electric field as probability is to the wave function.” Yum! .

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    2 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us