DATE : 04/11/2018 Test Booklet Code X I&II 18 TAMIL NADU Regd. Office : Aakash Tower, 8, Pusa Road, New Delhi-110005 | Ph.: 011-47623456 Answers & Solutions for NTSE (Stage-I) 2018-19 INSTRUCTIONS TO CANDIDATES 1. Use blue/black ball point pen only. There is no negative marking. 2. All the questions are compulsory. This test booklet contains 200 questions (Paper-I : 100 & Paper-II : 100) of one mark each. 3. Paper-I : MAT : 1 - 100 questions Paper-II : SAT : 101 - 200 questions 4. Answer each question by darkening the one correct alternative among the four choices on the OMR Sheet with blue/black ball point pen. 5. Students are not allowed to scratch/alter/change out an answer once marked on OMR Sheet, by using white fluid/eraser/blade/tearing/wearing or in any other form. 6. Separate sheet has been provided for rough work in this test booklet. 7. Please handover the OMR sheet to the invigilator before leaving the Examination Hall. 8. Darken completely the ovals of your answers on OMR Sheet in the time limit allotted for that particular paper. 9. Your OMR Sheet will be evaluated through electronic scanning process. Incomplete and incorrect entries may render your OMR sheet invalid. 10. Use of electronic gadgets, calculator, mobile etc., is strictly prohibited. 1 NTSE (S-I) 2018-19 PAPER-I : MENTAL ABILITY TEST (MAT) 1. 19, 24, 31, 42, 55, 72, __?__ 6. 6, 7, 10, 8, 16, 15, 26, 23, 42, 38, 68, __?__ (1) 83 (2) 89 (1) 61 (2) 80 (3) 91 (4) 93 (3) 106 (4) 120 Answer (3) Answer (1) Sol. 19, 24, 31, 42, 55, 72, 91 Sol. 6, 7, 10, 8, 16, 15, 26, 23, 42, 38, 68, 61 +5 +7 +11 +13 +17 +19 Alternative Numbers, , 6, 10, 16, 26, 42, 68 Consecutive Prime Numbers Sum of 2 No’s 2. 10, 58, 105, __?__, 196, 240, ...... give 3rd No. , 7, 8, 15, 23, 38, 61 (1) 150 (2) 151 (7+8=15, 8+15=23, 15+23 = 38, 23+38=61) (3) 154 (4) 147 7. Answer (2) 2 7 7 Sol. 10, 58, 105, 151, 196, 5 37 9 11 62 3 17 88 ? +48 +47 +46 +45 6 6 5 3. Z, W, R, K, __?__ (1) 20 (2) 59 (1) B (2) F (3) 85 (4) 10 (3) D (4) A Answer (4) Answer (1) Sol. Sol. Z, W, R, K, B d 26 23 18 11 2 2 7 3 5 7 9 a 5 37 9 c 17 ? 4. 1, 4, 13, 40, 121, __?__ 88 (1) 202 (2) 364 6 5 (3) 148 (4) 210 b Answer (2) ab+(c-d)=(5x6)+(9-2)=37 (17x5)+(x-7)=88 85 + x-7=88 4, 13, 40, 364 Sol. 1, 121, x-7 =3 +3 +9 +27 +81 +243 x =7+3 = 10 31 32 33 34 35 8. PEN : WRITING : : CYCLE : ________ (1) REPAIRING (2) CAR 5. 0, 1, 2, 3, 6, 11, 20, __?__ (3) RIDING (4) ROAD (1) 31 (2) 34 Answer (3) (3) 37 (4) 22 Sol. PEN : WRITING : CYCLE RIDING Answer (3) 9. EYE : FACE : : ________ Sol. 0, 1, 2, 3, 6, 11, 20, 37 (1) RING : FINGER (2) STEM : ROOT fibonacci series (3) KNOB : DOOR (4) SHOE : FOOT 0+1+2=3 1+2+3=6 2+3+6=11 3+6+11=20 Answer (3) 6+11+20=37 Sol. EYE : FACE : KNOB : DOOR 2 NTSE (S-I) 2018-19 10. WING : BEAK : : ________ Sol. 1001 = 7 x 11 x 13 (1) BUTION : SHIRT (2) PLUTO : VENUS 2431 = 11 x 13 x 17 (3) HOUSE : CHIMNEY (4) BIRD : CAGE N = 7 x 11 x 13 x 17 Answer (2) 17. The largest number which divides 62, 132 and 237 to leave the same remainder in each case is : Sol. WING : BEAK : : PLUTO : VENUS (1) 51 (2) 35 11. ROOM : HOUSE : : ________ (3) 8 (4) 53 (1) REFRIGERATOR : KITCHEN Answer (2) (2) CHAIR : ROOM Sol. 132 - 62 = 70 (3) ROOF : BUILDING 237 - 132 = 105 (4) WHEEL : CHAIR 237 - 62 = 175 Answer (3) HCF of 70, 105, 175 is 35. Sol. ROOM : HOUSE : : ROOF : BUILDING 18. Traffic lights at three different road crossings change 12. 5 : 29 : : __?