<p> Solutions to odd numbered homework problems from McQuarrie 4th edition </p><p>Chapter 1</p><p>5. (a) 2.77 x 10-8</p><p>(b) 1.82 x 10-3</p><p>(c) 1.23 x 108</p><p>(d) 1.254 x 103</p><p>7. 120.6 x 10-25</p><p>9. (a) centi (b) micro (c) milli (d) giga (e) mega (f) atto</p><p>11. (d) < (a) < (e) < (c) < (b) = (f)</p><p>13. 4.189 x 10-30 m3</p><p>15. 13.6 g/cm3</p><p>17. -268.93 oC</p><p>-426.47 oF</p><p>19. 150 m</p><p>25. -0.6 %</p><p>29. (a) 3 (b) 4 (c) 4 (d) 2 (e) unlimited</p><p>31. (a) 2 (b) 2.08 x 104 (c) 2.8 (d) 2.4 x 10-4</p><p>35. (a) 0.215 m (b) 7.56 m (c) 120 pg (d) 15 Gbyte </p><p>(e) 6.67 x 10-3 cm3 </p><p>51. (a) and (b) 59. (a) Group 1 average = 11.4 g/cm3</p><p>Group 2 average = 11.4 g/cm3</p><p>Group 3 average = 11.1 g/cm3</p><p>(b) Group 1 and 2 data is the most accurate since the % error is the lowest.</p><p>(c) Group 2 is the most precise since the three measurements are closest to each other.</p><p>61. 4.57 mL</p><p>73. No</p><p>Chapter 2</p><p>19 (a) lithium sulfide</p><p>(b) barium oxide</p><p>(c) magnesium phosphide</p><p>(d) cesium bromide</p><p>21. (a) silicon carbide</p><p>(b) gallium phosphide</p><p>(c) aluminum oxide</p><p>(d) beryllium chloride</p><p>23. (a) chlorine trifluoride and chlorine pentafluoride</p><p>(b) sulfur tetrafluoride and sulfur hexafluoride</p><p>(c) krypton difluoride and krypton tetrafluoride</p><p>(d) bromine oxide and bromine dioxide 25. (a) nitrogen dioxode</p><p>(b) ammonia</p><p>(c) zinc sulfide</p><p>(d) potassium oxide</p><p>77. (a) 53 protons in I and 53 protons in I-</p><p>(b) 78 neutrons in I and 78 neutrons in I-</p><p>(c) 53 electrons in I and 54 electrons in I-</p><p>79. In the first compound we have 1.87/1.87 = 1.00. In other words there is 1.00 g of oxygen for every 1.00 g of sulfur.</p><p>In the second compound we have 5.91/3.94 = 1.50. In other words there is 1.50 g of oxygen for every 1.00 g of sulfur. </p><p>The ratio 1.50/1.00 = 3/2 is itself a small whole number ratio thus illustrating the law of multiple proportions. </p><p>81. Atomic mass = 31.1, the element is phosphorous</p><p>Chapter 10</p><p>1. (a) calcium cyanide (b) silver perchlorate (c) potassium permanganate (d) strontium chromate</p><p>3. (a) ammonium sulfate (b) ammonium phosphate (c) calcium phosphate (d) potassium phosphate</p><p>5. (a) mercury (I) chloride (b) chromium (III) nitrate (c) cobalt (II) bromide (d) copper (II) carbonate</p><p>7. (a) Na2S2O3 (b) KHCO3 (c) NaClO (d) CaSO3</p><p>9. (a) Na2SO3 (b) K3PO4 (c) Ag2SO4 (d) NH4NO3</p><p>11. (a) Cr2O3 (b) Sn(OH)2 (c) Cu(C2H3O2)2 (d) Co2(SO4)3</p><p>13. (a) H2S (b) Al2O3 (c) K2Cr2O3 (d) Ni(C2H3O2)2 19. (a) organic (b) binary (c) organic (d) oyyacid</p><p>21. (a) sulfurous (b) bromic (c) hypophosphorous (d) periodic</p><p>23. (a) potassium hypobromite (b) calcium hydrogen phosphite </p><p>(c) lead (II) chlorite (d) nickel (II) perchlorate</p><p>Chapter 3</p><p>7. (a) 2 Na (s) + I2 (s) → 2 NaI (s)</p><p>(b) Sr (s) + H2 (g) → SrH2 (s)</p><p>(c) Ba (s) + Cl2 (g) → BaCl2 (s)</p><p>(d) Mg (s) + O2 (g) → MgO2 (s)</p><p>Chapter 11</p><p>1. (a) 0.519 mol (b) 4.1 mol (c) 638 mol (d) .0922 mol</p><p>21. empirical formula is C3H5O molecular formula is C3H5O</p><p>23. empirical formula is NaPO3 molecular formula is Na6P6O18</p><p>25. empirical formula is C3H4O3</p><p>81. 110 g of Sn required</p><p>83. empirical formula is C5H4 molecular formula is C10H8 Chapter 10</p><p>17. HCl, HClO, HC2H3O2</p><p>33. (a) decomposition (b) combination (c) single displacement (d) double displacement</p><p>51. (a) CuCl2 (aq) + Na2S (aq) → CuS (s) + 2 NaCl (aq)</p><p>Cu2+ (aq) + S2- (aq) → CuS (s)</p><p>(b) MgBr2 (aq) + K2CO3 (aq) → MgCO3 (s) + 2 KBr (aq)</p><p>2+ 2- Mg (aq) + CO3 (aq) → MgCO3 (s)</p><p>(c) BaCl2 (aq) + K2SO4 (aq) → BaSO4 (s) + 2 KCl (aq)</p><p>2+ 2- Ba (aq) + SO4 (aq) → BaSO4 (s)</p><p>(d) Hg2(NO3)2 (aq) + 2 KCl (aq) → Hg2Cl2 (s) + 2 KNO3 (aq)</p><p>2+ - Hg2 (aq) + 2 Cl (aq) → Hg2Cl2 (s)</p><p>53. (a) H2SO4 (aq) + 2 NaHCO3 (aq) → 2 CO2 (g) + 2 H2O (l) + Na2SO4 (aq)</p><p>+ - 2 H (aq) + 2 HCO3 (aq) → 2 CO2 (g) + 2 H2O (l) </p><p>(b) 2 HNO3 (aq) + CaS (aq) → H2S (g) + Ca(NO3)2 (aq)</p><p>+ 2- 2 H (aq) + S (aq) → H2S (g)</p><p>(c) 2 HCl (aq) + Na2SO3 (aq) → SO2 (g) + H2O (l) + 2 NaCl</p><p>+ 2- 2 H (aq) + SO3 (aq) → SO2 (g) + H2O (l) </p><p>55. (a) 2 HClO3 (aq) + Ba(OH)2 (aq) → 2 H2O (l) + Ba(ClO3)2 (aq)</p><p>+ - H (aq) + OH (aq) → H2O (l) (b) HC2H3O2 (aq) + KOH (aq) → H2O (l) + KC2H3O2 (aq) </p><p>- - HC2H3O2 (aq) + OH (aq) → H2O (l) + C2H3O2 (aq)</p><p>(c) 2 HI (aq) + Mg(OH)2 (s) → 2 H2O (l) + MgI2 (aq)</p><p>+ 2+ 2 H (aq) + Mg(OH)2 (s) → 2 H2O (l) + Mg (aq)</p><p>(d) H2SO4 (aq) + 2 RbOH (aq) → 2 H2O (l) + Rb2SO4 (aq)</p><p>+ - H (aq) + OH (aq) → H2O (l) </p><p>61. (a) calcium oxidized, chlorine reduced (b) aluminum oxidized, oxygen reduced (c) rubidium oxidized and bromine reduced (d) sodium oxidized and sulfur reduced</p><p>63. (a) 2 (b) 6 (c) 1 (d) 2</p><p>73. Place the metal in a solution of HCl. If the metal dissolves and hydrogen gas is produced, the metal is nickel since nickel is more active than hydrogen. If no reaction occurs then the metal is silver since silver is less active than hydrogen. Chapter 12</p><p>3. 