<p>Academic Chemistry Hess’s Law Worksheet Name: ______</p><p>1. From the following enthalpy changes, </p><p> o C + ½ O2 CO H = -110.5 kJ </p><p> o CO + ½ O2 CO2 H = -283.0 kJ </p><p> o calculate the value of H for the reaction: C + O2 CO2</p><p>2. From the following enthalpy changes, </p><p> o 2P + 3Cl2 2PCl3 H = -640 kJ </p><p> o 2P + 5Cl2 2PCl5 H = -886 kJ </p><p> o calculate the value of H for the reaction: PCl3 + Cl2 PCl5 </p><p>3. From the following enthalpy changes, </p><p> o C2H5OH + 3O2 2CO2 + 3H2O H = -1234.7 kJ </p><p> o CH3OCH3 + 3O2 2CO2 + 3H2O H = -1328.3 kJ </p><p> o calculate the value of H for the reaction: C2H5OH CH3OCH3 </p><p>4. From the following enthalpy changes, </p><p> o Cu + Cl2 CuCl2 H = -206 kJ </p><p> o 2Cu + Cl2 2CuCl H = -136 kJ </p><p> o calculate the value of H for the reaction: CuCl2 + Cu 2CuCl 5. From the following enthalpy changes, </p><p> o H2 + F2 2HF H = -542.2 kJ </p><p> o 2H2 + O2 2H2O H = -571.6 kJ </p><p> o calculate the value of H for the reaction: 2F2 + 2H2O 4HF + O2</p><p>6. From the following enthalpy changes, </p><p> o Xe + F2 XeF2 H = -123 kJ </p><p> o Xe + 2F2 XeF4 H = -262 kJ </p><p> o calculate the value of H for the reaction: XeF2 + F2 XeF4 </p><p>7. From the following enthalpy changes, </p><p> o 4NH3 + 5O2 4NO + 6H2O H = -1170 kJ </p><p> o 4NH3 + 3O2 2N2 + 6H2O H = -1530 kJ </p><p> o calculate the value of H for the reaction: N2 + O2 2NO </p><p>8. From the following enthalpy changes, </p><p> o 2Al + 1.5O2 Al2O3 H = -1601 kJ </p><p> o 2Fe + 1.5O2 Fe2O3 H = -821 kJ </p><p> o calculate the value of H for the reaction: 2Al + Fe2O3 2Fe + Al2O3 9. From the following enthalpy changes, </p><p> o H2O2 H2O + ½ O2 H = -94.6 kJ </p><p> o H2 + ½ O2 H2O H = -286.0 kJ </p><p> o calculate the value of H for the reaction: H2 + H2O2 2H2O </p><p>10. From the following enthalpy changes, </p><p> o C + O2 CO2 H = -393.5 kJ </p><p> o H2 + ½ O2 H2O H = -285.8 kJ </p><p> o 2C2H2 + 5O2 4CO2 + 2H2O H = -2598.8 kJ </p><p> o calculate the value of H for the reaction: 2C + H2 C2H2</p>
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