From Brouwer's Thesis to the Fan Functional

From Brouwer's Thesis to the Fan Functional

From Brouwer's Thesis to the Fan Functional Ulrich Berger Swansea University University of Birmingham Theoretical Computer Science Seminar February 21, 2020 1 / 36 Overview 1. Introduction 2. Brouwer's thesis 3. Abstract bar induction 4. Vacuous truth 5. Proving uniform continuity 6. Extracting the fan functional 2 / 36 Introduction What are the logical roots of intriguing algorithms/computing principles? I Primitive recursion comes from induction on N. I General recursion comes from wellfounded induction. I The extended Euklidean algorithm comes from a classical proof that Z is a principal ideal ring. I Normalization by evaluation (for the typed lambda-calculus) comes from the Tait/Girard proof of strong normalization, respectively a completeness proof for intuitionistic logic. I ... Where does Tait's fan functional come from? 3 / 36 The fan functional The fan functional computes for every continuous function on Cantor space with values in N its least modulus of uniform continuity: FAN :(f0; 1gN ! N) ! N FAN(F ) = µn 8α; β (α =n β ! F α = F β) Def where α =n β = 8k 2 N (k < n ! α k = β k). So, clearly, this must come from: Fan theorem: Every continuous function on Cantor space with values in N is uniformly continuous. The real question is what are the right logical and mathematical principles and what is the right formal system for a proof of this theorem in order to extract the fan functional, more precisely, a purely functional program that computes it? 4 / 36 Brief history of the fan functional Tait introduced the Fan functional in 1963 and showed that it is recursively continuous but not computable by Kleene's schemata S1-S9, thus shattering Kleene's hope that S1-S9 is a universal notion of computation in higher types. Tait's proof of non-S1-S9-computability had a gap which was noted and fixed in various ways by Gandy, Hyland, Normann, Escardo . The above holds if S1-S9 is interpreted in the hereditarily total continuous functionals by Kleene and Kreisel (1959). If, however, S1-S9, is interpreted in the partial continuous functionals by Scott and Ershov (1970s), then there is an S1-S9 (equivalently PCF) definable functional whose restriction to total arguments is the Fan functional (Gandy 19??, B 1990). In 2000, Normann proved that, in fact, every total recursive functional can be S1-S9 defined in this way, so S1-S9 is universal, when interpreted in the 'right' way. In 2015, Escardo and Oliva generalized the Fan functional to the notion of 'products of selection functionals' and applied it to game theory. 5 / 36 Brouwer's thesis Brouwer's thesis (BT) Every bar is inductive. A predicate P on natural numbers is a bar if 8α9n P(¯α n) P is an inductive bar if IBP (hi) holds where, inductively, (i) If P(s), then IBP (s). (ii) If IBP (s ∗ n) for all n 2 N, then IBP (s). More compactly, µ IBP (s) = P(s) _ 8n IBP (s ∗ n)(µ means 'least') Hence BT can be written as the schema 8α9n P(¯α n) ! IBP (hi) 6 / 36 Bar induction for decidable bars (BI) If (1) P is a bar, (2) P decidable and P ⊆ Q, (3) 8s (8n Q(s ∗ n) ! Q(s)), then Q(hi). Where 'P decidable' means 8n (P(n) _:P(n)). It is easy to see that BT implies BI. 7 / 36 Issues with BT and BI (regarding applicability) BT 8α9n P(¯α n) ! IBP (hi) I restricted to natural numbers I talks about infinite sequences I the premise has computational content which is often not available I the conclusion has unwanted computational content I decidability of the bar P (required in BI) is too restrictive Therefore, we weaken and generalize premise and conclusion. 8 / 36 Paths and accessibility Let ≺ be an arbitrary binary relation. ν Path≺(x) = 9y ≺ x Path≺(y)(ν means 'greatest') µ Acc≺(x) = 8y ≺ x Acc≺(y) Classically, Path≺ and Acc≺ are complements of each other. Path≺(x) means (with dependent choice) that there is an infinite ≺-descending sequence starting with x. Acc≺(x) means that ≺-induction is valid at x. Def Setting s ≺P t = 9n s = t ∗ n ^ :P(t): :Path≺P (hi) means that P is a bar, Acc≺P (hi) means that P is an inductive bar, provided P is decidable. 