__ : 41 after every 48 sec, 72 sec and 108 sec respectively. (1) 30 (2) 6 IF they all change simultaneously at 7 : 00 : 00 (3) 7 (4) 4 house then at what time will they again change simultaneously? Answer (3) (1) 7 : 14 : 00 Hrs (2) 7 : 14 : 12 Hrs Sol. 5 : 29 :: 7 :41 (5x6-1) = 29 7x6-1 = 41 (3) 7 : 07 : 12 Hrs (4) 7 : 09 : 12 Hrs 13. CANADA : DOLLAR : : GERMANY : _______ Answer (3) (1) YEN (2) DOLLAR Sol. 48 = 24 x 3 (3) DEUTSCHE MARK (4) RIYAL 72 = 23 x 32 Answer (3) 108 = 22 x 33 Sol. L.C.M. = 24 x 33 CANADA : DOLLAR :: GERMANY : DEUTSCHE MARK = 16 x 27 14. CARBOHYDRATE : POTATO : : FAT : ______ = 432 seconds (1) CARROT (2) TOMATO 7 : 07 : 12 (3) WATER (4) GHEE 19. A student got twice as many sums wrong as he got Answer (4) right. If he attended 60 sums in all, how many did Sol. CARBOHYDRATE : POTATO : FAT : GHEE he solve correctly? (1) 12 (2) 16 15. DAVIS CUP : LAWN TENNIS : : DEODHAR TROPHY : ______ (3) 24 (4) 20 (1) FOOTBALL (2) CRICKET Answer (4) (3) HOCKEY (4) SHUTTLE COCK Sol. Let 'x' be the number of questions solved. Answer (2) 2x + x = 60 Sol. DAVIS CUP : LAWN TENNIS : : 3x = 60 DEODHARTROPHY : CRICKET x = 20 16. There are four prime numbers written in ascending 111 1 order. The product of the first three is 1001 and that 20. ... ? of the last three is 2431. The last number is : 5 6 6 7 7 8 24 25 (1) 17 (2) 19 (1) 0.36 (2) 0.16 (3) 23 (4) 13 (3) 0.016 (4) 1.6 Answer (1) Answer (2) 3 NTSE (S-I) 2018-19 11 54 54 22 Sol. 24. If x and y then xy is : 525 54 54 4 (1) 322 (2) 100 0.16 25 (3) 312 (4) 85 2x 3 21. If 1 then the value of x is : Answer (1) 1 x Sol. 1 1x 22 x54,y54 5 6 22 2 (1) 6 (2) 5 xy(xy)2xy 4 5 = 322 (3) 5 (4) 4 25. If 13 3.605 and 130 11.40 find : Answer (2) (1) 37.34 (2) 37.034 Sol. (3) 37.0034 (4) 37.304 2x 3 1 Answer (4) 1 x 1 Sol. 37.304 1x 11111 6 ? x 26. 5 98 87 76 65 54 22. If x means +, means , means x and + (1) 8 (2) 5 means then 36 + 18 9 3 x 26 is : (3) 3 (4) - 3 (1) 40 (2) 78 Answer (2) (3) 1 (4) 1 Sol. Answer (4) 98 87 76 65 54 Sol. 1 9887766554 32 23. Notebooks were distributed equally among children 5 of a class. The notebooks each child got was one- eighth of the number of children. IF the number of (0.03)22 (0.21) (0.065) 2 ? children is half, each child would have got 16 27. 22 2 (0.003) (0.021) (0.0065) notebooks. The total number of notebooks distributed is : 1 (1) 10 (2) 100 (1) 512 (2) 312 (3) 248 (4) 428 1 (3) 10 (4) 100 Answer (1) Answer (3) Sol. Let 'x' be the number of children. Sol. x Each child will get books. 22 2 8 (0.03) (0.21) (0.065) 22 2 xx2 (0.003) (0.021) (0.0065) x Therefore, total books distributed 22 2 88 (0.03) (0.21) (0.065) 22 2 ⎛⎞2 (0.03) (0.21) (0.065) x ⎜⎟ 1022 10 10 2 ⎝⎠8 Given 16 = x = 64 22 2 ⎛⎞x ⎛⎞(0.03) (0.21) (0.065) 102 ⎜⎟ ⎜⎟ ⎜⎟22 2 ⎝⎠2 ⎝⎠(0.03) (0.21) (0.065) Total number of books distributed = 512 10 4 NTSE (S-I) 2018-19 28. A lead pencil is in the shape of right circular cylinder. 31. A cone, a hemisphere and a cylinder have equal The pencil is 28 cm long and its radius is 3 mm. IF bases. IF the heights of the cone and the cylinder the lead is of radius 1 mm, the volume of the wood are equal to its common radius, then the ratio used is : between their volumes is : (1) 0.352 cm3 (2) 7.04 cm3 (1) 2 : 3 : 1 (2) 3 : 2 : 1 (3) 3.52 cm3 (4) 70.4 cm3 (3) 1 : 2 : 3 (4) 2 : 1 : 3 Answer (2) Answer (3) Sol. Volume of the wood used for Sol. ⎛⎞⎛⎞⎛⎞3122 12 ⎜⎟28 cm3 r:333 r:r Pencil ⎜⎟⎜⎟⎜⎟ 33 ⎝⎠⎝⎠⎝⎠10 10 12 42 ::1 28 33 10 10 1: 2: 3 22 2 28 725 32. One side of a rhombus is 20 cm and one diagonal 3 is 24 cm. Find the area of the rhombus. 7.04cm (1) 200 cm2 (2) 384 cm2 29. The difference between a two digit number and the number obtained by interchanging the positions of its (3) 298 cm2 (4) 348 cm2 digits is 36. The difference between the two digits of Answer (2) that number is : 1 24 32 (1) 4 (2) 3 Sol. Area of Rhombus 2 (3) 6 (4) 5 12 32 Answer (1) 384cm2 Sol. Let the digits be x & y with x > y. Given (10x + y) - (x + 10y) = 36 33.