Translate and Reflect Trigonometric Graphs

Translate and Reflect Trigonometric Graphs

<p>14.2 Translate and Reflect Trigonometric Graphs</p><p>Goal  Translate and reflect trigonometric graphs.</p><p>Your Notes TRANSLATION OF SINE AND COSINE GRAPHS To graph y = a sin b(x  h) + k or y  a cos b(x  h) + k where a > 0 and b > 0, follow these steps: 2 Step 1 Identify the amplitude a, the period , the horizontal shift h, and the vertical shift k of the graph. b Step 2 Draw the horizontal line y = k, called the _midline_ of the graph. Step 3 Find the five key points by translating the key points of y = a sin bx or y = a cos bx _horizontally_ h units and _vertically_ k units. Step 4 Draw the graph through the five translated key points. Your Notes</p><p>Example 1 Graph a vertical translation</p><p>Graph y = 3 sin 2x + 1</p><p>Solution Step 1 Identify the amplitude, period, horizontal shift, and vertical shift.</p><p>Amplitude: a = _3_ Horizontal shift: h = _0_</p><p>2 2 Vertical shift: k = _1_ Period:  b 2 = _  _</p><p>Step 2 Draw the midline of the graph, y = _1_. Step 3 Find the five key points. On y = k: (0, 0 + 1) = _(0, 1)_ ;</p><p>Because the graph is shifted up 1 unit, the y-coordinates of the five key points will be increased by 1.</p><p>     , 0 1   , 1 ;  2   2 </p><p> , 0 1  , 1     Maximum: , 31   , 4  4   4   3   3  Minimum:  ,31   ,2  4   4  Step 4 Draw the graph through the key points.</p><p>Checkpoint Graph the function. 1. y = 4 sin 2x + 3 Your Notes</p><p>Example 2 Combine a translation and a reflection</p><p>1    Graph y = 3 sin  x . 4  4  Step 1 Identify the amplitude, period, horizontal shift, and vertical shift.</p><p> Amplitude:  a  = _3_ Horizontal shift: h = 4 2 2 Period:  b 1 Vertical shift: k = _0_ 4 = _8  _ Step 2 Draw the midline of the graph. Because _ k = 0_ , the midline is the _ x -axis_. 1    Step 3 Find the five key points of y =  3  sin  x  . 4  4       On y = k: 0  ,0   , 0 ;  4   4     17  4  ,0   , 0 ;  4   4 </p><p>Because the graph is shifted to the  right units, the 4 x-coordinates of the five key points will be increased  by 4</p><p>    33  8  ,0   , 0  4   4      9  Maximum: 2  , 3   , 3  4   4      25  Minimum: 6  ,  3   ,  3  4   4  Step 4 Reflect the graph. Because a < 0, the graph is reflected in the midline y = 0. So,  9   9   25   25   , 3 becomes  ,3and  ,3 becomes  , 3 .  4   4   4   4 </p><p>The minimum and maximum of the original graph become the maximum and minimum, respectively, of the reflected graph. Step 5 Draw the graph through the key points found. Your Notes</p><p>Example 5 Model with a tangent function</p><p>Flagpole You watch a classmate lower a flag on a 20-foot flagpole. You are standing 15 feet from the base of the flagpole. Write and graph a model that gives the flag's distance d (in feet) from the top of the flagpole as a function of the angle of elevation .</p><p>Solution Use a tangent function to write an equation relating d and .</p><p> opp 20  d tan  =  Definition of tangent adj 15</p><p>__15 tan  __= __20  d__ Multiply each side by 15. __15 tan   20__ = _  d _ Subtract 20 from each side. __15 tan  + 20__ = _ d _ Solve for d. The graph is shown at the right. Checkpoint Complete the following exercises. 2. Graph y = 2 cos (x + ).</p><p>3. Write and graph a model for Example 3 if you stand 10 feet from the flagpole.</p><p>Homework ______</p><p>______</p>

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