9 / 36 Brouwer's thesis without computational content The implication Acc≺(x) !:Path≺(x) is intuitionistically valid (easy ≺-induction). The converse is can be viewed as a version of Brouwer's thesis: BT0 8x (:Path≺(x) ! Acc≺(x)) Both, the premise and conclusion of BT0, are Harrop formulas (do not contain _ or 9 at a strictly positive position). Therefore, BT0 has no computational content and hence does not spoil program extraction. 10 / 36 Abstract bar induction (ABI) µ y ≺∗ x = y = x _ 9z (y ≺∗ z ^ z ≺ x) (refl. trans. closure) Def y ≺P x = y ≺ x ^ :P(x) Let x0 be arbitrary (playing the role of the empty sequence). ABI If (1) :Path≺P (x0) ∗ (2) 8x ≺ x0 (:P(x) _ Q(x)), ∗ (3) 8x ≺ x0 (8y ≺ x Q(y) ! Q(x)), then Q(x0). Lemma. BT0 implies ABI. Proof. Assume (1), (2), (3). By BT0, Acc≺P (x0). We prove ∗ Acc≺P ⊆ Q by wellfounded induction. By i.h., 8y ≺P x Q(y). We have to show Q(x). We do a case analysis according to (2). If Q(x), we are done. If :P(x) then the i.h. is equivalent to the premise of (3), hence, again Q(x). 11 / 36 Vacuous truth If A is a formula, then V(A) is a Harrop formula with r V(A) Def= 8a (a r A). For example, r V(?! A) since, a r (?! A) ≡ ? ! a r A. Intuitively, V(A) expresses that A is vacuously true or true (realizable) for trivial reasons. Valid (realizable) rules we will use in the following: A (A Harrop) V(A) A !V(B) V(A) ^ V(B) V(A ! B) V(B ^ A) 8x V(A(x)) 9x V(A(x)) V(8x A(x)) V(9x A(x)) 12 / 36 LEMV , a realizable law of excluded middle :A ! BA !V(B) B Lemma (LEM) The rules for V(·) are realizable. Proof. We only look at LEMV . Assume a r (:A ! B) and r (A !V(B)), that is, (:9c c r A) ! a r B and (9c c r A) ! 8b b r B. Using the law of excluded middle, we conclude a r B. 13 / 36 Abstract bar induction with vacuous bars ABIV If (1) :Path≺P (x0), ∗ (2) 8x ≺ x0 (P(x) !V(Q(x))), ∗ (3) 8x ≺ x0 (8y ≺ x Q(y) ! Q(x)), then Q(x0). Lemma BT0 implies ABIV . Proof. The proof is almost identical to the proof for ABI. The only difference is that we use LEMV to do a case analysis, on whether P(x) holds, using (2). The extracted program takes as input a realizer g of (3) (note that (2) is Harrop) and returns h hi where h s = g s (λa (h (s ∗ a))): 14 / 36 Proving uniform continuity We aim to prove that every total continuous functional F on Cantor space is uniformly continuous and extract from the proof the fan functional that computes the minimal modulus of uniform continuity of F . Language: Sorts: s0 (partial natural numbers), s1 (' s0 ! s0), s2 (' s1 ! s0). Constants: 0; 1; ?, where 0; 1 represent at the same time the first two natural numbers and the Booleans, and ? represents ’undefined’ (not to be confused with the formula ?). Function symbols: +; −, application operation (written by juxtaposition), common (primitive recursive) operations to define finite and infinite sequences. Relation symbol: < (ordinary ordering of numbers). Axioms: The usual disjunctions-free axioms for 0; 1; +; −; <. µ Natural numbers: N(x) = x = 0 _ N(x − 1). Def Booleans: B(x) = x = 0 _ x = 1 15 / 36 Partial functionals We define the partial Booleans and natural numbers as well as the partial functionals of type 1 and 2: Def B?(x) = x 6= ?! B(x) Def N?(x) = x 6= ?! N(x) 1 Def B?(α) = 8n (N(n) ! B?(α n)) 2 Def 1 B?(F ) = 8α (B?(α) ! N?(F α)) 16 / 36 Continuity Specialization order: x v y Def= x 6= ?! x = y α v β Def= 8n 2 N (α n v β n) Monotonicity, finitarity, continuity: Def 1 Mon(F ) = 8α; β 2 B? (α v β ! F α v F β) Def 1 Fin(F ) = 8α 2 B? (8n 2 N F (α " n) = ?! F α = ?) Cont(F ) Def= Mon(F ) ^ Fin(F ) where (α " n) k = if k < n then α k else ?. 17 / 36 Totality Total1(α) Def= 8n (N(n) ! α n 6= ?) Total2(F ) Def= 8α (Total1(α) ! F α 6= ?)) 1 Def 1 1 B (α) = B?(α) ^ Total (α) 2 Def 2 1 B (F ) = B?(F ) ^ Total (F ) 18 / 36 Uniform continuity A type 2 functional F is uniformly continuous if there is (a least) n 2 N such that F α = F β for all total α; β agreeing below n. Def 1 UCont(F ; n) = 8α; β 2 B (α =n β ! F α = F β) UCont(F ) Def= 9n 2 N UCont(F ; n) Def where α =n β = 8k 2 N (k < n ! α k = β k). 2 We aim to prove that every F 2 B? which is total and continuous is uniformly continuous. 19 / 36 Extremal points In the following let F be a total continuous functional, that is, 2 F 2 B and Cont(F ).

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