1. Basic Properties of the Tor Functor for Exercises 24–26 on Pages 34

1. Basic Properties of the Tor Functor for Exercises 24–26 on Pages 34

1. Basic properties of the tor functor For exercises 24–26 on pages 34–35 of Atiyah-Macdonald, let us review the definition and basic properties of the Tor functor. Let M and N be A-modules and consider a free resolution of M, say d3 d2 d1 d0 · · · −−−−→ F2 −−−−→ F1 −−−−→ F0 −−−−→ M −−−−→ 0. Consider the complex d3 d2 d1 · · · −−−−→ F2 −−−−→ F1 −−−−→ F0 −−−−→ 0 obtained by deleting M. A The A-modules Torn (M, N) may be defined as the homology modules of the complex obtained by tensoring with N. Thus A (ker dn ⊗ 1) Torn (M, N) = . (im dn+1 ⊗ 1) An important fact is that one gets the same modules no matter what free (or projective) resolution one takes A ∼ A of M. It is also the case that Torn (M, N) = Torn (N,M). A basic property of the Tor functor is that if 0 −−−−→ M ′ −−−−→ M −−−−→ M ′′ −−−−→ 0 is a short exact sequence of A-modules, then tensoring this sequence over A with N induces a long exact sequence A ′′ A ′ A · · · −−−−→ Tor2 (M , N) −−−−→ Tor1 (M , N) −−−−→ Tor1 (M, N) −−−−→ A ′′ ′ ′′ Tor1 (M , N) −−−−→ M ⊗A N −−−−→ M ⊗A N −−−−→ M ⊗A N −−−−→ 0. In particular, if F is a free A-module and 0 −−−−→ K −−−−→ F −−−−→ M −−−−→ 0 A ∼ A is a short exact sequence, then we have Tori+1(M, N) = Tori (K, N) for each positive integer i and A Tor1 (M, N) measures how far tensoring with N fails to preserve exactness of the given sequence. Let I and J be ideals in a ring A. One can show that: ∼ (1) (A/I) ⊗A (A/J) = A/(I + J). A ∼ (I∩J) (2) Tor1 (A/I, A/J) = IJ . 1 Let k be a field, let x,y be indeterminates over k, and let R be either the polynomial ring k[x,y] or the formal power series ring k[[x,y]]. Let m = (x,y)R. R m m m One can calculate the modules Tori (R/ , R/ ) by considering the free resolution of R/ α β 0 −−−−→ R −−−−→ R2 −−−−→ R −−−−→ R/ m −−−−→ 0 where α(1) = (y, −x), β(1, 0) = x, and β(0, 1) = y, and then tensoring with R/ m. One sees that R m m R m m Tor1 (R/ , R/ ) is nonzero while Tori (R/ , R/ ) = 0 for i > 1. Let I = (f1, . , fn)R be an m-primary ideal in R. Assume that there exists a free resolution of I α β 0 −−−−→ Rn−1 −−−−→ Rn −−−−→ I −−−−→ 0 such that for some choice of bases for Rn−1 and Rn the map α is defined by left multiplication by a matrix M ∈ Rn×n−1. One can show that (1) the ideal I is minimally generated by n elements ⇐⇒ all the entries of M are in the maximal ideal m of R, and R m ∼ R m ∼ m (2) Tor1 (I,R/ ) = Tor2 (R/I, R/ ) = (I : )/I. (3) If I is minimally generated by n elements, then (I : m)/I =∼ (R/ m)n−1. It then follows that (I : m)/I is minimally generated by n − 1 elements. The ideal (I : m)/I of the ring R/I is called the socle of R/I. An ideal I is said to be irreducible if I is not the intersection of two properly bigger ideals of the ring. For R the polynomial ring k[x,y] or the formal power series ring k[[x,y]] and m = (x,y)R, if the ideal I is m-primary, then I is irreducible ⇐⇒ (I : m)/I is one-dimensional as a vector space over R/ m. 2.

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