<p>ME 362 Stream Function Page 1 of 3</p><p>Stream Function ( ):</p><p> Definition: u and v y x</p><p>u v Characteristic: It always satisfies the continuity equation (i.e., 0 ) x y</p><p> Physical meaning: = constant is a streamline</p><p>Change in can be used to determine the flow direction</p><p>Stream Function ( ) vs. Volume Flow (Q) :</p><p>Consider two streamlines as shown below:</p><p> = + d 2 1 dQ dy u 1</p><p> v</p><p> dx</p><p>Volume flow in = Volume flow out dQ udy vdx u , v y x dy dx y x d</p><p> 2 Q d dQ d 2 1 1</p><p> Q is related to the change in </p><p> The flow direction can be determined by checking whether increases or decreases ME 362 Stream Function Page 2 of 3</p><p>Flow Direction:</p><p>There are two ways to determine the direction of flow:</p><p>1) By looking at the change in :</p><p> </p><p>Q Q </p><p> Q 2 1</p><p> If 2 1 Q is positive (indicates flow is to the right)</p><p> If 2 1 Q is negative (indicates flow is to the left)</p><p>2) By looking at direction of u and v:</p><p> streamlines</p><p> v V ~ Q</p><p> By the definition of streamline, the velocity field is always tangent to streamline u Velocity (V) is related to volume flow rate (Q) (because Q = V*A)</p><p> We can find out the flow direction by looking at the velocity direction of u and v</p><p>Direction of u and v Direction of V Direction of Q ME 362 Stream Function Page 3 of 3</p><p>Solution Procedure: </p><p>Step 1: Ensure that continuity equation is satisfied</p><p>u v 0 x y</p><p>Step 2: Solve for stream function </p><p> u udy y or v vdx x </p><p>Step 3: Find the flow direction</p><p> look at the change in </p><p> or</p><p> look at velocity direction of u and v</p><p>Example:</p><p>Given a 2-D velocity field:</p><p> y x u ; v ; r x 2 y 2 r 2 r 2</p><p>1) Show that the flow field satisfies mass conservation 2) Find the corresponding stream function 3) Find the flow direction</p><p>To aid your analysis, here are some derivatives and integrals already performed for you: u 2xy u 2x 2 1 x r 4 y r 4 r 2 v 2y 2 1 v 2xy x r 4 r 2 y r 4 y dy ln x 2 y 2 f x x 2 y 2</p>
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