<p> Grade 10 – LC3 – Reinforcement Lessons 5.1 to 5.4</p><p>Name: Date: ___/3/2010</p><p>Section: 10._____ </p><p>Question I</p><p>Circle the correct answer </p><p>1. The minimum value of the Quadratic function : f ( x ) = x 2 – 4 x + 2 is </p><p> a. 0 b. 2 c. -2 d. -4 </p><p>2. Use the graph to determine the solutions of the Quadratic function : </p><p> f(x) = x 2 – x – 6 a. -6 b. -2 c. -3 and 2 d. – 2 and 3</p><p>3. Simplify ( 2 – 5 i ) ( 2 + 5 i ) </p><p> a. 21</p><p>IAT-LC3 1/8 b. -1 c. 9 d. 4 – 10 i </p><p>4. Find a Quadratic equation with roots – 4 and 6 </p><p> a. x2 – 24 x – 2 = 0 b. x 2 – 2 x – 24 = 0 c. x 2 + 2 x – 24 = 0 d. x 2 + 2 x + 24 = </p><p>IAT-LC3 2/8 Question II</p><p> f (x) = x 2 – 2 x - 4</p><p>1. Find the y-intercept, the equation of the axis of symmetry and the x coordinate of the vertex </p><p> y-intercept : </p><p> axis of symmetry : </p><p> vertex : </p><p>2. Make a table of values that includes the vertex </p><p>X </p><p> f ( x )</p><p>IAT-LC3 3/8 3. Use this information to graph this function </p><p>4. Use the related graph to determine its solutions </p><p>5. Determine whether the function has a maximum or a minimum value and find the maximum or minimum value</p><p>6. State the domain and the range of the function</p><p>IAT-LC3 4/8 Question III</p><p>Solve by Factoring : </p><p>1. x 2 – 4 x – 12 = 0 </p><p>2. 9 x 2 – 36 = 0 </p><p>3. x 2 – 9 x = 0 </p><p>4. 2 x 2 – 12 x + 18 = 0 </p><p>IAT-LC3 5/8 Question IV</p><p>Simplify : </p><p>1.  49 = </p><p>2.  25x 6 = </p><p>3.  64a 8b 6 = </p><p>4. ( 3 + 6 i ) ( 4 - 3 i ) = </p><p>5. ( 2i + 3 ) – ( 21i – 4 )</p><p>6. ( 2i + 5 ) + ( 32i - 6 )</p><p>7. (- 2i) (5 i) (-4 i) = </p><p>IAT-LC3 6/8 8. 2 i (- 2 i) 2 = </p><p>9. i 27=</p><p>2  i 10. 4  3i</p><p>11. Solve the equation below: </p><p>3 2 x - 1 = 0 4</p><p>12. Solve for m and n: </p><p>14 + 2i = 2m +9ni</p><p>IAT-LC3 7/8 13. The impedance in one part of a series circuit is 3 + 4j ohms, and the impedance in another part of the circuit is 2 – 6j. Add these complex numbers to find the total impedance in the circuit.</p><p>14. The voltage in a circuit is 14 – 8j volts, and the impedance is 2 – 3j ohms. What is the current?</p><p>IAT-LC3 8/8</p>