0.0250 M</p><p>7. 8.3 mL</p><p>13. HI is a strong electrolyte, NH4Br is a strong electrolyte, HC2H3O2 is a weak electrolyte, KOH is a strong electrolyte, CH3OH is a nonelectrolyte </p><p>15. 0.30 M in Ca2+ and 0.60 M in OH-</p><p>2+ 2- 27. 3.93 g of Cu(s) produced, [Zn ] = 0.165 M, [SO4 ] = 0.165 M</p><p>29. 0.171 M</p><p>31. (a) 2.8 uL</p><p>(b) 8.33 mL</p><p>37. 92.0 g/mol</p><p>3+ - 43. [Sc ] = .0495 M, [NO3 ] = 0.149 M</p><p>45. 0.0500 M</p><p>53. 0.200 M</p><p>63. 10.1 mL, 2.51 g</p><p>81. 71.3%</p><p>Chapter 13</p><p>41. 0.901 g</p><p>43. 0.54 g</p><p>49. 442 m/s</p><p>53. 200 mL/hr.</p><p>55. 70.5 g/mol 63. 16.7 bar</p><p>73. 480 g</p><p>75. C3H6O3</p><p>77. 595 OC</p><p>81. 0.733 g</p><p>85. 91.8 g/mol</p><p>87. 87.0% Zn, 13.0% Al</p><p>Chapter 14</p><p>61. -46.3 kJ/g , -2040 kJ/mol</p><p>63. 370 g</p><p>65. -827 kJ/mol</p><p>73. (a) work done by the system on the surroundings, w is (-)</p><p>(b) no work is done</p><p>(c) work done on the system by the surroundings, w is (+)</p><p>(d) work done by the system on the surroundings, w is (-)</p><p>83. (a) U = -564.2 kJ/mol</p><p>(b) U = -506.3 kJ/mol</p><p>(c) U = -184.6 kJ/mol</p><p>87. -1.48 x 103 kJ Chapter 4</p><p>1. Ba<Kr<Ne<He</p><p>3. 4.41 aJ (4.41x10-18 J)</p><p>5. 0.52 MJ</p><p>17. 3.33 m</p><p>19. 285 nm</p><p>21. 6 photons</p><p>31. 3.97 x 10-12 m = 3.97 pm</p><p>37. Wavelegth will be greater.</p><p>45. 0.5450 aJ (5.450x10-19 J)</p><p>69. 4→3 , 1855 nm 4→2 , 484.7 nm 4→1 , 97.15 nm 3→2 , 656.1 nm 3→1 , 102.5 nm 2→1 , 121.5 nm</p><p>Chapter 5</p><p>5. (b) 1p (d) 2d</p><p>9. If l=2 then n must be greater than or equal to 3. If ml = 3 then l must be greater than or equal to 3. 11. n l ml ms</p><p>5 2 2 +1/2</p><p>5 2 2 -1/2</p><p>5 2 1 +1/2</p><p>5 2 1 -1/2</p><p>5 2 0 +1/2</p><p>5 2 0 -1/2</p><p>5 2 -1 +1/2</p><p>5 2 -1 -1/2</p><p>5 2 -2 +1/2</p><p>5 2 -2 -1/2</p><p>13. s orbital 2 p subshell 6 d subshell 10 f subshell 14</p><p>27. (a) [Ar]4s2</p><p>(b) [Ar]4s23d104p5</p><p>(c) [He]2s22p1</p><p>(d) [Ar]4s23d10</p><p>(e) [Xe]6s24f145d4</p><p>31. (a) 2</p><p>(b) 2</p><p>(c) 3</p><p>(d) 4 37. (a) 0</p><p>(b) 3</p><p>(c) 0</p><p>(d) 1</p><p>(e) 0</p><p>39. (a) Ar (b) N (c) Ne</p><p>(d) I (e) Ar</p><p>45.</p><p>17. 3.33 m</p><p>19. 285 nm</p><p>21. 6 photons</p><p>31. 3.97 x 10-12 m = 3.97 pm</p><p>37. Wavelegth will be greater.</p><p>45. 0.5450 aJ (5.450x10-19 J)</p><p>69. 4→3 , 1855 nm 4→2 , 484.7 nm 4→1 , 97.15 nm 3→2 , 656.1 nm 3→1 , 102.5 nm 2→1 , 121.5 nm </p>