<p>Current – the ______of charge in a circuit. Charge is measured in ______symbol______Current is measured in ______symbol______An ______is a ______per second *for current to flow in a circuit, the circuit must be closed/open</p><p>Voltage (Potential Difference) – When charge is flowing in a circuit, the energy of the charge, (______) is converted to other forms when going through a resistive device(light bulb, heating element, speaker, etc). The voltage is how much energy per unit charge is converted.</p><p>Voltage = Energy converted/unit charge (______)/(______) = Volts symbol______</p><p>Resistance - ______the flow of electrons in a complete circuit Measured in ______symbol______*The resistance of a resistor is independent of the current through the resistor and the potential difference across it.</p><p>OHM’S LAW *For most conductors (not semiconductors) the resistance is the ratio of voltage to current.</p><p>R = V/ I Problem: A 1.5 V battery is connected to a small light bulb with a resistance of 3.5 . What is the current through the bulb?</p><p>Circuits Symbols Series Circuit</p><p>The total resistance in a series circuit is the ______of the individual resistances.</p><p>Current in a series circuit is the ______throughout the circuit</p><p>The voltage in a series circuit is ______between the individual resistances.</p><p>1. In the diagram above, what is the total resistance?</p><p>2. What would be the voltage across each resistor?</p><p>3. What is the current flowing through each resistor?</p><p>Parallel Circuit</p><p>The total resistance in this circuit is ______than the resistance of each individual resistance.</p><p>The current in this circuit is ______between the branches of the circuit</p><p>The voltage is the ______across each resistor in a parallel circuit.</p><p>1. In the diagram above what is the total resistance in this circuit?</p><p>2. If R1 and R2 are the same (10), the current flowing through each branch of the circuit will be equal/unequal</p><p>3. What is the voltage across both 10 resistors?</p>